Practice Theorem 7 (distributive Laws) (6.3.7) - Boolean Algebra and Simplification Techniques - Part A
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Theorem 7 (Distributive Laws)

Practice - Theorem 7 (Distributive Laws)

Learning

Practice Questions

Test your understanding with targeted questions

Question 1 Easy

Simplify the expression A.(B + C) using the distributive law.

💡 Hint: Look for the term that is ANDed across the sum.

Question 2 Easy

Using distributive law, rewrite X + (Y.Z).

💡 Hint: Think about how the first term can be expanded.

4 more questions available

Interactive Quizzes

Quick quizzes to reinforce your learning

Question 1

What is the output of X.(Y + Z) when X=1, Y=0, Z=1?

1
0
undefined

💡 Hint: Evaluate each variable based on its value.

Question 2

True or False? X + (Y.Z) simplifies to (X + Y)(X + Z).

True
False

💡 Hint: Think about how OR distributes over AND.

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Challenge Problems

Push your limits with advanced challenges

Challenge 1 Hard

Prove using truth tables that both sides of X + (Y.Z) = (X + Y)(X + Z) hold true.

💡 Hint: Remember, each variable can be either 0 or 1, leading to 2^3 combinations.

Challenge 2 Hard

Simplify the following Boolean expression using the distributive law: A.(B + C) + A.D.

💡 Hint: See how many terms start with A and combine accordingly.

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Reference links

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