Practice Solution To Problem 3 (2.6) - Non-Uniform Flow and Hydraulic Jump (Contd.)

Practice: Solution to Problem 3

Lesson 2.6Non-Uniform Flow and Hydraulic Jump (Contd.)

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10 questions

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6 sample questions

Question 1.
What is a rectangular channel?
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Think about the shape of the channel.
Question 2.
Define discharge in hydraulic terms.
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Remember the unit of measurement is m³/s.
3Question 3.
What is the formula for calculating dy/dx in gradually varied flow?
- dy/dx = (S0 - Sf) / (1 - (Q^2 * T) / (g * A^3))
- dy/dx = (Sf - S0) / (1 - (A^2 * T) / (g * Q^3))
- dy/dx = (T - Q) / (S0 - Sf)
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Recall the definitions and relationships of the variables involved.
4Question 4.
True or False: The critical depth is always less than the normal depth for mild slopes.
- True
- False
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Analyze the definitions of critical and normal depths in context to slope types.
Question 5.
If a rectangular channel experiences a flow velocity of 2 m/s, 8 m in width, and 5 m in depth, with an energy slope of 0.001 and a bed slope of 0.0005, determine the dy/dx for the channel.
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Identify each parameter from the problem correctly before plugging into the formula.
Question 6.
In a channel with a width of 6 m, depth of 1.2 m, and a discharge of 3.5 m³/s, evaluate the critical and normal depths and examine the flow profile details.
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Skip to the step where you apply both depth calculations to classify the flow condition.

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