Practice Exercises - 5 | 3. Simultaneous Equations | IB Class 10 Mathematics – Group 5, Algebra
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Using Substitution to Solve Simultaneous Equations

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0:00
Teacher
Teacher

Today, we'll focus on how to use the substitution method to solve simultaneous equations. Can someone remind me what substitution means?

Student 1
Student 1

Isn't it when we replace one variable with another?

Teacher
Teacher

Exactly! We rearrange one equation to express one variable in terms of the other. Let's dive into this with a problem: Solve for x and y in these equations: x + y = 7, and 2x - y = 4.

Student 2
Student 2

I think we can rearrange the first equation to y = 7 - x!

Teacher
Teacher

Great job! Who can substitute this expression into the second equation?

Student 3
Student 3

I can do that! If we substitute y in the second equation, it becomes 2x - (7 - x) = 4.

Teacher
Teacher

Perfect! Now, what do we get when we simplify this?

Student 4
Student 4

We get 3x - 7 = 4, which simplifies to 3x = 11, so x = 11/3.

Teacher
Teacher

Awesome! Now how do we find y?

Student 1
Student 1

We substitute x back into y = 7 - x.

Teacher
Teacher

Exactly! And what do we get for y?

Student 2
Student 2

Y = 7 - (11/3), which is 21/3 - 11/3 = 10/3.

Teacher
Teacher

Fantastic! So, our solution is (11/3, 10/3).

Teacher
Teacher

In summary, to solve using substitution, rearrange one equation, substitute, simplify, and solve for both variables.

Using Elimination to Solve Simultaneous Equations

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0:00
Teacher
Teacher

Now let's explore the elimination method. Who can explain what we do here?

Student 3
Student 3

We eliminate one variable by adding or subtracting the equations, right?

Teacher
Teacher

That's correct! Let’s solve this example: 3x + 2y = 16 and 2x - 2y = 4. What’s the first step?

Student 4
Student 4

We can add the two equations together!

Teacher
Teacher

Yes! What do we get?

Student 1
Student 1

6x = 20, so x = 20/6, which simplifies to x = 10/3.

Teacher
Teacher

Great! Now let's substitute x back to find y. Who can do that?

Student 2
Student 2

We use the first equation: 3(10/3) + 2y = 16, which gives us 10 + 2y = 16.

Teacher
Teacher

Awesome! Now, can you solve for y?

Student 3
Student 3

Yes! 2y = 6, so y = 3.

Teacher
Teacher

Fantastic! Thus, our solution is (10/3, 3). Remember, the elimination method works well when we can easily eliminate one variable.

Graphing Simultaneous Equations

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0:00
Teacher
Teacher

Next, let’s talk about graphing as a method to solve simultaneous equations. What do you think we do here?

Student 4
Student 4

We draw the lines for both equations and see where they intersect?

Teacher
Teacher

Exactly! Let's graph these equations: y = x + 1 and y = 2x - 2. Who can tell me the slopes?

Student 1
Student 1

The first line has a slope of 1 and the second line has a slope of 2.

Teacher
Teacher

Great! How do we plot these?

Student 2
Student 2

We start with y-intercepts; for the first line, it’s 1, and for the second, it’s -2. Then we follow the slope.

Teacher
Teacher

Excellent approach! As we graph, where do you see the lines intersecting?

Student 3
Student 3

They intersect at (1, 3).

Teacher
Teacher

Correct! The solution to the system of equations is at that intersection point.

Teacher
Teacher

In summary, graphing provides a visual representation of the solutions, and the point of intersection gives us our answer.

Real-Life Applications of Simultaneous Equations

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0:00
Teacher
Teacher

Finally, let’s discuss how simultaneous equations are used in real life. Can anyone give me an example?

Student 2
Student 2

How about calculating costs for items, like tickets to a concert?

Teacher
Teacher

Great example! Let’s consider a problem: A cinema charges $8 for a child and $12 for an adult. If 5 children and 3 adults together cost $84, and 2 children and 5 adults cost $86, let’s form our equations. Who can help?

Student 3
Student 3

We can let x be the child ticket price and y be the adult ticket. So we have: 5x + 3y = 84 and 2x + 5y = 86.

Teacher
Teacher

Exactly right! Now let’s solve this system of equations. What would our first step be?

Student 4
Student 4

We could use elimination since we can multiply and align the y terms.

Teacher
Teacher

Good thinking! After solving this, what would we find?

Student 1
Student 1

We find the price for each ticket! This shows how important simultaneous equations are for everyday life.

Teacher
Teacher

Exactly! So to summarize, simultaneous equations allow us to solve problems with multiple conditions in real-world applications.

Introduction & Overview

Read a summary of the section's main ideas. Choose from Basic, Medium, or Detailed.

Quick Overview

This section provides practical exercises to apply knowledge on solving simultaneous equations.

Standard

The exercises in this section guide students through solving simultaneous equations using substitution, elimination, and graphical methods, as well as real-world applications. Students will consolidate their understanding through structured problem sets.

Detailed

Practice Exercises

This section focuses on several exercises meant to reinforce your understanding of simultaneous equations. Each exercise is designed to cover different methods of solving these equations, including substitution, elimination, and graphical approaches. The exercises also involve real-life scenarios that relate to the application of simultaneous equations, enhancing your ability to convert practical problems into mathematical equations. Working through these practice problems will not only improve your skills but also prepare you for higher-level mathematics that builds on these foundational concepts.

