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Good morning, class! Today, we're going to explore linear equations with variables on both sides. Can anyone remind me what a linear equation is?
Isn't it an equation where the highest power of the variable is 1?
Yes, like y = 2x + 5!
Exactly! Now, when we have variables on both sides, the goal is to isolate the variable. What do you think is the first step?
Maybe move all variable terms to one side?
Right! So if we have something like 6x + 5 = 2x + 13, we can subtract 2x from both sides. Can someone do that for me?
Sure! That gives us 4x + 5 = 13.
Great job! Now, can we solve for x?
Yes! We subtract 5 from both sides to get 4x = 8.
Exactly! What do we do next?
Divide by 4 to find x equals 2!
Perfect! Always remember to check your answer by plugging it back in to see if both sides are equal.
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Letโs take another example, 3 - 2y = 7y + 12. Whatโs our first move?
We can add 2y to both sides to get 3 = 9y + 12!
Exactly! Then what do you think we do next?
Subtract 12 from both sides to simplify it further.
Yes, so now we have -9 = 9y. Who can tell me what the final step is?
Divide both sides by 9, which gives us y = -1.
Fantastic! Always remember to use inverse operations to isolate the variable. How can we check our answer?
Plugging -1 back into the original equation to see if both sides match.
Correct! Checking helps us verify our solution.
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Letโs tackle a more complex equation: 5m + 1 = 2m + 10. Whatโs our strategy?
We should start by moving 2m to the left side!
Correct! What does that give us?
It gives us 3m + 1 = 10.
And then whatโs the next step?
Subtract 1 from both sides to get 3m = 9.
Exactly! So how do we isolate m now?
Divide by 3, so m = 3!
Great job! How can we ensure our answer is correct?
Substituting 3 back into the original equation!
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Now that we've gone through the steps, letโs practice with some group exercises. Start with the equation: 4k - 7 = 9k + 3. Whatโs the first step?
We should move the variable terms to one side, so let's subtract 4k.
Good thinking! What does that result in?
The equation becomes -7 = 5k + 3.
Now what?
Subtract 3 from both sides to get -10 = 5k.
Exactly! And how do we find k now?
We can divide both sides by 5 to get k = -2!
Excellent work! Practice makes perfect, and remember to check your solutions after solving.
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In this section, students learn to solve linear equations that include variables on both sides. The process involves rearranging the equation to gather all variable terms on one side and constant terms on the other, followed by using inverse operations to isolate the variable.
This section focuses on solving linear equations where the unknown variable appears on both sides of the equation. The main objective is to isolate the variable to determine its value.
Understanding how to solve such equations is crucial as it lays the groundwork for more complex algebraic problem-solving. It emphasizes the importance of balancing equations and critical thinking in mathematical reasoning.
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The key here is to gather all variable terms on one side of the equation and all constant terms on the other.
When solving linear equations that have variables on both sides, the first step is to isolate the variable by rearranging the equation. This means you should move all terms that contain the variable to one side of the equals sign and all constant terms to the other side. This helps you focus on solving for the variable without any confusion from the constants.
Think of it like balancing a scale - if you add or remove weight from one side, you have to do the same to the other side to keep it balanced. If you're trying to find out how much weight is on each leg of the scale, you need to know exactly how much is contributing to each side.
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Example 1: Positive variable terms Solve: 6x + 5 = 2x + 13
To solve the equation 6x + 5 = 2x + 13, start by isolating the variable terms. First, subtract 2x from both sides to get 4x + 5 = 13. Next, subtract 5 from both sides, resulting in 4x = 8. Finally, divide both sides by 4 to find that x = 2. Checking this gives you 6(2) + 5 = 17 and 2(2) + 13 = 17, confirming the solution is valid.
Imagine you have a jar with some candies that you want to share. If you have 6 candies in one pile and others in smaller piles, the total should equal the sum of the smaller piles after adjusting how many you take from which pile. Your goal is to find out how many candies you have in certain piles (the variables), while keeping track of the others (the constants).
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Example 2: Negative variable terms Solve: 3 - 2y = 7y + 12
To solve the equation 3 - 2y = 7y + 12, start by moving the variables to one side. Add 2y to both sides, leaving you with 3 = 9y + 12. Next, get rid of the constant by subtracting 12 from both sides, resulting in -9 = 9y. Finally, divide both sides by 9 to find y = -1. To check, substitute -1 back into the equation and confirm that both sides equal the same value.
Consider a situation where you are measuring different amounts of liquid in two containers. If container A starts with 3 liters but you pour out and add to container B at the same time, the challenge is to determine how much liquid is in each container at any time. The equation helps to track your pours in and out, aiming for a balance between what goes in and out.
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Practice Problems 3.4:
1. Solve: 5m + 1 = 2m + 10
2. Solve: 4k - 7 = 9k + 3
3. Solve: 10 - 3p = p + 2
The practice problems encourage you to apply what you've learned about isolating variables and solving for them. Start with each equation, rearranging terms to create a form where you can find the value of the variable easily. Here, you're putting into practice the steps of moving variable terms to one side and constants to the other.
Imagine working on a project where you need to allocate resourcesโlike spending a budget of $10 among various activities. Each problem equates to figuring out how to balance your budget against the activities you want to fund, much like balancing the equations to arrive at a specific number.
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Key Concepts
Isolating the Variable: The process of getting the variable by itself on one side of the equation.
Inverse Operations: Mathematical operations that reverse the effect of each other, necessary for solving equations.
Verification: Checking the solution by substituting back into the original equation.
See how the concepts apply in real-world scenarios to understand their practical implications.
Example 1: For the equation 6x + 5 = 2x + 13, isolating the variable gives x = 2.
Example 2: Moving variables and isolating gives us y = -1 in the equation 3 - 2y = 7y + 12.
Use mnemonics, acronyms, or visual cues to help remember key information more easily.
To solve with a twist, move terms to the left, inverse is key, keep it cleft!
Imagine a treasure hunt where you need to isolate the treasure (variable) from obstacles (constants) by moving step by step!
I.S.O.L.A.T.E - Isolate, Shift, Operate, Leave alone, Answer, Verify, End!
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Review the Definitions for terms.
Term: Linear Equation
Definition:
An algebraic equation where the highest exponent of the variable is 1.
Term: Isolate
Definition:
To get one variable alone on one side of the equation.
Term: Inverse Operations
Definition:
Operations that undo each other, such as addition and subtraction or multiplication and division.
Term: Check the Solution
Definition:
Plugging the value of the variable back into the original equation to verify correctness.