Practice Example 1.25: Gradient Calculation between Points - 1.7 | 1. Examples and Solutions | Surveying and Geomatics
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1.7 - Example 1.25: Gradient Calculation between Points

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Learning

Practice Questions

Test your understanding with targeted questions related to the topic.

Question 1

Easy

What instrument is used to measure horizontal and vertical distances in surveying?

💡 Hint: It's a surveying tool that combines flexibilities in measuring.

Question 2

Easy

What does the term 'gradient' refer to?

💡 Hint: Think about the steepness of a hill.

Practice 4 more questions and get performance evaluation

Interactive Quizzes

Engage in quick quizzes to reinforce what you've learned and check your comprehension.

Question 1

What is the formula to calculate horizontal distance using a tacheometer?

  • A) D = K * S * sin²θ
  • B) D = K * S * cos²θ + C * sinθ
  • C) D = V / gradient

💡 Hint: Recall the role of angles in the formula.

Question 2

True or False: The gradient is expressed as a simple ratio of vertical change to horizontal distance.

  • True
  • False

💡 Hint: Consider how steep a hill can be.

Solve and get performance evaluation

Challenge Problems

Push your limits with challenges.

Question 1

Given vertical angle readings and stadia distances, calculate the exact position and gradient between two stadium sections using a tacheometer.

💡 Hint: Ensure stadia readings are taken consistently to minimize errors.

Question 2

Analyze and demonstrate how measurement errors in tacheometric readings affect overall gradient calculations in a construction project.

💡 Hint: Think about how misreading an angle alters the slope calculation.

Challenge and get performance evaluation