89.2.1 - Example of Differential Amplifier with Current Mirror
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Introduction to Differential Amplifiers
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Today, we will explore differential amplifiers. Who can tell me what a differential amplifier does?
It amplifies the difference between two input signals.
Great! And what might be a reason to use a current mirror in this context?
To maintain current balance without needing external biasing.
Exactly! This allows for more efficient circuit designs. Remember, a current mirror can mirror current to another transistor based on the reference current it receives.
So, it keeps the currents equal, right?
Exactly! That's key for maintaining balance in our amplifier. Let’s sum this up: 'A differential amplifier compares and amplifies variations between two input signals while a current mirror ensures consistent biasing.'
Calculating DC Currents in Transistors
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Now, let’s move to calculating DC currents. What was the given resistor value?
It was 11.4 kΩ.
Correct! Given that, what current do we expect to flow through this resistor?
1 mA.
Right. Since we have a balanced input, this current is equally split. How much current flows through each transistor?
0.5 mA through each.
Exactly. Remember, for balanced operation, we need equal currents in both branches. Let’s jot down: 'Balance in differential amplifiers is crucial for output accuracy.'
Understanding Gain Calculations
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Next, let’s calculate the differential and common mode gains. Who remembers the key components?
We need to consider the small signal models and resistor values.
Correct! We model only small signal resistances in our analysis. Can you describe how we differentiate the gains?
Differential mode gain is based on the difference in signals, while common mode gain is when both inputs see the same voltage.
Exactly! And why do we want a high differential gain and a low common mode gain?
To improve signal integrity and reduce noise in the output!
Well done! Remember, the goal of pairing these gains is to have a robust amplifier design. 'High differential and low common mode gains lead to better performance.'
Introduction & Overview
Read summaries of the section's main ideas at different levels of detail.
Quick Overview
Standard
The section provides an in-depth examination of how a differential amplifier's efficiency can be enhanced using a current mirror, detailing the calculations for DC currents, differential mode gain, and common mode gain. The significance of balancing currents in transistors and the implications for amplifier performance are also discussed.
Detailed
In this section, we study the example of a differential amplifier that employs a current mirror as an active load. The primary focus is on how transistor arrangements facilitate current mirroring, ensuring balance in operating conditions with minimal external biasing requirements. Starting with a given resistor value, we calculate DC currents through the transistors, confirming that the currents through the current mirrors match the expected values. The subsequent analysis shifts to small signal models to derive differential and common mode gains, characterized by the relationships established through resistor values and transconductance. We also observe the implications of early voltage on gain calculations. The significance of distinguishing between differential and common mode gains is highlighted, especially in the context of maintaining a high differential gain while minimizing common mode gain, ultimately leading to better amplifier performance in real applications.
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Introduction to Differential Amplifier with Current Mirror
Chapter 1 of 6
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Chapter Content
Yeah. Welcome back to our next example. So here we do have the differential amplifier and the load of course, it is active load, but internally we do have current mirror. So, what we are expecting here is transistor-7 DC wise it will be mirroring its own DC current into transistor-8 and that is good.
Detailed Explanation
In this introduction, we learn about a differential amplifier that has an active load and uses a current mirror. The key feature is that transistor-7 keeps its DC current consistent, which is mirrored to transistor-8. This mirroring is important for the balance and efficiency of the circuit.
Examples & Analogies
Think of a group of people running a relay race. Each runner (transistor) has to pass the baton (current) to the next runner while maintaining their speed (current value). The better they mirror each other's speeds, the smoother the race will be.
Current Mirroring in Action
Chapter 2 of 6
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Chapter Content
In fact, we want this current should also be the same as the one from a balance point of view. So, we do not have to put any external circuit to bias here and in addition to that, this transistor-7 may also mirror signal current, in case if we have say g_v current coming here at the collector.
Detailed Explanation
The goal of current mirroring is to maintain a stable operating point without needing additional circuitry for biasing. Furthermore, transistor-7 does not only mirror the DC current, it can also adapt to signal currents, which enables the amplifier to function dynamically.
