Practice How to Use the Pumping Lemma to Prove Non-Regularity (Proof by Contradiction) - 2.9.3 | Module 2: Deterministic Finite Automata (DFA) and Regular Languages | Theory of Computation
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2.9.3 - How to Use the Pumping Lemma to Prove Non-Regularity (Proof by Contradiction)

Learning

Practice Questions

Test your understanding with targeted questions related to the topic.

Question 1

Easy

What is the Pumping Lemma?

πŸ’‘ Hint: Think about what regular languages can do with their structure.

Question 2

Easy

What is one property that the Pumping Lemma guarantees?

πŸ’‘ Hint: Why is having a non-empty segment important?

Practice 4 more questions and get performance evaluation

Interactive Quizzes

Engage in quick quizzes to reinforce what you've learned and check your comprehension.

Question 1

Which of the following is a condition of the Pumping Lemma?

  • |y| = 0
  • |xy| > p
  • |y| β‰₯ 1

πŸ’‘ Hint: Consider the consequences of having an empty segment.

Question 2

True or False: The Pumping Lemma applies only to regular languages.

  • True
  • False

πŸ’‘ Hint: Think about the definitions we discussed.

Solve 1 more question and get performance evaluation

Challenge Problems

Push your limits with challenges.

Question 1

Prove that the language L = { a^n b^n | n β‰₯ 0 } is not regular using the Pumping Lemma.

πŸ’‘ Hint: Focus on how changing the count of a's by factoring in y affects the overall string.

Question 2

Consider the language L = { x ∈ {0,1}* | x has a prime length }. Prove it is not regular.

πŸ’‘ Hint: Analyze how prime numbers behave under addition and repetition.

Challenge and get performance evaluation