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Let's start by discussing how we delete a node in a binary search tree, beginning with the simplest case: when the node is a leaf. Can anyone tell me what a leaf node is?
A leaf node is a node that has no children!
Exactly! So when we delete a leaf node, we simply remove it. For example, if we are deleting node '65' because it is a leaf, we just take it out of the tree.
So we don't have to worry about maintaining child links in this case?
Correct! A leaf deletion is straightforward. To remember this, you can think of the acronym SHORT β Simply Heave Out Rightly the Tree.
Ah! That's a good way to remember it!
Let's summarize: deleting a leaf node means simply removing it; no restructuring is needed.
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Now letβs move on to the next scenario: deleting a node that has only one child. Who can explain how we handle this case?
Do we just remove the node and connect its parent to the child?
Yes, exactly! If we delete node '74', for instance, and it has child '91', we simply adjust the parent node to point to '91' instead of '74'. Remember the mnemonic 'CROSS' β Connect the Right Output of the Single child.
So, itβs like moving the child up?
Correct! This process is often referred to as promoting the child. Anyone have questions about this step?
Not at the moment!
Great! So just to recap: deleting a node with one child involves promoting that child to its parents position.
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Now for the final and most complex scenario: deleting a node that has two children. Which approach do we take here?
We find the maximum value from the left subtree to move up!
Exactly! If we decide to delete node '37', we look to the left subtree to find the largest value there. In this case, what would that be?
It would be '28'!
Right! So we replace '37' with '28', and then we also need to delete '28'. To do that, we check if itβs a leaf or has children.
If itβs a leaf we just remove it, but if it has one child, we promote that child, right?
Perfect! Remember: the acronym MAP β Maximize After Promotion β helps keep this in mind.
Iβll remember that!
Letβs summarize: when deleting a node with two children, find the max on the left and do a two-level deletion.
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Lastly, letβs wrap up with the time complexity of our operations. Can anyone identify how deletion complexity relates to tree structure?
It depends on the height of the tree?
Exactly! In a balanced tree, deletion operations can be done in logarithmic time. So, what happens if we have an unbalanced tree?
It could potentially take linear time since it would resemble a linked list!
Spot on! Itβs crucial that we maintain balance in our trees. The term to remember here is BALANCE β Binary Adjustment Like A New Careful Entry.
That makes it easy to remember!
Let's sum up: tree height influences deletion complexity and we need to maintain balance to optimize performance.
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The section details the complexities of deleting nodes in a binary search tree, discussing three key scenarios: removing a leaf, bypassing a node with one child, and replacing a node with its maximum value from the left subtree. Each scenario is illustrated with examples and explanations of the relevant code functions.
This section focuses on the deletion operations in binary search trees (BST), highlighting how nodes can be effectively removed based on certain conditions.
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So, delete is a little bit more complicated than insert. So, basically whenever we find v in the tree and that can only be one v remember this is not like deleting from the list that we had before where we were removing the first copy of v in a search tree we have only one copy of every value if at all. If we find v we must delete it. So, we search for v as usual now if the node that we are searching for is a leaf then we are done we just delete it and nothing happens.
To delete a value (v) from a binary search tree, we first search for that value. If the value is located in a leaf node, which means it has no children, deleting it is straightforward; we simply remove it from the tree, and nothing else in the tree is affected.
Imagine a library where a particular book (representing the value) is found on a shelf (the tree) but has no other books around it (no children). If the librarian decides to remove that book from the shelf, they can easily take it off without affecting the other books.
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Now, we try to delete 74. So, we find 74 and we find that it has only one child. So, if it has only one child then we can promote this child. We can effectively short circuit this link and move this whole thing up and make 52 point to 91 directly.
When deleting a node (like 74) that has only one child, we can easily adjust the tree's structure. We simply connect the parent of the deleted node directly to its only child. This operation is known as 'promoting the child.' It simplifies the tree and maintains its properties.
Imagine you have a vending machine (the tree) with a snack (the node) that is stuck (the node being deleted) but only has one snack option (the one child). Instead of leaving the machine empty, you can just remove the stuck snack and immediately promote the next snack available, thereby keeping the machine stocked.
