Power Requirement Estimation - 3 | Overview 72 | Construction Engineering & Management - Vol 1
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Rolling Resistance Calculation

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Teacher
Teacher

To begin, let's discuss rolling resistance, which is important for understanding how much effort a vehicle needs to overcome friction when moving. Who can tell me how we convert vehicle weight?

Student 1
Student 1

We convert kilograms to tons, right?

Teacher
Teacher

That's correct! For instance, if the gross weight of a machine is 50,000 kg, how many tons does that equate to?

Student 2
Student 2

It would be 50 tons, since 1000 kg equals 1 ton.

Teacher
Teacher

Excellent! Now, if the rolling resistance is 28 kg per ton, how do we calculate the total rolling resistance?

Student 3
Student 3

We multiply the gross weight in tons by the rolling resistance value.

Teacher
Teacher

Correct again! So, what would be the total rolling resistance?

Student 4
Student 4

That's 50 tons multiplied by 28 kg per ton, giving us 1400 kg.

Teacher
Teacher

Well done! To recap, rolling resistance is calculated as the vehicle's weight in tons multiplied by the rolling resistance per ton. This is vital for understanding how much energy a vehicle needs while moving.

Penetration Resistance

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Teacher
Teacher

Next, let's address penetration resistance. If a tire sinks 6 cm into the surface, how do we calculate the force needed?

Student 1
Student 1

We know that it takes 6 kg per ton per centimeter of sinking, so we multiply that by the depth and the weight of the machine.

Teacher
Teacher

Exactly! How would that calculation look if our machine weighs 50 tons?

Student 2
Student 2

It would be 6 kg multiplied by 6 cm, then multiplied by 50 tons, giving us 1800 kg for penetration resistance.

Teacher
Teacher

Spot on! Now, if we combine that with our rolling resistance, what’s the total resistance we’re looking at?

Student 3
Student 3

That would be 1400 kg from the rolling resistance plus 1800 kg from penetration resistance, totaling 3200 kg.

Teacher
Teacher

Good job! Always remember that total resistance is the sum of different resistances, which gives us the tractive effort required.

Grade Resistance and Grade Assistance

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Teacher
Teacher

Let's move on to grade resistance. What is it and how does it impact our vehicle's performance on slopes?

Student 4
Student 4

Grade resistance is the additional force needed to move the vehicle uphill against gravity.

Teacher
Teacher

That's right! What happens when we move downhill?

Student 1
Student 1

That would be grade assistance, where gravity helps us and reduces the amount of power needed!

Teacher
Teacher

Great! So, how do we calculate the tractive effort needed to overcome grade resistance?

Student 2
Student 2

We use the grade percentage. For example, a 4% slope means we need 10 kg per ton, which gives us 400 kg for a 40 ton vehicle.

Teacher
Teacher

Perfect! And why is it important to choose haul routes wisely?

Student 3
Student 3

Choosing downslope routes reduces our power requirements, which means lower costs.

Teacher
Teacher

Exactly! Understanding these principles reduces operational expenses significantly. Always consider the entire haul route!

Usable and Available Power

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Teacher
Teacher

Now, let's dive into usable power versus available power. How do we define usable power?

Student 1
Student 1

Usable power is the amount of power that can be effectively used for the work needed after overcoming resistances.

Teacher
Teacher

Right! And how do project conditions affect this?

Student 2
Student 2

Things like altitude and temperature can affect how much power the machine can actually deliver.

Teacher
Teacher

Exactly! Remember, the manufacturer's rating is under standard conditions, and real-world factors can cause inefficiencies.

Student 3
Student 3

So, if we know our total available power and subtract resistance power need, we get the usable power for towing?

Teacher
Teacher

That's correct! Always calculate the difference to ensure the machine can handle the load effectively!

Introduction & Overview

Read a summary of the section's main ideas. Choose from Basic, Medium, or Detailed.

Quick Overview

This section discusses the estimation of power requirements for vehicles, focusing on rolling resistance, penetration resistance, and grade resistance.

Standard

The section outlines how to calculate the power required for vehicles operating in various conditions by assessing rolling resistance, penetration resistance, and grade resistance. It emphasizes the importance of understanding these forces to select appropriate machinery and avoid inefficiencies in project sites.

