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Today, we’re starting with the fundamental concept of shear stress. Who can tell me what shear stress is?
Isn't it the force acting parallel to the surface area of a fluid?
Exactly! Shear stress is defined as the tangential force divided by the area it acts upon. It plays a crucial role in understanding fluid motion. Can anyone tell me how we represent it mathematically?
Is it C4 = BC * (du/dy)?
Well done! BC is the dynamic viscosity, and du/dy is the velocity gradient. Remember, for shear stress, think of the acronym 'Shear Force Fits Area' – SFFA!
What if the viscosity increases? How does that affect shear stress?
Great question! Higher viscosity means greater resistance to flow, thus increasing shear stress for the same velocity gradient. Summarizing, shear stress is essential to describe how fluids behave under shear forces.
Let's now shift our focus to terminal velocity. Can anyone explain what terminal velocity is?
It’s the maximum speed an object reaches when falling through a fluid, right?
Correct! At terminal velocity, the gravitational force is balanced by the drag force acting against gravity. What factors affect terminal velocity in fluids?
The object's shape and size, right? And also the fluid’s viscosity?
Exactly! Larger area and greater viscosity increase drag, thus impacting terminal velocity. Remember, when forces are balanced, the object does not accelerate further. Using the mnemonic 'FBD Equals Zero' can help you recall the balance of forces at terminal velocity.
Are there specific formulas to help calculate terminal velocity?
Yes, the general equation is vital: V = 2WR / (C * BC), where W is the weight, R is the characteristic dimension, and C is a coefficient related to shape. This encapsulates how intertwined shear stress and terminal velocity are.
Now, let’s put our knowledge to the test with an example problem on shear stress. The velocity distribution in a flow over a plate is given by u = 4y - y^2. How do we find the shear stress at y=0?
We need to differentiate the equation to find du/dy and then multiply by the viscosity!
Exactly! The derivative gives us the velocity gradient. After calculating that, plug in the viscosity to find the shear stress. What do we get?
At y=0, it should yield a value of 6 Pa.s.
Very good! Now, how about a terminal velocity problem—if a block of 90 N moves down an inclined plane with a film of oil, how would we start?
We analyze the balance between the weight component down the slope and the shear stress opposing motion!
Perfect! Remember to account for all forces involved and apply the relevant equations to find terminal velocity!
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The section discusses the fundamentals of shear stress and terminal velocity, illustrating their significance through example problems. It covers essential equations and relationships, enabling students to apply theoretical concepts to practical scenarios in fluid mechanics.
In hydraulic engineering, understanding shear stress and terminal velocity is crucial for analyzing fluid flow behaviors. This section presents example problems illustrating the application of these concepts.
These concepts help engineers design systems involving fluid flow—whether in pipelines, channels, or natural bodies of water—by predicting behaviors and optimizing performance. Understanding and calculating shear stress and terminal velocity aid in developing efficient designs in hydraulic structures.
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The velocity distribution in a viscous flow over a plate is given by u = 4y – y² for y which is less than 2 meters. Here, u is velocity in m/s at a point distance y from the plate if the coefficient of dynamic viscosity is 1.5 Pa.sec determine the shear stress at y=0 and y=2 m.
In this problem, we're given a velocity function u that describes how velocity changes with respect to distance (y) from a plate. To find the shear stress, we first need to calculate the derivative of u with respect to y, which gives us the rate of change of velocity (the velocity gradient). The formula for shear stress (τ) is τ = μ * du/dy, where μ is the dynamic viscosity. After calculating du/dy, at y=0 and y=2, we plug these values into our shear stress formula to find the resulting shear stress values at both points.
Imagine a thick syrup being spread over a surface. If you push down on one side of the syrup, the velocity at that point will increase faster than at the other side. By calculating shear stress, we can understand how much force is needed to keep spreading the syrup smoothly, similar to our plate covered by a viscous fluid.
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A 90 N rectangular solid block slides down a 30° inclined plane, the plane is lubricated by a 30 mm thick film of oil of relative density 0.9 and viscosity 8.0 poise. If the contact area is 0.3 m², estimate the terminal velocity of the block. Weight of the block is acting downwards at terminal velocity, the sum of the forces acting on the block in the direction of its motion is 0.
In this example, we need to find the terminal velocity (V) of a block sliding down an incline. We identify the forces acting on the block: gravity pulls it down, while friction (due to viscous forces) opposes the motion. At terminal velocity, these forces are balanced. We calculate the gravitational force component that pulls the block down the incline and set it equal to the force due to shear stress at the contact area, given by shear stress multiplied by area. Using the given viscosity and the thickness of the lubricant, we solve for V.
Think of a sled sliding down a snowy hill. Initially, it speeds up as gravity pulls it down, but as it slides further, friction from the snow pushes back, causing it to reach a constant speed. This constant speed is analogous to terminal velocity. By calculating how much friction (viscosity) resists the sled's movement, we can determine how fast it will slide.
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Key Concepts
Shear Stress: This is the tangential force per unit area within a fluid that results from motion or external forces acting on the fluid layers. The mathematical representation of shear stress (C4) can be derived using the equation:
C4 = BC * (du/dy)
where BC is the dynamic viscosity and du/dy is the velocity gradient.
Terminal Velocity: This is the constant speed achieved by an object moving through a viscous fluid when the forces of gravity and buoyancy are balanced by the drag force opposing the motion. The terminal velocity can be influenced by various factors including fluid viscosity, the shape of the object, and the surface area in contact with the fluid.
These concepts help engineers design systems involving fluid flow—whether in pipelines, channels, or natural bodies of water—by predicting behaviors and optimizing performance. Understanding and calculating shear stress and terminal velocity aid in developing efficient designs in hydraulic structures.
See how the concepts apply in real-world scenarios to understand their practical implications.
Calculating shear stress from the equation u = 4y - y^2 at different values of y.
Determining the terminal velocity of a rectangular solid block sliding down an inclined plane with a lubricating film.
Use mnemonics, acronyms, or visual cues to help remember key information more easily.
Shear stress, it's no jest, measure force put to the test!
Imagine a cube sliding in honey—slow, but steady. The honey’s resistance keeps it from falling fast, like a weight reaching a terminal point of rest.
Remember 'D.V.' for Dynamic Viscosity: It's about how fluids flow smoothly and easily.
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Review the Definitions for terms.
Term: Shear Stress
Definition:
The tangential force per unit area acting on a fluid, often denoted by C4.
Term: Terminal Velocity
Definition:
The constant speed achieved by an object when the gravitational force is balanced by the drag force.
Term: Dynamic Viscosity
Definition:
A measure of a fluid's resistance to flow, represented by BC.
Term: Velocity Gradient
Definition:
The rate of change of velocity in a fluid, denoted as du/dy.