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Today we'll explore a vital property of divisibility. Consider three positive integers: a, b, and c. If a divides the product of b and c and a is coprime to b, what can we conclude about a and c?
Is it that a divides c?
Exactly! This implies a must divide c. Remember, this is a crucial concept that we'll use later. Let's denote this property as DAB – 'Divides A implies B'.
Could you provide an example?
Sure! If a is 3, b is 5, and c is 15, here, 3 divides 5 * 15. Thus, since 3 and 5 are coprime, it confirms that 3 divides 15.
Got it! So, DAB is important for our discussions on congruences?
Correct! Now let’s look at Euclid’s Lemma for further depth on this topic.
Euclid's Lemma tells us that if p is a prime and p divides the product of n numbers, then it must divide at least one of those numbers. Why do you think this statement is important?
Because it helps us understand which numbers a prime can divide in a product?
Absolutely! It's essential for comprehending prime factorization. Let's take it further by proving this lemma via induction. First, let’s verify for a single number, which is straightforward.
So, for n=1, if p divides a1, then that’s trivial?
Exactly! Now assume it's true for k numbers, and how would you prove it for k+1?
Maybe we look at p’s GCD with the k numbers? If it’s 1, it must divide the next?
Perfect reasoning! That’s how we derive our conclusion for k+1 numbers. Induction is a powerful tool!
Now that we've covered divisibility, let’s move on to the uniqueness proof in the context of CRT. We know there’s at least one solution in the range from 0 to M-1. How do we prove it’s unique?
Do we need to refute a second solution?
Exactly! Assume we have two solutions, x and y, both satisfying the same system. How do we derive their relationship?
We can calculate x - y and show it’s divisible by each of the moduli?
Right! And if both solutions are in the range from 0 to M-1, what conclusion do we draw?
That x must equal y, proving uniqueness!
Exactly! We have now established that CRT provides a unique solution for a system of linear congruences.
Before finalizing our uniqueness proof, let’s discuss the Helping Lemma. If two numbers a and b are congruent under n moduli, what can we infer about them?
They should be congruent under the combined modulus M.
Correct! That's pivotal. It allows us to infer that their difference must be divisible by M. Why is this useful?
Because if they are different, they cannot be congruent under M as well?
Precisely! This lemma is essential for establishing the uniqueness of solutions in CRT.
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In this section, we discuss the uniqueness of solutions to linear congruences in the context of the Chinese Remainder Theorem (CRT). We start with foundational properties of divisibility, delve into Euclid’s Lemma, and conclude with proving that there is a unique solution modulo M for a system of linear congruences involving pairwise relative prime moduli.
This section elaborates on the uniqueness of solutions derived from the Chinese Remainder Theorem (CRT) by proving that if two values satisfy a system of linear congruences, they must be equal in the context of modular arithmetic.
The section begins by introducing key properties:
1. A basic property of divisibility states that if a divides the product of two numbers while also being coprime to one of them, it divides the other. This is foundational for understanding congruences in modular arithmetic.
2. Euclid's Lemma, which asserts that a prime dividing a product of integers must divide at least one of the factors, is also crucial. The proof is offered through mathematical induction, emphasizing its significance in proving the uniqueness part of CRT.
Building on these principles, the section transitions into proving the main theorem. It establishes a lemma stating that if two numbers are congruent under multiple moduli that are pairwise coprime, they are congruent under the product of these moduli, M. The uniqueness proof leverages this lemma to show that if two solutions exist for the system of congruences within a specified range, they must be identical.
In summary, the section provides a thorough examination of the uniqueness aspect of the Chinese Remainder Theorem, enriching the reader's foundational understanding of modular arithmetic and its applications.
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Now, coming back to the uniqueness proof part for the Chinese remainder theorem in the last lecture, we showed that there exists at least one solution in the range 0 to M – 1. How do I prove that there is no other solution possible satisfying the same system of linear congruences and which is also in the range 0 to M - 1, we have to refute the existence of a second solution.
In this part of the proof, the lecturer emphasizes that we've already established the existence of at least one solution within the range from 0 to M – 1. The next step is to demonstrate that there cannot be another distinct solution in this range. If there were another solution, it would contradict the earlier finding. Essentially, the proof will eliminate the possibility of a second solution existing by refuting its existence.
Imagine trying to find your assigned seat in a classroom where no two students can sit in the same place. You have one spot, and if someone else claims to have a different seat, it creates confusion. The goal is to prove no other person could 'claim' that second seat by showing there’s only one valid position for each student.
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So, again we will take the help of a helping lemma and this helping lemma will be useful later as well. So, what this helping lemma says is the following: imagine you are given n modulus which are pairwise relatively prime that means, you take any pair of modulus m and they are co-prime to each other. And suppose you know that you are given 2 numbers a and b which are congruent with respect to all the n individual modulus...
