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4.2. Word Problem Example

Interactive Audio Lesson

Session 1: Understanding Word Problems

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Sarah
SarahInstructor

Today, we’re going to learn how to solve word problems using algebra. Can anyone tell me what a word problem is?

Noah
Noah

Is it a math problem that is written in words instead of numbers?

Sarah
SarahInstructor

Exactly! Word problems present a scenario and require us to translate that into a mathematical equation. For example, ‘three times a number plus five equals twenty.’ Can someone express this in equation form?

Isabella
Isabella

It would be written as 3x + 5 = 20, right?

Sarah
SarahInstructor

Absolutely! In this case, 'x' represents the unknown number we want to find. Now, let’s discuss the steps to isolate x.

Session 2: Solving the Equation

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Robert
RobertInstructor

To solve the equation 3x + 5 = 20, we need to isolate x. What’s the first step?

Akash
Akash

I think we need to subtract 5 from both sides to get rid of the 5.

Robert
RobertInstructor

Correct! So, when we subtract 5, what do we have?

Ananya
Ananya

We get 3x = 15.

Robert
RobertInstructor

Great! Now, we need to divide both sides by 3. What do we get?

Noah
Noah

x = 5!

Robert
RobertInstructor

Fantastic! So, the number we were looking for is 5. Remember this process of isolating variables; it’s key for solving word problems.

Session 3: Real-World Application of Word Problems

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Sarah
SarahInstructor

Now, let’s think about why mastering word problems is important. Can anyone give me a real-life example that could be modeled with a word problem?

Isabella
Isabella

Maybe something like calculating the cost of tickets for a concert?

Sarah
SarahInstructor

Yes! If a ticket costs $10 and you want to buy several tickets, you can represent the total cost with an equation. For instance, if you want to buy x tickets, the equation would be 10x.

Akash
Akash

And if I want to spend $100, then it would be 10x = 100?

Sarah
SarahInstructor

Exactly! You can solve for x to find out how many tickets you can buy. This kind of setup and calculation is very common in everyday scenarios.

Overview

Short Summary

This section illustrates how to solve word problems using algebraic equations.

Medium Summary

The section focuses on the application of algebraic concepts to solve word problems, specifically focusing on the process of setting up and solving linear equations derived from the problem statement.

Detailed Summary

In this section, we delve into the strategy of solving word problems using algebraic expressions and equations. Linear equations often represent word problems, enabling us to derive the unknown through systematic steps. Understanding the structure of a word problem helps in translating the words into mathematical statements, thereby allowing algebraic manipulation to find solutions. We explore a practical example: finding a number that satisfies the equation built from a narrative, emphasizing the importance of isolating variables and using inverse operations to achieve the correct answer.

Audio Book

Voice:
Understanding the Word Problem

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"If 3 times a number plus 5 equals 20, find the number"

Detailed Explanation

This statement presents a problem where we need to find an unknown number. The phrase '3 times a number' suggests that we multiply a variable, usually represented by 'x'. The equation is constructed as follows: 3x + 5 = 20. Here, '3x' represents three times the unknown number, and '+ 5' indicates we add 5 to it. We want to find the value of 'x' such that the equation is true.

Examples & Analogies

Think of it like a treasure hunt. You have a treasure chest (your number), and you know that if you multiply the number of treasures by 3 and then add 5 other items, you will have a total of 20 items in the chest. Your job is to figure out how many treasures you originally had!

Setting Up the Equation

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3x + 5 = 20

Detailed Explanation

In this equation, we are expressing the relationship given in the word problem mathematically. The left side, 3x + 5, must equal the right side, which is 20. We will use algebraic methods to manipulate this equation to find the value of 'x'.

Examples & Analogies

Imagine you're trying to balance a scale. On one side, you have 3 times the number of candies you have (plus 5 extra candies), and on the other side, you know you need to have exactly 20 candies to balance. You need to find out how many candies you originally had on your side.

Isolating the Variable

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First, subtract 5 from both sides: 3x + 5 - 5 = 20 - 5

Detailed Explanation

To isolate the variable 'x', you need to remove the '+ 5' by performing the same operation on both sides of the equation. Subtracting 5 from both sides gives us: 3x = 15. This process is known as maintaining the balance of the equation—it ensures that what we do on one side must be done on the other to keep the equation true.

Examples & Analogies

Think of sharing a cake equally; if you take away the same amount from both sides, the portions remain equal. Here, by taking away 5 from both sides, you're simplifying the problem to find out how many times 'x' fits into the remaining total.

Finding the Value of x

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Now, divide both sides by 3: x = 15 / 3

Detailed Explanation

After simplifying the equation to 3x = 15, we can find the value of 'x' by dividing both sides by 3. This gives us x = 5. By dividing, we are figuring out how many times 3 fits into 15, thereby solving for 'x'.

Examples & Analogies

Imagine you have 15 slices of pizza, and you need to share them evenly among 3 friends (you included). Dividing the total number of slices by 3 gives you how much pizza each person gets; in this case, 5 slices each. Similarly, here we are dividing to find out the original amount.

Conclusion of the Problem

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The solution is x = 5

Detailed Explanation

At this point, we have solved the equation and found that the number we were looking for is 5. This means that if you take 3 times 5, you get 15, and when you add 5, you end up with 20, which confirms our solution.

Examples & Analogies

So, if you have found that you ate 5 pieces of chocolate out of a larger box, and your friend added 5 more pieces, it should feel complete when you look back and see that you ended up with a total of 20 pieces in the box!

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Key Concepts

Core takeaways and short definitions to help you quickly recall the key ideas from this section.

Word Problems: Scenarios described in words that can be converted into algebraic expressions.

Linear Equations: Equations of the form ax + b = c, used to represent relationships.

Isolating Variables: The process of rearranging an equation to solve for a specific variable.

Examples

Step-by-step examples to apply the section's ideas and test your understanding.

1

If three times a number plus five equals twenty, the equation can be represented as 3x + 5 = 20.

2

To find how many tickets you can buy for 100ifeachticketcosts100 if each ticket costs 10, set up the equation 10x = 100.

Memory Aids

Interactive tools to help you remember key concepts

🎵

Rhymes

When a word problem comes your way, set it up right and solve today!
📖

Stories

Imagine a baker with x cookies, who sold 5. If he has 20 left, how many did he bake in the first place?
🧠

Memory Tools

W.R.S. - Word-Represents-Solve. First, recognize that it’s a word problem, represent it as an equation, and then solve.
🎯

Acronyms

S.I.S.T. - Set Up the equation, Isolate the variable, Solve for the variable, and Thoroughly check your answer.

Flash Cards

Glossary

Word Problem

A mathematical problem expressed in words, requiring translation into an algebraic expression or equation.

Variable

A symbol (often a letter) used to represent an unknown value in mathematical equations.

Linear Equation

An equation that makes a straight line when graphed, often in the form ax + b = c.

Isolate

To manipulate an equation to solve for one variable, typically by getting the variable alone on one side.