17.6 - Final Answer
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Introduction to Simultaneous Linear Differential Equations
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Today, we will explore simultaneous linear differential equations and how they model real-world systems like electrical circuits or mechanical systems. Does anyone know what a simultaneous linear differential equation is?
I think it's when two or more equations related to different variables are solved together.
Exactly! These equations often arise in systems where several variables interact. Today’s focus is on how to handle them using Laplace transforms.
Why do we use Laplace transforms instead of solving them directly?
Great question! Laplace transforms convert differential equations into algebraic ones, which are generally simpler to solve.
That sounds helpful! How does this process work?
Let's break it down! We'll start with the transformation steps. Remember the acronym 'LAP' - Laplace transform, Algebraic equations, and then back to the time domain.
Steps to Solve Simultaneous Equations with Laplace Transforms
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Now, we will discuss the steps involved in solving these equations using Laplace transforms. Can anyone remind me of the first step?
We need to take the Laplace transform of the equations!
Correct! After applying the Laplace transform, we use the properties for derivatives. For instance, \(L\{\frac{dx}{dt}\} = sX(s) - x(0)\). Which step do we take next?
We form the algebraic equations from that?
Exactly! Once we have those, we can manipulate them algebraically to solve for our unknowns.
Inverse Laplace Transform
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After we find \(X(s)\) and \(Y(s)\), how do we get back to the time domain?
I think we use the inverse Laplace transform?
Correct! The inverse transform helps us retrieve \(x(t)\) and \(y(t)\). Can anyone recall the standard forms used for the inverse?
There's the cosine and sine forms depending on the coefficients!
That's right! For example, \(L^{-1}\{\frac{s-a}{(s-a)^2+b^2}\} = e^{at}\cos(bt)\). It’s crucial to remember these forms for your calculations.
Introduction & Overview
Read summaries of the section's main ideas at different levels of detail.
Quick Overview
Standard
Simultaneous linear differential equations are common in engineering systems. The Laplace transform simplifies the solution process by converting these equations into algebraic forms, making it easier to solve for unknown functions and apply inverse transformations to retrieve solutions in the time domain.
Detailed
Application of Laplace Transforms to Simultaneous Linear Differential Equations
In engineering and applied mathematics, systems modeled by simultaneous linear differential equations often arise when dealing with interconnected physical systems like electrical circuits, mechanical systems, or control applications. Solving these equations directly through classical approaches can be complicated and time-consuming. This is where Laplace transforms come into play, offering a systematic method for solving equations algebraically in the s-domain, which drastically simplifies the process.
Objectives
- Convert a system of simultaneous linear differential equations into algebraic equations using Laplace transforms.
- Solve for the unknown functions via algebraic manipulation.
- Retrieve the time-domain solutions utilizing inverse Laplace transforms.
Theoretical Framework
Simultaneous linear differential equations can typically be represented as:
$$\frac{dx}{dt} = a_{11} x + a_{12} y + f_1(t)$$
$$\frac{dy}{dt} = a_{21} x + a_{22} y + f_2(t)$$
where \(x(t)\) and \(y(t)\) are time functions, and \(a_{ij}\) are constants, while \(f_1(t)\) and \(f_2(t)\) are known functions.
Steps to Solve Using Laplace Transforms
- Take Laplace transforms of both equations assuming initial conditions \(x(0)\) and \(y(0)\).
- Apply differentiation properties: \(L\{\frac{dx}{dt}\} = sX(s) - x(0)\) and \(L\{\frac{dy}{dt}\} = sY(s) - y(0)\).
- Formulate the system of algebraic equations in terms of \(X(s)\) and \(Y(s)\).
- Utilize substitution or elimination to solve the algebraic equations.
- Finally, apply inverse Laplace transforms to obtain \(x(t)\) and \(y(t)\).
Solved Example
Given the system:
$$\frac{dx}{dt} = 3x + 4y$$
$$\frac{dy}{dt} = -4x + 3y$$
with initial conditions \(x(0) = 1, y(0) = 0\).
This section details a systematic procedure to derive \(x(t)\) and \(y(t)\), illustrating the step-by-step transformations involved.
Summary
- Simultaneous linear differential equations are prevalent in systems with multiple interacting variables.
- Laplace transforms transform these systems into solvable algebraic equations.
- Initial conditions are integrated smoothly during the transformation process.
- Inverse Laplace transforms retrieve time domain solutions, crucial for applications in control systems and engineering dynamics.
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Final Solutions for x(t) and y(t)
Chapter 1 of 1
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Chapter Content
x(t)=e^{3t} ext{cos}(4t), y(t)=-e^{3t} ext{sin}(4t)
Detailed Explanation
In this final part, we present the solutions obtained from the earlier steps of solving the system of simultaneous linear differential equations. We have derived the functions x(t) and y(t) after applying the Inverse Laplace Transform. The expression for x(t) involves an exponential function multiplied by a cosine function, which reflects oscillatory behavior, indicating that x(t) behaves like a wave modulated by an exponential growth factor. Similarly, y(t) has a sine function multiplied by the same exponential growth factor but with a negative sign, indicating it's oscillating in a phase difference compared to x(t). This shows a typical behavior of solutions in systems involving harmonic oscillators with damping or growth.
Examples & Analogies
Think of x(t) and y(t) as the positions of two connected springs in a mechanical system. When you pull on one spring (x(t)), it affects the other spring (y(t)). As one spring vibrates up and down, the movement will create a wave-like pattern in both springs, similar to how waves operate on the surface of water when you drop a stone; they ripple outwards. The +e^{3t} indicates that this system grows over time, like when you're inflating a balloon, causing the springs to oscillate more wildly.
Key Concepts
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Laplace Transform: A method to simplify the solving of differential equations by converting them into algebraic form.
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Simultaneous Equations: A set of equations related to multiple variables that need to be solved together.
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Algebraic Manipulation: Techniques used to solve equations that do not involve derivatives.
Examples & Applications
Consider the equations \( \frac{dx}{dt} = 2x + 3y \) and \( \frac{dy}{dt} = -x + 4y \). By applying the Laplace transform and solving, we can find \(x(t)\) and \(y(t)\).
In an electrical circuit with interconnected components, simultaneous linear differential equations represent the relationship between current and voltage across components.
Memory Aids
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Rhymes
Transform, solve, and then backtrack, / In algebraic form, on the right track!
Stories
Imagine two friends, X and Y, trying to figure out how to work together. They take turns speaking (like taking Laplace transforms) to share their needs before they come together to solve their problems in the real world.
Memory Tools
The three critical steps to solving simultaneous equations!
Acronyms
LAPS - Laplace Transform, Algebraic Manipulation, and Solve for functions.
Flash Cards
Glossary
- Simultaneous Linear Differential Equations
Equations that involve multiple functions of time and their derivatives, solved concurrently.
- Laplace Transform
An integral transform used to convert a function from the time domain into the complex frequency domain.
- Inverse Laplace Transform
The process of converting a function from the frequency domain back to the time domain.
- Algebraic Equations
Equations where the variables are not differentiated, allowing easier manipulation and solution.
- sDomain
The domain in which functions are expressed in terms of complex frequency variable 's' for ease of analysis.
Reference links
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