Lecture – 68: Multi-Transistor Amplifiers: Amplifier with Active Load (Contd.) – Numerical Examples (Part A) - 68.1.1 | 68. Multi-Transistor Amplifiers : Amplifier With Active Load (Contd.) –Numerical Examples (Part A) | Analog Electronic Circuits - Vol 3
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Interactive Audio Lesson

Listen to a student-teacher conversation explaining the topic in a relatable way.

Introduction to Active Loads

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0:00
Teacher
Teacher

Today, we're exploring multi-transistor amplifiers with active loads. Can anyone tell me why we prefer active loads over passive ones?

Student 1
Student 1

Active loads help enhance the voltage gain, right?

Teacher
Teacher

Exactly! Active loads, such as current mirrors, can significantly boost the gain of the amplifier. Remember the mnemonic 'More Gain, More Active' to help you recall this.

Student 2
Student 2

But how do we correctly set up the transistors in this scenario?

Teacher
Teacher

Great question! We'll dive into specific examples shortly, but first, let's cover how we design these configurations for BJTs and MOSFETs.

Numerical Example Setup

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0:00
Teacher
Teacher

Let's look at a specific example. We've chosen two transistors with Beta values of 100 and 200. Can anyone explain why these values matter?

Student 3
Student 3

If the Beta values differ, we need to adjust the biasing to ensure equal collector currents, right?

Teacher
Teacher

Exactly! This ensures both transistors operate in their active regions effectively. We’ll calculate the required collector current next. Can someone remind us how we find that?

Student 4
Student 4

I think we use the supply voltage minus the base-emitter voltage divided by the resistor value.

Teacher
Teacher

That's right! And multiplying it by Beta gives you the collector current. Now let’s perform that calculation.

Current Calculations

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Teacher
Teacher

We calculated the DC output voltage to be 6 V. Now, let’s determine the individual collector currents for both transistors. Who can help me with transistor-1?

Student 1
Student 1

For transistor-1 with a Beta of 100, I would use the voltage drop across the load resistor.

Teacher
Teacher

Exactly! With a supply of 12V and V_BE(on) of 0.6V, you derive the collector current as 2 mA. And what about transistor-2 with a Beta of 200?

Student 2
Student 2

Following the same method, it also results in 2 mA, right?

Teacher
Teacher

Correct! Both transistors now match, compensating for their Beta differences through our design.

Small Signal Parameters

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0:00
Teacher
Teacher

Now, let’s discuss small signal parameters, which are crucial for analyzing amplifier performance. Can anyone tell me what transconductance is?

Student 3
Student 3

It's the change in output current over the change in input voltage, right?

Teacher
Teacher

Exactly! We can denote it using 'g_m'. Now, for our transistors, how do we compute their small signal resistance 'r_pi'?

Student 4
Student 4

We use the Beta value divided by 'g_m', correct?

Teacher
Teacher

Correct again! This plays into our gain calculations next. Let's derive those gains using our previously calculated values.

Comparison of Active vs. Passive Loads

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0:00
Teacher
Teacher

We've gone through our active load amplifier setup. Now, let’s compare its performance against a passive load. Student_2, what do you recall about bandwidth?

Student 2
Student 2

I remember that the bandwidth for passive loads tends to be higher due to lower resistance.

Teacher
Teacher

Yes! While active loads offer higher gain, they may sacrifice bandwidth. Can we remember this as 'Higher Gain, Lower Bandwidth'?

Student 1
Student 1

That's a good way to summarize it!

Teacher
Teacher

Exactly! Keep these comparisons in mind, as they’re critical for applying these concepts to real circuits.

Introduction & Overview

Read a summary of the section's main ideas. Choose from Basic, Medium, or Detailed.

Quick Overview

This section discusses numerical examples related to amplifiers with active loads, emphasizing design guidelines for both BJT and MOSFET amplifiers.

Standard

In this section, the instructor continues the topic of multi-transistor amplifiers with active loads, providing detailed numerical examples and design principles essential for understanding common emitter and common source amplifiers. It covers collector current calculations, DC output voltages, small signal parameters, and performance comparison with passive loads.

Detailed

Detailed Summary

In this section of the lecture, the focus is on multi-transistor amplifiers with active loads, particularly emphasizing numerical examples that illustrate their practical implementation and benefits.

