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Today, we'll discuss current mirrors, crucial components in analog circuits that allow for precise current reproduction. Can anyone explain the basic concept of a current mirror?
Is it a circuit that copies current from one branch to another?
Exactly! A current mirror ensures that the output current in one branch mirrors the reference current. This configuration is vital for ensuring consistent performance in various applications.
What types of transistors do we use in current mirrors?
Good question! We commonly use MOSFETs and BJTs. Each has unique characteristics that suit different design requirements. Do you remember the importance of operating in saturation for these transistors?
Yes! If theyβre not in saturation, they wonβt function properly.
Exactly! This saturation condition is essential for reliability. Let's summarize: Current mirrors replicate current, and saturation is key for operational stability.
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Now, let's focus on calculating voltages and currents in current mirrors. The calculations can seem complex, but they follow a systematic approach. Can anyone outline the basic steps?
Do we start by identifying our given values like supply voltage and resistor values?
Correct! Once we have our supply voltage and resistances, we can apply Kirchhoff's laws to find unknown voltages or currents. For example, if we have a 12 V supply and a resistor of 19 kβ¦, how would we begin?
I think we calculate the voltage drop across the resistor first?
Exactly! Then we subtract that from the supply voltage to find the voltage across the MOSFET. This method helps us maintain clarity throughout the calculations.
So it's about breaking it down into smaller, manageable parts?
Precisely! Conceptualizing the problem in parts is key. To recap: Identify values, calculate drops, and solve systematically.
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Next, letβs discuss output resistance. Can anyone explain why output resistance matters in current mirrors?
Higher output resistance means the current is less affected by changes in output voltage, right?
Exactly! It ensures that the output current remains stable even if the output voltage varies. So, how can we calculate this output resistance?
By using the formula that includes transconductance and output resistance of the connected transistors?
Correct! The formula incorporates the transconductance of each transistor and their channel length modulation effects. Let's summarize: Higher output resistance translates to improved performance.
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Finally, letβs connect our learning to real-world applications. How are current mirrors utilized in amplifiers?
They are used as active loads to improve efficiency and performance in amplifiers!
Absolutely! By implementing current mirrors, we can enhance the gain of amplifiers without additional power consumption. Can you think of any specific amplifier types that utilize this configuration?
Common source amplifiers!
Exactly! They are an excellent example where the current mirror aids in achieving high output resistance and gain. Letβs summarize todayβs discussion: Current mirrors serve as a cornerstone in analog circuit design, enhancing performance in various applications.
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The section elaborates on calculating voltage and current in non-ideal transistor circuits, specifically current mirrors. It emphasizes using various transistor configurations, such as MOSFET and BJT, while addressing parameters like threshold voltage, output resistance, and biasing techniques to optimize circuit performance.
In this section, we explore the calculations related to voltage and current in current mirror circuits. Current mirrors are essential in analog electronics for maintaining an accurate reference current. Initially, we focus on the MOSFET version and establish the role of cascode transistors in improving output resistance and compensating for non-idealities due to base current losses and Early voltage effects.
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So in the next example, we are starting with MOSFET version and then after that we will go to the BJT version. And so, here transistor-3 it has been added on the main current mirror. So, the main current mirror it is constructed by M1 and M2 and whatever the reference current it is coming, it is mirroring here.
In this section, we are discussing the concept of current mirrors using MOSFETs. Current mirrors are circuits that create an output current which is a precise copy of an input reference current. In this example, we start by constructing a current mirror circuit using two MOSFETs (M1 and M2). Then, we add another transistor (M3) to enhance its performance. This addition allows the circuit to maintain the desired current output even when the output voltage changes, making it more reliable for analog applications.
Think of a current mirror like a team of identical twins who are tasked to weigh the same amount. One twin is given a scale (the input current) and is supposed to measure their weight (the output current). The other twin tries to match their weight by maintaining the same diet (output performance), regardless of external factors like different schools they might attend (output voltage). If one twin starts veering off diet but the other remains strict, the accuracy in matching weights falters.
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To have meaningful operation of this circuit, we require its gate voltage V_GS1 to be sufficiently high. This should ensure that transistor-2 and maybe transistor-3 are in the saturation region of operation.
For the current mirror to operate effectively, it's crucial to keep both M2 and M3 in a saturation state. This means the gate-source voltage (V_GS) must be higher than a certain threshold. Keeping them in saturation ensures that they can mirror the input reference current accurately. If the gate voltage is not sufficiently high, these transistors could go into the cutoff region, failing to operate correctly.
Imagine a water faucet that only works when the tap is turned properly (gate voltage). If you donβt turn it enough (not high enough voltage), the water (current) won't flow out as intended. Similarly, for a MOSFET to work well, it needs just the right voltage at the gate.