Detailed

In this section, we explore the crucial concepts of power requirement estimation for vehicles, especially in the context of working conditions at project sites. We begin by converting vehicle weight from kilograms to tons to facilitate calculations for rolling resistance, which is expressed in kilograms per ton. By multiplying the gross weight of a machine (50 tons) with the rolling resistance value (28 kg per ton), we derive a total rolling resistance of 1400 kg. Next, we discuss penetration resistance, which is determined by the depth tires sink into a surface (6 cm in this case), requiring additional weight to be calculated (1800 kg). Summing these resistances gives us a total resistance of 3200 kg, indicative of the tractive effort needed to move the vehicle. The section further introduces concepts like grade resistance, defined as the additional force required to move a vehicle up an incline, and contrasts it with grade assistance, which reduces required power when descending. Based on a given slope percentage (e.g. 4%), the calculations for tractive effort are demonstrated, using guidelines from literature for both rolling and grade resistance. The importance of understanding usable power from available power is emphasized, particularly how it fluctuates based on project conditions and machine specifications. Ultimately, accurate estimation of these resistances is essential for optimal machinery selection and efficient operation on project sites.

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Vehicle Weight Conversion

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So, let us convert the vehicle weight into tons, because your rolling resistance is commonly expressed as kg per ton. So, let us convert the weight of the machine into tons you know that the gross weight of the machine is given as 50,000 kg. So, 1000 kg = 1 ton, so divided you will get the gross weight of the machine as 50 tons.

Detailed Explanation

To estimate power requirements, we first need to convert the weight of the vehicle from kilograms to tons since rolling resistance is typically calculated in kg per ton. By dividing the total weight (50,000 kg) by 1000, we find that the vehicle weighs 50 tons. This conversion is crucial for understanding subsequent calculations concerning rolling resistance.

Examples & Analogies

Imagine you have a bag that weighs 50,000 grams, which can be cumbersome to think about. If you convert this weight to kilograms (50 kg), it's easier to visualize carrying it. Similarly, converting the vehicle's weight to tons simplifies our calculations.

Calculating Rolling Resistance

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Now the rolling resistance you need to calculate for this particular haul route it is given as 28 kg per ton. So, you multiply the gross weight of the machine by the rolling resistance value. So, gross weight is 50 tons multiplied by the rolling resistance is 28 kg per ton for that particular haul route. So, now we are going to calculate for your particular vehicle what is the total rolling resistance? That is nothing but 1400 kg, so 1400 kg is your rolling resistance.

Detailed Explanation

Next, we need to estimate the rolling resistance, which is given as 28 kg per ton for this specific route. To find the total rolling resistance, multiply the gross weight of the vehicle (50 tons) by the rolling resistance value (28 kg per ton). This calculation gives us a total rolling resistance of 1400 kg, which indicates how much force is needed to keep the vehicle moving at a constant speed.

Examples & Analogies

Think about pushing a heavy box across a rough surface. The force you need to keep it moving is akin to the rolling resistance. In this case, you would need to push harder if the box is heavier or if the surface is rougher.

Finding Penetration Resistance

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Now we need to find the penetration resistance. It is given to you in the problem that the tyre is sinking to the depth of 6 centimeters into the surface. So, you know that for each centimeter of penetration the amount of effort needed is 6 kg per ton per centimeter you know that. So, you multiply that by how much is the depth of penetration? It is nothing but 6 centimeter, and what is the gross weight of the machine? It is nothing but 50 tons. So, that gives you the penetration resistance as 1800 kg.

Detailed Explanation

The next step is to calculate the penetration resistance. The problem states that the tire sinks 6 centimeters into the surface, and it requires 6 kg of effort per ton for each centimeter of penetration. To find the total penetration resistance, multiply the depth of penetration (6 cm) by the gross weight (50 tons) and then by the effort required (6 kg per ton). This results in a penetration resistance of 1800 kg, which adds to the overall resistance faced by the vehicle.

Examples & Analogies

Imagine walking on soft sand; the deeper you sink, the harder it is to walk. Similarly, as the tires sink further into the ground, more effort is needed to keep moving forward.

Total Resistance Calculation

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Now we can find the total resistance, that is nothing but add your rolling resistance and the penetration resistance. It is nothing but your 1400 kg + 1800 kg, so that gives me the answer as 3200 kg is the total resistance.

Detailed Explanation

To understand how much effort is needed from the machine, we must add the rolling resistance (1400 kg) and the penetration resistance (1800 kg). Thus, the total resistance encountered by the vehicle is 3200 kg. This is the total opposing force the vehicle needs to overcome in order to operate effectively.