The helping lemma states that if we have multiple moduli that are pairwise co-prime, and two numbers a and b are congruent to each other under all these moduli, then a and b must also be congruent with respect to the product of these moduli, denoted as M. This lemma serves as a foundational principle essential for ensuring unique solutions in modular arithmetic.
Consider that each modulus represents a different time zone, and a and b are two appointments in those time zones. If both appointments occur at the same local time across every time zone, they effectively reflect the same rendezvous time, even when seen from the perspective of the larger global time.
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Now, let us consider an arbitrary prime factor of the bigger modulo M and suppose it is appearing with power e in the prime power factorization that means so, M = 2e1, 3e2 and so on and some pe so on. So, I am taking an arbitrary prime which is appearing with some power in the prime power factorization of M...
Here, the proof examines how if a prime factor appears in the prime factorization of M, it must also appear in the prime factorization of the differences a-b. The proof follows through logical deductions using earlier established principles like Euclid’s lemma, asserting that if such a factor divides M, it must divide at least one of the smaller moduli. This connection ultimately confirms that the difference a - b must be divisible by M.
This can be likened to ensuring that each house (representing prime factors) on a block (representing M) has direct access to the main road. If all homes are linked well enough to the main street, it becomes evident that each house must share some common service line with the route connected to M. Just as vehicles (the factors) must also align with the road (M) to traverse to other areas, thus ensuring they connect back through one main route.
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So, we will prove it as follows. On contrary imagine you have 2 solutions, 2 solutions in the range 0 to M - 1 satisfying this system of linear congruences and those solutions be let x and y. That means x satisfies this system of n linear congruences that when x is congruent to a modulo m...
In this step, we assume for contradiction that there are two different solutions, x and y. By showing that both these solutions lead to the same results across all linear congruences, we then derive that x must be equal to y. This contradiction indicates that our original assumptions (that there were two distinct solutions) must be false, leading us to conclude that there is a unique solution.
Picture a race where two runners mistakenly claim to finish at different times, yet their times recorded at each checkpoint (moduli) are identical. When reviewed, you realize both must have crossed the finish line at the same moment, proving only one valid finishing time exists, hence reaffirming that they cannot be two separate winners.
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And since both x and y were in the range 0 to M - 1, that means they were strictly less than M, and both of them are congruent, then that is possible only when x = y that shows that there exists a unique solution modulo M satisfying your system of linear congruences.
In concluding the uniqueness proof, it is established that since both solutions x and y are confined within the bounds of 0 to M - 1 and are congruent, they must necessarily be equal. This final step reinforces that the earlier proofs and assumptions hold true, solidifying the assertion of a singular unique solution under the system of linear congruences.
Think of tracking attendance in a classroom—if two students claim they attended the same class and are accounted as present at every roll call, if they remain in the same class and timeframe, they are, without a doubt, the same individual rendering only one valid attendee for each session.
Learn essential terms and foundational ideas that form the basis of the topic.
Key Concepts
Uniqueness of Solutions: The proof establishes that for a given system of linear congruences, the solution is unique modulo the product of the moduli.
Divisibility Property: If a divides bc and a is coprime to b, then a must divide c.
Euclid’s Lemma: A prime number dividing a product of integers must divide at least one of those integers.
Pairwise Relatively Prime: A set of moduli that do not share any common factors.
Helping Lemma: If two numbers are congruent modulo several pairwise coprime integers, they are congruent under their product.
See how the concepts apply in real-world scenarios to understand their practical implications.
If we have two congruences: x ≡ 2 mod 3 and x ≡ 5 mod 7, we can determine a unique solution in range 0 to 20 using CRT.
Finding the unique solution for the system: x ≡ 1 mod 4, x ≡ 2 mod 5, x ≡ 3 mod 7 results in x = 11.
Use mnemonics, acronyms, or visual cues to help remember key information more easily.
If divides the pack but stays apart, it gets through the other, that’s where it starts.
Imagine two friends walking along a line. If they both walk parallel and skip every 3rd step and every 5th step, they will eventually step on the same spot at the 15th step, illustrating how they must meet.
DAB: Divides A implies B. Use this to remember the property of divisibility.
Review key concepts with flashcards.
Review the Definitions for terms.
Term: Congruence
Definition:
A relation indicating that two numbers leave the same remainder when divided by a modulus.
Term: Pairwise Relatively Prime
Definition:
A set of numbers where each pair of numbers has no common divisor other than 1.
Term: Divisibility
Definition:
A condition where one integer can be divided by another without leaving a remainder.
Term: Euclid's Lemma
Definition:
If p is a prime number that divides the product of some integers, it must divide at least one of those integers.
Term: Chinese Remainder Theorem (CRT)
Definition:
A theorem stating that under certain conditions, simultaneous linear congruences have a unique solution modulo the product of the moduli.