Audio Book

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Exercise 1: Solve Using Substitution

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  1. Solve using substitution:

𝑥 +𝑦 = 7,
2𝑥 −𝑦 = 4

Detailed Explanation

In this exercise, we are given two equations. To use the substitution method, we typically start by solving one of the equations for one variable and substituting that into the other equation to solve for another variable. Here, we could rearrange the first equation (𝑥 + 𝑦 = 7) to express 𝑦 in terms of 𝑥: 𝑦 = 7 - 𝑥. We then substitute this expression for 𝑦 into the second equation (2𝑥 - 𝑦 = 4) and solve for 𝑥.

Examples & Analogies

Imagine you have a total of 7 apples and you're trying to figure out how many you have in two baskets. If you also know that twice the apples in basket one minus the apples in basket two equal 4, you can use this information to find out how many are in each basket.

Exercise 2: Solve Using Elimination

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  1. Solve using elimination:

3𝑥+2𝑦 = 16,
2𝑥−2𝑦 = 4

Detailed Explanation

In this exercise, we are using the elimination method to find values for 𝑥 and 𝑦. The first step is to align the equations for easy comparison. We can multiply the second equation by 1 to match the coefficient of 𝑦 in the first equation. Then, we can add or subtract the equations to eliminate one variable. For instance, adding them together allows us to eliminate 𝑦, making it easier to solve for 𝑥.

Examples & Analogies

Think about a store where one type of item costs more than another. You're trying to determine how many of each item you have based on their total cost. Using the elimination method is akin to combining costs strategically so you can figure out the quantities easily.

Exercise 3: Graph and Find Intersection

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  1. Graph the following equations and find the point of intersection:

𝑦 = 𝑥 +1,
𝑦 = 2𝑥−2

Detailed Explanation

This exercise requires plotting both equations on the same graph to find their intersection point, a visual representation of where the two equations meet. Start by identifying key points for each equation—select values for 𝑥, calculate 𝑦, and plot these points on a coordinate plane. Then, draw the lines for both equations and observe where they intersect, which gives the solution to the simultaneous equations.

Examples & Analogies

Imagine you are meeting a friend at a park. You both are following different paths but want to meet at the same spot. Graphing the equations is like mapping out each path. The point where you both arrive (the intersection) tells you where to meet.

Exercise 4: Word Problem on Prices

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  1. A shop sells pens for $2 and pencils for $1. If 4 pens and 3 pencils cost $11, and 2 pens and 5 pencils cost $9, find the cost of each.

Detailed Explanation

In this word problem, we are asked to set up two equations based on the information given about the prices of pens and pencils. Let 𝑥 be the cost of pens and 𝑦 be the cost of pencils. From the problem, we can create these equations: 4𝑥 + 3𝑦 = 11 and 2𝑥 + 5𝑦 = 9. We can then use either the substitution or elimination method to solve for 𝑥 and 𝑦, giving us the prices.

Examples & Analogies

Think of having a small budget for office supplies. You're trying to buy a mix of pens and pencils but need to stick to your spending limit. This problem is like a puzzle where the goal is to determine how much each item costs, helping you stay within budget.

Definitions & Key Concepts

Learn essential terms and foundational ideas that form the basis of the topic.

Key Concepts

  • Substitution Method: A technique for solving simultaneous equations by substituting one equation into another.

  • Elimination Method: A technique for solving simultaneous equations by eliminating one variable.

  • Graphical Method: A visual method for solving simultaneous equations by plotting graphs of the equations.

Examples & Real-Life Applications

See how the concepts apply in real-world scenarios to understand their practical implications.

Examples

  • Example 1: Solve the simultaneous equations x + y = 7 and 2x - y = 4 using substitution.

  • Example 2: Solve the simultaneous equations 3x + 2y = 16 and 2x - 2y = 4 using elimination.

Memory Aids

Use mnemonics, acronyms, or visual cues to help remember key information more easily.

🎵 Rhymes Time

  • When equations clash, don’t be rash, substitute or eliminate and make a splash!

📖 Fascinating Stories

  • Imagine two friends selling tickets; one sells adult tickets while the other sells child tickets. To find out how much they each charge when combined together, they must solve equations that represent their total sales.

🧠 Other Memory Gems

  • S.E.-S.E.- Always start with Simultaneous Equations - Solve with Elimination or Substitution!

🎯 Super Acronyms

S.S.E. - Solve with Substitution then Eliminate, the secret to solving simultaneous equations.

Flash Cards

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Glossary of Terms

Review the Definitions for terms.

  • Term: Simultaneous Equations

    Definition:

    A set of equations with two or more unknown variables that are solved together.

  • Term: Substitution Method

    Definition:

    A technique used to solve simultaneous equations by substituting one variable in terms of the other.

  • Term: Elimination Method

    Definition:

    A technique used to solve simultaneous equations by eliminating one variable to solve for the other.

  • Term: Graphical Method

    Definition:

    A method of solving equations by graphing them and identifying the intersection point.

  • Term: Coefficient

    Definition:

    A numerical or constant factor in front of a variable in an equation.