Examples & Analogies

Think of it like a team of horses pulling a wagon: if one horse can pull 1400 kg easily on flat ground but encounters a muddy patch that needs an additional 1800 kg of pull, then as a team, they must exert a total force of 3200 kg to move the wagon forward.

Determining Tractive Effort

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So, I need tractive effort of at least 3200 kg to overcome this resistance in a project site. So, the total tractive effort needed to overcome this resistance is 3200 kg. So, select the machine accordingly, that is the purpose of estimating all this resistance, so that we can know what is the required power for your machine? Select a machine that can generate enough power to overcome this resistance.

Detailed Explanation

With the total resistance now known to be 3200 kg, we determine that the machine must generate at least this amount of tractive effort to move effectively at the project site. This estimation guides the selection of a machine that can produce the required power to overcome the resistance.

Examples & Analogies

When you go to buy a car, you want one that can handle the conditions you will face, like hills or heavy loads. Similarly, here we need to choose a machine that has enough power to move effectively against the total resistance.

Understanding Grade Resistance

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Now so far, we have discussed about the rolling resistance, let us look into the other part of the resistance in your project site that is your grade resistance. Most often you can see that equipment has to climb up a slope. So, when the machine is climbing up the slope, obviously you need some additional efforts to make it move up the slope because it is pulling against the gravity.

Detailed Explanation

Grade resistance refers to the additional force required when the machine climbs a slope, as it works against the force of gravity. When climbing, machines require more power because they have to lift their weight vertically, making it harder to move. Understanding grade resistance is important for ensuring that the selected equipment can efficiently handle the terrain.

Examples & Analogies

When you walk up a hill, you know it takes more effort than walking on flat ground. Just as we adjust our speed or take breaks when hiking up a steep slope, machines need more power to handle grade resistance when climbing.

Grade Assistance Concept

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Now similar to this, we should also know about what is grade assistance? So, we discussed about what is grade resistance, there is something called as grade assistance that means what? When your machine is moving down the slope, you can see that the amount of power needed gets reduced because it can easily move down by the gravity.

Detailed Explanation

While we discussed how machines face additional challenges when climbing slopes, grade assistance refers to the reduction of required power when moving downhill. The weight of the machine works with gravity, thus requiring less energy to continue moving downward, presenting a contrast to the uphill effort previously discussed.

Examples & Analogies

Consider riding a bike down a hill. You might need to pedal hard going up, but when going down, gravity helps you and you can coast with little effort. This is akin to how machines benefit from grade assistance when moving downwards.

Calculating Grade Resistance

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So, now let us see how to calculate the grade resistance. Grade resistance is nothing but by simple elementary I mean a mechanics people have worked out this the relations. Say for example, for 1% of grade so the amount of tractive effort needed to overcome this 1% of grade it is 10 kg per ton.

Detailed Explanation

To calculate grade resistance, we use a simple guideline that states for 1% of slope, the force needed is 10 kg per ton. This means as the slope percentage increases, the tractive effort required increases accordingly. Understanding this relationship helps us to estimate the machinery required for various grades.

Examples & Analogies

Think about driving a vehicle: the steeper the hill you need to ascend, the harder you have to push the gas pedal to maintain speed. This mirrors how the more steeply a machine must climb, the greater the force needed to move it.

Impact of Slope Percentage

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So, say for example, if your slope percentage is say 5%, it means what? In a horizontal distance of 100 meter you will have a surface rise of vertical surfaces rise of 5 meter that is 5%.

Detailed Explanation

Slope percentage provides a specific way to quantify how steep an incline is. A 5% slope indicates that for every 100 meters traveled horizontally, the elevation increases by 5 meters. Understanding slope percentages can improve route planning and machinery selection as steeper grades require machines with greater tractive effort.

Examples & Analogies

Picture a ramp. If the ramp rises 5 meters over a horizontal distance of 100 meters, that slope is 5%. Knowing this helps you decide how much power is needed to climb it. It's like understanding the steepness of a hill on your way to a destination.

Selecting the Right Haul Route

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So, when you select your haul route, so we have to be very careful in the selection of your haul route. So, if there is a option that you can use the down slope, it is always preferable to use down slopes, because your power required gets reduced.

Detailed Explanation

Carefully selecting a haul route is crucial because it can significantly impact the power requirements. Using downhill routes can minimize the power needed, leading to reduced operational costs and increased efficiency. Therefore, route planning should prioritize keeping resistance as low as possible.

Examples & Analogies

Just as you would prefer a downhill path for a bicycle to conserve energy and increase your speed, heavy machinery also benefits from operating on favorable slopes to reduce power requirements.

