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12.5. Example Problem

Interactive Audio Lesson

Session 1: Understanding the Problem Setup

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Sarah
SarahInstructor

Today, we will explore an example problem centered around the One-Dimensional Heat Equation. Can anyone tell me the importance of boundary and initial conditions in solving PDEs?

Noah
Noah

I think they help define the solution uniquely?

Sarah
SarahInstructor

Exactly! In our example, we’ll have boundary conditions stating that the ends of the rod are at zero temperature. This specifies how our solution behaves at the boundaries. What was our initial condition?

Isabella
Isabella

It’s given as u(x,0)=x(L−x)u(x,0) = x(L - x).

Sarah
SarahInstructor

Perfect! This initial condition gives us the temperature distribution along the rod at time t=0t=0.

Session 2: Computing Fourier Sine Coefficients

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Robert
RobertInstructor

To solve our example, we need to compute the Fourier sine coefficients for the initial condition function. Who can remind us of the formula to compute these coefficients?

Akash
Akash

It’s Bn=2L∫0Lf(x)sin⁡(nπxL)dxB_n = \frac{2}{L} \int_0^L f(x) \sin\left(\frac{n\pi x}{L}\right)dx!

Robert
RobertInstructor

Right! So, we will use this formula to find our coefficients. Why is this important?

Ananya
Ananya

Because the coefficients help form the solution based on the initial temperature distribution!

Robert
RobertInstructor

Excellent point! This links our initial condition to the overall solution.

Session 3: Final Formulation

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Sarah
SarahInstructor

Now that we have our Fourier coefficients, we can plug them into our general solution. Can anyone remind what the general solution looks like for the heat equation?

Noah
Noah

It’s a series involving the coefficients and exponential decay terms, right?

Sarah
SarahInstructor

Exactly! The final form will be something like: u(x,t)=∑n=1∞Bnsin⁡(nπxL)e−α2(nπL)2tu(x,t) = \sum_{n=1}^{\infty} B_n \sin\left(\frac{n\pi x}{L}\right)e^{-\alpha^2(\frac{n\pi}{L})^2 t}. Why is the exponential term significant?

Isabella
Isabella

It controls how the heat diffuses over time!

Sarah
SarahInstructor

You're all doing great! So, in conclusion, how does this example reflect on the larger context of solving PDEs?

Akash
Akash

It shows the step-by-step approach to using boundary conditions and initial conditions in our solutions.