Practice Data Summary and Input Variables - 1.3 | 4. Production Value of the Bulldozer | Construction Engineering & Management - Vol 2
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Data Summary and Input Variables

1.3 - Data Summary and Input Variables

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Learning

Practice Questions

Test your understanding with targeted questions

Question 1 Easy

What is a correction factor?

💡 Hint: It alters theoretical productivity values.

Question 2 Easy

Why is soil density important in earthmoving operations?

💡 Hint: Think about the relationship between density and effort.

4 more questions available

Interactive Quizzes

Quick quizzes to reinforce your learning

Question 1

What does a correction factor do?

Adjusts productivity
Decreases costs
Increases machine speed

💡 Hint: It helps align theory with reality.

Question 2

True or False: High soil density always results in higher productivity.

True
False

💡 Hint: Consider the relationship between density and machine efficiency.

1 more question available

Challenge Problems

Push your limits with advanced challenges

Challenge 1 Hard

A bulldozer operates with a soil density of 1900 kg/m³, and a correction factor of 0.7 relative to its ideal curve of 150 m³/hr. What is the adjusted productivity?

💡 Hint: Use correction factor multiplied with ideal productivity.

Challenge 2 Hard

If the operational cost is 3000 rupees per hour and unit productivity was adjusted to 50 m³/hr, calculate the new unit cost.

💡 Hint: Relate your cost with the adjusted productivity to find the answer.

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