Grade Resistance and Assistance - 2.1 | Overview 72 | Construction Engineering & Management - Vol 1
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Rolling Resistance Calculation

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Teacher
Teacher

Today we will start by discussing rolling resistance, which is expressed in kg per ton of vehicle weight. Who can explain how to calculate the rolling resistance for a machine weighing 50 tons and having a rolling resistance of 28 kg per ton?

Student 1
Student 1

Isn't it just multiplying the weight by the rolling resistance value? So, it would be 50 tons times 28 kg per ton?

Teacher
Teacher

Exactly! So, what do we get when we perform that multiplication?

Student 2
Student 2

That would be 1400 kg of rolling resistance.

Teacher
Teacher

Well done! Remember, the formula we use is: Total Rolling Resistance = Gross Weight × Rolling Resistance Value. Can anyone tell me why it's important to know the rolling resistance?

Student 3
Student 3

It helps us select the right machine for a project based on the strength needed to overcome that resistance!

Teacher
Teacher

Good connection! Knowing this helps in estimating the power requirement too.

Student 4
Student 4

Does that mean higher weight will always lead to higher rolling resistance?

Teacher
Teacher

Correct! Heavier machines will generally experience greater rolling resistance. Great observation!

Grade Resistance Explanation

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Teacher
Teacher

Moving on, let's talk about grade resistance. Can anyone define what happens when a machine is climbing a slope?

Student 1
Student 1

It faces resistance because it’s moving against gravity!

Teacher
Teacher

Great! And how can we calculate the resistance based on grade percentage?

Student 2
Student 2

For every 1% grade, we need 10 kg of tractive effort per ton, right?

Teacher
Teacher

Exactly! So, if the slope is 5%, what would be the tractive effort needed for a vehicle weighing 10 tons?

Student 3
Student 3

That would be 5 times 10, which is 50 kg, multiplied by 10 tons, resulting in 500 kg.

Teacher
Teacher

Awesome! That’s how grade resistance builds up. Now, what about grade assistance? How does that play into our calculations when descending?

Student 4
Student 4

It reduces the power needed since gravity assists in moving downwards!

Teacher
Teacher

Correct! Understanding these concepts is essential for project planning. Let’s summarize: rolling resistance opposes movement, while grade assistance can ease the load when going downhill.

Total Resistance Calculation

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Teacher
Teacher

Now let's calculate total resistance. Remember, total resistance is the sum of rolling resistance and grade resistance. How do we calculate total resistance based on our previous examples?

Student 1
Student 1

We would add the rolling resistance and grade resistance values together!

Teacher
Teacher

Exactly. So if we have 1400 kg of rolling resistance and 600 kg of grade resistance, what is the total?

Student 2
Student 2

That would be 2000 kg!

Teacher
Teacher

Right! And why is it important to know this total resistance?

Student 3
Student 3

So we can ensure the machinery selected can handle that resistance correctly!

Teacher
Teacher

Well said! Next, we will dive into usable power. This will tie everything together.

Usable Power and Selection of Machinery

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Teacher
Teacher

Let's shift our focus to usable power. How do we determine the usable power from the total power available in our machinery?

Student 1
Student 1

We subtract the power used to overcome resistance from the total power, correct?

Teacher
Teacher

Exactly! If our total is 7000 kg and we have 1500 kg used for resistance, what remains for towing?

Student 2
Student 2

That would be 5500 kg available for towing!

Teacher
Teacher

Well done! Knowing the usable power directly influences the machinery we select for our tasks. What factors could affect usable power?

Student 3
Student 3

Altitude and temperature would be big factors as they affect efficiency!

Teacher
Teacher

Correct! Keep in mind that various conditions can change how we assess power capabilities.

Introduction & Overview

Read a summary of the section's main ideas. Choose from Basic, Medium, or Detailed.

Quick Overview

This section explains how to calculate rolling resistance and grade resistance in vehicles, along with the concept of grade assistance when moving downhill.

