12.3.2 - Division of a polynomial by a monomial
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Understanding Polynomial and Monomial Division
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Good morning, class! Today, we are diving into how to divide a polynomial by a monomial. First, can anyone remind me what a polynomial is?
A polynomial is an expression that consists of variables and coefficients, combined using addition, subtraction, and multiplication.
Exactly! And what about a monomial?
A monomial is a single term that can be a number, variable, or the product of numbers and variables.
Great! Now, let’s explore how to divide a polynomial by a monomial. What do you think is the first step?
Maybe we should factor the polynomial?
Exactly! Let's take the polynomial `4y³ + 5y² + 6y` and divide it by `2y`. We start by factoring out `2y`.
So, we rewrite the polynomial to show that `2y` is common in all terms?
That's right! And then we can simplify further. Let’s summarize: We factor out `2y` from each term.
Common Factors in Polynomial Division
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Now that we’ve factored out `2y`, can you simplify `4y³, 5y²,` and `6y` individually divided by `2y`?
For `4y³ ÷ 2y`, we get `2y²`. For `5y² ÷ 2y`, it simplifies to `2.5y`, which is `y`. And for `6y ÷ 2y`, it's `3`.
Excellent work! Now, can we gather these results back together?
Yes! We can write it as `2y² + 2.5y + 3`.
Good job! Remember, separating the common factor helps us divide each term easily.
This makes division less complicated!
Exactly! So, whenever you see a polynomial division, look for those common factors.
Alternative Method for Polynomial Division
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Now, let’s discuss another way to perform polynomial division. Instead of factoring out common terms, we can directly divide each term. Can anyone explain how this method works?
We just divide `4y³`, `5y²`, and `6y` by `2y` directly?
Exactly! Let’s run through it with our example: `4y³ + 5y² + 6y` divided by `2y`.
Right! So, `4y³ ÷ 2y = 2y²`, `5y² ÷ 2y = 2.5y`, and `6y ÷ 2y = 3`.
Well done! And what do we get when we summarize these results?
We still get `2y² + 2.5y + 3`!
Exactly! Both methods lead to the same result. It’s important to be comfortable with both approaches.
Introduction & Overview
Read summaries of the section's main ideas at different levels of detail.
Quick Overview
Standard
The section teaches the process of dividing a polynomial by a monomial using two methods: separating common factors from each term or dividing each term individually. This process helps simplify expressions and is essential for algebraic manipulations.
Detailed
Division of a Polynomial by a Monomial
In this section, we delve into the process of dividing a polynomial by a monomial, an essential skill in algebra. A polynomial can consist of multiple terms, and when we want to divide such an expression by a monomial, we can utilize two effective methods.
Key Concepts:
- Factorization: The polynomial is expressed as a sum of terms, each of which can be factorized to identify common factors with the monomial.
- Common Factors: We take the common factor out from each term in the polynomial, allowing us to simplify the expression.
- Division of Each Term: Alternatively, we can directly divide each term of the polynomial by the monomial, which often leads to a straightforward simplification.
Example:
For instance, consider dividing the polynomial 4y³ + 5y² + 6y by the monomial 2y. We can express each term in this polynomial in terms of 2y, allowing for simplification:
- Factor out
2y:
4y³ + 5y² + 6y = 2y(2y² + y + 3)
The division then yields a simplified result as follows:
(4y³ + 5y² + 6y) ÷ 2y = 2y² + y + 3.
Through this section, students will understand how to effectively handle polynomial expressions when divided by monomials, vital for more advanced algebraic concepts.
Similar Question
Example : Divide \( 18(x^2y + y^2z + z^2x) \) by \( 6xyz \) using both methods.
Solution:
\[ 18(x^2y + y^2z + z^2x) = 18 \cdot (x^2y) + 18 \cdot (y^2z) + 18 \cdot (z^2x) \]
\[ = 3 \cdot 6(x^2y + y^2z + z^2x) \]
Taking out the common factor, we have:
\[ = 3\cdot6(x + y + z) \]
Therefore,
\[ \frac{18(x^2y + y^2z + z^2x)}{6xyz} = 3(x + y + z) \]
Alternately, \( 18(x^2y + y^2z + z^2x) \) can also be simplified to \( 3x^2y + 3y^2z + 3z^2x = 3(x^2y + y^2z + z^2x) \)
\[ = 3\cdot 6(x + y + z) \]
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Audio Book
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Introduction to Polynomial Division
Chapter 1 of 5
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Chapter Content
Let us consider the division of the trinomial 4y3 + 5y2 + 6y by the monomial 2y.
Detailed Explanation
In polynomial division, we want to divide a polynomial expression by a monomial. For instance, we are dividing the polynomial 4y³ + 5y² + 6y by 2y. This process involves determining how many times the monomial fits into each term of the polynomial.
Examples & Analogies
Think of this division as sharing a bag of candies (the polynomial) among friends (the monomial). If each friend gets a certain number of candies, you need to know how many bags you have for each friend to get their fair share.
Factoring Out the Common Monomial
Chapter 2 of 5
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Chapter Content
4y3 + 5y2 + 6y = (2 × 2 × y × y × y) + (5 × y × y) + (2 × 3 × y) (Here, we expressed each term of the polynomial in factor form) we find that 2 × y is common in each term.
