Industry-relevant training in Business, Technology, and Design to help professionals and graduates upskill for real-world careers.
Fun, engaging games to boost memory, math fluency, typing speed, and English skills—perfect for learners of all ages.
Enroll to start learning
You’ve not yet enrolled in this course. Please enroll for free to listen to audio lessons, classroom podcasts and take practice test.
Listen to a student-teacher conversation explaining the topic in a relatable way.
Let's begin with the definition of a partition of a set. A partition of a set, say C, is a collection of non-empty, pairwise disjoint subsets of C, such that their union returns the original set C.
Can you explain what pairwise disjoint means?
Great question! Pairwise disjoint means that any two subsets do not have any elements in common. For example, if A and B are two subsets of C, then A ∩ B equals the empty set.
Could you give an example of a partition?
Certainly! If C = {1, 2, 3, 4} then one possible partition could be {{1, 2}, {3, 4}}.
What if the subsets overlapped?
If subsets overlap, it wouldn't be a proper partition. Partitions require that the subsets are completely disjoint!
To summarize, a partition includes subsets that are non-empty, collectively exhaustive (their union forms the original set), and pairwise disjoint.
Now let's delve into how equivalence relations relate to partitions. Can anyone remind me what an equivalence relation is?
It's a relation that is reflexive, symmetric, and transitive.
Exactly! When we have an equivalence relation R defined on a set C, it allows us to group elements into equivalence classes. I claim that these classes form a partition of C. Can anyone identify one of the properties we need to prove that?
They must be non-empty, right?
Correct! Each equivalence class must contain at least one element because each element is related to itself due to the reflexity of R. What’s our next proof requirement?
We need to show that the union of all classes equals C.
Exactly! Since every element belongs to some equivalence class, the union gives back the original set. Lastly, do we remember the final proof condition?
They need to be pairwise disjoint!
Yes! That follows from our earlier classes, where we discussed that two different equivalence classes cannot share elements. For our final recap: equivalence classes must be non-empty, their union must yield C, and they must be pairwise disjoint.
Suppose you have a partition of a set. How could we create an equivalence relation from it?
Do we link every element in the subclass?
Precisely! For each subset in the partition, we form pairs by considering all elements in that subset.
Can you give an example of that?
Certainly! Let's say we have a partition of {1, 2, 3, 4} into {{1, 2}, {3, 4}}. For the equivalence relation, we would form pairs like (1, 1), (1, 2), (2, 1), (2, 2) for the first subset, and similar pairs for the second subset.
And each of those subsets will form their own equivalence class?
Exactly! Hence the equivalence classes correspond directly to the subsets of the partition.
Let's summarize: the process of constructing an equivalence relation creates classes that mirror the subsets in the partition.
Now that we have constructed our equivalence relation, we need to prove that it is reflexive, symmetric, and transitive.
For reflexivity, each element should relate to itself.
Exactly! Each element in a subset generates a pair to itself, demonstrating reflexivity. What about symmetry?
If (a, b) is in the relation, then (b, a) must also be in it!
Correct! We add pairs (x, y) from any subset, ensuring symmetry naturally follows. Now, who can tell me about transitivity?
If we have (a, b) and (b, c), then (a, c) should also be part of the relation!
Well done! By ensuring all elements are in the same subset, transitivity holds. So, we established that this constructed relation is indeed an equivalence relation.
To recap: all three properties—reflexivity, symmetry, and transitivity—are satisfied in our relation defined from the partition.
Read a summary of the section's main ideas. Choose from Basic, Medium, or Detailed.
The section covers key proofs related to equivalence relations, demonstrating how equivalence classes constitute partitions of sets, and vice versa, highlighting the non-empty, union, and disjoint characteristics of these classes.
In this section, we explore the relationship between equivalence relations and partitions of a set. An equivalence relation over a set C forms equivalence classes, which are subsets of C that fulfill three properties essential for a partition: non-empty subsets, the union of subsets equals C, and pairwise disjointness among subsets. More formally, for a given equivalence relation R, the corresponding equivalence classes are guaranteed to satisfy these conditions, asserting that they indeed form a partition. Conversely, any partition of a set can be used to construct an equivalence relation whose equivalence classes are simply the subsets in the partition. The significant conclusion drawn here is that the number of distinct equivalence relations on a set equals the number of its possible partitions.
Dive deep into the subject with an immersive audiobook experience.
Signup and Enroll to the course for listening the Audio Book
What we now want to establish here is a very interesting relationship between the equivalence from an equivalence relation to the partition of a set. So, we want to establish relationship between equivalence relation and partition of a set. So, imagine you are given a set C consisting of elements. Now what I can prove here is that if R is an equivalence relation over the set C and if the equivalence classes which I can form with respect to the relation R are constituted, then my claim here is that the equivalence classes constitutes a partition of the set C.
This chunk introduces the fundamental goal of the section: to prove that equivalence classes formed by an equivalence relation on a set result in a partition of that set. An equivalence relation groups elements based on a defined relation (like equality) and these groups (or classes) do not overlap and cover the entire set, satisfying partition requirements.
