68.1.9 - Small Signal Gain and Resistance
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Understanding Active Loads
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Today, we'll learn how active loads increase voltage gain in amplifiers. Can anyone explain what an active load is?
Isn't it a load that can vary its resistance based on the current flowing through it?
Exactly! Active loads, like transistors configured as loads, help improve gain compared to passive loads. Remember the acronym GAIN?
What does GAIN stand for?
Gain, Active components, Input signal processing, and Node analysis. This will help us remember the key aspects of small signal amplifiers.
Small Signal Parameters
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Let's talk about small signal parameters. What do you think these are?
Are they the parameters used when small AC signals are superimposed on DC levels?
Great point! One key parameter is transconductance, which defines how effectively a transistor can control an output current. The formula is g_m = I_D/V_{GS}.” Can you think of how this might impact performance?
Higher transconductance means better gain, right?
Exactly! And remember to analyze resistance, such as output resistance, when figuring overall gain.
Numerical Examples
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Now, let's work through some numerical examples. First, we need to compute the collector current for each transistor. Who can remind me how to calculate it?
We need to use the supply voltage minus V_BE, divided by the resistance values, right?
Exactly! So let's consider we have a supply voltage of 12V and a base-emitter voltage drop of 0.6V. If the resistors for our design are 570kΩ and 1.14MΩ, what do we get for the collector currents?
After calculating, we should arrive at 2mA for both transistors.
Great! This ensures balance for operation in the active region. Always check that your currents match!
Output Resistance and Gain Calculation
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Next, let's calculate the output resistance and gain. Why do you think these metrics are important?
They help us understand how much the amplifier can drive a load and how much signal amplification we can achieve!
Correct! The output resistance is found through parallel calculations and helps in determining the voltage gain. We can use the formula A_v = g_m * R_{out}. How would you calculate that using our small signal equivalent circuit?
We combine the resistances we found and multiply them by the transconductance values for our specific transistors.
Excellent! Remember, the gain can significantly change with different configurations.
Importance of Cutoff Frequency
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Lastly, let’s discuss cutoff frequencies. Can anyone explain their significance?
They determine the frequency range over which our amplifier will perform effectively.
Exactly! For our active load designs, we saw that the upper cutoff frequency is crucial. How do we calculate it?
We take the output resistance and load capacitance to find the f_c formula!
Right, it's calculated as f_c = 1 / (2 * π * R_{out} * C_{load}). Always use appropriate units to get accurate results.
Introduction & Overview
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Quick Overview
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This section delves into small signal models for multi-transistor amplifiers, focusing on small signal gain, input and output resistances, and their calculations. It explores the inherent design principles for amplifiers with active loads and discusses numerical examples to enhance understanding.
Detailed
Detailed Summary
This section focuses on small signal gain and resistance in the context of multi-transistor amplifiers, specifically those featuring active loads. Active loads help enhance voltage gain, and understanding the relationships between current, resistance, and voltage is essential for effectively designing and analyzing amplifiers. The section provides step-by-step numerical examples of a BJT-based common emitter amplifier and a common source MOSFET amplifier, showcasing:
- The concept of electrical parameters such as early voltage, dynamic resistance, and temperature effects on transistor behavior.
- How to calculate collector current based on biasing resistors and transistor parameters to ensure matched operation between transistors.
- Small signal parameters including transconductance and input/output resistances.
- The importance of understanding cutoff frequencies and signal swings, critical for ensuring optimal performance in amplification tasks.
Through thorough explanations and numerical calculations, the section aims to solidify the concepts of small signal models and resistance in amplifiers, enabling learners to grasp the design and operational principles effectively.
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Understanding Small Signal Parameters
Chapter 1 of 5
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Chapter Content
So, from that we can calculate the small signal parameters of the transistors namely in a g say g of transistor-1 it is thermal equivalent voltage we can consider that is 26 m mV. So, this is . So, that is ℧. So, likewise g it is also = ℧, then r = β of transistor-1 divided by g of the transistor.
Detailed Explanation
In this chunk, we are calculating the small signal parameters for two transistors used in the circuit. Each transistor has a transconductance 'g', which represents its ability to control the output current based on the input voltage. The thermal equivalent voltage is mentioned as 26 mV, which is a standard value for many transistors at room temperature. Additionally, the internal resistance, denoted as 'r', is determined by dividing the transistor's beta (β, also known as current gain) by the transconductance (g). This calculation helps in understanding how the transistor behaves when small signal inputs are applied.
Examples & Analogies
Think of the transistor as a valve that controls water flow. The flow rate is analogous to the current flowing through the transistor. The g and r parameters tell us how sensitive the valve is to adjustments in pressure (or voltage), similar to how much the valve opens or closes when you adjust a handle.
Calculating Output Voltage and Collector Current
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So, to get the DC voltage at the output node say V what we can do? we can compare β I × ( ) of transistor-1 = β I of transistor-2 × ( ) of transistor-2.
