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Today, we'll start with how we convert vehicle weight into tons, which is essential for calculating rolling resistance. If the vehicle weighs, let's say, 50,000 kg, how do we convert that?
We divide by 1000, right? So it would be 50 tons?
Exactly! Good job! Converting to tons is necessary because the rolling resistance is generally expressed as kg per ton.
What’s the rolling resistance in our example?
For our haul route, it’s given as 28 kg per ton. So, what’s the total rolling resistance for 50 tons?
That would be 50 tons multiplied by 28 kg per ton, which equals 1400 kg.
Correct! That's a crucial step in understanding power needs.
Let's recap: Always start by converting weight to tons for rolling resistance calculations. Ready for the next part?
Now, let’s discuss penetration resistance. It depends on how deep the tires sink. For instance, if a tire sinks 6 cm into the ground, does anyone know how we can calculate that resistance?
Is it based on the depth times the resistance per ton?
Right! It’s 6 cm times 6 kg per ton per cm. Can anyone calculate that for 50 tons?
That would be 1800 kg!
Exactly! So the total resistance is rolling resistance plus penetration resistance. What’s our total?
That would be 1400 kg + 1800 kg, which equals 3200 kg total.
Great teamwork! Remember, the total resistance is vital for determining the necessary tractive effort.
Next, we need to consider grade resistance, which adds to the challenges when machines are climbing slopes. Can anyone tell me how this type of resistance works?
It increases the effort needed to pull the load, right? Especially on steep slopes.
Absolutely! The percentage of the slope dictates the additional force needed. For a 5% grade, what’s the requirement?
That would be 5% times 10 kg per ton. If our load is 50 tons, that’s 500 kg for grade resistance.
Exactly! Understanding how to calculate this is crucial for selecting the right haul route!
Finally, let’s discuss usable power. What is it, and how does it differ from the available power provided by manufacturers?
Usable power is the actual power available for work after considering resistance, while available power is what the manufacturer states.
Correct! And what factors affect the usable power?
Altitude and temperature can affect it since they determine how much power can be realized on site.
Excellent point! Understanding the differences ensures we select the right machinery for the conditions.
Now, let’s apply these principles to a problem. A tractor weighs 15 tons with a rolling resistance of 60 kg per ton on a 4% slope. How would we approach calculating the usable power?
First, we calculate the grade resistance, which is 4 times 10 kg per ton for that slope.
And then for rolling resistance, that gives us a total of 1500 kg when we add everything up.
Fantastic! After finding total resistance, what’s our next step?
We subtract that from the maximum rimpull to find usable power for towing the load!
Exactly! Applying our calculations to practical situations reinforces our understanding.
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The section explains the conversion of vehicle weight to tons, calculation of rolling resistance, penetration resistance, grade resistance, and the overall power required for a machine to operate effectively on different terrains.
In this section, we dive into how to accurately estimate power requirements necessary for machinery by considering key factors such as rolling resistance, penetration resistance, and grade resistance.
We start with converting the gross weight of the machine from kilograms to tons, where a machine weighing 50,000 kg is equivalent to 50 tons. Rolling resistance is defined as 28 kg per ton, leading us to calculate the total rolling resistance for a particular haul route as 1400 kg.
Further, we discuss penetration resistance, determined by the depth to which tires sink into the surface. Given a penetration depth of 6 cm and the requirement of 6 kg per ton per centimeter, we calculate the total penetration resistance at 1800 kg. Adding both rolling and penetration resistance gives a total resistance of 3200 kg, representing the minimum tractive effort required.
Additionally, we look at grade resistance, which is vital when machinery operates on inclines. Grade resistance is influenced by the slope percentage, with 10 kg per ton required for every 1% increase in slope, underscoring the need for careful route selection that minimizes resistance and operating costs.
Lastly, the concept of usable power is introduced, which is based on available power from the manufacturer’s specifications adjusted for project conditions, highlighting the importance of weight on the driven wheels and traction effects on performance.
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So, let us convert the vehicle weight into tons, because your rolling resistance is commonly expressed as kg per ton. So, let us convert the weight of the machine into tons you know that the gross weight of the machine is given as 50,000 kg. So, 1000 kg = 1 ton, so divided you will get the gross weight of the machine as 50 tons. Now the rolling resistance you need to calculate for this particular haul route it is given as 28 kg per ton. So, you multiply the gross weight of the machine by the rolling resistance value. So, gross weight is 50 tons multiplied by the rolling resistance is 28 kg per ton for that particular haul route. So, now we are going to calculate for your particular vehicle what is the total rolling resistance? That is nothing but 1400 kg, so 1400 kg is your rolling resistance.
