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3.3. Rimpull and Drawbar Pull

Interactive Audio Lesson

Session 1: Converting Vehicle Weight and Calculating Resistance

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Sarah
SarahInstructor

To start, let’s convert vehicle weight into tons since rolling resistance is frequently expressed in kg per ton. Can anyone tell me how we do that?

Noah
Noah

We divide the weight in kg by 1000, because 1000 kg equals 1 ton.

Sarah
SarahInstructor

Exactly! For example, if our machine weighs 50,000 kg, how many tons does it weigh?

Isabella
Isabella

That would be 50 tons.

Sarah
SarahInstructor

Correct! Now, the rolling resistance is given as 28 kg per ton. Can anyone help me calculate the total rolling resistance for our 50 tons machine?

Akash
Akash

We multiply 50 tons by 28 kg per ton to get 1400 kg.

Sarah
SarahInstructor

Great job! So the total rolling resistance is 1400 kg.

Ananya
Ananya

What does that mean for the machine? How do we move it?

Sarah
SarahInstructor

It means that the machine needs 1400 kg of tractive effort to overcome that resistance!

Session 2: Understanding Penetration and Total Resistance

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Robert
RobertInstructor

Now let’s add another layer—penetration resistance. If the tire sinks 6 cm into the surface, how do we figure out the penetration resistance?

Noah
Noah

We multiply the depth of penetration by the effort required per centimeter and then by the total weight.

Robert
RobertInstructor

Very well! Given that it requires 6 kg per ton per centimeter for penetration, how do we calculate that?

Isabella
Isabella

We can multiply 6 kg by 6 cm and then by 50 tons, resulting in 1800 kg.

Robert
RobertInstructor

Exactly! Let’s find the total resistance. Can someone add the rolling and penetration resistance for us?

Akash
Akash

That would be 1400 kg plus 1800 kg, equaling 3200 kg total resistance.

Robert
RobertInstructor

Correct! Now, we know the machine needs at least 3200 kg of tractive effort to overcome this resistance.

Session 3: Exploring Grade Resistance and Assistance

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Sarah
SarahInstructor

When machinery ascends a slope, what do we call the opposing force?

Ananya
Ananya

That’s called grade resistance!

Sarah
SarahInstructor

Exactly! And what happens when the machine is moving down a slope?

Noah
Noah

That’s grade assistance, which reduces the power needed!

Sarah
SarahInstructor

Perfect! Let’s say we have a 5% slope. How would we quantify the grade resistance required?

Isabella
Isabella

For each 1% of grade, we need 10 kg per ton. So it would be 5 times that for a 5% slope, or 50 kg per ton.

Sarah
SarahInstructor

Right! Can someone calculate the needed tractive effort if our machine is 50 tons?

Akash
Akash

That would be 50 times 50 kg, which equals 2500 kg!

Sarah
SarahInstructor

Awesome! So, how do we apply this when planning our haul route?

Ananya
Ananya

We should avoid steep slopes if we can, to reduce required power and costs.