Current Divider Rule (cdr) (1.3.5.3) - Foundations of DC Circuits
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Current Divider Rule (CDR)

Current Divider Rule (CDR)

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Interactive Audio Lesson

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Introduction to Current Divider Rule

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Teacher
Teacher Instructor

Today, we're diving into the Current Divider Rule, or CDR, which is really useful for analyzing parallel circuits. Can anyone tell me why we would need to divide current in a circuit?

Student 1
Student 1

Maybe to see how much current goes through each component?

Teacher
Teacher Instructor

Exactly! The CDR helps us figure out the current through different branches of a parallel circuit. Remember this formula: for two resistors in parallel, we can use `I1 = Itotal Γ— (R2 / (R1 + R2))`. Can someone recall what the variables mean?

Student 2
Student 2

Itotal is the total current coming into the circuit?

Teacher
Teacher Instructor

Correct! And R1 and R2 are the resistances of the individual resistors. Let's remember: as resistance increases, the current through that resistor decreases. That's the essence of the CDR!

Solving a Simple Example

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Teacher
Teacher Instructor

Let's work on an example. Suppose we have a total current of 6 A entering a parallel circuit with R1 = 3Ξ© and R2 = 6Ξ©. Can anyone tell me how to find the currents I1 and I2?

Student 3
Student 3

We can use the CDR formulas you mentioned earlier!

Teacher
Teacher Instructor

Yes! Let's start with I1. Can you calculate it?

Student 4
Student 4

Using the formula, `I1 = 6 A Γ— (6 / (3 + 6))`, I get I1 = 4 A!

Teacher
Teacher Instructor

Great job! Now, how about I2?

Student 1
Student 1

I2 = 6 A Γ— (3 / (3 + 6)). That gives us I2 = 2 A.

Teacher
Teacher Instructor

Perfect! You've both applied the Current Divider Rule successfully.

Understanding Percentages of Current Division

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Teacher
Teacher Instructor

Let's reflect on the current division in terms of percentages. What percent of the total current is I1?

Student 2
Student 2

I1 is 4 A, and the total is 6 A, so that's approximately 66.67%!

Teacher
Teacher Instructor

Exactly! And what about I2?

Student 3
Student 3

I2 is 2 A out of 6 A, so about 33.33%.

Teacher
Teacher Instructor

Good! By understanding these proportions, we can better design circuits. Remember, the lower the resistance, the higher the current takes that path according to CDR.

Introduction & Overview

Read summaries of the section's main ideas at different levels of detail.

Quick Overview

The Current Divider Rule (CDR) is a method used in circuit analysis to find the current flowing through individual resistors in a parallel circuit.

Standard

The Current Divider Rule (CDR) is essential for analyzing parallel circuits, where it allows for the determination of current distribution among different branches. By applying specific formulas, engineers can predict how much current flows through each parallel resistor based on their resistances.

Detailed

Current Divider Rule (CDR)

The Current Divider Rule (CDR) is a vital technique in electrical engineering used for analyzing parallel circuits. It helps determine how the total current entering a parallel network divides among the various branches of the network. This rule is particularly useful when dealing with two or more resistors connected in parallel.

Key Concepts:

  1. Basic Formula: The current through a resistor in a parallel circuit can be computed using the following formulas:
  2. For resistor R1:

I1 = Itotal Γ— (R2 / (R1 + R2))

  • For resistor R2:

I2 = Itotal Γ— (R1 / (R1 + R2))
2. Application Examples: If you have a total current of 6 A flowing into a circuit with two resistors (R1 = 3Ξ© and R2 = 6Ξ©), you can calculate the current flowing through each resistor using the current divider rule.
- For R1:
I1 = 6 A Γ— (6Ξ© /(3Ξ© + 6Ξ©)) = 6 A Γ— (6 / 9) = 4 A
- For R2:
I2 = 6 A Γ— (3Ξ© /(3Ξ© + 6Ξ©)) = 6 A Γ— (3/9) = 2 A

Significance:

The CDR is especially critical for circuit designers and engineers as it allows efficient calculations in complex circuit layouts without resorting to more laborious methods such as node or mesh analysis.

Audio Book

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Introduction to Current Divider Rule

Chapter 1 of 3

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Chapter Content

● Current Divider Rule (CDR): Used to find the current through a specific resistor in a parallel circuit with two branches.

Detailed Explanation

The Current Divider Rule (CDR) is a method used in parallel circuits to determine how the total current splits between two parallel resistors. When current flows into a junction where two resistors are paralleled, the current is divided between those resistors based on their resistance values. The key idea is that more current will flow through the path of lower resistance. Therefore, the formula allows us to calculate the individual current through each resistor using the total current entering the parallel combination and their respective resistances.

Examples & Analogies

Imagine water flowing through two hoses of different diameters. The larger diameter hose allows more water to flow through it than the smaller one. Similarly, in a circuit, if you have two resistors in parallel, the resistor with the lower resistance (analogous to the wider hose) will allow more current to pass through it compared to the resistor with higher resistance.

