Diagonals of a Parallelogram
The diagonals of a parallelogram, such as quadrilateral ABCD, are significant in understanding its geometric properties. While it is known that the diagonals are generally not equal in length, they have a unique and important characteristic: they bisect each other.
Key Concept: Bisection of Diagonals
- Definition: To bisect means to divide into two equal parts. In the case of a parallelogram, when the diagonals (e.g., AC and BD) intersect at a point O, they divide each other into two equal segments (AO = CO and BO = DO).
- Activity: By folding a cut-out parallelogram to find the midpoints of the diagonals, students can observe that the midpoints coincide at the intersection point, showcasing the bisection property visually.
- Geometric Proof: Using congruent triangles formed by the diagonals, specifically triangles AOB and COD, we apply the ASA (Angle-Side-Angle) congruency criterion to establish AO = CO and BO = DO, confirming that diagonals bisect each other.
Understanding this property of diagonals is essential as it lays the groundwork for further exploration of parallelograms and their relationships with other geometric figures.
Similar Questions
- Example : HELP is a parallelogram (Lengths are in meters). Given that OE = 5 and HL is 7 more than PE? Find OH.
Solution: If OE = 5 then OP also is 5 (Why?)
PE = 10,
Therefore, HL = 10 + 7 = 17
Hence
\[ OH = \frac{1}{2} \times 17 = 8.5 \; \text{(meters)} \]
- Example: HELP is a parallelogram (Lengths are in feet). If OE = 6 and HL is 4 less than PE, find OH.
Solution: If OE = 6 then OP also is 6 (Why?)
PE = 12,
Therefore, HL = 12 - 4 = 8
Hence
\[ OH = \frac{1}{2} \times 8 = 4 \; \text{(feet)} \]
- Example: HELP is a parallelogram (Lengths are in inches). Given that OE = 3 and HL is 6 more than PE, find OH.
Solution: If OE = 3 then OP also is 3 (Why?)
PE = 5,
Therefore, HL = 5 + 6 = 11
Hence
\[ OH = \frac{1}{2} \times 11 = 5.5 \; \text{(inches)} \]
- Example: HELP is a parallelogram (Lengths are in kilometers). If OE = 7 and HL is twice PE, find OH.
Solution: If OE = 7 then OP also is 7 (Why?)
PE = 4,
Therefore, HL = 2 \times 4 = 8
Hence
\[ OH = \frac{1}{2} \times 8 = 4 \; \text{(kilometers)} \]
- Example: HELP is a parallelogram (Lengths are in centimeters). If OE = 2 and HL is 9 more than PE, find OH.
Solution: If OE = 2 then OP also is 2 (Why?)
PE = 6,
Therefore, HL = 6 + 9 = 15
Hence
\[ OH = \frac{1}{2} \times 15 = 7.5 \; \text{(centimeters)} \]