Cycle Time Calculation - 3.2 | 4. Production Value of the Bulldozer | Construction Engineering & Management - Vol 2
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Understanding Ideal Conditions and Job Efficiency

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0:00
Teacher
Teacher

Today, we're talking about the cycle time calculation, which is critical for estimating productivity in earthmoving projects. Can anyone tell me what we mean by 'ideal conditions'?

Student 1
Student 1

I think ideal conditions refer to situations where everything works perfectly as planned, like operating for a full hour.

Teacher
Teacher

Exactly! Ideal conditions often mean 60 minutes of effective working time. However, if a bulldozer only works for 50 minutes, we need to apply what factor?

Student 2
Student 2

That's the job efficiency correction factor, right?

Teacher
Teacher

Yes! The job efficiency correction factor adjusts our calculations to reflect actual operations. Remember the acronym 'JE' for Job Efficiency.

Student 3
Student 3

So how do we calculate that?

Teacher
Teacher

Good question! You would divide the actual working minutes by 60. So, in this case, it would be 50 divided by 60, which equals approximately 0.83.

Student 4
Student 4

What does that mean for productivity?

Teacher
Teacher

It means our productivity estimate will be reduced by this correction factor. Great discussion on job efficiency!

The Role of Soil Density in Productivity

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Teacher
Teacher

Next, let's consider soil density. Who remembers the standard density for our productivity curves?

Student 1
Student 1

It's 1365 kg/m³.

Teacher
Teacher

Correct! Now, if our project soil is denser, say 1750 kg/m³, what must we do with our calculations?

Student 2
Student 2

We need to apply a correction factor.

Teacher
Teacher

Right again! And why is this adjustment necessary?

Student 3
Student 3

Because denser soil makes it harder for the bulldozer to push, reducing productivity.

Teacher
Teacher

Exactly! The correction for increased soil density would typically be less than 1, indicating reduced productivity. Always keep soil density in mind!

Operator Skills and Material Type Factors

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Teacher
Teacher

Moving on to operator skill. If the operator’s skill is average versus excellent, what impact does that have?

Student 1
Student 1

The productivity would go down since the less skilled operator might not use the machine efficiently.

Teacher
Teacher

Exactly! This is another situation where we apply a correction factor of less than one. Can anyone give me an example of a material type affecting productivity?

Student 4
Student 4

Non-cohesive silty sand?

Teacher
Teacher

Spot on! So, how do both operator skill and material type affect productivity when combined?

Student 3
Student 3

We multiply correction factors together, right?

Teacher
Teacher

Precisely! This combined effect may significantly reduce our expected productivity. Always remember each factor's impact and to apply it systematically!

Visibility and Slope Factors

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Teacher
Teacher

Let's talk about visibility and slope. If visibility is poor, what impact does that have on the bulldozer's operation?

Student 2
Student 2

It would probably decrease productivity since the operator can't see well.

Teacher
Teacher

Correct! Visibility adjustment is another correction factor, usually less than one. How about slope? What happens when moving downhill?

Student 1
Student 1

The productivity increases since gravity helps!

Teacher
Teacher

Exactly! For downhill slopes, the correction factor might be greater than one, enhancing productivity. Can someone summarize how we evaluate these factors graphically?

Student 4
Student 4

By referring to the curves from the equipment handbook that relate factors to productive output!

Teacher
Teacher

Right again! Excellent work discussing visibility and slope influences!

Introduction & Overview

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Quick Overview

This section discusses the factors impacting cycle time calculation for earthmoving operations, emphasizing correction factors related to soil density, operator skill, and job efficiency.

Standard

In this section, various factors influencing the cycle time calculation in earthmoving operations are analyzed. These include soil density variations, operator skills, gear transmission modes, and correction factors like job efficiency and the type of material being moved. Correction factors are crucial for adjusting maximum production values derived from manufacturer curves to align with actual project conditions.

Detailed

Detailed Summary

In earthmoving operations, accurately calculating cycle time is essential for estimating productivity and costs. This section specifically addresses the correction factors needed to adjust theoretical productivity values based on ideal curve conditions (such as those provided by equipment manufacturers) to the realities of specific job site conditions.

