Finding Number of Diagonals - 23.3.1 | 23. Full Binary Tree Definition | Discrete Mathematics - Vol 2
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Introduction to Diagonals

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Teacher
Teacher

Today, we will learn about diagonals in a convex polygon. Who can tell me what a diagonal is?

Student 1
Student 1

A diagonal is a line segment connecting two non-adjacent vertices.

Teacher
Teacher

Exactly! Now, if I have a polygon with n sides, can anyone guess how many vertices it has?

Student 2
Student 2

It has n vertices, right?

Teacher
Teacher

Correct! Let's think about how many diagonals we can create from one vertex. If we take a vertex, how many neighbors does it have?

Student 3
Student 3

It has two immediate neighbors.

Teacher
Teacher

Great observation! So, if we can't connect to ourselves or our neighbors, how many other vertices can we connect to?

Student 4
Student 4

It will be n - 3 because we subtract the vertex itself and the two neighbors.

Teacher
Teacher

Exactly! Remember this key concept: each vertex connects to only n - 3 valid diagonals. Let's summarize what we learned so far. Diagonals are formed by connecting vertices that aren't adjacent, and from each vertex, we have n - 3 connections.

Total Number of Diagonals

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Teacher
Teacher

Now, how do we find the total number of diagonals in the polygon with n vertices?

Student 1
Student 1

We can multiply the number of diagonals from one vertex by the total number of vertices!

Teacher
Teacher

Excellent point! But remember, when we multiply n by (n - 3), we are double counting because each diagonal connects two vertices. What do we do to correct this?

Student 2
Student 2

We divide the total by 2!

Teacher
Teacher

Exactly! So the formula becomes: $$\frac{n(n-3)}{2}$$. Who can tell me why it's only valid for n >= 3?

Student 3
Student 3

Because with fewer than 3 sides, you can't have diagonals at all!

Teacher
Teacher

That's right! Always keep in mind the context of your formulas. Now, let's summarize: To find the total number of diagonals in a polygon, use $$\frac{n(n-3)}{2}$$, valid for n >= 3.

Application of Diagonal Formula

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Teacher
Teacher

Let’s apply our diagonal formula to a pentagon. How many sides does it have, and what is n?

Student 4
Student 4

A pentagon has 5 sides, so n equals 5.

Teacher
Teacher

Fantastic! Now plug it into our formula.

Student 1
Student 1

So it’s $$\frac{5(5-3)}{2} = \frac{5 \cdot 2}{2} = 5$$. There are 5 diagonals in a pentagon.

Teacher
Teacher

Perfect! Now, let’s try a hexagon. How many sides does a hexagon have?

Student 2
Student 2

It has 6 sides.

Teacher
Teacher

Right! Now, calculate the number of diagonals.

Student 3
Student 3

I can calculate that: $$\frac{6(6-3)}{2} = \frac{6 \cdot 3}{2} = 9$$. So, a hexagon has 9 diagonals!

Teacher
Teacher

Excellent work! To recap: We calculated the number of diagonals using our formula and verified it with pentagon and hexagon examples.

Introduction & Overview

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Quick Overview

This section discusses how to determine the number of diagonals in a convex polygon based on its number of sides using combinatorial methods.

Standard

The section explains that in a convex polygon with n sides, the number of diagonals can be calculated by examining the endpoints that do not form edges. It derives the formula for the total number of diagonals through a basic counting argument and by eliminating invalid connections.

Detailed

Finding Number of Diagonals

In a convex polygon with n sides, the number of diagonals can be found using a counting technique. The central idea revolves around each vertex of the polygon, noting that no diagonal can connect to immediate neighbors or itself. Thus, for each vertex, the potential endpoints for a diagonal are restricted to avoid edges of the polygon itself.

When focusing on a particular vertex, three vertices are disqualified as potential endpoints:
- The vertex itself.
- The vertex on its left (the previous vertex).
- The vertex on its right (the next vertex).

As a result, each vertex can form diagonals with the other n - 3 vertices. Since the polygon has n vertices, the calculation yields a total of:

$$\text{Total Diagonals} = \frac{n(n-3)}{2}$$

The division by 2 accounts for the fact that each diagonal has been counted twice (once from each end). This formula is only applicable for polygons with n >= 3, as triangles and simpler shapes do not have any diagonals.

Audio Book

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Introduction to Diagonals in a Polygon

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The third question is how many diagonals are there in a convex polygon with n sides? So, again we can derive the formula using induction or some other mechanism but we will count it directly.

