8 - Practice Problems
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Decoding Resistors
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Today, let's start with decoding a 4-band resistor. For instance, we have the colors yellow, violet, red, and gold. Who remembers what each color represents?
Is yellow 4 and violet 7?
Great! Yellow is indeed 4, and violet is 7, which gives us 47. The third color red is a multiplier of 100. So, 47 times 100 is what?
That would be 4700 ohms!
Correct! Now, what about the gold band at the end? It indicates the tolerance of the resistor, which is 5%. Can anyone explain what that means?
It means the actual resistance can vary by 5% from 4700 ohms?
Exactly! This is important in ensuring our circuits work correctly. Remember: 'Gold gives variance, keep circuits in balance!'
To summarize, a yellow-violet-red-gold resistor has a base resistance of 4700 ohms with a tolerance of +/- 5%.
Series Circuit Calculations
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Now letβs look at a series circuit with resistors R1 = 150 Ξ© and R2 = 300 Ξ© connected to an 18 V battery. How do we find the total resistance?
We just add them together since it's a series circuit, right? So 150 + 300 is 450 Ξ©.
Exactly! So we have 450 Ξ© total resistance. Now, how do we find the current I in the circuit?
We can use Ohm's Law, I = V/R. That would be 18 V divided by 450 Ξ©.
Which equals 0.04 A or 40 mA!
Perfect! Now, what about the voltage drop across each resistor?
For R1, V1 = 0.04 A times 150 Ξ© = 6 V and for R2, it would be 0.04 A times 300 Ξ©, which is 12 V.
Great job! So we have verified that 6 V plus 12 V equals the total potential of 18 V. 'Series means add and always check, volts and amps connect!'
Parallel Circuit Problems
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Now let's shift gears and discuss parallel circuits. If we have three resistors: 100 Ξ©, 200 Ξ©, and 300 Ξ© connected in parallel on a 12 V supply, can someone help me find the equivalent resistance?
For parallel resistors, we use the formula 1/R_eq = 1/R1 + 1/R2 + 1/R3?
Exactly! Applying that formula gives us what?
1/R_eq = 1/100 + 1/200 + 1/300. Calculating that gives us... let's see... 0.01 + 0.005 + 0.00333.
That totals up to approximately 0.0183, so R_eq is about 54.64 Ξ© when we take the reciprocal.
Fantastic! Now can we find the current through each branch?
Sure! The total current I_total would be V/R_eq, which is 12 V divided by 54.64 Ξ©.
I_total is about 0.219 A.
Exactly right! Keeps you thinking: 'Parallels are split, but together they shine, current flows freely through each vine!'
Quick recap: In parallel circuits, we focus on voltages staying equal while currents divide!
Introduction & Overview
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Quick Overview
Standard
The practice problems in this section provide students with an opportunity to apply their knowledge of resistors, series and parallel circuits, and Ohm's Law. Each problem challenges different aspects of the material covered throughout the chapter.
Detailed
The Practice Problems section offers a set of practice questions that cover key concepts from the chapter, including the decoding of resistor color codes, analysis of series and parallel circuit behavior, and calculations of current and voltage in various scenarios. These problems are essential for consolidating students' understanding of electrical concepts and encourage the application of theoretical knowledge in practical situations.
Audio Book
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Problem 1: Decoding a Resistor
Chapter 1 of 5
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Chapter Content
- Decode a 4-band resistor (yellow-violet-red-gold) and calculate its tolerance range.
Detailed Explanation
To decode a 4-band resistor, you need to understand what each color represents:
- The first two bands represent significant digits. For the resistor (yellow-violet-red-gold):
- Yellow (4) and Violet (7) give us 47.
- The third band (red) indicates the multiplier, which is 10^2 or 100. Therefore, 47 Γ 100 = 4700 ohms or 4.7 kΞ©.
- The fourth band (gold) indicates the tolerance, which is Β±5%.
- To calculate the tolerance range, take 5% of 4700 ohms, which is 235 ohms.
- Hence, the resistor's tolerance range is from 4700 - 235 = 4465 ohms to 4700 + 235 = 4935 ohms.
Examples & Analogies
Think of a resistor like a recipe. Each color band is like an ingredient that contributes to the final dish. The first two colors give you the base of the recipe (flavors), the third color tells you how much to multiply (servings), and the gold band tells you how flexible the recipe is (tolerance). This way, even if you don't get it exactly right, you'll still end up with a dish that's closely aligned with what you intended!
Problem 2: Series Circuit Calculations
Chapter 2 of 5
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Chapter Content
- In a series circuit containing R1=150 Ξ©, R2=300 Ξ© on 18 V, calculate I, V1, V2, power dissipated by each resistor.
Detailed Explanation
In a series circuit, the total resistance is the sum of individual resistances. So, R_total = R1 + R2 = 150 Ξ© + 300 Ξ© = 450 Ξ©.
- To find the current (I), use Ohm's Law: I = V/R. Therefore, I = 18 V / 450 Ξ© = 0.04 A (40 mA).
- Next, find the voltage drop across each resistor:
- For R1: V1 = I Γ R1 = 0.04 A Γ 150 Ξ© = 6 V.
- For R2: V2 = I Γ R2 = 0.04 A Γ 300 Ξ© = 12 V.
- Finally, to find the power dissipated by each resistor, use the formula P = I^2 Γ R:
- P1 = (0.04 A)^2 Γ 150 Ξ© = 0.24 W.
- P2 = (0.04 A)^2 Γ 300 Ξ© = 0.48 W.