  1. Purpose of Active Loads: Active loads enhance voltage gain compared to passive loads. The section begins with the context of using active loads in Common Emitter (CE) and Common Source (CS) amplifiers, demonstrating this through various calculations.
  2. Example Setup: The instructor details a specific example where two transistors, Q1 and Q2, each with varying Beta (β) values, are analyzed. The lecture discusses parameters such as base-emitter voltages, early voltages, supply voltages, and bias resistors, leading to the equalization of collector currents for both transistors.
  3. Calculation of Collector Current: The section provides step-by-step calculations for the collector currents of both transistors. Transistor-1 has a Beta of 100 while transistor-2’s Beta is 200, requiring careful biasing to match their collector currents at 2 mA.
  4. DC Output Voltage Calculation: The lecture elaborates on calculating the DC output voltage, leading to an obtained value of 6V at the output node. It explains how the early voltage of the transistors affects the calculations and maintains the integrity of design.
  5. Small Signal Parameters: The section discusses the derivation of small signal parameters such as transconductance (g) and output resistance (
    ). These parameters are crucial for analyzing amplifier performance in small signal scenarios.
  6. Signal Swing and Upper Cutoff Frequency: The instructor explains the potential signal swing around the DC levels and analyzes the effects of input capacitance on the upper cutoff frequency of the amplifier.
  7. Performance Comparison: Finally, a comparison is drawn between the CE amplifier with active load and one with passive load, highlighting significant differences in voltage gain, input/output resistances, and bandwidths while ensuring that the gain-bandwidth product remains consistent across the two configurations.

This comprehensive understanding is foundational for students studying analog electronic circuits.

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Analog Electronic Circuits _ by Prof. Shanthi Pavan
Analog Electronic Circuits _ by Prof. Shanthi Pavan

Audio Book

Dive deep into the subject with an immersive audiobook experience.

Introduction to Active Load

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Dear students, so welcome back to our NPTEL online certification course on Analog Electronic Circuit, myself Pradip Mandal from E and EC department of IIT Kharagpur. Today we are going to continue Amplifiers with Active Load we have started this topic and today primarily we will be discussing about Numerical Examples.

Detailed Explanation

In this introductory section, the speaker welcomes the students back to the course and gives an overview of what will be discussed in the lecture. The focus will be on amplifiers that use an active load, which are important in increasing the voltage gain in electronic circuits. Active loads are often preferred over passive loads because they can provide better performance, making them a common topic in advanced electronics.

Examples & Analogies

Think of active loads in amplifiers like a turbocharger in a car engine. Just as a turbocharger uses the engine’s exhaust to produce more power without adding much weight, active loads allow amplifiers to achieve higher gains without compromising the circuit's design.

Example Circuit Introduction

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So, the plan for today it is Numerical Examples and inherent design guidelines; while we will be going through the numerical examples we will also be given hint towards how to design a circuit specifically for CE amplifier having active load and then common source amplifier having active load.

Detailed Explanation

Here, the plan for the day is laid out, focusing on practical numerical examples. The speaker emphasizes that, alongside the examples, students will learn about design guidelines for two types of amplifiers: the Common Emitter (CE) amplifier and the Common Source amplifier, both incorporating active loads. This integrates theory with practical application.

Examples & Analogies

Designing an amplifier is much like planning a construction project. You wouldn't just start building without a blueprint; similarly, engineers need guidelines to make effective amplifiers that perform well with active loads.

Active Load Characteristics

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So, here we do have the different parameters of the two transistors for Q β is 100, for Q β is 200, just for a change we are taking different value 1 2 of β. And V of transistor-1 it is we are approximating it is 0.6 V.

Detailed Explanation

In this part, the speaker describes the parameters of the transistors being used in the example. The β (beta) values are mentioned for two different transistors: Q1 has β = 100 and Q2 has β = 200. Additionally, the base-emitter voltage V_BE for both transistors is approximated to 0.6 V, a typical operating value for silicon-based BJTs. The different beta values are important to note as they affect current gain in the circuit.

Examples & Analogies

Imagine you are baking cookies and have different ovens. One has settings that are very precise (like Q2 with a higher beta) and another has more variation (like Q1 with a lower beta). The precise settings lead to more consistent results, just as a higher beta in a transistor can lead to more reliable amplification.

Current Calculation Approach

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To make a balance of that the collector current of transistor-1 and collector current of transistor-2 they should be equal and to do so, to get that what we have done it is that the, base current of transistor-1 and base current of transistor-2 we are making it different.

Detailed Explanation

This chunk discusses how to ensure that the collector currents in both transistors are matched. Since the transistors have different beta values, to achieve equal collector currents, adjustments have to be made in the base currents. This is a crucial aspect of amplifier design, as unbalanced currents can lead to distorted outputs.

Examples & Analogies

Think of this like balancing two scales with weights. If one side is more sensitive (like the transistor with a higher beta), you need to adjust the weights on the other side to make sure they balance. In electronics, this means adjusting currents rather than physical weights.