Detailed Explanation

This chunk introduces the problem of finding the number of diagonals in a convex polygon with 'n' sides. A diagonal connects two non-adjacent vertices, and since the polygon is convex, we can count the diagonals directly by considering the properties of the vertices.

Examples & Analogies

Think of a convex polygon as a flat piece of string bent into a shape, like a triangle or a pentagon. The vertices are points along this string. Counting the diagonals is like counting the rope sections that stretch across the inside of the shape without touching the edges.

Counting with Fixed Vertex

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Imagine you are given a convex polygon consisting of n sides and where the vertices are v1 to vn, now let us focus on some arbitrary vertex vi and try to count the number of diagonals that we can have where vi is one of the end points.

Detailed Explanation

We start by selecting an arbitrary vertex, say 'vi'. To form a diagonal with 'vi', we cannot connect it to its immediate neighbors 'vi-1' and 'vi+1', nor can we connect it to itself. Hence, the valid choices for the other end of the diagonal exclude these three vertices. This results in (n - 3) possible diagonals for each vertex.

Examples & Analogies

Imagine standing at one corner of a square room (your vertex). You can't shake hands (make a diagonal) with the people next to you (immediate neighbors), nor can you shake hands with yourself. The number of people left to shake hands with is like the remaining vertices you can connect with.

Total Diagonal Calculation

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So, now it turns out that the total number of diagonals will be n(n-3)/2. Why over 2? Because what we did here is with vi being one of the end points I have n - 3 diagonals.

Detailed Explanation

The final formula n(n-3)/2 calculates the total number of diagonals. We've counted diagonals for each vertex vi, resulting in n(n-3) counts. However, this counts each diagonal twice (once for each endpoint). To get the actual number, we divide by 2.

Examples & Analogies

Consider each handshake you count when you say hello to people in a party. You count every handshake when you say hi to your friend, and your friend counts the same when they greet you. To know how many unique handshakes happened, you divide by 2!

Conclusion on the Diagonal Count

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But now my k can range from 1 to n; my k could be vertex number v1, my k could be vertex number v2 and so on. So, if I take the summation over k being equal to 1 to n then I get the total number of triangulations for n + 2 sided convex polygon.

Detailed Explanation

The total diagonal count formula gives us a comprehensive understanding. It highlights that diagonals connect every vertex except immediate neighbors, demonstrating how each has (n - 3) options. This provides a consistent method for counting across all vertices.

Examples & Analogies

Think of a group project where each student (vertex) must connect with every other student (make diagonals) but can’t link with their direct partners (neighbors). Summing up all potential connections gives insight into collaboration opportunities among the students.

Definitions & Key Concepts

Learn essential terms and foundational ideas that form the basis of the topic.

Key Concepts

  • Diagonals: Line segments connecting two non-adjacent vertices.

  • Convex Polygon: A polygon where all points on the line segments between any two points in the polygon lie inside or on the polygon.

  • Formula for Diagonals: The total diagonals in a convex polygon can be calculated using the formula $$\frac{n(n-3)}{2}$$.

Examples & Real-Life Applications

See how the concepts apply in real-world scenarios to understand their practical implications.

Examples

  • In a triangle, which has 3 sides, the number of diagonals is $$\frac{3(3-3)}{2} = 0$$.

  • In a quadrilateral, which has 4 sides, the number of diagonals is $$\frac{4(4-3)}{2} = 2$$.

  • In a pentagon, the number of diagonals is $$\frac{5(5-3)}{2} = 5$$.

Memory Aids

Use mnemonics, acronyms, or visual cues to help remember key information more easily.

🎵 Rhymes Time

  • To find the diagonals, don’t delay, n times n minus three, divided by two makes the way.

📖 Fascinating Stories

  • Once a polygon had n sides and wanted to find its diagonals. After asking each vertex, it learned to subtract three for its friends and divide the journey by two!

🧠 Other Memory Gems

  • For Diagonals: 'n n-3 half'. Think of 'N-n' for Not adjacent neighbors.

🎯 Super Acronyms

D = n(n-3)/2; where D is Diagonal count, n is sides connected out of which no more than 3 interfere.

Flash Cards

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Glossary of Terms

Review the Definitions for terms.

  • Term: Diagonal

    Definition:

    A line segment that connects two non-adjacent vertices in a polygon.

  • Term: Convex Polygon

    Definition:

    A polygon where all interior angles are less than 180 degrees and vertices point outward.

  • Term: Endpoint

    Definition:

    One of the terminal points that define a line segment such as a diagonal.