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Today, we're introducing two-step linear equations. These are equations requiring two operations to solve. Can anyone tell me what that means?
Does that mean we have to do two different things to isolate the variable?
Exactly! For instance, in the equation 2x + 3 = 11, we first need to undo the addition before we can isolate 'x' by using its inverse operation.
What's the inverse operation for addition?
Great question! The inverse operation for addition is subtraction! So we would subtract 3 from both sides of the equation.
Wouldn't that change the equation?
Not at all! Remember, whatever we do to one side, we must do to the other to keep it balanced. Shall we try an example together?
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Let's solve the equation 2x + 3 = 11 step by step. Who can tell me the first step?
We subtract 3 from both sides, right?
Correct! That gives us 2x = 8. Now what do we do next?
Now we divide both sides by 2.
Exactly! Dividing gives us x = 4. Remember to check your work by plugging it back in to see if it holds true!
So we replace x with 4 in the original equation, and it should equal 11?
Yes! You all have grasped the concept well. Now let's practice some together.
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Let's try another equation: 3y - 7 = 8. What do we do first?
We add 7 to both sides.
Correct! That leaves us with 3y = 15. And now?
Divide both sides by 3!
Well done! So we find that y = 5. Anyone want to try solving one?
Can we solve 2x - 4 = 10?
Yes, go for it!
I add 4 to both sides which gives 2x = 14. Then I divide by 2, and I get x = 7.
Fantastic! You all are getting the hang of it.
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Now let's do some practice problems together. First up, let's simplify: 3m - 7 = 8.
We add 7 to both sides to get 3m = 15!
Right! What's next?
Then we divide by 3 to find m = 5.
Excellent! Remember, practice is essential to mastering these skills. Keep practicing!
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In this section, we explore the process of solving two-step linear equations by applying inverse operations to isolate the variable. Through examples and practice problems, students learn the systematic approach for handling both addition/subtraction and multiplication/division in equations, ensuring a solid conceptual understanding.
In this section, we delve deeper into solving two-step linear equations, which involve two operations applied to the variable. The fundamental concept of this process is the use of inverse operations to isolate the variable on one side of the equation. This ensures that students can efficiently solve equations of the form a + b = c
or a * b = c
by systematically undoing operations in reverse order.
Key Concepts:
1. Inverse Operations: The concept of performing the opposite operation to simplify equations is crucial. Examples are addition and subtraction or multiplication and division.
2. Stepwise Process: The typical approach is to first eliminate any addition or subtraction, followed by division or multiplication, ensuring the equation remains balanced throughout.
3. Check Your Work: Students practice validating their solution by plugging it back into the original equation, ensuring it maintains equality.
4. Practice Problems: Various practice scenarios help students apply their knowledge, hone their skills, and become proficient in solving a variety of two-step equations.
This section lays a strong foundation for the upcoming discussion of more complex algebraic equations, reinforcing problem-solving strategies that are applicable across different mathematical contexts.
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These equations involve two operations. We generally undo addition/subtraction first, then multiplication/division.
Two-step linear equations require you to perform two different operations to isolate the variable. The common approach is to first address any addition or subtraction and then deal with multiplication or division. This allows us to simplify the equation step-by-step until we find the value of the variable.
Imagine you are trying to find out how much money you need to save to buy a video game that costs $50. You have saved $20 already. If we represent the amount you still need to save as 'x', we can write the equation: x + 20 = 50. First, you would figure out how much more money you need by subtracting the $20 from both sides, leading you to x = 30.
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Solve: 2x + 3 = 11
โ Step 1: Undo the addition. Subtract 3 from BOTH sides. 2x + 3 - 3 = 11 - 3
โ Step 2: Undo the multiplication. Divide BOTH sides by 2. 2x / 2 = 8 / 2
โ Result: x = 4
โ Check: 2(4) + 3 = 8 + 3 = 11 (True!)
In this example, we begin with the equation 2x + 3 = 11. The first step is to get rid of the constant term '3.' We do this by subtracting 3 from both sides, which leaves us with 2x = 8. Next, we isolate the variable 'x' by dividing both sides by 2. This leads us to the solution x = 4. To verify, we can substitute back into the original equation to make sure both sides are equal.
Consider that you're buying two packs of candy, and the total cost (including a $3 sales tax) is $11. By removing the sales tax first (subtracting), you find the cost of the two packs without the tax is $8. Dividing by 2 gives you the price of a single pack of candy, which is $4.
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Solve: (y / 4) - 1 = 2
โ Step 1: Undo the subtraction. Add 1 to BOTH sides. (y / 4) - 1 + 1 = 2 + 1
โ Step 2: Undo the division. Multiply BOTH sides by 4. (y / 4) * 4 = 3 * 4
โ Result: y = 12
โ Check: (12 / 4) - 1 = 3 - 1 = 2 (True!)
We start with the equation (y / 4) - 1 = 2. First, we need to eliminate the '-1' by adding 1 to both sides, resulting in (y / 4) = 3. Next, to get 'y' by itself, multiply both sides by 4, giving us y = 12. A quick check confirms our solution is correct.
Imagine you're sharing a pizza with friends. After eating, you realize that each person needs to eat one more slice to reach the full amount of pizza (2 slices each). From the total amount that was initially divided by 4 (the number of friends), adding back what was reduced lets you find the total slices each person originally had.
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These practice problems give you hands-on experience with two-step linear equations. The problems vary slightly, but the method remains the same: isolate the variable by first removing constants through addition or subtraction, and then dealing with any multiplication or division.
Think about planning a budget. Each problem tells a story of balancing income and expenses. For instance, in one problem, if you earned some money but also had expenses, solving for your net profit helps you see how much money you really have left to spend.
Learn essential terms and foundational ideas that form the basis of the topic.
Key Concepts
Inverse Operations: To solve two-step equations, use inverse operations like addition/subtraction or multiplication/division to isolate the variable.
Order of Operations: When solving, always handle addition/subtraction before multiplication/division to maintain balance.
Check Solutions: Always substitute your solution back into the original equation to ensure it is correct.
See how the concepts apply in real-world scenarios to understand their practical implications.
Example 1: Solve 2x + 3 = 11: Subtract 3 from both sides to get 2x = 8, then divide by 2 to find x = 4.
Example 2: Solve 3y - 7 = 8: Add 7 to both sides to get 3y = 15, then divide by 3 for y = 5.
Use mnemonics, acronyms, or visual cues to help remember key information more easily.
First, subtract, then divide; Easy steps you can't hide.
Imagine a detective searching for clues in a foggy alley. They must first uncover the mystery (subtract) before revealing the truth (divide) behind the case!
SIFT - Subtract, Inverse, Find, Then (isolate the variable).
Review key concepts with flashcards.
Review the Definitions for terms.
Term: TwoStep Linear Equation
Definition:
An equation that requires two operations to solve.
Term: Inverse Operation
Definition:
An operation that reverses the effect of another operation (e.g., addition is the inverse of subtraction).
Term: Isolate
Definition:
To get the variable alone on one side of the equation.
Term: Balanced Equation
Definition:
An equation where both sides are equal.