Practice Data Summary and Input Variables - 1.3 | 4. Production Value of the Bulldozer | Construction Engineering & Management - Vol 2
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Practice Questions

Test your understanding with targeted questions related to the topic.

Question 1

Easy

What is a correction factor?

💡 Hint: It alters theoretical productivity values.

Question 2

Easy

Why is soil density important in earthmoving operations?

💡 Hint: Think about the relationship between density and effort.

Practice 4 more questions and get performance evaluation

Interactive Quizzes

Engage in quick quizzes to reinforce what you've learned and check your comprehension.

Question 1

What does a correction factor do?

  • Adjusts productivity
  • Decreases costs
  • Increases machine speed

💡 Hint: It helps align theory with reality.

Question 2

True or False: High soil density always results in higher productivity.

  • True
  • False

💡 Hint: Consider the relationship between density and machine efficiency.

Solve 1 more question and get performance evaluation

Challenge Problems

Push your limits with challenges.

Question 1

A bulldozer operates with a soil density of 1900 kg/m³, and a correction factor of 0.7 relative to its ideal curve of 150 m³/hr. What is the adjusted productivity?

💡 Hint: Use correction factor multiplied with ideal productivity.

Question 2

If the operational cost is 3000 rupees per hour and unit productivity was adjusted to 50 m³/hr, calculate the new unit cost.

💡 Hint: Relate your cost with the adjusted productivity to find the answer.

Challenge and get performance evaluation