Problems and Solutions - 2 | 20. Non-Uniform Flow and Hydraulic Jump (Contd.) | Hydraulic Engineering - Vol 2
K12 Students

Academics

AI-Powered learning for Grades 8–12, aligned with major Indian and international curricula.

Professionals

Professional Courses

Industry-relevant training in Business, Technology, and Design to help professionals and graduates upskill for real-world careers.

Games

Interactive Games

Fun, engaging games to boost memory, math fluency, typing speed, and English skills—perfect for learners of all ages.

Interactive Audio Lesson

Listen to a student-teacher conversation explaining the topic in a relatable way.

Finding the Rate of Change of Water Depth

Unlock Audio Lesson

0:00
Teacher
Teacher

Welcome back, students! Today, we are going to calculate the rate of change of water depth in a rectangular channel. Can anyone tell me what parameters we need to solve this problem?

Student 1
Student 1

We need the width, depth, velocity, and slopes!

Teacher
Teacher

Correct! We have a channel that is 10 meters wide and 1.5 meters deep, with a flow velocity of 1 meter per second. Let's calculate the area of flow. Can someone remind me the formula for the area in a rectangular channel?

Student 2
Student 2

It’s width times depth, so for our numbers, it’s 10 times 1.5.

Teacher
Teacher

Exactly! That gives us 15 square meters. Next, we need to find the discharge, which is area times velocity. What do we get?

Student 3
Student 3

That would be 15 cubic meters per second.

Teacher
Teacher

Right! Now, we apply the equation for gradually varied flow. Does anyone remember the formula for the rate of change of depth?

Student 4
Student 4

Yes! It’s dy/dx = (S0 - Sf) / (1 - Q² * T / (g * A³)).

Teacher
Teacher

Well done! Let's plug in our numbers and calculate dy/dx together.

Understanding Gradually Varied Flow

Unlock Audio Lesson

0:00
Teacher
Teacher

Now that we have computed dy/dx, let’s look at another problem involving a rectangular channel with different parameters. What details do we need to assess the type of gradually varied profile?

Student 1
Student 1

We need the channel width, bed slope, discharge, and the depth at a point!

Teacher
Teacher

Correct! We have a bottom width of 4 meters, a slope of 0.0008, a discharge of 1.5 cubic meters per second, and a depth of 0.3 meters. How do we begin?

Student 2
Student 2

First, we calculate the specific discharge per meter by dividing the discharge by the width.

Teacher
Teacher

Exactly! That leads us to calculate the critical depth as well. Who remembers the formula for critical depth related to specific discharge?

Student 3
Student 3

It’s qc = q² / g^(1/3).

Teacher
Teacher

Good! Let’s compute this together to determine the type of profile.

Application of Manning’s Equation

Unlock Audio Lesson

0:00
Teacher
Teacher

Now, let’s use Manning’s equation to find normal depth with the parameters we have. Can anyone recall the basic form of Manning's equation?

Student 4
Student 4

It’s Q = (1/n) A R^(2/3) S^(1/2).

Teacher
Teacher

Absolutely! Let’s determine the hydraulic radius and solve for normal depth based on our channel dimensions.

Student 1
Student 1

For a rectangular channel, the area is by, and the hydraulic radius R is A/P.

Teacher
Teacher

Great connection! Now, using our calculated values, what can we infer about the type of slope?

Student 2
Student 2

Since our normal depth is greater than critical depth, it indicates a mild slope!

Teacher
Teacher

Correct! It’s essential in hydrodynamics to understand these distinctions as they affect flow behavior.

Introduction & Overview

Read a summary of the section's main ideas. Choose from Basic, Medium, or Detailed.

Quick Overview

This section addresses important problem-solving techniques in hydraulic engineering with a focus on various flow scenarios.

Standard

The section delves into practical problems related to hydraulic engineering, specifically around the rates of change of water depth in different channel scenarios. Key flow parameters are analyzed, including discharge and slope, leading to insights on gradually varied flow and hydraulic jumps.

Detailed

In this section, we solve various problems related to hydraulic flow in channels. The first problem involves finding the rate of change of water depth in a rectangular channel. Given parameters like channel width, depth, velocity, and slopes, we calculate the discharge and apply equations for gradually varied flow. The second problem explores a scenario where the depth is known, and we determine the type of gradually varied profile using Manning's equation and critical depth calculations. Important concepts include the significance of channel slope types (e.g., mild, steep) and how they relate to flow behavior.

Audio Book

Dive deep into the subject with an immersive audiobook experience.

Problem 1: Rate of Change of Water Depth

Unlock Audio Book

Signup and Enroll to the course for listening the Audio Book

The question is; find the rate of change of depth of water in a rectangular channel, which is 10 meter wide and 1.5 meter deep, when the water is flowing with a velocity of 1 meters per second.

Detailed Explanation

In this problem, we are given a rectangular channel with specific dimensions: a width of 10 meters and a depth of 1.5 meters. The water flows through the channel at a velocity of 1 meter/second. We are tasked with calculating the rate of change of water depth, denoted as dy/dx, which indicates how much the water depth changes as we move along the channel. To begin, we need to gather all the relevant information and apply it systematically using known hydraulic equations.

Examples & Analogies

Imagine a water slide at a park where the angle of the slide changes. When you slide down, the depth of water underneath you varies based on how steep the slide is. The calculation we are doing helps us understand how quickly the depth changes as you move along the water slide.

