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Today, we're diving into the concept of shear stress (τ) and how it varies across different cross-sections of beams under non-uniform bending. Can someone tell me what shear stress is?
Isn't shear stress the force per unit area acting parallel to the cross-section?
Exactly! Now, shear stress plays a crucial role in how beams respond to bending moments. Let's connect this to the formula for shear stress: τ = VQ/Ib.
What do the variables in that formula represent?
Good question! V is the shear force, Q is the first moment of area, I is the moment of inertia, and b is the width of the section at the point of interest. Remembering 'VQIB' might help you recall these variables.
Can we apply this to different shapes of beams?
Absolutely! Let's explore how this formula applies to rectangular, circular, and I-beam cross-sections.
Now, let's assess shear stress in a rectangular cross-section. Who can describe how we find Q(y) for this shape?
Q(y) is the area above the point where we want to calculate shear stress multiplied by the distance to the centroid of that area.
Correct! For a rectangle, Q(y) simplifies to y multiplied by the area of the section above where τ is being analyzed. The moment of inertia I can also be calculated easily. Let’s calculate τ at a distance y from the neutral axis.
So τ is maximum at the centroid?
Yes! It decreases towards the edges due to the absence of shear force at those boundaries. Illustrating this helps anchor our understanding.
Next, let's talk about circular cross-sections. How does shear stress distribution change compared to rectangles?
For circular sections, τ can't just be independent of z, right?
Exactly! We realize that this assumption leads to contradictions. In practice, τ varies significantly across circular sections, especially at the perimeter.
So it’s essential to analyze this carefully in engineering designs?
Yes, understanding these differences is crucial in structural applications. Incorporating figures or diagrams can also clarify this.
We've covered rectangular and circular sections. Now, what's unique about I-beams regarding shear stress?
The cross-section changes abruptly which affects how we calculate τ.
Exactly! The shear stress exhibits jumps corresponding to these abrupt width changes. This variance plays a significant role in structural integrity.
Does this mean we should be more cautious when using I-beams?
Yes, absolutely! Each type of beam has its own characteristics, and understanding this helps us in effective design and application. Remember 'I-beams Jump', when thinking about their shear stresses!
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The section discusses how shear stress varies in different types of cross-sections, including rectangular, circular, and I-beam sections, focusing on the effects of non-uniform bending. It highlights the significance of factors such as shear force and geometrical properties on τ distribution.
In this section, we examine the variation of shear stress (C4) in beams undergoing non-uniform bending. The analysis distinguishes between different types of cross-sections: rectangular, circular, and I-beams, emphasizing the influence of geometrical properties and shear forces on the distribution of shear stress.
For a rectangular beam, shear stress (C4) is shown to be independent of the z-coordinate and varies with the y-coordinate. We derive the first moment of the area (Q(y)) above the line where shear stress is being calculated, alongside the area of the cross-section (b).
The expression for shear stress can be derived as:
$$ \tau_{yx} = \frac{V \cdot Q(y)}{I \cdot b(y)} $$
where V is the total shear force, I is the second moment of area, and b(y) is the width of the cross-section. As observed, shear stress is maximum at the centroid and decreases toward the edges of the section.
In circular beams, we further analyze the assumption of shear stress (C4) being independent of the z-coordinate, discovering it leads to contradictions where shear stress should be zero nonetheless. This realization informs us that while practical approximations often use this assumption, the actual distribution is more complex.
For I-beams, due to abrupt changes in width, shear stress exhibits a jump corresponding to these changes. The centroid remains at the center due to symmetry, and again, we apply the same shear stress formula to account for these changes in geometry.
Through comparative analysis, the variations in τ across different cross-sections highlight that shear stress is inherently linked to the shape and loading conditions of the beam, impacting design and analysis in structural mechanics.
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A typical rectangular cross section is shown in Figure 8 and we want to find the value of τ at a distance of y from the neutral axis.
As τ is independent of z, it will have the same value over lines parallel to the z-axis. For applying equation (13), we need to find Q(y), b(y) and I. As this is a rectangular cross section, width b(y) is constant and equal to b. We have already derived I for a rectangular cross section in one of the previous lectures to be.
We only need to obtain expression for the first moment Q(y) of the area above the y line where τ is to be calculated (shown as the shaded region in Figure 8). The first moment will simply be the y-coordinate of the centroid of the shaded area multiplied by the shaded area. As the height of the shaded area is -y, its centroid will be at half of this distance from the y line and hence at.
Thus, Q(y) becomes
while τ becomes
As V is the total shear force on the cross-section and b is the area of the cross-section, equals average shear stress τ while τ at the neutral axis is.
Likewise, at the periphery of the cross section, τ is.
The variation of y vs τ is shown in Figure 9.
We observe that due to the presence of shear force in the cross section, shear stress is maximum at the centroid and vanishes at the two ends. There is another way to realize the vanishing of shear stress at the ends. The points y = ±h/2 also lie on top and bottom surfaces of the beam, respectively. There is no external traction on the bottom surface whereas on the top surface, the distributed load b(x) acts in the y direction. Thus, τ is zero at both top and bottom surfaces. However, due to τ and τ being equal, shear stress on the cross-sectional plane vanishes at y = ±h/2.
