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27.3.2. Finding Output Resistance
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Today we’ll discuss how we derive the output voltage in a common emitter amplifier, defined by v_out = -gm * Rc * v_be. Can anyone remind me what ‘gm’ represents?
It stands for transconductance, right?
Exactly! Transconductance (B3m) measures how effectively the input voltage modifies the output current. Now, if we incorporate the emitter resistance, how do we affect the output voltage?
Adding emitter resistance decreases the voltage gain?
Right, it does! The voltage gain expression becomes A = -gm * Rc / (1 + gm * Re). Here’s a mnemonic to remember this: ‘Gain’s Momentum Requires Efficiency,’ or GmRc/Re!
That's a catchy way to remember it!
Great! Let’s summarize: gain relies heavily on both the transconductance and the effective resistances in the circuit.
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Next, let’s discuss input and output resistance for the CE configuration. What do you think is the first step in determining the input resistance?
Do we apply a test voltage to the input and measure the resulting current?
Exactly! We’ll be finding the voltage across R and the emitter resistance, leading to Rin = r + (1 + B2)Re. Now can someone clarify why understanding this output resistance matters?
Because it tells us how the amplifier will respond to load changes?
Spot on! Let’s also remember the output resistance can be affected by parallel elements and ideal current sources, calculated as Ro = Rc || (rp + Re).
So by managing Ro, we can better tailor our amplifier’s performance?
Absolutely, managing those values is crucial for stable performance. Keep this in mind as we move forward!
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Now let’s shift gears to design considerations. Why is it important to select Rc and Re carefully?
Because if we choose wrong values, the performance can degrade due to too low of a gain?
Exactly! Allowing too large a value in Re can significantly drop the gain. We aim for a lower cutoff frequency to keep the amplifier responsive to AC signals while stabilizing against beta variation. What should we consider?
The resistor values must maintain the operational stability without compromising performance?
Yes, it’s a balancing act! Remember, lower resistance improves responsiveness, but increases current flow, raising power dissipation. Always seek a suitable compromise!
That makes sense! It’s a calculated risk.
Well said! Balancing stability and performance is key in amplifier design. Recap: select component values carefully and remember how they impact not just gain but also stability.
Overview
Short Summary
This section focuses on understanding the output resistance of a common emitter amplifier, covering how it can be calculated and its implications on amplifier design.
Medium Summary
In this section, we explore the parameters of output resistance in the common emitter amplifier context. We derive equations for both input and output resistances, emphasizing how emitter resistance influences these parameters and the overall gain of the amplifier. Practical considerations and design guidelines for maintaining desired performance metrics in real-world circuits are also discussed.
Detailed Summary
Finding Output Resistance
This section delves into the common emitter amplifier, focusing on determining output resistance and input resistance, and their significant impact on the overall performance of the amplifier circuit. The fundamental relationships derived from the small signal equivalent circuit model illustrate how various resistances affect both gain and stability.
Key Points:
- The output voltage relation is derived from the gain function of the circuit, contingent upon the input-base voltage and the transistor’s transconductance, denoted as
A = -gm * Rc / (1 + gm * Re)whereRcis the collector resistance andReis the emitter resistance. - The addition of an emitter resistor (
Re) plays a dual role: it improves the thermal stability of the circuit but reduces the voltage gain due to increasedRe. As noted, the presence ofRecan lead to desensitizing the circuit's gain against variations in transistor beta (B2), posing a challenge in circuit design. - To find the output resistance (
Ro), various circuit components are considered, particularly the effects of the existing resistors and the ideal current source model introduced by the transistor. Calculation leads to an expression expressed asRo = Rc || (r_p + (Re || r)), accommodating practical resistance coefficients. - Practical design considerations, such as maintaining a low lower cutoff frequency while considering biasing stability, are critical, notably when dealing with the trade-offs involved with resistor values and their impacts on performance.
The conclusions drawn in this section emphasize the need for strategic component selection in amplifier design to optimize both resistance and gain while maintaining operational integrity.
Reference YouTube Videos
Audio Book
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Create a free accountWhile we will be doing this similar kind of exercise, we need to find as I said that we need to find what will be the output resistance R of this voltage amplifier, while we are mapping this small signal equivalent circuit into a voltage amplifier.
Detailed Explanation
To find the output resistance of a voltage amplifier, we perform an analysis similar to that of input resistance. First, we apply a small voltage signal at the output port and then monitor the resulting current. We essentially need to determine how the output voltage behaves when we vary the output current—this is a key characteristic of a circuit's output resistance. Since we're applying a voltage, we want to keep the input signals fixed to ensure we're measuring resistance accurately.
Examples & Analogies
Imagine you're trying to determine how 'hard' a sponge is. If you press a sponge (apply a voltage), the amount of water it releases (current) can tell you how compact or loose the sponge material is (equivalent to resistance in the circuit). This analogy helps us understand that by applying a known input (pressure), we can measure the resulting output (water flow) to gauge the sponge's characteristics.
