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Let's start by discussing what a differential amplifier is. Can anyone explain its primary function?
Isn't it used to amplify the difference between two input voltages?
Exactly! It's designed to amplify the difference while rejecting any signals that are common to both inputs. This brings us to common mode gain. Why is it important?
We want it to be low, right? To prevent interference from signals that are the same on both sides?
Correct! Lower common mode gain improves the amplifier's performance. Remember the acronym 'CMA-L' which stands for 'Common Mode Amplifier - Low' to help you recall this concept easily.
A good way to remember it!
Glad you liked it! Now, how do we ensure low common mode gain while achieving high differential gain?
By using current mirrors to balance the circuit, right?
Exactly! Balancing the currents through matched transistors is key. Letβs explore the advantages of current mirrors next.
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Current mirrors are essential in maintaining consistent current levels in differential amplifiers. Can someone summarize how they function?
They copy the current flowing through one active device to another, ensuring both have the same current.
Exactly! And whatβs the significance of this in our context?
It helps to stabilize the output and allows for effective differential signaling.
Great! So now, letβs calculate the currents in our circuit. What happens when we apply a common mode voltage?
The currents will split evenly between the two branches, right?
Correct! Half will flow through each, which is essential for proper operation. Additionally, what voltage levels do we expect at the output nodes?
They should be equal and determined by the supply voltage minus the drop across the mirror transistors.
Absolutely! Let's confirm this when we calculate the actual output voltage later on.
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Now, letβs calculate the differential and common mode gains using the known resistances and transconductance. Can anyone provide the expression for differential mode gain?
It involves the transconductance multiplied by the effective resistance, correct?
Yes, that's right! So, if we have gm and resistances in parallel, how do we express the total gain?
The formula would be A_d = gm * (R1 || R2), where R1 and R2 are the resistances at the outputs!
Awesome! And how about the common mode gain? Why is it generally lower?
Because it gets impacted directly by the degeneration resistors, lowering the overall gain.
Exactly! This degradation is beneficial as it reduces the undesired signals. Now, let's calculate the numerical values based on the provided example.
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In this section, we explore the concept of common mode gain within differential amplifiers utilizing current mirrors as active loads. We discuss the analysis of DC currents through transistors and the significance of matched devices in maintaining performance, alongside the calculations for both common mode and differential mode gains.
This section delves into the calculation of common mode gain for differential amplifiers, particularly those incorporating current mirrors.
Through this exploration, the significance of maintaining low common mode gain while achieving higher differential mode gain in differential amplifier designs is thoroughly investigated.
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Here we do have this resistor it is practically , and if we apply same voltage here and same voltage here namely v . So, that makes this voltage and this voltage to be equal in_c so, even though we do have r connected here. But we do have voltage dependent current source which depends on this voltage, making this node very insensitive or a smarter way to calculate their common mode voltage we can say that common mode gain.
Common mode gain refers to the ability of a circuit to respond to signals that are common to both inputs. In this case, if the same voltage (v_in) is applied to both inputs of the amplifier, the common mode signals will mostly not be amplified due to the design of this amplifier configuration. The presence of a resistor (r) affects this gain, but the circuit's response is largely defined by its inherent characteristics, such as the voltage-dependent current source present, rendering the node high impedance.
Think of it like a two-person conversation where both speakers say the same thing at the same time; the listeners (the amplifier) only respond to the differences in their speech patterns and effectively ignore common statements. This mimics how a differential amplifier handles signals.
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Essentially, it is and in this circuit since we are applying same voltage here and here v with same polarity. In that case this node of course, it is remaining high impedance or rather I should say degenerated node. So, we do have this resistored remaining there and it is degenerating the circuit and this gain as you have discussed before it will be the gain of this circuit which is getting degenerated by r or if I split the circuit it will be rather 2 r.
The common mode gain can be calculated assuming the applied voltage at both inputs remains the same. When the resistors are present, they provide degenerative feedback that reduces gain. Therefore, we can quantify the common mode gain by considering this degeneration, typically leading to a scenario where the effective impedance doubles, resulting in a lower gain overall. Essentially, it can be represented as the output gain of the circuit modified by the presence of the load resistors.
Imagine a playground swing where pushing with both hands (the inputs) creates oscillating motion, but only caring about the swings' sideways movements instead of pushing evenly. This uneven push leads to the swing amplifying side-to-side rather than up and down, somewhat similar to how the amplifier behaves with common mode signals.
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So, the corresponding gain here it is g Γ so that is the impedance here divided by 1 + g (2r ). In fact, after removing this 1 you can remove this g also, so that gives us a common mode gain = . In fact, g it is given to us and also yeah so it is becoming this is . So, that gives us how much 26 Γ 10β5.
The formula derived illustrates a relationship where the common mode gain reduces relative to the total impedance present thanks to the feedback offered by the resistors. Simplifying the calculations allows us to find that the common mode gain approximates to a low value (in this case, 26 Γ 10^-5), indicating that the circuit is well-designed to favor differential signals over common mode signals.
Picture a wind turbine designed to generate energy from wind against the resistance of the tower (representing common signals). The turbine is optimized to turn only by capturing wind from a particular direction (the desired signal), minimizing energy loss from any other directions (common signals), thus efficiently focusing on what truly matters.
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Key Concepts
Differential Mode Gain: Reflects how much a differential amplifier can magnify the difference between two input signals.
Common Mode Gain: The unwanted amplification of signals common to both inputs, ideally minimized for effective operation.
Transconductance: A crucial parameter in amplifiers, indicating how well the device can convert input voltage variations into output current changes.
See how the concepts apply in real-world scenarios to understand their practical implications.
In a differential amplifier using a current mirror, if the input voltages are V1 = 2V and V2 = 1V, the differential output would be scaled based on the gain settings and resistances connected.
Using a BJT configuration, if the base-emitter voltage is 0.7V and the collector current is set at 1mA, the small-signal transconductance can be calculated as gm = Ic/Vt, where Vt is the thermal voltage (approximately 25mV at room temperature).
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In a circuit with a mirror so bright, currents match just right; keep the common noise away, let the difference in signals play.
Imagine two singers, each with a microphone, amplifying only their unique voices while drowning out a common noise - that's like a differential amplifier rejecting common inputs!
Remember 'CMA-L' for Common Mode Amplifier - Low, a reminder that we want a low common mode gain.
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Review the Definitions for terms.
Term: Differential Amplifier
Definition:
An electronic amplifier that amplifies the difference between two input signals while rejecting any signals that are common to both inputs.
Term: Common Mode Gain
Definition:
The gain of a differential amplifier with common signals at both inputs, ideally minimized for better performance.
Term: Transconductance
Definition:
The ratio of the change in output current to the change in input voltage, indicative of amplifier gain.
Term: Current Mirror
Definition:
A circuit configuration that allows one current to be controlled by another current, functioning to replicate or βmirrorβ the current in another part of the circuit.
Term: Active Load
Definition:
A load in a circuit that actively controls the current flowing through it, often used for better performance in amplifiers.