Using Literature for Grade Resistance

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So, there are sufficient information’s in different literature which I have cited in the references towards the end of the lecture, you can go through. So, you can find the tables, which provide you the grade resistance for different percentage of gradient.

Detailed Explanation

Resourceful literature is available, providing tables that outline the grade resistance for various slopes. These can be helpful when planning operations, as they quantitatively express the resistance associated with different gradients, enhancing the decision-making process when selecting equipment.

Examples & Analogies

Think of these resources like a weather forecast providing essential information about different conditions for travel - using the right data can help ensure you choose the best route and equipment for your task.

Converting Resistance to Gradient

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So, you know the rolling resistance in kg per ton, so you know that 1% of grade equal to 10 kg per ton. So, you divide it by 10 kg per ton, you will get the equivalent gradient percentage.

Detailed Explanation

It's also beneficial to convert rolling resistance expressed in kg per ton into an equivalent gradient percentage. This allows for a better comparison between rolling and grade resistance, providing a more accurate assessment of the overall resistance for a vehicle.

Examples & Analogies

Imagine wanting to compare distances in miles against kilometers. Converting units helps clarify which distance is greater. Similarly, converting resistance to gradients gives a clearer picture of what to expect on the route.

Estimating Usable Power

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So, so far what we have discussed is about the required power. So, what is the total power required by the machine to overcome the different resistances in the project site, in the underfoot conditions.

Detailed Explanation

Up to this point, we've assessed the total power required for the machine to overcome all resistances. It is essential for operational planning to know this value as it dictates the capacity of the machinery we need. Understanding total power requirements ensures that we select machinery that meets operational needs.

Examples & Analogies

Just like a student needs to know how many textbooks they need to carry for a semester, knowing the total power requirement helps in selecting the correct machinery capacity for their load.

Available Power Determination

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So, the available power you can get the data easily, because the manufacturer would have done the horsepower rating of the machine. So, the available power is determined by the SAE rating.

Detailed Explanation

Available power is defined by the horsepower rating provided by the manufacturer, which undergoes standardized testing by organizations like SAE (Society of Automotive Engineers). This rating provides guidance for understanding what machine can deliver under optimal conditions.

Examples & Analogies

When you purchase a new car, the horsepower rating gives insight into how powerful the engine is. Similarly, understanding the available power of machinery is crucial for matching tasks with suitable equipment.

Factors Affecting Usable Power

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Now let us see what is this usable power? So, out of the available power prescribed by the manufacturer, how much amount of power becomes usable to you? That depends upon your project condition.

Detailed Explanation

Usable power refers to the portion of power derived from the manufacturer's available power rating that can be effectively employed in actual work situations. Its effectiveness can vary based on environmental factors like altitude and temperature, which can affect equipment efficiency.

Examples & Analogies

It's like how a smartphone battery might last longer in cool temperatures but drain quickly in heat. Similarly, environmental conditions impact how much power you can actually use from your machinery.

Determining Actual Usable Power

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So, we need to estimate this usable power of this particular machine. We are going to see how to estimate the usable power? Say for example, when we are using a tractor for towing the load.

Detailed Explanation

To find the actual usable power of a machine, we assess the total available power and subtract the energy necessary to overcome resistances specific to the project's conditions. This helps quantify how much power is genuinely available for load towing or other tasks.

Examples & Analogies

Think about budgeting money: if you earn a salary (available power) but have expenses like rent and groceries (resistances), the remaining amount (usable power) is what you can spend on leisure or savings.

Understanding Rimpull and Drawbar Pull

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So, the usable power you can express in terms of rimpull or drawbar pull. So, depending upon the mounting of your machine.

Detailed Explanation

Rimpull and drawbar pull are terms used to describe usable power depending on whether the machine is wheel-mounted (rimpull) or track-mounted (drawbar pull). These values are crucial for understanding equipment capabilities in specific applications.

Examples & Analogies

Imagine a truck (rimpull) compared to a bulldozer (drawbar pull). Each has different capacities for pulling loads based on their design; knowing these terms helps in selecting the right machinery for the task.

Calculating Usable Force

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So, how to calculate this usable force? So, this usable force is going to depend upon the traction of your travel surface. So, as I told you how much amount of the total power becomes usable, it depends upon the degree of traction between your wheel and the ground.