Firstly, we need to convert the weight of the vehicle from kilograms to tons to make it compatible with the units of rolling resistance, which is expressed in kg per ton. Given that the machine weighs 50,000 kg, we divide this by 1000 to find that it weighs 50 tons. Next, we need to calculate the rolling resistance, which is given as 28 kg per ton. To find the total rolling resistance, we multiply the gross weight (50 tons) by the rolling resistance (28 kg per ton), resulting in a total rolling resistance of 1400 kg.
Think of rolling resistance like how hard it is to push a heavy cart. If the cart weighs more (like our vehicle), it becomes harder to push it just like a heavier truck has more rolling resistance. By converting weights into piles of bricks (tons), we can see how much harder it is based on how much we are trying to push.
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Now we need to find the penetration resistance. It is given to you in the problem that the tyre is sinking to the depth of 6 centimeters into the surface. So, you know that for each centimeter of penetration the amount of effort needed is 6 kg per ton per centimeter. So, you multiply that by how much is the depth of penetration? It is nothing but 6 centimeter, and what is the gross weight of the machine? It is nothing but 50 tons. So, that gives you the penetration resistance as 1800 kg.
The penetration resistance is determined by how deeply the tyre sinks into the surface—in this case, 6 centimeters. For every centimeter of penetration, it requires 6 kg of effort per ton of weight. Therefore, we multiply the depth of penetration (6 cm) by the effort per cm and the gross weight of the machine (50 tons), which gives us the penetration resistance of 1800 kg.
Imagine trying to push a toy car into soft sand. The deeper you push it, the harder it becomes to move because you're fighting against the sand that gets packed in. Similarly, when a tyre sinks into the ground, it increases the force needed to pull the vehicle forward.
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Now we can find the total resistance, that is nothing but add your rolling resistance and the penetration resistance. It is nothing but your 1400 kg + 1800 kg, so that gives me the answer as 3200 kg is the total resistance. So, I need tractive effort of at least 3200 kg to overcome this resistance in a project site.
To determine the total resistance a vehicle must overcome, we simply add the rolling resistance (1400 kg) to the penetration resistance (1800 kg). This gives us a total resistance of 3200 kg. Therefore, the machine must generate at least 3200 kg of tractive effort to move.
You can liken this scenario to dragging a heavy box across a floor with some obstacles inside. If the box has to overcome a weighted hurdle (penetration) and has friction with the floor (rolling resistance), you need to use a combined amount of strength to lift and move it over both hurdles.
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Now so far, we have discussed about the rolling resistance, let us look into the other part of the resistance in your project site that is your grade resistance. Most often you can see that equipment has to climb up a slope. So, when the machine is climbing up the slope, obviously you need some additional efforts to make it move up the slope because it is pulling against the gravity.
Grade resistance occurs when a machine has to move up a slope, requiring extra effort to overcome the force of gravity acting against the movement. This means the steeper the slope, the more tractive effort is needed to get the vehicle moving upwards.
Imagine riding a bicycle uphill. The steeper the hill, the more effort you need to pedal. This additional effort required to combat gravity is what we refer to as grade resistance in vehicles.
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Now similar to this, we should also know about what is grade assistance? So, we discussed about what is grade resistance, there is something called as grade assistance that means what? When your machine is moving down the slope, you can see that the amount of power needed gets reduced because it can easily move down by the gravity.
Grade assistance is the opposite of grade resistance, occurring when a machine is moving downhill. In this case, gravity helps the vehicle move, reducing the amount of power needed to do so.
Picture yourself on a skateboard going down a hill. You gain speed easily and do not need to work hard. Here, gravity is assisting you, just as it does for machines on a downhill slope.
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So, let us see how to calculate the grade resistance. Grade resistance is nothing but by simple elementary mechanics people have worked out this the relations. Say for example, for 1% of grade so the amount of tractive effort needed to overcome this 1% of grade it is 10 kg per ton.
Grade resistance is calculated based on the percentage of the slope. For every 1% grade, you need 10 kg of effort for each ton of weight to overcome the incline. This relationship helps in estimating the additional power required when climbing slopes.
It's like adding weights to a weighted vest when you try to climb up a staircase. The heavier you are (or the steeper the stairs), the more effort you need to exert to move effectively.