Detailed Explanation
In this step, we rewrite each term of the polynomial in its factor form to spot common factors. Here, 2y is a common factor in each term: 4y³ can be factored as 2y(2y²), 5y² as 2y(2.5y), and 6y can be factored as 2y(3). This identification allows us to factor out 2y from the entire polynomial.
Examples & Analogies
Imagine a group project where everyone has shared responsibilities. If everyone is responsible for bringing 2 notebooks, you can factor out the notebooks from each person's contribution and just account for the dwindled amount of resources separately.
Dividing the Polynomial by the Monomial
Chapter 3 of 5
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Chapter Content
Therefore, (4y3 + 5y2 + 6y) ÷ 2y = 2y(2y² + y + 3) = 2y² + y + 3.
Detailed Explanation
Once the common factor 2y is factored out, we can divide the whole polynomial by 2y. The polynomial simplifies to 2y² + y + 3, which are the new coefficients of each term after the division. This shows how many 'units' of y we have in each term.
Examples & Analogies
Consider dividing a pizza (the polynomial) into slices (the monomial). After removing an equal number of slices (the common factor), you simply count how many entire slices are left in total, leading to a simpler understanding of your remaining pizza.
Alternative Method: Direct Division of Each Term
Chapter 4 of 5
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Chapter Content
Alternatively, we could divide each term of the trinomial by the monomial using the cancellation method.
Detailed Explanation
In this alternative approach, we separately divide each term of the polynomial by the monomial. For 4y³ ÷ 2y, we get 2y²; for 5y² ÷ 2y, we get 2.5y; and for 6y ÷ 2y, we get 3. When summed up, this results in 2y² + 2.5y + 3, adding simplicity to the process through direct calculation.
Examples & Analogies
Imagine splitting tasks among friends: if each friend can handle one specific task at a time, you divide each task equally, leading to a straightforward understanding of how many tasks are left once shared.
Conclusion
Chapter 5 of 5
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Chapter Content
Therefore, using both methods, we arrive at the result of the division of the polynomial by the monomial.
Detailed Explanation
This final section summarizes that whether factoring out the common monomial or directly dividing each term, both methods provide a consistent and accurate result.
Examples & Analogies
This is akin to using two different approaches to budgeting a project. Regardless of how you track expenses—by category (factoring) or individually (direct division)—the total expenditure will remain the same, reinforcing that you can achieve the same goal through varied methods.
Key Concepts
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Factorization: The polynomial is expressed as a sum of terms, each of which can be factorized to identify common factors with the monomial.
-
Common Factors: We take the common factor out from each term in the polynomial, allowing us to simplify the expression.
-
Division of Each Term: Alternatively, we can directly divide each term of the polynomial by the monomial, which often leads to a straightforward simplification.
-
Example:
-
For instance, consider dividing the polynomial
4y³ + 5y² + 6yby the monomial2y. We can express each term in this polynomial in terms of2y, allowing for simplification: -
Factor out
2y: -
4y³ + 5y² + 6y = 2y(2y² + y + 3) -
The division then yields a simplified result as follows:
-
(4y³ + 5y² + 6y) ÷ 2y = 2y² + y + 3. -
Through this section, students will understand how to effectively handle polynomial expressions when divided by monomials, vital for more advanced algebraic concepts.
-
Similar Question
-
Example : Divide \( 18(x^2y + y^2z + z^2x) \) by \( 6xyz \) using both methods.
-
Solution:
-
\[ 18(x^2y + y^2z + z^2x) = 18 \cdot (x^2y) + 18 \cdot (y^2z) + 18 \cdot (z^2x) \]
-
\[ = 3 \cdot 6(x^2y + y^2z + z^2x) \]
-
Taking out the common factor, we have:
-
\[ = 3\cdot6(x + y + z) \]
-
Therefore,
-
\[ \frac{18(x^2y + y^2z + z^2x)}{6xyz} = 3(x + y + z) \]
-
Alternately, \( 18(x^2y + y^2z + z^2x) \) can also be simplified to \( 3x^2y + 3y^2z + 3z^2x = 3(x^2y + y^2z + z^2x) \)
-
\[ = 3\cdot 6(x + y + z) \]
Examples & Applications
To divide the polynomial 4y³ + 5y² + 6y by the monomial 2y: Factor out 2y, yielding the result 2y(2y² + y + 3) which simplifies to 2y² + y + 3.
Dividing 24(x²y + xy² + xyz) by 8xyz results in 3(x + y + z) after common factor removal.
Memory Aids
Interactive tools to help you remember key concepts
Rhymes
Dividing by monomial, it’s simple, don’t fear, just take out what’s shared, keep the process clear.
Stories
Imagine you have a box of different fruits represented as a polynomial. To share evenly, you take out what all fruits have in common - the monomial - and then see what remains for sharing!
Memory Tools
Use 'FACTOR' to remember: Factor Out Common Terms, then Apply Simplifying Rules.
Acronyms
D.A.M. = Divide, Apply Common Factors, Multiply the Remainder.
Flash Cards
Glossary
- Polynomial
An algebraic expression made up of one or more terms, with variables represented in non-negative integer exponents.
- Monomial
A single term that can be a number, a variable, or a product of numbers and variables.
- Common Factor
A number or expression that divides each term of a polynomial without leaving a remainder.
Reference links
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