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2.2. Example Problem: Determining Pressure at Bottom of Tank

Interactive Audio Lesson

Session 1: Understanding Pressure Variation

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Sarah
SarahInstructor

Good morning class! Today, we will explore how pressure varies in fluids at different depths. Can anyone tell me how pressure changes when we go deeper in a fluid?

Noah
Noah

I think pressure increases as we go deeper!

Sarah
SarahInstructor

Exactly! The pressure increase can be calculated using the formula: P = h * γ, where 'h' is the depth and 'γ' is the specific weight of the fluid. Can anyone remind me what specific weight means?

Isabella
Isabella

Isn't specific weight the weight per unit volume of the fluid?

Sarah
SarahInstructor

That's correct! As we dive deeper into this topic, we will apply these principles to calculate pressure at different points in our example tank.

Session 2: Setting Up the Problem

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Robert
RobertInstructor

Let’s consider a tank that is 6 meters deep, containing 4 meters of water and 2 meters of oil. Who can provide me the initial steps to find the pressure at the tank's bottom?

Akash
Akash

First, we need to determine the pressure at the water-oil interface, right?

Robert
RobertInstructor

Absolutely! We can denote this pressure as P2. If we start with atmospheric pressure at the top, how should we calculate P2?

Ananya
Ananya

It should be P1 plus the pressure due to the oil column!

Robert
RobertInstructor

Correct! We will calculate P2 using the specific weight of oil. Remember the formula: P2 = P1 + h_oil * γ_oil.

Session 3: Calculating the Pressures

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Sarah
SarahInstructor

Now, let’s compute P2 with our known values. What is the specific weight of the oil if its relative density is 0.88?

Noah
Noah

It would be 0.88 times the specific weight of water, which is approximately 9790 N/m³.

Sarah
SarahInstructor

Excellent! So, what’s the specific weight of the oil?

Isabella
Isabella

It’s around 8615.2 N/m³.

Sarah
SarahInstructor

Now, using this value, let’s calculate P2 as we discussed earlier.

Session 4: Summing Up the Calculations

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Robert
RobertInstructor

Great work so far! After computing P2 as 17230.4 N/m², how do we find P3?

Akash
Akash

We add the pressure from the water column to P2. So, P3 = P2 + (4m * γ_water).

Robert
RobertInstructor

Exactly! And what is the result?

Ananya
Ananya

The final pressure at the bottom, P3, is 56390.4 N/m² or 56.39 kPa!

Robert
RobertInstructor

Well done! This demonstrates how we can calculate pressures in a hydraulic system.