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Today we'll be solving logarithmic equations. To begin, who can tell me the relationship between logarithms and exponents?
Logarithms are the opposite of exponents!
Correct! If we have \( log_a(b) = c \), it means \( a^c = b \). This is important for solving equations. What would be our first step to solve \( log_x = 2 \)?
We can convert it to exponential form, so it becomes \( x = 10^2 \).
Exactly! This gives us the solution \( x = 100 \). Remember, converting to exponential form is key in solving these problems.
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Let's try an equation: \( log(x+2) = 1 \). Who wants to solve it?
We convert it to exponential, so it's \( x + 2 = 10^1 \), which means \( x + 2 = 10 \).
Great! What do we do next?
We subtract 2 from both sides to find \( x = 8 \).
Perfect! This application of logarithms allows us to solve equations step by step.
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Now, let's address a more complex example: \( log(x) + log(x-3) = 1 \). How can we simplify this?
We can use the product rule to combine the logs into one: \( log[x(x-3)] = 1 \).
Exactly! What does this conversion tell us?
It means \( x(x-3) = 10^1 \) or \( x^2 - 3x - 10 = 0 \).
Bingo! Now we solve the quadratic. Remember to check for valid solutions.
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Lastly, after solving, why do we need to check our solutions?
To make sure that the values we find make the logarithms valid!
Exactly! Since logarithms must have positive arguments, any invalid solutions will be excluded from our final answers.
So, we only keep valid answers!
Correct! Remember, valid arguments are key to logarithmic equations.
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In this section, students learn how to solve logarithmic equations by converting them into exponential form. Key examples illustrate methods for solving equations using logarithmic properties and rules, reinforcing the understanding of logarithms in mathematical contexts.
This section addresses the fundamental techniques for solving logarithmic equations. Each equation can often be simplified by converting from logarithmic form to exponential form, facilitating easier manipulation. The section introduces key examples that demonstrate this conversion and the application of logarithmic laws.
The section concludes with practice exercises to solidify the concepts and prepare students for real-world applications.
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🔹 Example 1:
Solve: log 𝑥 = 5
→ Convert to exponential form:
𝑥 = 25 = 32
In this example, we start with the logarithmic equation: log 𝑥 = 5. To solve for 𝑥, we need to rewrite the equation in its exponential form. The notation 'log 𝑥 = 5' tells us that 𝑥 is the number we get when we raise the base (which is 10, if not specified) to the power of 5. This means:
Think of logarithmic functions like a special kind of detective story where you are looking for missing information. Just like detectives have their clues (the logs), they have to convert the information into a different form to figure out what happened. In solving our equation 𝑥 = 10^5, it's like uncovering a clue that reveals how 'large' our answer is. The larger the exponent, like 5 in this case, the bigger the mystery unfolds because we realize we're dealing with a very large number!
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🔹 Example 2:
Solve: log (𝑥+1) = 2
→ 𝑥+1 = 32 = 9
→ 𝑥 = 8
For this example, we start with log (𝑥 + 1) = 2. To solve for 𝑥, we convert the logarithmic statement to exponential form. It tells us that:
- 𝑥 + 1 = 10^2,
- Which simplifies to 𝑥 + 1 = 100.
- Now, we can solve for 𝑥 by subtracting 1 from both sides:
- 𝑥 = 100 - 1,
- Thus, 𝑥 = 99. This is an application of using logarithms to find values that are represented in a different way.
Imagine you are accumulating points in a video game, and needing to reach a certain level. The game level requirement states that you need to collect 10^2 or 100 experience points to level up. This problem resembles how we worked through our equation by determining how much more you needed to achieve a level by simplifying what you had (the +1), ultimately determining your exact score needed to achieve that great transformation into the next level!
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🔹 Example 3:
Solve: log𝑥 + log(𝑥 − 3) = 1
Use product rule:
log[𝑥(𝑥−3)] = 1
→ 𝑥(𝑥−3) = 10^1 = 10
→ 𝑥^2 − 3𝑥 − 10 = 0
→ Solve quadratic: (𝑥−5)(𝑥+2) = 0
→ 𝑥 = 5 or 𝑥 = −2
But 𝑥 = −2 is not valid (log of negative number is undefined),
Final answer: 𝑥 = 5
In this example, we have two logarithmic terms combined: log𝑥 + log(𝑥 − 3) = 1. To solve this, we can utilize the product rule of logarithms, which states that the sum of logs is the log of the product of those numbers. By applying this rule, we write:
- log[𝑥(𝑥−3)] = 1.
Next, we convert this back to exponential form:
- 𝑥(𝑥−3) = 10^1, which simplifies to 𝑥(𝑥−3) = 10.
- This leads us to the quadratic equation: 𝑥^2 − 3𝑥 − 10 = 0.
- Solving the quadratic gives us two potential solutions: 𝑥 = 5 or 𝑥 = −2. However, we must discard 𝑥 = −2 because logarithms cannot take a negative input. Thus, the valid solution is 𝑥 = 5.
Consider an instance where you're mixing two ingredients to achieve a specific flavor (like the terms log𝑥 and log(𝑥−3)). The total desired outcome (1) can be thought of as the result of combining those ingredients. If we think of each part (the logs) representing a recipe ratio, applying the product rule helps ensure the correct balance is achieved in the cooking process. Thus, our final solution (5) represents a perfectly balanced flavor, while any negative mixing (like -2) would spoil the dish and is not acceptable!
Learn essential terms and foundational ideas that form the basis of the topic.
Key Concepts
Exponential Conversion: Understanding that if
\( log_a(b) = c \), then this translates to \( a^c = b \), simplifying the solution process.
Application of Log Rules: Using the product, quotient, and power rules to manage complex logarithmic expressions.
The section concludes with practice exercises to solidify the concepts and prepare students for real-world applications.
See how the concepts apply in real-world scenarios to understand their practical implications.
Solve \( log(x) = 2 \): Convert to exponential \( x = 10^2 = 100 \).
Solve \( log(x+1) = 2 \): Convert to \( x+1 = 10^2 = 100 \) leading to \( x = 99 \).
Use mnemonics, acronyms, or visual cues to help remember key information more easily.
Logarithm, don't be grim, to the base we climb, till we find what we seek dimes.
Imagine a treasure map where 'x' represents the treasure’s location. Logarithms help us find where to dig by converting secrets into clear paths!
Remember LOG: L - Look for positive arguments, O - Observe the base, G - Grab the solution after solving!
Review key concepts with flashcards.
Review the Definitions for terms.
Term: Logarithm
Definition:
The power to which a base must be raised to produce a given number.
Term: Exponential Form
Definition:
The representation of a logarithm in the form \( a^c = b \).
Term: Product Rule
Definition:
A logarithmic rule stating that \( log_a(mn) = log_a(m) + log_a(n) \).
Term: Quotient Rule
Definition:
A logarithmic rule stating that \( log_a(m/n) = log_a(m) - log_a(n) \).
Term: Power Rule
Definition:
A logarithmic rule stating that \( log_a(m^k) = k \cdot log_a(m) \).