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Today, we're going to explore how we search for values within an array. Can anyone tell me what searching means in this context?
It means finding whether a value is present in the array.
Exactly! Now, we distinguish between searching in unsorted versus sorted arrays. What do you think happens in each case?
In an unsorted array, we have to check every item, right?
Correct! That's an O(n) complexity. Now, can someone explain why sorting can help in our search with binary search?
Because if it's sorted, we can eliminate half of the elements each time we look for the target value!
Well said! This leads us to the concept of binary search.
Let's talk more about how binary search actually works. Who can summarize the steps for us?
We start by checking the middle element. If it matches, we found it. If not, we look to the left or right depending on whether our target is smaller or larger!
Great summary! And each time we make this decision, what happens to our search space?
It gets halved each time.
Exactly! This is why binary search is efficient. How do we express the time complexity mathematically?
It's O(log n) because we're dividing the problem in half.
Perfect! Now remember, binary search requires a sorted array. What would happen if we tried to implement it on an unsorted one?
It wouldn't work correctly because we wouldn't know which side to search.
Now, let’s analyze the time complexity again. Can anyone remind me how we derive it?
By using recurrence relations, right?
That's correct! We write T(n) = 1 + T(n/2). We repeat this until n becomes 1, which helps us see the logarithmic relationship. How many times can we divide n before hitting 1?
Log base 2 of n times!
Excellent! Thus, the complexity we discussed becomes clearer: it's O(log n). Who can think of a practical example where this is useful?
Searching through a large database of sorted records, like in a library catalog.
Finally, let’s touch on the implications. What must we ensure before applying binary search?
The array must be sorted.
Exactly! If it’s not sorted, what do we have to revert to?
Linear search!
Great! Does anyone see a downside to using binary search in terms of implementation?
It can be complex, especially if we’re also incorporating recursion!
Good point! And what about performance compared to linear search?
It’s definitely faster for larger sorted arrays!
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The section discusses the difference between linear search in unsorted arrays and the logarithmic efficiency of binary search in sorted arrays. It illustrates the algorithm's steps, its recursive nature, and how its performance can be mathematically evaluated, concluding that binary search operates in O(log n) time complexity.
In this section, we address the problem of searching a value in a collection, focusing on both unsorted and sorted sequences, specifically arrays. When searching in an unsorted array, we may have to perform a linear search, resulting in O(n) complexity since every element may potentially need to be checked. In contrast, if the array is sorted, we can apply binary search, a much faster algorithm that works by dividing the search interval in half each time.
When implementing binary search, we start by checking the value at the midpoint of the array. If the value matches the target value, the search is complete. If the target value is smaller than the midpoint value, we recursively search the left half of the array. If it's larger, we search the right half. This halving continues until the search interval is empty, yielding a time complexity of O(log n).
The section also covers the recursive nature of the binary search algorithm, deriving its time complexity using recurrence relations. Finally, it emphasizes the requirement that binary search operates only on sorted arrays, while presenting the significant advantage of identifying an absent element by examining only a small subset of the data.
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So, on the other hand if the sequence is sorted and in particular if it is an array, we can be a little more intelligent. So, what we know is that the values are assigned in ascending order. So, if you probe the value in the middle and check is this equal to K, if the value that we have is equal to K of course, we have found it. If it is smaller than the value here, then we only need to search this half, and if it is larger than we need to search in this half.
When we have a sorted array, we can apply a more efficient search method known as binary search. Instead of checking each element one-by-one, binary search allows us to eliminate half of the elements at each step. By checking the middle element of the array:
1. If it's equal to our target value K, we've found our answer.
2. If it's smaller than K, we know that K must be in the upper half of the array.
3. If it's larger than K, K must be in the lower half. This method dramatically reduces the number of checks needed compared to linear search.
Think about searching for a word in a dictionary. You don’t go through each word one-by-one; instead, you open the dictionary roughly in the middle and see if your word is on that page. If it’s earlier in the alphabet, you go to the earlier half of the dictionary, and if it’s later, you go to the later half. This way, you find the word much faster!
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So, here is a simple recursive algorithm for binary search. So, in general it searches an array, remember that when we do the search we might be searching different segments depending on how far we progress the search. So, in general binary search takes a value K to search an array and two end points, left and right and just to make sure that we get a everything right, you will have the convention that it searches from the index l to the index r minus 1.