Current Divider Rule Formulas

Chapter 2 of 3

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Chapter Content

β—‹ Formula (for two resistors):
1. I1 = Itotal Γ— R1 + R2 (current through R1)
2. I2 = Itotal Γ— R1 + R2 (current through R2)

Detailed Explanation

The CDR has specific formulas for calculating the current through two parallel resistors, R1 and R2, when a total current, Itotal, enters the junction. The first formula (I1 = Itotal Γ— R1 / (R1 + R2)) gives the current flowing through resistor R1, while the second (I2 = Itotal Γ— R2 / (R1 + R2)) gives the current through R2. This division of current is proportional to the resistance values, ensuring that higher resistance gets less current.

Examples & Analogies

If you think of Itotal as a river split into two smaller streams, the width of the streams represents the resistances R1 and R2. If one stream (R1) is wider (lower resistance), it will carry more water (current), while the narrower stream (R2) will carry less, demonstrating how current distribution works in electrical circuits.

Numerical Example

Chapter 3 of 3

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Chapter Content

β—‹ Numerical Example: A total current of 6 A enters a parallel combination of two resistors, R1 = 3Ξ© and R2 = 6Ξ©. Current through R1: I1 = 6 A Γ— 3Ξ© + 6Ξ© / 6Ξ© = 6 A Γ— 9 / 6 = 4 A.

Detailed Explanation

In this numerical example, we begin with a total current of 6 A entering the parallel combination of resistors R1 (3Ξ©) and R2 (6Ξ©). To find how much current flows through R1, we apply the CDR formula. Substituting the values, we find that:

I1 = 6 A Γ— (3Ξ© / (3Ξ© + 6Ξ©)) = 6 A Γ— (3/9) = 6 A Γ— (1/3) = 2 A.

We can similarly calculate I2 for R2. Because the total current (6A) must equal I1 + I2, if we find I1 to be 2 A, then I2 would be 4 A (since 6 A = 2 A + 4 A). This reinforces our understanding of current division and the importance of recognizing resistance values in that division.

Examples & Analogies

Continuing with the water analogy, think of a garden sprinkler system where one sprinkler (R1) has a smaller nozzle compared to another (R2). If a total of 6 gallons of water per minute is directed into the system and the smaller nozzle can distribute water at a lower rate, the smaller nozzle might only deliver 2 gallons, while the larger one efficiently delivers the remaining 4 gallons, parallelly demonstrating how the currents are divided based on resistors’ capacities.

Key Concepts

  • Basic Formula: The current through a resistor in a parallel circuit can be computed using the following formulas:

  • For resistor R1:

  • I1 = Itotal Γ— (R2 / (R1 + R2))

  • For resistor R2:

  • I2 = Itotal Γ— (R1 / (R1 + R2))

  • Application Examples: If you have a total current of 6 A flowing into a circuit with two resistors (R1 = 3Ξ© and R2 = 6Ξ©), you can calculate the current flowing through each resistor using the current divider rule.

  • For R1:

  • I1 = 6 A Γ— (6Ξ© /(3Ξ© + 6Ξ©)) = 6 A Γ— (6 / 9) = 4 A

  • For R2:

  • I2 = 6 A Γ— (3Ξ© /(3Ξ© + 6Ξ©)) = 6 A Γ— (3/9) = 2 A

  • Significance:

  • The CDR is especially critical for circuit designers and engineers as it allows efficient calculations in complex circuit layouts without resorting to more laborious methods such as node or mesh analysis.

Examples & Applications

Example: For a parallel circuit with R1 = 2Ξ© and R2 = 4Ξ© and a total input current of 8 A, the current through R1 would be I1 = 8 A Γ— (4/(2+4)) = 6.67 A and through R2 would be I2 = 8 A Γ— (2/(2+4)) = 2.67 A.

If R1 = 5Ξ© and R2 = 10Ξ© with Itotal of 10 A, then I1 = 10 Γ— (10/(5+10)) = 6.67 A and I2 = 10 Γ— (5/(5+10)) = 3.33 A.

Memory Aids

Interactive tools to help you remember key concepts

🎡

Rhymes

In parallel they stand, resistors side by side, divide the current right, in the great current tide.

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Stories

Imagine a flowing river, with several branches. Each branch represents a resistor and the water is current. The narrower the branch, the less water flows through, while a wider branch allows more.

🧠

Memory Tools

CDR: Calculate, Divide, Result. Just remember to calculate the total resistance, divide based on values, and find out your current result!

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Acronyms

CDR

Current Divided Reliably.

Flash Cards

Glossary

Current Divider Rule (CDR)

A method used to determine the current flowing through individual components in a parallel circuit.

Total Current (Itotal)

The sum of currents flowing into a parallel circuit before division.

Resistance (R)

Resistance is the opposition to the flow of electric current, measured in ohms (Ξ©).

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