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Now coming to the different sizes of different transistors given here, we do have for transistor-1, we do have the K1 = 1 mA/VΒ². On the other hand for transistor-2 and transistor-3, we do have K2 = 4 mA/VΒ².
Each MOSFET in the circuit has associated parameters determining how they behave. For example, the current gain factor (K) for transistor M1 is 1 mA/VΒ², while for M2 and M3, it's greater at 4 mA/VΒ². This implies that M2 and M3 can drive more current for the same voltage compared to M1. Using different sizes allows more flexibility in designing circuits tailored to specific requirements.
Consider a power adapter (transistor) with different outputs. An adapter with a rating of 1A can charge a phone slowly, while one rated at 4A can do it much faster. Similarly, by adjusting the ratings (or sizes) of the transistors, we influence how efficiently the circuit performs depending on the requirements.
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So to calculate that, in some of our previous examples we have done that this current which is I_DS1 is also creating a drop here and after subtracting this drop from 12V supply, it is giving us the V_GS1. So, V_GS1 = V_DD - I_DS1 * R_BIAS.
When calculating the gate-source voltage V_GS1 for our current mirror, we must account for the voltage drop caused by the current flowing through the bias resistor (R_BIAS). The relationship shows that if we have a higher current, it creates a larger voltage drop, consequently reducing the gate voltage. This calculation is crucial to ensure that transistors remain in the saturation region to perform optimally.
Consider a water tank system where water pressure (voltage) decreases as water flows through pipes (resistors). If too many pipes are used or they are too narrow (higher current through the bias resistor), the pressure at the end drops significantly, affecting the flow at the end point. Here, the voltage supply must be adjusted accordingly based on the resistance.
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So, we need to find what will be the small signal output resistance. And R_out = g_m3 * r_o3 + r_o2.
The small signal output resistance is an essential parameter for analyzing how well our current mirror can maintain a constant output current under varying voltage conditions. By calculating it as the product of transconductance (g_m3) and the output resistance of transistor M3 (r_o3), plus the output resistance of M2 (r_o2), we can evaluate the performance robustness of the current mirror. A higher output resistance indicates better performance.
Think of a sturdy bridge (output resistance) that can handle heavy vehicular traffic without bending under pressure. A well-constructed bridge ensures smooth movement (consistent current) even if more vehicles (varying voltage) try to cross simultaneously. A weak bridge might crumble under heavy load, indicating the importance of robust design.
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So, what we can do for simplicity, we let we consider V_GS1 = V_GS1, so that we can write this is negative with V_th but then since we are adding it, we also have to subtract here the same V_th.
In simplifying our equations for V_GS1 based upon the threshold voltage, we can express this in terms of a single variable for clarity in calculations. Itβs essential to manage these algebraic manipulations carefully, so they reflect in the performance metrics. This approach helps extract relationships that can guide us in adjusting biases for optimal current mirror function.
Imagine organizing a team of workers who have different roles, such as a project manager adding and subtracting responsibilities (V_th) so the project functions smoothly. If every change balances out, the overall work will flow efficiently, just as managing voltages and currents does in our circuit.
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Key Concepts
Current Mirror: A key circuit that replicates a reference current.
Saturation in Transistors: Essential for consistent performance in current mirrors.
Output Resistance: Critical for maintaining stable current under variable conditions.
Transconductance: Vital for determining how effectively a transistor controls the output current.
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In a MOSFET current mirror, when the reference current is set at 1 mA with a 12 V supply, the corresponding output current can be determined using the characteristics of the employed transistors.
When using BJTs, if the base-emitter voltage is approximately 0.6 V, a current mirror can maintain a reference current even as supply voltage varies.
Use mnemonics, acronyms, or visual cues to help remember key information more easily.
In a current mirror circuit tight, Transistors work just right, Saturation keeps it true, Current copiers are the view.
Once in a circuit land, a tiny transistor dreamed of having a twin. In each branch, they mirrored their current, ensuring balanced power flows, making the whole circuit shine with uniformity.
Remember 'I See', for Current Mirrors: 'I' for increased stability, and 'C' for current replication.
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Review the Definitions for terms.
Term: Current Mirror
Definition:
A circuit configuration that copies a current from one branch to another, maintaining a constant output current.
Term: Saturation Region
Definition:
The operating region of a transistor where it behaves like a closed switch, ensuring maximum current flow.
Term: Output Resistance
Definition:
The resistance seen by the output of a transistor, affecting the current stability under varying loads.
Term: Transconductance
Definition:
The measure of how effectively a transistor can control the output current based on the input voltage.