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Create a free accountWhat you have to do? Again we will be stimulating this circuit from this port by say a signal source called v or say v and then we can observe the corresponding current let we mark it as say i.
Detailed Explanation
In the process of measuring output resistance, we introduce a known voltage signal (stimulus) at the output and then measure the current that flows as a result. The output resistance R can be derived from the ratio of the output voltage to the current flowing through the circuit. By applying the voltage signal and making the other signals ground, we ensure the circuit operates under controlled conditions, allowing for an accurate measurement of output resistance.
Examples & Analogies
Consider a water faucet: when you turn it on (apply a voltage), water flows out (current). If you want to know how hard you can press the faucet without wasting water, you'd measure how much water flows out with each turn (this is analogous to measuring the voltage and current in a circuit). This helps to understand the faucet's characteristics just like measuring output resistance does for an electrical circuit.
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Create a free accountFrom that we can say directly that R = R . Now, this is of course, we are assuming that the conductance here it is 0. Now, if I consider the additional conductance of course, will be having the influence of this part also.
Detailed Explanation
We find that the output resistance ( R ) can be simply taken as the resistance components in parallel, assuming ideal conditions (i.e., no significant conductance). This means that the output resistance we measure will be affected by any additional conductance present in the circuit when determining its overall value. If we take the conductance into account, it can slightly alter the calculations.
Examples & Analogies
Think of combining two hoses to water a garden: if both hoses output a fixed amount of water without any blockage (zero conductance), we can simply add them for total output efficiency. But if one hose has a blockage (added conductance), the total output gets affected. So understanding the individual contributions is crucial, just like in measuring output resistance where additional circuit elements can change the outcomes.
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Create a free accountIf you see this circuit, we may frequently come to this circuit again and again and so, let me draw this circuit as a general one. So, we do have current source here which is g m times whatever you say v and then we do have the r here and then we do have the resistance here.
Detailed Explanation
In circuits, especially in amplifiers, it's important to recognize that additional conductance beneath the circuit can dramatically change the output behavior. For a more accurate representation of output resistance, we must account for all components (like resistors and sources) that influence the current flow. This gives a deeper understanding of how the circuit behaves under different conditions, ensuring reliable designs.
Examples & Analogies
Imagine a road system: when calculating traffic flow, you don't just look at one road; you consider all connecting routes and traffic signals that affect how cars move (akin to resistance in circuits). Just like in traffic systems, understanding each component in a circuit helps us predict its performance accurately.
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Create a free accountSo, let me rewrite whatever I just now have said that output resistance R which is R in parallel with whatever the resistance it is coming from this circuit and that resistance it is ... R .
Detailed Explanation
The final output resistance is the total resistance measured at the output port, which takes into account both the inherent resistance of the amplifier and any additional resistances present in the circuit. Recognizing these parallel components is vital for accurate output performance. This expression gives us a framework for how to analyze and calculate the resistances together.
Examples & Analogies
Visualize pouring water into a bucket with holes: if the bucket's material has holes (resistance) and the bottom has a hole too (additional resistance), the effective storage capacity decreases. Similarly, when calculating output resistance, it's essential to consider both the internal resistance of the amplifier and any additional resistances that affect total performance.
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Key concepts
Core takeaways and short definitions to help you quickly recall the key ideas from this section.
- Transconductance (gm):
It is essential for determining how input voltage affects output current.
- Voltage Gain (A):
The ratio of output voltage to input voltage, heavily influenced by emitter resistance.
- Output Resistance (Ro):
Key to understanding how much load the amplifier can handle effectively.
- Input Resistance (Rin):
Determines how much input signal the amplifier can accept without impacting voltage.
- Design Considerations:
Emphasizes the necessity for balancing component values for optimal amplifier performance.
Examples
Step-by-step examples to apply the section's ideas and test your understanding.
In a typical common emitter amplifier, if gm = 0.02 S and Rc = 4.7 kΩ with Re = 1 kΩ, calculate the voltage gain.
When designing an amplifier, if you wish to target a lower cutoff frequency of 20Hz while maintaining gain stability, carefully select Re and Rc within practical ranges.
Memory aids
Flash Cards
Glossary
Transconductance (gm)
A measure of the change in output current per change in input voltage.
Output Resistance (Ro)
The equivalent resistance seen by the load connected to the output terminal of the amplifier.
Input Resistance (Rin)
The resistance presented at the input terminal of the amplifier scheme.
Emitter Resistance (Re)
Resistance connected to the emitter terminal, stabilizing operating points in amplifiers.
Collector Resistance (Rc)
Resistance connected to the collector terminal influencing output voltage gain.
Small Signal Equivalent Circuit
A linearized model representing the behavior of nonlinear devices for small variations in input.