10.1.1 - Introduction to Heron's formula
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Introduction to Triangles
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Today, we are exploring how we can find the area of a triangle when we only know the lengths of its sides. Do you remember how we usually find the area of a triangle?
Yes! We use the formula for area as 1/2 times the base times the height.
But what if we don’t know the height?
Excellent question! This is where Heron’s formula comes into play. It allows us to calculate the area without needing the height. Do you want to hear how this works?
Understanding Heron's Formula
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"Heron's formula states that the area \( A \) of a triangle with sides \( a \), \( b \), and \( c \) can be calculated using:
Applying Heron's Formula
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Now, using our earlier example of a triangle with sides 40 m, 32 m, and 24 m, we have \( s = 48 \) m. Can we find \( A \)?
Let’s calculate \( s-a, s-b, \) and \( s-c \). We get 8 m, 24 m, and 16 m respectively.
So then \( A = \sqrt{48(8)(24)(16)}\)?
Yes! And calculating that gives you the area of the triangle. Can someone show me how?
When we plug in the numbers, we get \( A = \sqrt{48 \times 8 \times 24 \times 16} = 384 \) m²!
Perfect! And you see how it matches our earlier result using height as well. Great teamwork!
Verifying the Formula
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We have calculated the area using both Heron’s formula and by calculating the height. Why is it helpful to verify our results in different ways?
It makes sure our calculations are correct!
And it helps us understand the right triangle property too.
Exactly! Verifying through different methods reinforces our understanding. Remember the importance of cross-checking!
Introduction & Overview
Read summaries of the section's main ideas at different levels of detail.
Quick Overview
Standard
This section introduces Heron's formula for calculating the area of a triangle given the lengths of its sides. It emphasizes the significance of this formula when determining area through height is complex, explaining the derivation of the formula, its components, and providing illustrative examples.
Detailed
Detailed Summary
Heron's formula provides a method to calculate the area of a triangle when the height is not known. The formula states:
\[ A = \sqrt{s(s-a)(s-b)(s-c)} \]
where \(s\) is the semi-perimeter defined as:
\[ s = \frac{a + b + c}{2} \]
This section begins with a scenario of finding the area of a triangular park with known sides (40 m, 32 m, 24 m), highlighting the inadequacy of using height for area calculation.
It further discusses the historical context, noting the contributions of Heron of Alexandria who formulated this equation between 10 C.E. – 75 C.E.
Three examples demonstrate calculating the area using Heron's formula, validating results through methods such as the right triangle area calculation, and verifying through multiple triangle types (equilateral and isosceles). Exercises at the end reinforce learning by encouraging students to apply this formula to both given and constructed problems.
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Defining the Area of a Triangle
Chapter 1 of 4
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Chapter Content
We know that the area of a triangle when its height is given, is
\[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \] . Now suppose that we know the lengths of the sides of a scalene triangle and not the height. Can you still find its area? For instance, you have a triangular park whose sides are 40 m, 32 m, and 24 m. How will you calculate its area? Definitely if you want to apply the formula, you will have to calculate its height. But we do not have a clue to calculate the height. Try doing so. If you are not able to get it, then go to the next section.
Detailed Explanation
The area of a triangle can typically be found using the formula that involves its base and height. However, if we only know the sides of the triangle (like with a scalene triangle), calculating the height may not be straightforward or possible. This introduces a problem for calculating the area based solely on side lengths, which is where Heron's formula comes into play. It allows us to find the triangle's area without needing to know its height.
Examples & Analogies
Imagine a triangular park where you want to put in flower beds. You know the lengths of the triangle's sides but not how high it is from the base to the top point where the flowers would grow. If you only have the side lengths, you might feel stuck. Heron's formula acts like a special tool that lets you calculate the area even when you don’t know how tall the triangle is.
Heron's Background
Chapter 2 of 4
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Chapter Content
Heron was born in about 10AD possibly in Alexandria in Egypt. He worked in applied mathematics. His works on mathematical and physical subjects are so numerous and varied that he is considered to be an encyclopedic writer in these fields. His geometrical works deal largely with problems on mensuration written in three books.