Detailed Explanation

The usability of a machine's power is directly influenced by traction, or the grip between the wheels and the ground. The better the traction, the more of the total power can be effectively translated into usable force, ensuring operational efficiency.

Examples & Analogies

If you're trying to sprint on ice (low traction), you'll struggle to run fast. Conversely, running on a solid track (high traction) allows more of your energy to be effectively used - this illustrates how traction impacts usable power.

The Role of Weight on Driving Gear

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So, another important thing to be noted is weight on the power running gear of the machine. So, in common equipment or the common wheels of the cars whatever we are using, you can see that all the wheels of the car are not driving wheels.

Detailed Explanation

Only specific wheels or axles are powered in many machines, meaning the weight distribution affects usable power. The weight on the driving wheels is the critical factor because it determines how much force can be exerted for traction on the surface.

Examples & Analogies

When pushing a heavy shopping cart, the more weight you place on the wheels that are being pushed, the easier it is to move. This is similar to how the weight on the driving wheels of machinery can enhance traction and usable power.

Calculating Rimpull

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So, assuming your coefficient of traction is sufficient, if there is proper traction, sufficient traction between your wheel and the ground. In that case your rimpull can be taken as a function of your horsepower of the machine.

Detailed Explanation

Rimpull calculation is influenced by the available horsepower and the coefficient of traction on the surface. If traction is adequate, you can derive a direct relationship where higher horsepower leads to increased rimpull, directly affecting how effectively a machine can tow loads.

Examples & Analogies

Just as a strong person can lift more weight if they have a solid grip versus a slippery handle, similarly, the more powerful the machine (higher horsepower) and the better the traction, the greater the rimpull they can achieve.

Estimating Rimpull with Speed

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Using this simple relationship, you can directly estimate the rimpull if you know the horsepower of the machine given by the manufacturer, and you should know that it is a function of speed; inverse function rimpull and the speed of the machine are inversely related.

Detailed Explanation

The relationship between rimpull and speed indicates that as the speed of the machine increases, the rimpull it can exert decreases. This inverse relationship is critical for operators to understand as it affects operational strategies.

Examples & Analogies

Think of a runner: when they sprint at high speed, they can't exert as much force to push against the ground as they can when they run slower. Similarly, for machines, maintaining the right speed is key to maximizing power output.

Working Through a Power Requirement Problem

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Now let us workout the problem on how to estimate the power requirements of the machine. So, a tractor weighing 15 tons is operating on a haul road, the gross weight of the machine is given as 15 tons.

Detailed Explanation

To consolidate our understanding, we can apply these principles to a specific problem. The scenario is set with a tractor weighing 15 tons and we will calculate the power needed using the same resistances discussed earlier. By analyzing these factors, we determine the tractor’s ability to operate effectively on the haul road.

Examples & Analogies

Solving a math problem often requires multiple steps. Similarly, estimating power requirements involves using various known values, combined through calculations, to arrive at a useful conclusion.

Calculating Grade Resistance in Practice

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First let us see what is the tractive effort needed to overcome the grade resistance? Grade resistance, you know the grade percentage it is nothing but 4%.

Detailed Explanation

In our problem, we calculate the tractive effort necessary to overcome grade resistance. Knowing that the slope is 4%, we apply the earlier mentioned guideline that relates slope percentage to tractive effort (10 kg per ton). This step focuses our calculation strategy on meeting the demands of the terrain.

Examples & Analogies

When preparing to climb a hill, knowing its steepness helps you gauge the energy needed to reach the top - similarly, understanding grade resistance shapes our approach towards overcoming inclines with machinery.

Rolling Resistance Calculation

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Now let’s calculate how to estimate a tractive effort to overcome the rolling resistance? It is nothing but for this particular haul route the rolling resistance value is given us 60 kg per ton.

Detailed Explanation

Next, we compute the rolling resistance needed for our tractor scenario. Using the given rolling resistance value for this haul route (60 kg per ton) and multiplying it by the gross weight of our machine allows us to derive the total force the machine needs to exert against rolling resistance.

Examples & Analogies

Consider driving a vehicle: the force needed to keep moving forward varies by how heavy the load is. In this case, it's similar; heavier tractors experience greater resistance, thus requiring a precise calculation for effective operation.

Total Resistance and Usable Power

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Now the total power required to overcome all the resistances are given here as 600 kg. So, 600 kg is nothing but your grade resistance, the power needed to overcome this grade resistance plus 900 kg is your rolling resistance.