  1. Ideal Conditions: The curves presented are only valid under ideal conditions, including 60 minutes of effective work per hour. However, if a bulldozer operates for only 50 minutes, a job efficiency correction factor applies.
  2. Soil Density Impact: The production values retrieved from the manufacturer's curve are based on specific soil densities. If the soil density in the project is higher (e.g., 1750 kg/m³ vs. the standard of 1365 kg/m³), a correction factor must be applied.
  3. Operator Skills: The curves assume an ideal operator skill level. If the operator has average skills, the productivity will decrease, necessitating a correction factor of less than one.
  4. Material Type: Non-cohesive materials like silty sand would reduce productivity, hence apply another correction factor.
  5. Additional Correction Factors: Other factors such as visibility conditions, dozing methods, and grade slopes can also enhance or reduce productivity, necessitating further corrections based on actual project conditions.

These correction factors ultimately ensure a more accurate estimation of the unit cost of the earthmoving operation, essential for effective project budgeting and bidding.

Audio Book

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Understanding Ideal Conditions

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And hope you remember these curves are valid only for these ideal conditions. So, 60 minutes hour but in your project in this problem we found that the machine is working for 50 minutes an hour.

Detailed Explanation

This part highlights that the productivity curves used in calculations depend on ideal conditions. Here, one ideal condition is that the machine operates for an entire hour (60 minutes). However, in the current project scenario, the machine only works efficiently for 50 minutes per hour. This difference is crucial because it will affect the final productivity results due to reduced active work time.

Examples & Analogies

Imagine a student who can only study effectively for 50 minutes before losing focus, even though a full study session is an hour long. Just like the student’s effective study time needs to be considered for proper planning, the machine's working time must be adjusted to calculate productivity accurately.

Applying Correction Factors

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So, you are supposed to apply the job efficiency, you have to apply the correction factor accordingly.

Detailed Explanation

Given that the machine operates less than the ideal amount of time, we need to apply a correction factor to account for decreased efficiency. This means adjusting the expected productivity from the ideal curves based on real-world conditions such as operating time and other factors like soil density and operator skill.

Examples & Analogies

Think of a chef preparing a meal. If they work in an understocked kitchen (like working under less than ideal conditions), the meal's preparation and cooking time increase. They might need to adjust their plan considering their limited resources, just like adjusting the productivity expectations based on working conditions.

Soil Density Adjustment

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But this curve value is applicable for a soil density of 1365 kg per meter cube. So, in our case the soil density is given us 1750 kg per meter cube in bank state that is to be noted.

Detailed Explanation

The productivity curve that was initially used assumes a specific soil density of 1365 kg/m³. However, in our case, the soil density is actually higher at 1750 kg/m³. This discrepancy implies that the bulldozer will face more resistance when working with denser soil, which will reduce its productivity. Therefore, this requires us to apply another correction factor to adjust for this difference.

Examples & Analogies

Imagine pulling a wagon filled with rocks versus one filled with feathers. The rock-filled wagon represents denser soil, which requires more effort to move. Just as the increased weight affects how fast you can pull the wagon, the denser soil affects bulldozer productivity.

Operator Skill Correction

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The curve was drawn for excellent operator skill. So, in our problem the operator skill is average. So, accordingly you have to choose the correction factor and apply.

Detailed Explanation

Since the ideal productivity curves assume an 'excellent operator' handling the machinery, the actual average skill level of the operator requires a correction. An average operator will likely work less efficiently than an expert, necessitating a decrease in expected productivity through a correction factor.

Examples & Analogies

Think of a sporting event. If a professional athlete (excellent operator) competes, the expectations are high. However, if an amateur (average operator) competes instead, you would expect less impressive performance, similar to how the bulldozer's output changes based on operator proficiency.

Material Type and Its Impact

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Similarly, the material type, material type is non-cohesive silty sand, so that will definitely reduce the productivity.

Detailed Explanation

The type of material being moved greatly affects productivity. Non-cohesive silty sand does not hold together well, which can influence how the bulldozer operates. This material's properties may slow down operations or require different techniques, further necessitating correction.

Examples & Analogies

Think about trying to move a pile of dry leaves versus a pile of water-soaked mud. The mud is heavier, stickier, and much harder to move. Like in construction, the bulldozer's efficiency is impacted by the nature of the material it is handling.

Visibility and Its Challenges

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Visibility is poor in the problem what we have discussed. So, that will reduce your correction factor, the productivity will reduce obviously we are working for 50 minutes an hour, so accordingly the correction factor should be applied.

Detailed Explanation

Poor visibility conditions can hinder the operator's ability to navigate and control the bulldozer effectively. This can reduce productivity, requiring a correction factor to account for reduced efficiency during operations in such conditions.