Think of a classroom where students are grouped by their favorite subjects. If you were to partition the students based on these subjects, each student belongs to one unique group, corresponding to their favorite subject, and together these groups make up the entire class. This mirrors how equivalence classes operate within a set.
Signup and Enroll to the course for listening the Audio Book
So, just to recall, the definition of partition demands me to prove three properties, the first property is that each of this subset should be non-empty. And that is trivial because I know that each of these equivalence classes is non-empty because each of these equivalence classes is bound to have at least one element. The second requirement from the partition is that the union of the various subsets should give me back the original set. So, my claim here is that if I take the union of all these equivalence classes, I will definitely get back my original set C. Third requirement from the partition was that the various subsets in the partition should be pairwise disjoint.
In this chunk, three key properties necessary for a set to be a partition are identified. First, every subset (equivalence class) must contain at least one element, which is guaranteed by the nature of equivalence relations. Second, all these subsets when combined (union) must cover the entire original set. Finally, the subsets must not overlap (be pairwise disjoint), which is a crucial aspect that ensures clarity in classification.
Consider a library that organizes books into genres. Each genre (like fiction, non-fiction) must have at least one book (non-empty), all the books in the library should fall under some genre (covering the whole set), and no book should belong to more than one genre (no overlap), mirroring the requirements of a functional partition.
Signup and Enroll to the course for listening the Audio Book
So, in this specific case, I have to show that you take any two equivalence classes, they should be pairwise disjoint and that is easy because in the last lecture we proved that two equivalence classes are either same or they are disjoint. You cannot have a common element present in two different equivalence classes which automatically establishes that these subsets are pairwise disjoint.
This part asserts that any two equivalence classes cannot share elements, which means they must be disjoint. This property is fundamental in showing that when constructing a partition from equivalence classes, there will not be any overlap or ambiguity about which class an element belongs to.
Imagine sorting fruits into baskets by type (apples, oranges). An apple cannot be found in the orange basket and vice versa. Each fruit belongs to one type only, similar to how each element of a set belongs to a single equivalence class.
Signup and Enroll to the course for listening the Audio Book
Now, I can prove the property in the reverse direction as well. What do I mean by that? I claim here that you give me any partition of a set C, say you give me a collection of subsets which constitute a partition of the set C. Then I can give you an equivalence relation R whose equivalence classes will be the subsets which you have given me in the partition.
Here, the text begins to discuss the duality between partitions and equivalence relations. It states that not only do equivalence relations lead to partitions, but you can also start with a partition and create an equivalence relation from it, demonstrating the interconnectedness of these concepts.
Think of a school’s system where each student is categorized by interest groups (sports, arts). This organization serves as a partition. Now, if we define a relation where students in the same interest group are considered 'related', we’ve essentially formulated an equivalence relation based on the original partition.
Signup and Enroll to the course for listening the Audio Book
Let us prove that a relation R that I am saying here will be reflexive, symmetric, and transitive. For proving that my relation R is reflexive, Symmetric and Transitive, I take any element i from the set C, and I must show that (i, i) is in R for reflexive property. Likewise, for symmetry, if (i, j) is in R, then (j, i) should also be in R, and for transitive property, if (i, j) and (j, k) are in R, then (i, k) should be in R.
This chunk focuses on proving whether the constructed relation R maintains the properties of an equivalence relation. These properties are essential for any relation to qualify as an equivalence relation, ensuring that elements are related appropriately based on the established criteria.
Consider a friendship relation in a network where if Alice is friends with Bob (reflexive), then it must also hold that Bob is friends with Alice (symmetric). If Alice is friends with Bob and Bob with Charlie, then Alice must also be friends with Charlie (transitive). This translates well to how we define relationships in mathematical equivalence.
Learn essential terms and foundational ideas that form the basis of the topic.
Key Concepts
Equivalence Relation: A relationship on a set that satisfies reflexivity, symmetry, and transitivity.
Partition: A division of a set into non-empty, disjoint subsets whose union equals the original set.
Equivalence Class: A subset of elements, all of which are equivalent to each other under a defined equivalence relation.
See how the concepts apply in real-world scenarios to understand their practical implications.
For a set C = {1, 2, 3, 4}, a partition can be {{1, 2}, {3, 4}}.
An equivalence relation on integers could relate integers with the same remainder when divided by 3.
Use mnemonics, acronyms, or visual cues to help remember key information more easily.
To partition well, disjoint we tell; with subsets not empty, we do it quite healthy.
Imagine a library where every book is either a novel, history, or science. Each section represents a partition, with no book placed outside its genre.
Remember P.E.P. for partitions: P=Pairwise disjoint, E=Equivalence class, P=Proper union.
Review key concepts with flashcards.
Review the Definitions for terms.
Term: Equivalence Relation
Definition:
A relation that is reflexive, symmetric, and transitive on a set.
Term: Partition
Definition:
A division of a set into non-empty, pairwise disjoint subsets.
Term: Equivalence Class
Definition:
A subset formed by elements related to one another under an equivalence relation.
Term: Pairwise Disjoint
Definition:
Subsets that do not share any elements.