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Today, we're going to discuss the concept of work in physics. To start, work is essentially the energy transferred when a force is applied over a distance. Can anyone tell me the formula for calculating work?
Isn't it W equals force times distance?
That's correct! The formula is W = F.d cosine(ΞΈ), where ΞΈ is the angle between the direction of the force and the displacement. Now, why do you think the angle matters?
I think it shows how much of the force is actually making the object move.
Exactly! If the force acts perpendicular to the displacement, no work is done. Remember, if the angle is 90 degrees, cos(90Β°) equals 0, so the work is zero. Can anyone give an example of a situation where work could be zero?
Like pushing against a wall? I'm exerting a force, but the wall doesn't move!
Good example! Letβs recap: Work is defined as the product of force and displacement, factoring in the angle. To remember this, we can use the acronym W = F * d cos(ΞΈ).
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Now that we understand work, let's shift to kinetic energy. Kinetic energy is the energy of motion. If an object is in motion, it possesses energy expressed by the formula K = (1/2) mvΒ². What do you think each symbol represents?
m is mass and v is velocity, but why do we multiply by 1/2?
Good question! The 1/2 factor comes from integrating the work done on an object to accelerate it from rest to its speed. As its velocity increases, so does its energy. Can someone explain why kinetic energy is always positive?
Because mass and velocity squared are always positive numbers, right?
Exactly! It shows that kinetic energy canβt be negative, reflecting that an object in motion is always said to carry energy. Letβs write the equation together: K = (1/2) mvΒ². Remember this equation as it illustrates how quickly an object moves impacts its energy.
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Let's discuss the work-energy theorem now. This theorem states that the work done on an object equals the change in its kinetic energy. Who can write that as an equation?
I think it's ΞK = W, right?
Absolutely right! ΞK represents the change in kinetic energy, W is the work done on the object. Can anyone give me an example of how this theorem applies in a real-world situation?
If I kick a ball, the work I do on the ball causes it to speed up, right?
Exactly! That's a perfect scenario illustrating the theorem. The work you apply results in the ball accelerating, demonstrating how forces affect motion. Letβs conclude todayβs lesson by recapping that work results in changes in energy, bridging our understanding of motion with force.
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The section presents the definitions of work and kinetic energy, and outlines the work-energy theorem, emphasizing the relationship between the work done on an object and its change in kinetic energy. It further discusses scalar products and their significance in calculating work in various scenarios.
In this section, we explore the fundamental concepts of work, kinetic energy, and the work-energy theorem, which are pivotal in understanding motion and energy conservation in physics.
Work is defined as the product of the force acting on an object and the displacement caused by that force, specifically in the direction of the force. Mathematically, work () is expressed as:
W = F.d = F d cos(ΞΈ)
where ΞΈ is the angle between the force vector and the displacement vector. The significance of the angle illustrates how not all applied forces result in work unless they contribute to displacement.
This section also clarifies that work can be positive, negative, or zero depending on the relationship between force and displacement. For instance, work is negative when the applied force and the displacement are in opposite directions, which is common in friction scenarios.
Kinetic energy (K) is described as the energy possessed by an object due to its motion, calculated as:
K = (1/2) mvΒ²
where m is the mass and v is the velocity of the object. This concept quantifies the capacity of an object to perform work owing to its motion.
The work-energy theorem connects the work done on an object to its change in kinetic energy. It is expressed as:
ΞK = W
where ΞK represents the change in kinetic energy, highlighting that the net work done on an object results in an equivalent change in kinetic energy. This theorem provides essential insights into how forces influence motion and energy in a system.
By establishing the mathematical frameworks of scalar products, it elucidates how vectors can be manipulated to yield scalar quantities that denote work done under varying conditions of force.
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The following relation for rectilinear motion under constant acceleration a has been encountered in Chapter 3,
vΒ² β uΒ² = 2as (5.2)
where u and v are the initial and final speeds and s the distance traversed. Multiplying both sides by m/2, we have
2 2 1 1
2 2mv mu mas Fsβ = = (5.2a)
where the last step follows from Newtonβs Second Law. We can generalise Eq. (5.2) to three dimensions by employing vectors
vΒ² β uΒ² = 2aΒ·d
Here a and d are acceleration and displacement vectors of the object respectively.