Examples & Analogies

Consider driving in foggy weather; it is more challenging to see the road. Consequently, you might drive slower to stay safe. Similarly, reduced visibility affects the bulldozer's efficiency, making it crucial to adjust productivity expectations.

Grade Percentage Consideration

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So, in this problem we are moving down the hill, so the grade percentage is -15%. So, accordingly you have to choose the curve supply by the manufacturer.

Detailed Explanation

Adjusting for the grade percentage—here indicated as -15% (downhill)—can actually enhance productivity. The slope contributes to the machine's effectiveness as gravity assists the bulldozer in moving material down the slope, thus necessitating another adjustment to the correction factor to reflect this advantage.

Examples & Analogies

Think of riding a bike downhill versus uphill. Riding downhill feels easier and faster due to gravity helping you. In construction, moving down a slope similarly boosts the bulldozer's efficiency, showing how changes in terrain can impact operations.

Final Adjustment for Soil Density

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So, we can compare both only when the volume is the same type of measure, but one volume is in bank state other volume is expressed in loosen state.

Detailed Explanation

To accurately apply the soil density correction, we must convert the bank state soil density (1750 kg/m³) to a loose state density value to compare it with the productivity curve's standard (1365 kg/m³). This ensures we understand how denser soil impacts machine performance and productivity calculations.

Examples & Analogies

When you weigh a bag of flour at the grocery store, the weight can vary depending on whether the flour is compacted or loose. In construction, just as measuring flour correctly is critical for a recipe, accurately comparing soil densities is vital for determining bulldozer productivity.

Calculating Cost and Productivity

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So, after you estimate the productivity you are asked to estimate the unit cost of proposed earthmoving operation per bank meter cube.

Detailed Explanation

Once productivity is estimated, the next step is calculating the cost per unit of work done (in bank meter cube terms). This involves dividing the total cost of machine operation by the estimated productivity to understand the financial aspect of the earthmoving task.

Examples & Analogies

It's like budgeting for a homemade pizza. If the total cost of ingredients is $20 and you can make 4 pizzas, the cost per pizza is $5. Similarly, here it’s crucial to know how much each unit of earthmoving costs to plan effectively.

Definitions & Key Concepts

Learn essential terms and foundational ideas that form the basis of the topic.

Key Concepts

  • Cycle Time Management: Understanding cycle time is crucial in productivity estimation.

  • The Significance of Correction Factors: These factors adjust theoretical productivity to reflect real conditions.

  • Job Efficiency: Effectively understanding job efficiency allows for better accuracy in estimations.

  • Importance of Soil Density: Soil properties play a major role in affecting equipment performance.

  • Operator Skill Impact: The operator’s craft can either enhance or decrease output efficiency.

Examples & Real-Life Applications

See how the concepts apply in real-world scenarios to understand their practical implications.

Examples

  • If a bulldozer's maximum productivity is 114.68 loose cubic meters per hour under ideal conditions but is working in a situation with a job efficiency of 83%, the effective productivity is reduced to 95.20 loose cubic meters per hour.

  • For a project with a soil density of 1750 kg/m³ (compared to the standard of 1365 kg/m³), a correction factor is applied, resulting in a productivity estimate lower than initially calculated.

Memory Aids

Use mnemonics, acronyms, or visual cues to help remember key information more easily.

🎵 Rhymes Time

  • If visibility is low and soil is dense, productivity decline can be quite immense!

📖 Fascinating Stories

  • Imagine a bulldozer struggling uphill in foggy conditions. The operator, unsure of the path, stops often, leading to decreased productivity - a perfect lesson on how conditions matter!

🧠 Other Memory Gems

  • Remember the acronym C-JSOM (Costs, Job Efficiency, Soil, Operator, Material) for factors influencing cycle time.

🎯 Super Acronyms

CROP for Cycle time Reduction using Optimal Processes, to remember the important factors.

Flash Cards

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Glossary of Terms

Review the Definitions for terms.

  • Term: Cycle Time

    Definition:

    The total time taken to complete a cycle of operation, including dozing, returning, and maneuvering time.

  • Term: Correction Factor

    Definition:

    A numerical adjustment applied to the productivity estimate to reflect actual working conditions.

  • Term: Job Efficiency

    Definition:

    The ratio of actual working time to theoretical maximum working time, expressed as a percentage.

  • Term: Soil Density

    Definition:

    The mass per unit volume of soil, which can affect the productivity of earthmoving operations.

  • Term: Operator Skill

    Definition:

    The proficiency level of the operator, which influences the overall effectiveness and efficiency of equipment operation.