In a rectangular beam, the shear stress τ at a certain distance y from the neutral axis can be calculated using the principles of static equilibrium and previous derivations. The assumption that τ is the same across all points parallel to the z-axis simplifies calculations. The width of the rectangular section remains uniform, and the first moment Q(y) is determined by the area above the y line where τ is being examined. This first moment reflects how the area is distributed concerning the neutral axis. The final shear stress calculation is proportional to the shear force and the geometric properties of the area. Importantly, shear stress reaches its maximum at the neutral axis and reduces to zero at the top and bottom surfaces of the beam due to the lack of external forces at those points.
Imagine holding a wide, flat piece of cardboard (the beam) horizontally with your hands applying gentle pressure downwards at the center (the neutral axis). The middle of the cardboard sags the most (maximum shear stress) whereas the ends stay flat (zero shear stress) since there’s no force acting on them. This illustrates how shear stress behaves in a rectangular beam under uniform loading.
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In the derivation for rectangular beams, we had assumed that τ is independent of z coordinate. For a circular beam however, this assumption cannot be used. Consider the beam shown in Figure 10 and analyze one of its cross-sections.
If τ is constant along lines parallel to z-axis, the shear stress will be as shown in Figure 11.
Basically, it is non-zero even at the ends. Let us work with a cylindrical coordinate system and assume a radial distributed load is acting (e.g., pressure load) which could also be zero. In that case τ must be zero on the lateral surface. So, τ must also be zero along the periphery of the cross section, i.e., shear stress cannot have radial component along the periphery of the cross-section in the cross-sectional plane. However, if we look at Figure 11, the assumption of τ being independent of the z coordinate leads to a non-zero radial component which is a contradiction. Thus, we conclude that for circular cross-sections, considering τ independent of z is not a good assumption. Still, this assumption is often used since it gives an approximate distribution of shear stress.
For circular cross-sections, the shear stress τ cannot be assumed to be the same along all parallel planes because of how the geometry influences stress distribution. When considering shear in circular beams, if we assume τ to be constant in z-direction, we may calculate a non-zero shear stress at the ends, which is incorrect. By analyzing the forces acting on a circular beam with a radial load, we see that τ must go to zero on the circular edge due to the absence of lateral forces. This realization is crucial for accurate modeling; however, approximations are still made in practice as constant τ can simplify calculations when the material response is generally understood.
Visualize a water pipe (the circular beam) that is under pressure. You notice that the pressure on the sides of the pipe (the ends) is zero because no water is pushing outward there; it is only in the middle where the force is acting. This shows how shear stress behaves differently in circular structures compared to rectangular ones.
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Figure 12 shows the cross-section of an I-beam. The centroid of this section would be at the center because of symmetry. So, the neutral axis passes through the center. There are two different values of width possible in the cross section. To find τ at a distance y from the neutral axis, we can again use equation (13). As the width changes abruptly in this case, the distribution of shear stress will also exhibit a jump corresponding to this abrupt change in width. A plot of y vs. τ is shown in Figure 13 exhibiting this jump.
I-beams are designed with a varying width across their height, creating regions of different shear stress distributions in response to forces applied to them. Given that the centroid is in the center due to symmetry, the neutral axis also lies there. Due to the abrupt change in widths of the sections, the shear stress does not vary uniformly; instead, there’s a noticeable jump in shear stress values as you move between these sections. This means that at certain points, you can have significant changes in stress based on the geometry of the beam. Utilizing the established equations allows for quantifying these variations precisely.
Think of an I-beam as a bridge structure. Depending on where you are on the bridge, the support and weight distribution change; sections with wider tops support more weight and experience different shear stress than narrower sections. This is similar to how an I-beam behaves under load.
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Key Concepts
Variation of Shear Stress: Shear stress in beams varies depending on the cross-section and loading conditions.
Q(y) for Rectangles: The first moment of area above a specified line is calculated for rectangular sections to find shear stress.
Shear Stress Distribution in Circular Sections: For circular sections, shear stress cannot be assumed constant along cross-sections, unlike rectangular beams.
I-Beam Characteristics: I-beams present unique complexities in shear stress distribution due to sudden changes in cross-section width.
See how the concepts apply in real-world scenarios to understand their practical implications.
For a rectangular beam with total shear force V = 100 N, width b = 10 cm, and height h = 20 cm, calculate shear stress at midheight using τ = VQ/Ib.
In a circular beam subjected to a uniform load causing shear V, consider the complications arising from assuming τ is constant at every z-coordinate.
Use mnemonics, acronyms, or visual cues to help remember key information more easily.
VQIB, fingers twirl, shifting loads cause shear to unfurl.
Imagine a thick book bending under pressure. The pages in the middle feel the most stress, while the pages at the ends feel hardly any at all. This is like shear stress in beams!
Remember 'VIBe the Shear': V for shear force, I for moment of inertia, B for width.
Review key concepts with flashcards.
Review the Definitions for terms.
Term: Shear Stress (τ)
Definition:
The stress component acting parallel to the cross-section of a material.
Term: Shear Force (V)
Definition:
The total internal force acting parallel to a cross-sectional area.
Term: First Moment of Area (Q)
Definition:
The first moment of the area above (or below) a reference line, used in calculating shear stress.
Term: Moment of Inertia (I)
Definition:
A measure of an object's resistance to changes in its shape or rotation, used in calculating bending stresses.
Term: Rectangular CrossSection
Definition:
A cross-section shaped like a rectangle, commonly used in beams.
Term: Circular CrossSection
Definition:
A beam cross-section shape that is circular, typically subject to different shear stress distributions.
Term: IBeam
Definition:
A beam characterized by its I-shaped cross-section, commonly used in construction.