Examples & Analogies
Imagine two musicians playing in harmony. If one adjusts their volume based on the music's dynamics (like the signal current), the other musician can adjust similarly, creating a balanced performance without additional adjustments.
Calculating Transistor Currents
Chapter 3 of 6
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Chapter Content
So to start with, we do have to find the DC currents through all the transistors. Again the value of this resistor is 11.4 k, so that makes this current = 1 mA.
Detailed Explanation
Calculating DC currents involves analyzing resistor values and applying Ohm's law. With a resistor valued at 11.4 kΩ, the current flowing through the circuit is determined to be 1 mA. This current level is crucial for the functionality of the amplifier.
Examples & Analogies
Think of a water system where the resistor acts like a valve controlling water flow. By adjusting the valve (resistor), you can ensure just the right amount of water (current) flows through to keep everything running smoothly.
Voltage at Junctions
Chapter 4 of 6
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Chapter Content
So, the voltage here is decided by the 12 V ‒ 0.6 V, so the voltage here is 11.4 V. In fact, it can be shown that the DC voltage at this point, assuming Q1, Q2, Q7, Q8 are identical, is also 11.4 V.
Detailed Explanation
The effective voltage at certain points in the circuit is determined by the supply voltage minus any drops due to components (like the 0.6 V drop across a transistor). Assuming all transistors are identical, the same voltage will be present across them, allowing uniform performance.
Examples & Analogies
Consider how a team uniform affects the players' performance on a field. If everyone wears the same uniform (identical transistors), they can work together seamlessly, resulting in better teamwork and efficiency.
Differential Mode Gain Calculation
Chapter 5 of 6
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Chapter Content
So now our next calculation is to find differential mode gain and common mode gain.
Detailed Explanation
Differential mode gain is a measure of how well the amplifier reacts to signals differing between its two inputs. This calculation helps evaluate how effectively the circuit amplifies the desired signals compared to any unwanted noise.
Examples & Analogies
Imagine a microphone that captures sound from two different instruments. The differential mode gain helps the sound engineer determine how well they can amplify the desired music signal while minimizing background noise.
Summary of Differential and Common Mode Gains
Chapter 6 of 6
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Chapter Content
So, in summary, now to analyze this circuit we can just simplify and say that this resistance is r_o8. The common mode gain essentially is very small.
Detailed Explanation
This part summarizes that the common mode gain is kept very low compared to the differential gain, thus ensuring better performance of the amplifier in processing desired signals while reducing the impact of noise and other unwanted signals.
Examples & Analogies
Think of how a spotlight focuses on a performer on stage (differential gain) while the rest of the stage is dim (common mode gain). By minimizing the unnecessary light on the background, the audience focuses exclusively on the performance.
Key Concepts
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Current Mirror: A mechanism that mirrors current between transistors maintaining balance.
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DC Current: The steady current that flows through the amplifier's components.
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Differential Mode Gain: Gain derived from the difference between two input signals.
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Common Mode Gain: Gain derived from common signals present on both inputs.
Examples & Applications
Example of calculating differential mode gain for a given resistor value and current.
Example illustrating the role of transistor-7 and transistor-8 in current mirroring.
Memory Aids
Interactive tools to help you remember key concepts
Rhymes
Differential gain, a signal's reign; Common's low, it's quite the show.
Stories
Imagine two friends at a distance comparing notes (differential signal) while another rises or lowers the lights (common signal) in their classroom. The focus on the notes ensures clarity despite the lighting around them.
Memory Tools
For gains, remember: 'D for Differential (D), C for Common (C)'.
Acronyms
DCG - 'Differential Current Gain' for remembering key concepts.
Flash Cards
Glossary
- Differential Amplifier
An amplifier that amplifies the difference between two input signals.
- Current Mirror
A circuit that generates a current identical to a reference current, aiding in bias stabilization.
- DC Current
The constant flow of electric charge, having fixed magnitude and direction.
- Differential Mode Gain
The gain experienced by the differential signals applied to the amplifier's inputs.
- Common Mode Gain
The gain experienced by signals common to both inputs of a differential amplifier.
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