Detailed Explanation
Here, we are determining the output DC voltage (V_OUT) by equating the collector current equations of both transistors. The equations factor in the beta (β) of each transistor, which affects the collector current based on the input. By ensuring that the product of the beta and the input current for both transistors is equal, we can derive the output voltage. This helps in ensuring balanced operation of the transistors within the amplifier circuit.
Examples & Analogies
Imagine two water tanks connected by pipes. The height of the water in each tank is crucial for maintaining the system's balance. If one tank (transistor) has a higher water level (more current), it will affect the flow to the other tank. Here, we ensure both tanks are at equal levels (currents) so that the system operates smoothly.
Understanding Output Resistance
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So, to find the output resistance what we have to do? We can stimulate this circuit by a signal called v and then we can observe the corresponding current here.
Detailed Explanation
This chunk discusses how to compute the output resistance of the circuit. To do this, we apply a test signal and measure the current that flows as a result. The output resistance is determined by the ratio of the output signal voltage to the output current. It's important to consider that while testing, all other voltage sources in the circuit should be at zero to ensure accurate measurement.
Examples & Analogies
Think of output resistance like the resistance of a drinking straw to flow. If you use your finger to block the top of the straw and then blow into it (applying a signal), you can measure how hard you have to blow (voltage) to achieve a certain flow of air (current). By measuring this, you can determine how much resistance the straw is adding to your effort.
Analyzing Input Capacitance
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So, while you are talking about the input capacitance we have to consider the C and so this is C and then this is C.
Detailed Explanation
In this part, we are analyzing the input capacitance of the circuit, which affects how quickly the amplifier can respond to changes in input signals. The capacitance values for different components in the circuit are considered, and their combined effects help determine the overall input capacitance. This is important for setting the upper cutoff frequency of the amplifier, thereby influencing its bandwidth.
Examples & Analogies
Input capacitance can be thought of like a sponge that absorbs water. If the sponge is soaked (charged) with water (input signal), it takes time to dry up (respond to new input changes). The combined capacity of all sponges (capacitors) will determine how fast or slow the system can respond to new water (signal).
Summary of Performance Metrics
Chapter 5 of 5
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Chapter Content
So, in summary what we can say that the cutoff frequency it is getting reduced gain got increased and output resistance also got increased.
Detailed Explanation
In this final chunk, a summary is provided regarding the performance of the circuit, focusing on how gains and bandwidth (cutoff frequencies) are affected by using active loads. It is noted that while the gain increases, the cutoff frequency tends to reduce due to higher capacitance and added electrical load. Understanding these trade-offs is crucial for the design and optimization of amplifiers.
Examples & Analogies
Consider a high-performance sports car (the amplifier with active load) versus a regular sedan (passive load). The sports car accelerates faster (higher gain) but has less torque (reduced bandwidth), just like the amplifier performs exceptionally well in gain but has other limitations, which could affect its overall performance in certain scenarios.
Key Concepts
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Small Signal Gain: The amplification factor of a small signal in relation to the input signal.
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Input Resistance (R_in): The resistance looking into the amplifier's input terminals, influencing how much signal is drawn from the source.
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Output Resistance (R_out): The resistance affecting the voltage drop across the output of the amplifier.
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Transconductance (g_m): Indicates how the output current varies in response to the input voltage.
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Cutoff Frequency: The frequency at which the output signal drops to 70.7% of its maximum value.
Examples & Applications
Example 1: Compute the small-signal gain for a common emitter amplifier with specified transconductance and load resistance.
Example 2: Calculate the output resistance of a given amplifier configuration, noting significant resistive components.
Memory Aids
Interactive tools to help you remember key concepts
Rhymes
If you're measuring gain, remember, it's g-m and so it's plain, the higher it goes, the louder it shows!
Stories
Imagine two transistors having a friendly competition to yield the best gain. They balance their currents, just like friends balance a scale, leading to amplifiers singing louder without fail!
Memory Tools
To recall small signal gain, think GAIN = Gain, Active components, Input signal processing, Node analysis.
Acronyms
RIG
Resistance
Input Gain. Always remember how these parameters play together in amplifiers!
Flash Cards
Glossary
- Transconductance (g_m)
The measure of how effectively a transistor can control output current with changes in the input voltage, calculated as I_D/V_{GS}.
- Output Resistance (R_{out})
The total resistance looking into the output terminal, affecting the ability to drive a load.
- Early Voltage (V_A)
The voltage related to the increasing slope of the transistor's output characteristics, affecting the output resistance.
- Cutoff Frequency
The frequency point at which the output signal power is reduced to half its full-band value, defining the operational bandwidth of an amplifier.
- Active Load
A load configuration utilizing active components (like transistors) to improve circuit performance in terms of voltage gain and linearity.
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