This chunk focuses on a fundamental equation of motion under constant acceleration known as the kinematic equation. It relates the squares of the final and initial velocities (vΒ² and uΒ²) of an object to the acceleration (a) and the distance (s) it travels. By recognizing that force (F) is related to mass (m) and acceleration via Newton's Second Law, we multiply this kinematic equation by half the mass, leading to the left side representing kinetic energy change. The right side introduces the connection to the work done on the object.
Imagine a car accelerating from a stoplight. The faster it goes (higher v), the more distance it covers (s) while accelerating. The car's engine provides a force that corresponds to its acceleration (a). By applying this equation, we can understand how much energy was used to achieve this acceleration, much like calculating gas usage based on speed and distance driven.
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The above equation provides a motivation for the definitions of work and kinetic energy. The left side of the equation is the difference in the quantity βhalf the mass times the square of the speedβ from its initial value to its final value. We call each of these quantities the βkinetic energyβ, denoted by K. The right side is a product of the displacement and the component of the force along the displacement. This quantity is called βworkβ and is denoted by W.
This chunk explains how the equation derived connects two important concepts in physics: kinetic energy (K) and work (W). Kinetic energy, defined as half the mass multiplied by the square of speed, represents the energy an object possesses due to its motion. Work is defined as the force applied to an object multiplied by the distance over which this force is applied. The relationship shows that the work done on an object results in a change in its kinetic energy.
Consider pushing a shopping cart in a grocery store. The harder you push (force), the farther it moves (displacement). If you apply enough force to accelerate the cart, you do work on it, which increases its speed and thus its kinetic energy. If you push gently, the cart moves less quickly and does not gain as much kinetic energy.
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Eq. (5.2b) is then Kf β Ki = W (5.3)
where Ki and Kf are respectively the initial and final kinetic energies of the object. Work refers to the force and the displacement over which it acts. Work is done by a force on the body over a certain displacement. Equation (5.2) is also a special case of the work-energy (WE) theorem: The change in kinetic energy of a particle is equal to the work done on it by the net force.
This chunk focuses on the work-energy theorem, which is a key principle in physics. The equation illustrates that the net work done on an object is equal to the change in its kinetic energy, effectively encapsulating how forces influence motion. This relationship helps clarify that work does not merely represent exertion; it indicates an energy transfer that can cause changes in velocity or speed.
Think of a skateboarder going down a ramp. The force of gravity does work on the skateboarder, causing them to accelerate and increase their kinetic energy as they descend. If they were to suddenly hit a rough patch and slow down, the work done against them would reflect a change in their kinetic energy, demonstrating the work-energy theorem in action.
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Example 5.2 It is well known that a raindrop falls under the influence of the downward gravitational force and the opposing resistive force. The latter is known...
This example illustrates the application of the work-energy theorem in a scenario involving gravitational force and air resistance. It showcases how the kinetic energy of the falling raindrop changes due to the net work done by these competing forces, allowing students to see a practical implication of the work-energy theorem.
Picture a raindrop falling from the sky. As it drops, it speeds up due to gravity (gain in kinetic energy) until it reaches terminal velocity. At this point, the downward force of gravity equals the upward air resistance, and it falls with constant speed. This situation exemplifies the forces at play in real life and how they alter an object's energy.
Learn essential terms and foundational ideas that form the basis of the topic.
Key Concepts
Work: The energy transferred by a force over a distance.
Kinetic Energy: Energy of an object due to its velocity.
Work-Energy Theorem: The relationship between work done on an object and the change in its kinetic energy.
Scalar Product: A mathematical way to measure force in relation to displacement.
See how the concepts apply in real-world scenarios to understand their practical implications.
When pushing a box across a floor, the work done depends on the force applied and the distance moved in the direction of that force.
A ball at rest has no kinetic energy, but when rolled, it gains kinetic energy that can be calculated using its mass and speed.
Use mnemonics, acronyms, or visual cues to help remember key information more easily.
Work and speed, energy we feed; push and pull, distances rule.
Imagine pushing a heavy door. The more you push, the further it swings. This story represents work; force times distance, bringing the door to life!
To find Work Done We Go: W = F Γ d Γ cos(ΞΈ).
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Review the Definitions for terms.
Term: Work
Definition:
The product of force and displacement in the direction of the force; measured in joules.
Term: Kinetic Energy
Definition:
The energy possessed by an object due to its motion, calculated using K = (1/2) mvΒ².
Term: WorkEnergy Theorem
Definition:
The principle stating that the work done on an object is equal to the change in its kinetic energy.
Term: Scalar Product
Definition:
The dot product of two vectors, resulting in a scalar quantity that represents magnitude and directional alignment.