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Now, finally, we have the difficult case which is you want to delete a node which is in the middle of the tree, in case this case 37. So, we come to 37 and we want to remove this. Now, if we remove this there will be a vacancy now, what do we fill the vacancy again and how do we adjust the shape of the tree. So, we look to the left and find the maximum value...
For nodes with two children like 37, we can't simply remove it because it creates a gap in the tree. To fill this gap, we take the maximum value from its left subtree (the largest node that is smaller than 37) and move it to the position of 37. This ensures that the binary search property remains intact. After that, we must also delete the original position of that maximum value, which is now a duplicate.
Think of a restaurant menu (the tree) where a popular dish (the node to delete) has two sides: an appetizer and a dessert. When removing the popular dish, instead of leaving a gap, the chef might choose the most popular appetizer to take its place, ensuring customers still have a delightful option. After that, the chef removes the original appetizer, maintaining the menu's appeal.
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We can now look at the function. If there is no value v then we just return the easy cases are when we do not find we are the current thing...
The complexity of deletions in a binary search tree depends on the height of the tree. If the tree is balanced, then the height is logarithmic, making deletion operations quite efficient. However, if the tree becomes unbalanced, like when nodes are added in a sorted manner, operations can degrade to linear time complexity (height proportional to the number of nodes). This emphasizes the importance of maintaining a balanced tree.
Consider a well-organized pantry (balanced tree) where every shelf (level of the tree) holds a manageable number of items (nodes). If you keep adding snacks in an orderly fashion without mixing them, soon you'll end up with one long shelf full of snacks (unbalanced tree), making it harder to find what you need (slower operation). Keeping things mixed up allows you to manage the snack variety better and maintain an easy-to-navigate system.
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If we have a balanced tree then it is not difficult to see then we have height logarithmic in an this is like a heap a heap is an example of a balanced tree...
Balanced trees ensure that operations such as search, insert, and delete remain efficient, typically with logarithmic time complexity. AVL trees are one example of self-balancing binary search trees. They automatically adjust their structure upon insertions or deletions to maintain a balance, thus preserving efficient operation times.
Think of an orchestra (the balanced tree) where all the musicians (nodes) play in harmony (insertions and deletions happen smoothly). If one musician plays out of turn (unbalanced tree), it disrupts the sound and organization, but if they follow the conductor's lead (balancing), the music flows effortlessly, making it enjoyable for everyone.
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Here we have a python code for the class tree that we showed in the lectures...
The text discusses a Python class structure for implementing tree operations. Important functions include checking if a node is empty or a leaf, converting a leaf to an empty node, and how to handle the actual insertion and deletion logic.
Imagine a programmer (you) trying to build a digital library (the code) where each function (method) is a tool like sorting, checking emptiness (is_empty), and managing books (nodes). Just as a librarian needs to know how to sort and retrieve books efficiently, the programmer must write effective code to manage the tree's operations smoothly.
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Key Concepts
Leaf Deletion: Remove immediately without restructuring.
Single Child Deletion: Promote the child to maintain links.
Two Children Deletion: Use maximum from left or minimum from right for replacement.
See how the concepts apply in real-world scenarios to understand their practical implications.
Deleting a leaf node like '65' involves simple removal without affecting the tree structure.
Deleting a node like '74' with one child means directly connecting its parent to its child, '91'.
For node '37', find '28' from its left subtree to replace it and delete '28' as well.
Use mnemonics, acronyms, or visual cues to help remember key information more easily.
When a leaf is flying free, it can be removed easily.
Imagine a tree where nodes talk. One day, a leaf node says goodbye with no other words. Meanwhile, a middle node with one child promotes the child like a proud parent to take over the family name.
DPT: Delete - Promote - Traverse for remembering node deletion steps.
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Review the Definitions for terms.
Term: Binary Search Tree (BST)
Definition:
A binary tree where each node follows the left child being less than the parent and the right child being greater.
Term: Leaf Node
Definition:
A node without any children in a tree structure.
Term: Promoting a Child
Definition:
The process of moving a child node up to the position of its parent node when the parent is deleted.