Examples & Analogies
Imagine a water system where the water has to flow through two pipes connected in a lineβone is narrow (R1), and the other is wide (R2). The total pressure pushed through both pipes (which corresponds to the voltage) is divided: some goes through the narrow section, creating a pressure drop (voltage drop) there, and most flows freely through the wider pipe. The water flowing (current) is the same for both sections since they are in series!
Problem 3: Parallel Circuit Computation
Chapter 3 of 5
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Chapter Content
- A 12 V circuit has three parallel branches: 100, 200, 300 Ξ©. Compute I1, I2, I3, I_total, R_eq.
Detailed Explanation
In a parallel circuit, the voltage is the same across each branch. Here, V = 12 V for all branches. To compute the current through each resistor, use Ohm's Law: I = V/R.
- For R1 = 100 Ξ©: I1 = 12 V / 100 Ξ© = 0.12 A.
- For R2 = 200 Ξ©: I2 = 12 V / 200 Ξ© = 0.06 A.
- For R3 = 300 Ξ©: I3 = 12 V / 300 Ξ© = 0.04 A.
- To find I_total, sum these currents: I_total = I1 + I2 + I3 = 0.12 A + 0.06 A + 0.04 A = 0.22 A.
- For the equivalent resistance (R_eq), the formula for parallel resistors is 1/R_eq = 1/R1 + 1/R2 + 1/R3; thus: 1/R_eq = 1/100 + 1/200 + 1/300.
- Finding a common denominator and solving gives R_eq β 58 Ξ©.
Examples & Analogies
Think of a multi-lane highway where each lane represents a different resistor branch. Cars (current) can take any lane to get to their destination (the power supply). Some lanes (resistors) allow more cars to pass (higher current), and the total number of cars traveling at the same time gives the total current from the power supply. Just as adding more lanes reduces traffic (decreases equivalent resistance), adding more resistors in parallel facilitates more current flow!
Problem 4: Ammeter Calibration
Chapter 4 of 5
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Chapter Content
- An ammeter with R_i=0.1 Ξ© reads 0.2 A on a circuit. External resistance measured separately is 60 Ξ©; calculate true current.
Detailed Explanation
To find the true current, we first apply the concept of effective resistance in the circuit. The total resistance influencing the current reading is the sum of the external resistance and the internal resistance of the ammeter: R_total = R_external + R_i = 60 Ξ© + 0.1 Ξ© = 60.1 Ξ©.
- Using Ohm's Law again to find voltage from the ammeter reading: V = I Γ R = 0.2 A Γ 60.1 Ξ© = 12.02 V.
- Now, using this voltage to find the true current through the external resistance: I_true = V / R_external = 12.02 V / 60 Ξ© β 0.2003 A. So the true current is approximately 0.2003 A.
Examples & Analogies
Consider a water fountain with a tap that shows how much water flows (like an ammeter). The readout can get skewed if there's a blockage (internal resistance) in the tap. To know how much water actually flows from the fountain, you need to account for the blockage when calculating the total flow, which gives you a clearer picture of true water flow from the source!
Problem 5: Designing an LED Resistor
Chapter 5 of 5
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Chapter Content
- Design a resistor for an LED (V_f=3.0 V, I=20 mA) on 12 V; calculate power rating required.
Detailed Explanation
To design a resistor for the LED, we need to limit the current. First, we determine the required resistance using Ohm's Law. The voltage across the resistor (V_R) is V_supply - V_f, so V_R = 12 V - 3 V = 9 V.
- Using Ohm's Law: R = V_R/I = 9 V / 0.02 A = 450 Ξ©. Thus, a 450 Ξ© resistor is needed to allow 20 mA through the LED.
- Next, calculate power rating using P = IΒ² Γ R: P = (0.02 A)Β² Γ 450 Ξ© = 0.18 W. To ensure safety, choose a resistor rated for at least double this value, so a 0.5 W resistor would be suitable.
Examples & Analogies
Imagine you are filling a balloon (LED) with air from a pump (battery). You want to ensure that the pump doesn't over-inflate the balloon, so you attach a regulator (resistor) that controls how much air can flow into it. The regulator must be appropriately sized to ensure it does not burn out from the pressure (power load) while accurately filling the balloon at the right rate!
Key Concepts
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Resistor color codes: Different colors represent different numeric values.
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Series circuits: Current is the same in all components but voltage is divided.
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Parallel circuits: Voltage is the same across branches but current divides.
Examples & Applications
A 4-band resistor with colors yellow, violet, red, and gold has a resistance of 4700 ohms with a tolerance of +/- 5%.
In a series circuit with resistors of 150 Ξ© and 300 Ξ© connected to an 18 V source, the total current is 0.04 A.
Memory Aids
Interactive tools to help you remember key concepts
Rhymes
For resistors, colors gleam, decode them right, fulfill the dream!
Stories
Imagine a series of friends walking in a line. Each friend holds hands while passing along a message, just like current through resistors.
Memory Tools
For parallel circuits, remember: 'Voltage prolific, current specific!'
Acronyms
SERIES
Same Current
Each Resistor Is Summed!
Flash Cards
Glossary
- Ohm's Law
A fundamental principle that relates voltage (V), current (I), and resistance (R) in electrical circuits, defined by the equation V = I Γ R.
- Resistor
An electrical component that resists the flow of current, causing a voltage drop across its terminals.
- Series Circuit
A type of electrical circuit in which components are connected end-to-end, leading to the same current flowing through all components.
- Parallel Circuit
An electrical circuit configuration where components are connected across the same two points, resulting in the same voltage across each component.
- Equivalent Resistance
The total resistance of a circuit that can be replaced by a single resistor without affecting the current and voltage in the circuit.
Reference links
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