Example of Differential Amplifier with Current Mirror - 89.2.1 | 89. Numerical examples on current mirror and its applications (Part-D) | Analog Electronic Circuits - Vol 4
K12 Students

Academics

AI-Powered learning for Grades 8–12, aligned with major Indian and international curricula.

Academics
Professionals

Professional Courses

Industry-relevant training in Business, Technology, and Design to help professionals and graduates upskill for real-world careers.

Professional Courses
Games

Interactive Games

Fun, engaging games to boost memory, math fluency, typing speed, and English skillsβ€”perfect for learners of all ages.

games

Interactive Audio Lesson

Listen to a student-teacher conversation explaining the topic in a relatable way.

Introduction to Differential Amplifiers

Unlock Audio Lesson

Signup and Enroll to the course for listening the Audio Lesson

0:00
Teacher
Teacher

Today, we will explore differential amplifiers. Who can tell me what a differential amplifier does?

Student 1
Student 1

It amplifies the difference between two input signals.

Teacher
Teacher

Great! And what might be a reason to use a current mirror in this context?

Student 2
Student 2

To maintain current balance without needing external biasing.

Teacher
Teacher

Exactly! This allows for more efficient circuit designs. Remember, a current mirror can mirror current to another transistor based on the reference current it receives.

Student 3
Student 3

So, it keeps the currents equal, right?

Teacher
Teacher

Exactly! That's key for maintaining balance in our amplifier. Let’s sum this up: 'A differential amplifier compares and amplifies variations between two input signals while a current mirror ensures consistent biasing.'

Calculating DC Currents in Transistors

Unlock Audio Lesson

Signup and Enroll to the course for listening the Audio Lesson

0:00
Teacher
Teacher

Now, let’s move to calculating DC currents. What was the given resistor value?

Student 4
Student 4

It was 11.4 kΞ©.

Teacher
Teacher

Correct! Given that, what current do we expect to flow through this resistor?

Student 1
Student 1

1 mA.

Teacher
Teacher

Right. Since we have a balanced input, this current is equally split. How much current flows through each transistor?

Student 2
Student 2

0.5 mA through each.

Teacher
Teacher

Exactly. Remember, for balanced operation, we need equal currents in both branches. Let’s jot down: 'Balance in differential amplifiers is crucial for output accuracy.'

Understanding Gain Calculations

Unlock Audio Lesson

Signup and Enroll to the course for listening the Audio Lesson

0:00
Teacher
Teacher

Next, let’s calculate the differential and common mode gains. Who remembers the key components?

Student 3
Student 3

We need to consider the small signal models and resistor values.

Teacher
Teacher

Correct! We model only small signal resistances in our analysis. Can you describe how we differentiate the gains?

Student 4
Student 4

Differential mode gain is based on the difference in signals, while common mode gain is when both inputs see the same voltage.

Teacher
Teacher

Exactly! And why do we want a high differential gain and a low common mode gain?

Student 1
Student 1

To improve signal integrity and reduce noise in the output!

Teacher
Teacher

Well done! Remember, the goal of pairing these gains is to have a robust amplifier design. 'High differential and low common mode gains lead to better performance.'

Introduction & Overview

Read a summary of the section's main ideas. Choose from Basic, Medium, or Detailed.

Quick Overview

This section explores the operation of a differential amplifier utilizing a current mirror, specifically focusing on DC current mirroring and the analysis of differential and common mode gains.

Standard

The section provides an in-depth examination of how a differential amplifier's efficiency can be enhanced using a current mirror, detailing the calculations for DC currents, differential mode gain, and common mode gain. The significance of balancing currents in transistors and the implications for amplifier performance are also discussed.

Detailed

In this section, we study the example of a differential amplifier that employs a current mirror as an active load. The primary focus is on how transistor arrangements facilitate current mirroring, ensuring balance in operating conditions with minimal external biasing requirements. Starting with a given resistor value, we calculate DC currents through the transistors, confirming that the currents through the current mirrors match the expected values. The subsequent analysis shifts to small signal models to derive differential and common mode gains, characterized by the relationships established through resistor values and transconductance. We also observe the implications of early voltage on gain calculations. The significance of distinguishing between differential and common mode gains is highlighted, especially in the context of maintaining a high differential gain while minimizing common mode gain, ultimately leading to better amplifier performance in real applications.

Youtube Videos

Analog Electronic Circuits _ by Prof. Shanthi Pavan
Analog Electronic Circuits _ by Prof. Shanthi Pavan

Audio Book

Dive deep into the subject with an immersive audiobook experience.

Introduction to Differential Amplifier with Current Mirror

Unlock Audio Book

Signup and Enroll to the course for listening the Audio Book

Yeah. Welcome back to our next example. So here we do have the differential amplifier and the load of course, it is active load, but internally we do have current mirror. So, what we are expecting here is transistor-7 DC wise it will be mirroring its own DC current into transistor-8 and that is good.

Detailed Explanation

In this introduction, we learn about a differential amplifier that has an active load and uses a current mirror. The key feature is that transistor-7 keeps its DC current consistent, which is mirrored to transistor-8. This mirroring is important for the balance and efficiency of the circuit.

Examples & Analogies

Think of a group of people running a relay race. Each runner (transistor) has to pass the baton (current) to the next runner while maintaining their speed (current value). The better they mirror each other's speeds, the smoother the race will be.