Output Voltage Calculation

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So, to get the DC voltage at the output node say V_OUT what we can do? we can compare β I × (R of transistor-1) = β I of transistor-2 × (R of transistor-2). Now this part and this part we have seen here they are equal.

Detailed Explanation

This section focuses on calculating the output DC voltage (V_OUT) of the amplifier circuit. By equating the products of the beta times collector currents with respect to their respective resistances, the speaker shows how to derive the output voltage. This establishes a vital relationship that determines how signals will behave in the circuit.

Examples & Analogies

Imagine you are calculating the final score of two competing teams in a game. If both teams have equal scoring methods but different strategies, as long as their final scores (like the output voltage) are calculated correctly, the game is balanced. Similarly, in this circuit, balance needs to be maintained for accurate amplification.

Operating Point and Parameters

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So, we do have I = I = 2 mA, V = V = 6 V. And yeah so, the other things we C1 C2 CE1 EC2 already have obtained namely I = 20 µA and I = 10 µA right.

Detailed Explanation

In this part, the speaker summarizes the operating point of the two transistors in the amplifier, identifying the collector currents and voltage at the emitters (or collectors). These operating points are crucial in understanding how the amplifier performs under complete circuit conditions and how much current flows through each transistor.

Examples & Analogies

Consider operating points like the pressure gauges in a water supply system. By knowing the pressure in each section, engineers can better understand how efficiently the system operates. Similarly, knowing the operating points in amplifiers helps in diagnosing performance issues.

Small Signal Parameters

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From that we can calculate the small signal parameters of the transistors namely in g say g of transistor-1 it is thermal equivalent voltage we can consider that is 26 mV.

Detailed Explanation

This chunk emphasizes the calculation of small signal parameters (like transconductance) which are significant for analyzing how small changes in input signal affect the output in linear operation. The thermal voltage is important in characterizing the response of transistors to small signals.

Examples & Analogies

Think of small signal parameters as the sensitivity settings on a microphone. The more sensitive the mic (or transistor), the better it can respond to tiny sounds (or signals). Just like you’d feel the difference when a mic is properly calibrated, the gain changes in amplifiers are greatly influenced by these small signal parameters.

Definitions & Key Concepts

Learn essential terms and foundational ideas that form the basis of the topic.

Key Concepts

  • Active Load: Enhances voltage gain while providing higher output impedance.

  • Collector Current: The current through the collector terminal, critical for amplifier operation.

  • Beta (β): Indicates how much current gain a transistor exhibits.

  • Small Signal Parameters: Key for analyzing amplifiers in the small signal context.

  • Gain-Bandwidth Product: A constant for amplifiers indicating the trade-off between gain and bandwidth.

Examples & Real-Life Applications

See how the concepts apply in real-world scenarios to understand their practical implications.

Examples

  • In calculating the collector current for transistor-1 with a supply voltage of 12V and V_BE(on) of 0.6V, if R_B1 = 570kΩ and β = 100, we find I_C = 2mA.

  • The active load configuration leads to a gain of approximately 1900 in the CE amplifier setup.

Memory Aids

Use mnemonics, acronyms, or visual cues to help remember key information more easily.

🎵 Rhymes Time

  • Active loads make voltage gain swell, with higher outputs, they do so well.

📖 Fascinating Stories

  • Imagine two friends, Beta and Alpha. Beta is energetic and helps his friends lift weights (current), while Alpha stays passive and can't help much. Beta always lifts more!

🧠 Other Memory Gems

  • When remembering parameters: 'Current (C) goes with Beta (B), Voltage (V) pairs with Gain (G).' (C-B, V-G)

🎯 Super Acronyms

Think 'POWER' for amplifiers

  • Performance
  • Output
  • Wattage
  • Efficiency
  • Resistance.

Flash Cards

Review key concepts with flashcards.

Glossary of Terms

Review the Definitions for terms.

  • Term: Active Load

    Definition:

    A load that enhances the performance of an amplifier by providing a higher output impedance, typically involving transistors.

  • Term: Collector Current (I_C)

    Definition:

    The current that flows through the collector terminal of a transistor.

  • Term: Transconductance (g_m)

    Definition:

    A measure of the change in output current per change in input voltage in transistor amplifiers.

  • Term: Beta (β)

    Definition:

    The current gain of a transistor; the ratio of collector current to base current.

  • Term: Cutoff Frequency

    Definition:

    The frequency at which the output of an amplifier drops to a specified level, commonly defined as -3dB of the maximum response.