Solution Steps for Problem 1

Unlock Audio Book

Signup and Enroll to the course for listening the Audio Book

Given: b = 10 meters, depth = 1.5 meters, velocity = 1 m/s, bed slope = 1 in 4000, slope of energy line = 0.00004. First, calculate area (A = b × depth = 10 × 1.5 = 15 m²) and discharge (Q = A × velocity = 15 m² × 1 m/s = 15 m³/s). The equation relating dy/dx is dy/dx = (S0 - Sf) / (1 - (Q² × T) / (g × A³)). Substituting known values gives dy/dx = 2.25 × 10⁻⁴.

Detailed Explanation

First, we identify our known quantities. We calculate the area of flow (A) by multiplying the width (b) by the depth of the channel. This gives us a flow area of 15 m². Next, we calculate the discharge (Q) by multiplying the flow area (A) by the flow velocity (1 m/s), resulting in a discharge of 15 m³/s. We then substitute these values into the derived formula for dy/dx, which relates the rate of change of depth with the slope of the channel and energy line. Upon simplifying, we find dy/dx to be approximately 2.25 × 10⁻⁴, indicating a gradual change in depth along the channel.

Examples & Analogies

Using the analogy of a garden hose with a nozzle, if you squeeze the hose, the water comes out faster and at a different height to water the plants. Similarly, our calculation shows how the change in slope and flow velocity affects how 'deep' the water feels at different points in the channel.

Problem 2: Gradually Varied Flow Profile

Unlock Audio Book

Signup and Enroll to the course for listening the Audio Book

A rectangular channel with a bottom width of 4 meters and a bottom slope of 0.0008 has a discharge of 1.5 m³/s. In a gradually varied flow in this channel, the depth at a certain location is found to be 0.30 meters. Assuming the Manning's n = 0.016, determine the type of gradually varied profile.

Detailed Explanation

In this problem, we need to analyze another rectangular channel with specific characteristics. We begin by noting the bottom width (b), slope (S0), discharge (Q), and the depth at a location (y). We then calculate the critical depth (yc) using the formula, yc = (q²/g)^(1/3), where q is the discharge per width. Using the values, we find yc to be 0.243 meters. We then apply Manning's equation to find the normal depth (y0). For normal depth, we use the Manning’s equation, and further analysis reveals that y0 is greater than yc, indicating a mild slope channel.

Examples & Analogies

Think of a winding river where the slope of the river bank changes. When there’s a decrease in slope, the river might spread out and deepen, while a steeper slope allows the river to flow quickly and remain shallow. This problem analyzes those variations in depth along the channel.

Solution Steps for Problem 2

Unlock Audio Book

Signup and Enroll to the course for listening the Audio Book

Given: b = 4 meters, y = 0.3 meters, Q = 1.5 m³/s, S0 = 0.0008, Manning's n = 0.016. Calculating small q gives 0.0375 m³/s/m. Critical depth yc is calculated as 0.243 m. Solving with Manning's equation yields y0 = 0.426 m. Since y0 > yc, we identify the profile as an M2 curve.

Detailed Explanation

We organize the information provided and compute the discharge intensity (small q), which simplifies our calculations. We then calculate the critical depth (yc) and analyze the geometry of the flow using Manning's equation, which helps us determine the normal depth (y0). By comparing the values of y and y0, we see that y0 is greater than yc, classifying it as an M2 curve, indicating a mild slope channel with certain characteristics.

Examples & Analogies

Consider a ski slope. At the top, it might be steep and quick, representing a shallow 'y' effect. But as you go down, if the slope flattens and widens, you experience a longer glide, similar to how the water behaves in our channel. Here, our analysis helps us predict that gentle transition.

Definitions & Key Concepts

Learn essential terms and foundational ideas that form the basis of the topic.

Key Concepts

  • Rate of change of depth: Key to analyzing flow in channels using hydrodynamic equations.

  • Discharge: Vital for understanding flow behavior and calculating hydraulic structures.

  • Channel slope influence: Determining mild, steep or adverse slopes affects the flow profile.

  • Manning's Equation application: A fundamental relationship for assessing flow characteristics in open channels.

Examples & Real-Life Applications

See how the concepts apply in real-world scenarios to understand their practical implications.

Examples

  • For a channel 10 meters wide, if the water depth increases from 1.2m to 1.5m, you would compute the rate of change of depth using appropriate discharge formulas.

  • In a scenario where a channel has a greater normal depth than critical depth, the flow profile indicates a mild slope.

Memory Aids

Use mnemonics, acronyms, or visual cues to help remember key information more easily.

🎵 Rhymes Time

  • In channels that flow with a gentle slope, depth's slow change is the key to hope.

📖 Fascinating Stories

  • Imagine a river flowing smoothly. As it meets hills, it has to adapt, slowly rising or falling, much like how we adjust when faced with curves in life.

🧠 Other Memory Gems

  • Use the acronym SF (Slope Forward), to remember that a higher S0 blazes a trail for steep flow while a lower S creates gentle waves.

🎯 Super Acronyms

DRY

  • Depth Rate Yield = dy/dx.

Flash Cards

Review key concepts with flashcards.

Glossary of Terms

Review the Definitions for terms.

  • Term: Gradually Varied Flow

    Definition:

    Flow in a channel where the water surface slope changes gradually.

  • Term: Critical Depth

    Definition:

    The depth at which the flow transitions between subcritical and supercritical conditions.

  • Term: Manning's Equation

    Definition:

    An empirical equation used to estimate the flow rate in an open channel based on channel shape and roughness.

  • Term: Hydraulic Radius

    Definition:

    The ratio of the area of flow to the wetted perimeter, important for characterizing flow in channels.