The binary search algorithm can be implemented recursively. The function takes three parameters: the target value K, and the left and right bounds of the current search segment, l and r. It operates as follows:
1. First, it checks if the current segment is valid (l < r). If it's not, the value isn't found.
2. It then calculates the midpoint index.
3. If the midpoint value equals K, it returns success.
4. If K is less than the midpoint value, the search continues in the left segment (from l to mid-1).
5. If K is greater than the midpoint value, it continues in the right segment (from mid+1 to r). This process repeats until K is found or the segment is invalid.
Consider how you might organize a treasure hunt in a large field. Instead of searching every inch of the field, you divide it into quarters. You check one quarter first. If the treasure isn’t there, you can eliminate that quarter from your search and focus only on the remaining three quarters. You continue dividing until you find the treasure or confirm it's not in the field.
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So, the crucial advantage of binary search is that each step we have the interval to search and at some point we will reach 1 and then when we have 1, we will get an interval of size 0 and so, we will get an immediate answer. So, we can write as we saw for such recursive functions, we can write what is called a recurrence. The base case is that when we have T of n we mean the time taken to search in a list or an array actually of size n. So, T of 0 is 1.
Binary search is highly efficient, with its time complexity being logarithmic, O(log n). This means that the number of operations needed to find K grows much slower than the size of the array. Specifically, every time we check the midpoint, we effectively halve the search space. Using recurrence relations, we define T(n) as the time taken to search in an array of size n, and we find that:
- T(0) = 1, which means if there are no elements, we can conclude immediately.
- For any other n, the recurrence T(n) = 1 + T(n/2) represents the time taken for each comparison plus the time for the next half. This logarithmic growth leads us to a very efficient search time even for large datasets.
Imagine you’re searching for your friend in a crowded mall. If you were to look through every person (linear search), it would take a long time. But what if you asked each section of the mall if they’ve seen your friend? After checking a few larger groups, you may quickly narrow down to just one section where your friend is. Binary search acts similarly, consistently narrowing the search area, allowing you to find your friend much faster.
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So, we mentioned in the previous unit about arrays and list that, things that work on list may not work on arrays and vice versa. So, here is an example of something it works only for arrays. The idea of looking up the midpoint and then going left works only, if you can find the midpoint constant time, if you have to spend time looking for the constant for the midpoint, then you cannot get this recurrence anymore which not going to be 1 plus T of n by 2, but it is going to be n plus T of n by 2 plus here n by 2 and then we will actually get a linear.
It's crucial to note that binary search can only be efficiently applied to data structures that allow for constant time access, like arrays. If, for instance, you were using a linked list where you had to traverse elements to find the midpoint, the efficiency drops dramatically. In this case, finding the midpoint during each call would take linear time, rendering the binary search less efficient, as it would not maintain the original logarithmic complexity.
Think of a bookshelf where books are stacked behind each other in a random order (like in a linked list). If you want to find the book in the middle, you can’t just ‘jump’ to it without removing the books in front. This is like losing the efficiency of binary search because you have to check more before you can determine where to look next.
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Key Concepts
Binary Search: A method of finding an element in a sorted array by continually dividing the search interval in half.
Time Complexity: Measures the performance of an algorithm based on the input size; significant for evaluating efficiency.
Recursion: A programming technique where the function calls itself to simplify complex problems.
See how the concepts apply in real-world scenarios to understand their practical implications.
Searching for the element 35 in a sorted array: [10, 15, 20, 25, 30, 35, 40] would involve checking the middle element and moving to the right half as 35 is greater than the midpoint.
In an unsorted array [3, 1, 4, 2], a linear search would be used to determine the presence of 4, requiring examination of multiple elements.
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In sorted arrays, don't despair, just split and search, you'll find it there!
Imagine searching for your friend in a group of sorted friends. Each time you check the center person, you either move left or right effectively eliminating a lot of unnecessary checks, and quickly finding them.
When searching in binary, check the middle, is it greater or small? Halve the search until you find it all!
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Review the Definitions for terms.
Term: Binary Search
Definition:
An efficient algorithm for finding a target value in a sorted array, where we reduce the search space by half each step.
Term: Time Complexity
Definition:
A computational complexity that describes the amount of time it takes to run an algorithm as a function of the length of the input.
Term: Recursion
Definition:
A method of solving problems where the function calls itself as a subroutine.
Term: Linear Search
Definition:
A straightforward method for finding a target value in an unsorted array by checking every element.
Term: O(n)
Definition:
Big O notation describing linear time complexity, where the time taken increases linearly with the number of elements.
Term: O(log n)
Definition:
Big O notation indicating logarithmic time complexity, showing efficient halving of search space.