Current Mirroring in Action

Unlock Audio Book

Signup and Enroll to the course for listening the Audio Book

In fact, we want this current should also be the same as the one from a balance point of view. So, we do not have to put any external circuit to bias here and in addition to that, this transistor-7 may also mirror signal current, in case if we have say g_v current coming here at the collector.

Detailed Explanation

The goal of current mirroring is to maintain a stable operating point without needing additional circuitry for biasing. Furthermore, transistor-7 does not only mirror the DC current, it can also adapt to signal currents, which enables the amplifier to function dynamically.

Examples & Analogies

Imagine two musicians playing in harmony. If one adjusts their volume based on the music's dynamics (like the signal current), the other musician can adjust similarly, creating a balanced performance without additional adjustments.

Calculating Transistor Currents

Unlock Audio Book

Signup and Enroll to the course for listening the Audio Book

So to start with, we do have to find the DC currents through all the transistors. Again the value of this resistor is 11.4 k, so that makes this current = 1 mA.

Detailed Explanation

Calculating DC currents involves analyzing resistor values and applying Ohm's law. With a resistor valued at 11.4 kΞ©, the current flowing through the circuit is determined to be 1 mA. This current level is crucial for the functionality of the amplifier.

Examples & Analogies

Think of a water system where the resistor acts like a valve controlling water flow. By adjusting the valve (resistor), you can ensure just the right amount of water (current) flows through to keep everything running smoothly.

Voltage at Junctions

Unlock Audio Book

Signup and Enroll to the course for listening the Audio Book

So, the voltage here is decided by the 12 V β€’ 0.6 V, so the voltage here is 11.4 V. In fact, it can be shown that the DC voltage at this point, assuming Q1, Q2, Q7, Q8 are identical, is also 11.4 V.

Detailed Explanation

The effective voltage at certain points in the circuit is determined by the supply voltage minus any drops due to components (like the 0.6 V drop across a transistor). Assuming all transistors are identical, the same voltage will be present across them, allowing uniform performance.

Examples & Analogies

Consider how a team uniform affects the players' performance on a field. If everyone wears the same uniform (identical transistors), they can work together seamlessly, resulting in better teamwork and efficiency.

Differential Mode Gain Calculation

Unlock Audio Book

Signup and Enroll to the course for listening the Audio Book

So now our next calculation is to find differential mode gain and common mode gain.

Detailed Explanation

Differential mode gain is a measure of how well the amplifier reacts to signals differing between its two inputs. This calculation helps evaluate how effectively the circuit amplifies the desired signals compared to any unwanted noise.

Examples & Analogies

Imagine a microphone that captures sound from two different instruments. The differential mode gain helps the sound engineer determine how well they can amplify the desired music signal while minimizing background noise.

Summary of Differential and Common Mode Gains

Unlock Audio Book

Signup and Enroll to the course for listening the Audio Book

So, in summary, now to analyze this circuit we can just simplify and say that this resistance is r_o8. The common mode gain essentially is very small.

Detailed Explanation

This part summarizes that the common mode gain is kept very low compared to the differential gain, thus ensuring better performance of the amplifier in processing desired signals while reducing the impact of noise and other unwanted signals.

Examples & Analogies

Think of how a spotlight focuses on a performer on stage (differential gain) while the rest of the stage is dim (common mode gain). By minimizing the unnecessary light on the background, the audience focuses exclusively on the performance.

Definitions & Key Concepts

Learn essential terms and foundational ideas that form the basis of the topic.

Key Concepts

  • Current Mirror: A mechanism that mirrors current between transistors maintaining balance.

  • DC Current: The steady current that flows through the amplifier's components.

  • Differential Mode Gain: Gain derived from the difference between two input signals.

  • Common Mode Gain: Gain derived from common signals present on both inputs.

Examples & Real-Life Applications

See how the concepts apply in real-world scenarios to understand their practical implications.

Examples

  • Example of calculating differential mode gain for a given resistor value and current.

  • Example illustrating the role of transistor-7 and transistor-8 in current mirroring.

Memory Aids

Use mnemonics, acronyms, or visual cues to help remember key information more easily.

🎡 Rhymes Time

  • Differential gain, a signal's reign; Common's low, it's quite the show.

πŸ“– Fascinating Stories

  • Imagine two friends at a distance comparing notes (differential signal) while another rises or lowers the lights (common signal) in their classroom. The focus on the notes ensures clarity despite the lighting around them.

🧠 Other Memory Gems

  • For gains, remember: 'D for Differential (D), C for Common (C)'.

🎯 Super Acronyms

DCG - 'Differential Current Gain' for remembering key concepts.

Flash Cards

Review key concepts with flashcards.

Glossary of Terms

Review the Definitions for terms.

  • Term: Differential Amplifier

    Definition:

    An amplifier that amplifies the difference between two input signals.

  • Term: Current Mirror

    Definition:

    A circuit that generates a current identical to a reference current, aiding in bias stabilization.

  • Term: DC Current

    Definition:

    The constant flow of electric charge, having fixed magnitude and direction.

  • Term: Differential Mode Gain

    Definition:

    The gain experienced by the differential signals applied to the amplifier's inputs.

  • Term: Common Mode Gain

    Definition:

    The gain experienced by signals common to both inputs of a differential amplifier.