CBSE 12 Maths Question Paper-2021 Term-1 by Pavan | Practice Test to Test Your Knowledge
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CBSE 12 Maths Question Paper-2021 Term-1

CBSE 12 Maths Question Paper-2021 Term-1

This mock test includes actual CBSE Class 12 Maths board exam questions from the year 2021 Term-1, helping students understand exam trends and practice real paper format

2025-08-12
CBSE Class 12 2021 Mathematics Grade 12

Duration

30 min

Questions

30

Marking

Negative

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sin(π/3 − sin^(-1)(−1/2)) is equal to:

A
1/2
B
1/3
C
-1
D
1

The value of k (k < 0) for which the function f(x) is continuous at x = 0 is:

A
±1
B
-1
C
±1/2
D
1/2

If A = [aij] is a square matrix of order 2 such that aij = 1 when i ≠ j and aij = 0 when i = j, then A^2 is:

A
[1 0; 1 0]
B
[1 1; 0 0]
C
[1 1; 1 0]
D
[1 0; 0 1]

Value of k for which A = [k 8; 4 2k] is a singular matrix is:

A
4
B
-4
C
±4
D
0

Find the intervals in which the function f(x) = x^2 − 4x + 6 is strictly increasing:

A
(-∞, 2) ∪ (2, ∞)
B
(2, ∞)
C
(-∞, 2)
D
(-∞, 2] ∪ (2, ∞)

Given that A is a square matrix of order 3 and |A| = -4, then |adj A| is equal to:

A
-4
B
4
C
-16
D
16

A relation R in set A = {1,2,3} is defined as R = {(1, 1), (1, 2), (2, 2), (3, 3)}. Which of the following ordered pair in R shall be removed to make it an equivalence relation in A?

A
(1, 1)
B
(1, 2)
C
(2, 2)
D
(3, 3)

If [2a + b, a - 2b; 5c - d, 4c + 3d] = [4 −3; 11 24], then value of a + b – c + 2d is:

A
8
B
10
C
4
D
-8

The point at which the normal to the curve y = x + 1/x, x > 0 is perpendicular to the line 3x − 4y − 7 = 0 is:

A
(2, 5/2)
B
(±2, 5/2)
C
(-1/2, 5/2)
D
(1/2, 5/2)

sin(tan^(-1)(x)), where |x| < 1, is equal to:

A
x/√(1 − x^2)
B
1/√(1 − x^2)
C
1/√(1 + x^2)
D
x/√(1 + x^2)

Let the relation R in the set A = {x ∈ Z : 0 ≤ x ≤ 12}, given by R = {(a, b) : |a – b| is a multiple of 4}. Then the equivalence class containing 1 is:

A
{1, 5, 9}
B
{0, 1, 2, 5}
C
D
A

If e^x + e^y = e^(x+y), then dy/dx is:

A
e^y - x
B
e^(x + y)
C
-e^(y - x)
D
2e^(x - y)

Given that matrices A and B are of order 3×n and m×5 respectively, then the order of matrix C = 5A + 3B is:

A
3×5
B
5×3
C
3×3
D
5×5

If y = 5 cos(x) − 3 sin(x), then d²y/dx² is equal to:

A
-y
B
y
C
25y
D
9y

For matrix A = [2 5; -11 7], (adjA)′ is equal to:

A
[-2 -5; 11 -7]
B
[7 5; 11 2]
C
[7 11; -5 2]
D
[7 -5; 11 2]

The points on the curve x²/9 + y²/16 = 1 at which the tangents are parallel to the y-axis are:

A
(0, ±4)
B
(±4, 0)
C
(±3, 0)
D
(0, ±3)

Given that A = [aij] is a square matrix of order 3×3 and |A| = −7, then the value of ∑ ai²Aij for i=1 to 3 is:

A
7
B
-7
C
0
D
49

If y = log(cos(ex)), then dy/dx is:

A
cos(ex)−1
B
e^−x cos(ex)
C
e^x sin(ex)
D
−e^x tan(ex)

Based on the given shaded region as the feasible region in the graph, at which point(s) is the objective function Z = 3x + 9y maximum?

A
Point B
B
Point C
C
Point D
D
Every point on the line segment CD

The least value of the function f(x) = 2cos(x) + x in the closed interval [0, π/2] is:

A
2
B
π/6 + √3
C
π/2
D
The least value does not exist

The function f: R ⟶ R defined as f(x) = x³ is:

A
One-on but not onto
B
Not one-one but onto
C
Neither one-one nor onto
D
One-one and onto

If x = a sec(θ), y = b tan(θ), then d²y/dx² at θ = π/6 is:

A
-3√3b/a²
B
-2√3b/a
C
-3√3b/a
D
-b/3√3a²

In the given graph, the feasible region for a LPP is shaded. The objective function Z = 2x − 3y, will be minimum at:

A
(4, 10)
B
(6, 8)
C
(0, 8)
D
(6, 5)

The derivative of sin^(-1)(2x√(1 − x²)) w.r.t sin^(-1)(x), −1/√2 < x < 1/√2, is:

A
2
B
π/2 − 2
C
π/2
D
-2

If A = [1 −1 0; 2 3 4; 0 1 2] and B = [2 2 −4; −4 2 −4; 2 −1 5], then:

A
A⁻¹ = B
B
A⁻¹ = 6B
C
B⁻¹ = B
D
B⁻¹ = 1/6 A

The real function f(x) = 2x³ − 3x² − 36x + 7 is:

A
Strictly increasing in (−∞, −2) and strictly decreasing in (−2, ∞)
B
Strictly decreasing in (−2, 3)
C
Strictly decreasing in (−∞, 3) and strictly increasing in (3, ∞)
D
Strictly decreasing in (−∞, −2) ∪ (3, ∞)

Simplest form of tan^(-1) (√(1 + cos(x)) + √(1 − cos(x)) / √(1 + cos(x)) − √(1 − cos(x))) , π < x < 3π/2 is:

A
π/4 − x/2
B
3π/2 − x/2
C
-x/2
D
π − x/2

Given that A is a non-singular matrix of order 3 such that A² = 2A, then value of |2A| is:

A
4
B
8
C
64
D
16

The value of b for which the function f(x) = x + cos(x) + b is strictly decreasing over R is:

A
b < 1
B
No value of b exists
C
b ≤ 1
D
b ≥ 1

Let R be the relation in the set N given by R = {(a, b) : a = b – 2, b > 6}, then:

A
(2,4) ∈ R
B
(3,8) ∈ R
C
(6,8) ∈ R
D
(8,7) ∈ R