Detailed Explanation
Heron of Alexandria was a notable figure in the history of mathematics. His contributions laid foundational work in applied mathematics, including geometry. His exploration of different geometrical shapes and their areas demonstrates his extensive knowledge. His book focused on measurements of various shapes, but notably, it contains the formula for the area of a triangle, leading to his prominent legacy in mathematics.
Examples & Analogies
Think of Heron like a pioneer explorer in a vast land of geometry. Just as explorers mapped new territories, Heron mapped out mathematical principles that help us navigate the complexities of shapes, starting with triangles. His writings are like guides we still use today for our own explorations in geometry.
Introduction to Heron's Formula
Chapter 3 of 4
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Chapter Content
The formula given by Heron about the area of a triangle, is also known as Hero’s formula. It is stated as:
\[ \text{Area of a triangle} = \sqrt{s(s-a)(s-b)(s-c)} \]
where a, b and c are the sides of the triangle, and \(s = \frac{a+b+c}{2}\), the semi-perimeter of the triangle.
Detailed Explanation
Heron's formula allows us to calculate the area of any triangle when we know the lengths of all three sides. We first find the semi-perimeter (s) by adding the lengths of the three sides and dividing by 2. Once we have s, we can plug it into the formula using the three sides to find the area. This is particularly useful for triangles where finding the height is complicated.
Examples & Analogies
Imagine you are an architect needing to figure out how much space a triangular rooftop will cover. You have the measurements of the side lengths but no idea of the height. Heron’s formula is like a secret recipe that uses just those side lengths to calculate the area, ensuring you know how much roofing material you'll need without any guesswork.
Practical Application of Heron's Formula
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Chapter Content
This formula is helpful where it is not possible to find the height of the triangle easily. Let us apply it to calculate the area of the triangular park ABC, mentioned above (see Fig. 10.2). Let us take a = 40 m, b = 24 m, c = 32 m, so that we have s = \[ \frac{40 + 24 + 32}{2} = 48 \] m. Thus, we can apply Heron's formula to find the area.
Detailed Explanation
When applying Heron's formula to the triangular park, we start by determining the semi-perimeter using the side lengths of the triangle. After calculating s, we then substitute it and the sides into the formula, allowing us to find the area in an effective manner without needing to calculate the height. This process exemplifies the utility of Heron’s formula in practical situations.
Examples & Analogies
Think of the triangular park as a pizza slice. You know the lengths of the crust and the sides (like your measuring tape), but you can’t measure how high it rises in the middle. Heron’s formula lets you calculate the area of that pizza slice just from knowing those crust lengths, helping you decide how many slices you can serve to your friends at a picnic!
Key Concepts
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Heron's Formula: Used to find the area of a triangle with known side lengths.
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Semi-perimeter: Defined as half the perimeter of the triangle.
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Right Triangle: A triangle where one angle measures 90 degrees.
Examples & Applications
{'example': 'Find the area of a triangle with sides 40 m, 24 m, and 32 m.', 'solution': '\[ s = \frac{40 + 24 + 32}{2} = 48 \ m \] \n\[ A = \sqrt{48(48-40)(48-24)(48-32)} = \sqrt{48 \times 8 \times 24 \times 16} = 384 \ m^2 \]'}
{'example': 'Calculate the area of an equilateral triangle with side length 10 cm.', 'solution': '\[ s = \frac{10 + 10 + 10}{2} = 15 \ cm \] \n\[ A = \sqrt{15(15-10)(15-10)(15-10)} = \sqrt{15 \times 5 \times 5 \times 5} = 25\sqrt{3} \ cm^2 \]'}
Memory Aids
Interactive tools to help you remember key concepts
Rhymes
Heron's way to find the area, sides in play, and math won’t stray.
Memory Tools
SAS - Semi-perimeter, Area, Sides.
Stories
Imagine Heron, a wise man, finding triangles' secrets hidden in the land.
Acronyms
HAS - Height Alternative is Heron’s solution.
Flash Cards
Glossary
- Heron's Formula
A formula to calculate the area of a triangle when the lengths of all three sides are known.
- Semiperimeter
Half of the triangle's perimeter, calculated as \( s = \frac{a + b + c}{2} \).
- Triangle
A polygon with three edges and vertices.
- Scalene Triangle
A triangle where all sides are of different lengths.
Reference links
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