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So now let us see what is this usable power? So, out of the available power prescribed by the manufacturer, how much amount of power becomes usable to you? That depends upon your project condition that depends upon the altitude of your project site and the temperature at your place.
Usable power refers to the portion of the total power output that can actually be converted into effective work. This is influenced by external conditions such as altitude and temperature, as these can reduce the effective power output of a machine compared to its manufacturer's rating.
Think of a car engine rated to produce 200 horsepower at sea level. If you're driving at a high altitude, the air is thinner, and the engine can't perform at full strength. Therefore, even though it has the capacity for 200 horsepower, the usable power might only be 150 horsepower.
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So, another important thing to be noted is weight on the power running gear of the machine.
The weight placed on the power driving gear of a machine (such as the drive wheels) is crucial because it determines how much traction the vehicle can achieve. More weight typically increases traction, leading to higher usable force.
This is similar to how you would walk better on a firm surface when wearing shoes that grip well. If you're too light or the surface does not allow for good grip, you might slip. The more weight pressing down on the grip (wheels), the better the traction.
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So usable force is nothing but weight on the paver running gear multiplied by the coefficient of traction of the travel surface.
Usable force can be determined by multiplying the weight on the driving gear (the part of the machine that drives it) with the coefficient of traction, which is the measure of how well the tires grip the surface. A higher coefficient of traction means more usable force, resulting in better performance.
Think of trying to pull a heavy wagon. If the ground is muddy, it’s hard to get a grip and pull it along the surface. If the wagon has more weight, say with additional luggage, you can pull it better if you're on a solid path, akin to how usable force operates between the tires and the ground.
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Now let us workout the problem on how to estimate the power requirements of the machine. So, a tractor weighing 15 tons is operating on a haul road, the gross weight of the machine is given as 15 tons. It means it includes it is empty weight as well as the load it is carrying, with the rolling resistance of 60 kg per ton, it is given you can take it from the literature also for this particular haul route. For this particular mounting, what is the rolling resistance? The tables are available you can take it. And this machine is climbing a slope of 4% the gradient is given, the maximum rimpull in the first gear is 7000 kg.
To solve the problem, we start with the tractor's gross weight (15 tons) and the rolling resistance (60 kg per ton). First, we use these figures to calculate total rolling resistance and grade resistance, especially given that the tractor is climbing a 4% grade. Then, we can determine the total resistance and analyze whether the maximum rimpull (7000 kg) is sufficient to complete the task.
Consider a scenario where you're planning to transport a heavy load in a truck up a hill. Before starting, you want to understand if the truck can handle both the weight it's carrying and the incline of the road. You would calculate just like we did for the tractor to determine if the truck has enough power to make the trip.
Learn essential terms and foundational ideas that form the basis of the topic.
Key Concepts
Weight Conversion: Converting vehicle weight from kilograms to tons is necessary for resistance calculations.
Rolling Resistance: Calculated by multiplying gross weight by rolling resistance rate (kg per ton).
Penetration Resistance: Dependent on the tire's depth in the surface and needs proper calculation.
Grade Resistance: The force opposing movement on an incline; calculated based on the gradient percentage.
Usable Power: Power available for actual work after accounting for resistance.
See how the concepts apply in real-world scenarios to understand their practical implications.
For a vehicle weighing 50 tons and having a rolling resistance of 28 kg per ton, the total rolling resistance is calculated as 50 tons x 28 kg/ton = 1400 kg.
Using a depth of 6 cm for penetration resistance at 6 kg per ton per cm, the resistance is 50 tons x 6 kg/ton/cm x 6 cm = 1800 kg.
Use mnemonics, acronyms, or visual cues to help remember key information more easily.
To measure weight in tons, divide by 1000, it's fun!
Imagine a tractor on a hill, pulling a heavy cart. It needs extra might to move up the slope, just like you need energy to climb a flight of stairs.
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Review the Definitions for terms.
Term: Rolling Resistance
Definition:
The force opposing the motion of a vehicle due to the weight of the vehicle and the type of surface.
Term: Penetration Resistance
Definition:
The resistance encountered when tires sink into a surface, calculated by depth and effort per unit.
Term: Grade Resistance
Definition:
The additional effort required for a machine to move up an incline due to gravitational forces.
Term: Usable Power
Definition:
The effective power available for performing work after accounting for resistance.
Term: Available Power
Definition:
The power rating provided by the manufacturer under standard conditions.