Detailed Explanation

After computing both grade resistance (600 kg) and rolling resistance (900 kg), we sum these values to understand the total power required for this tractor to function effectively. Knowing this total helps guide equipment selection and operational planning as it determines how much power the machinery will use.

Examples & Analogies

Think of a football game: each team works together to tackle both offense and defense. Similarly, our power calculations require a combined effort (both grade and rolling resistance) to understand the total force needed for the tractor to operate successfully.

Understanding Rimpull Available

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So, the maximum rimpull available for this machine as given by the manufacturer is 7000 kg. Now you need to know what is a grade resistance on the rolling resistance?

Detailed Explanation

Identifying the maximum rimpull available helps us understand the tractor’s capabilities based on the manufacturer's specifications. This value is essential to see how much of this total capacity will be consumed by resisting forces (grade and rolling). This evaluation is paramount for ensuring that the equipment can operate in required conditions.

Examples & Analogies

Much like knowing a vehicle’s towing capacity can inform you of what load you can safely transport, understanding the maximum rimpull available allows for informed decision-making regarding the loads the tractor can handle.

Final Usable Power for Tow Operations

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So, out of this 7000 kg, 1500 kg will be used for overcoming the resistances. So, for overcoming the different resistances in the project site, you are going to spend 1500 kg.

Detailed Explanation

Finally, we determine that after accounting for the power used to overcome resisting forces (1500 kg), the remaining rimpull which can be interpreted as usable power for towing loads is 5500 kg. This final assessment is crucial in understanding how effectively the machine can perform its intended work.

Examples & Analogies

Think of it like having $7000 in your budget: if you spend $1500 on bills (used for resistances), you are left with $5500 for savings or shopping. Similarly, the usable power left signifies what's available for performing actual work after meeting necessary resistance.

Definitions & Key Concepts

Learn essential terms and foundational ideas that form the basis of the topic.

Key Concepts

  • Rolling Resistance: Resistance that a vehicle experiences when it rolls over a surface, primarily dependent on vehicle weight and surface characteristics.

  • Penetration Resistance: The force required to move a tire that has sunk into a soft surface.

  • Grade Resistance: The force opposing a vehicle's motion when moving uphill.

  • Grade Assistance: The benefit of gravity when a vehicle is moving downhill.

  • Usable Power: The net power available for work after accounting for resistive forces.

Examples & Real-Life Applications

See how the concepts apply in real-world scenarios to understand their practical implications.

Examples

  • Calculating the rolling resistance for a 50-ton vehicle on a haul route with a rolling resistance of 28 kg per ton yields a total rolling resistance of 1400 kg.

  • For a vehicle sinking 6 cm into soft ground with a weight of 50 tons, penetration resistance is calculated as 1800 kg based on the formula of 6 kg per ton per cm.

  • A vehicle on a 4% incline requires a total tractive effort of 600 kg for grade resistance, calculated as 4% times 10 kg per ton times the weight of the vehicle.

Memory Aids

Use mnemonics, acronyms, or visual cues to help remember key information more easily.

🎵 Rhymes Time

  • When driving uphill it’s tough, due to grade resistance, it’s often rough; on level ground, we roll so light, with rolling resistance, it feels just right!

📖 Fascinating Stories

  • Imagine a car trying to drive up a hill. It struggles with additional weight - that’s grade resistance! But when it rolls down, gravity helps it glide, that’s grade assistance, making it easier to ride.

🧠 Other Memory Gems

  • R-P-G-U (Rolling, Penetration, Grade Resistance, Usable Power) helps remember the essential forces affecting vehicle movement.

🎯 Super Acronyms

R-G-R-U (Resistance, Grade, Resistance, Usable) captures the key types of resistance and power in vehicle operation.

Flash Cards

Review key concepts with flashcards.

Glossary of Terms

Review the Definitions for terms.

  • Term: Rolling Resistance

    Definition:

    The resistance encountered by a vehicle's tires when rolling on a surface, affected by weight and surface conditions.

  • Term: Penetration Resistance

    Definition:

    The resistance force arising when a tire sinks into a soft surface, calculated per centimeter of depth.

  • Term: Grade Resistance

    Definition:

    The additional tractive effort required to move a vehicle uphill against gravity.

  • Term: Grade Assistance

    Definition:

    The decrease in power required when a vehicle moves downhill, supported by gravity.

  • Term: Usable Power

    Definition:

    The effective power available for a vehicle to perform work after accounting for resistances.

  • Term: Available Power

    Definition:

    The maximum power output of a machine as specified by the manufacturer.