Standard

Through calculations for rolling and penetration resistance based on machine weight and slope percentage, the section highlights the importance of understanding resistance forces in selecting appropriate machinery for construction projects. It also introduces the concept of grade assistance while descending slopes.

Detailed

Detailed Summary of Grade Resistance and Assistance

This section elaborates on the different types of resistance encountered by vehicles during operation, focusing on rolling resistance and grade resistance, as well as the beneficial aspect of grade assistance when descending slopes.

Key Points:

  1. Rolling Resistance Calculation: The section begins by explaining that rolling resistance is quantified in kg per ton of vehicle weight. The example provided highlights a machine weighing 50 tons having a rolling resistance of 28 kg per ton, leading to a total of 1400 kg of rolling resistance from detailed calculations.
  2. Penetration Resistance: Further calculations for penetration resistance based on the tire's depth of penetration into the surface show that a depth of 6 centimeters translates into 1800 kg of resistance.
  3. Total Resistance: By summing the rolling and penetration resistance, the total resistance of 3200 kg is established, highlighting the required tractive effort needed for machine operation.
  4. Grade Resistance Explanation: The content explains how grade resistance occurs when a machine climbs slopes, requiring additional effort against gravity. The relation between slope percentage and the tractive effort needed to overcome this resistance is emphasized.
  5. Grade Assistance Introduction: Conversely, the concept of grade assistance is introduced, indicating how gravitational pull can aid in movement on a downhill slope, thus reducing power requirements.
  6. Calculating Grade Resistance: The formula for calculating grade resistance is introduced, outlining that for every 1% grade, a vehicle requires 10 kg of tractive effort per ton. This guideline is applicable for slopes less than 10%.
  7. Equivalent Gradient Conversion: Instructions on converting rolling resistance into an equivalent gradient are also outlined, enhancing the understanding of how different resistances relate.
  8. Usable Power Insights: Finally, the section transitions into the discussions regarding available and usable power for machinery, emphasizing the factors that affect these power calculations, including site conditions and manufacturer specifications.

Audio Book

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Converting Vehicle Weight

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So, let us convert the vehicle weight into tons, because your rolling resistance is commonly expressed as kg per ton. So, let us convert the weight of the machine into tons you know that the gross weight of the machine is given as 50,000 kg. So, 1000 kg = 1 ton, so divided you will get the gross weight of the machine as 50 tons. Now the rolling resistance you need to calculate for this particular haul route it is given as 28 kg per ton.

Detailed Explanation

In this section, we start with a practical conversion of vehicle weight from kilograms to tons. This is important because rolling resistance, a significant factor affecting vehicle performance, is calculated in kg per ton. The given gross weight is 50,000 kg, and as there are 1,000 kg in a ton, this converts to 50 tons (50,000 kg / 1,000 kg/ton). This sets the stage for calculating rolling resistance.

Examples & Analogies

Think of converting your weight from grams to kilograms. If you're 50,000 grams (which is like a heavy suitcase), you can easily see that this is equal to 50 kilograms when you divide it by 1,000. It’s a simple conversion but essential for understanding how heavy a suitcase is when considering how much strength is needed to lift it.

Calculating Rolling Resistance

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So, you multiply the gross weight of the machine by the rolling resistance value. So, gross weight is 50 tons multiplied by the rolling resistance is 28 kg per ton for that particular haul route. So, now we are going to calculate for your particular vehicle what is the total rolling resistance? That is nothing but 1400 kg, so 1400 kg is your rolling resistance.

Detailed Explanation

Once we have the gross weight in tons, we can calculate the total rolling resistance. This is done by multiplying the gross weight of the machine (50 tons) by the rolling resistance value given (28 kg per ton). The calculation gives us 50 tons * 28 kg/ton = 1400 kg of rolling resistance. This tells us how much force is needed to overcome the resistance caused by the vehicle's weight as it rolls over the ground.

Examples & Analogies

Imagine pushing your bike up a hill. The heavier the bike (representing our machine weight), the more effort (rolling resistance) you need to exert. If your bike is like 50 tons heavy, and every ton adds a steady weight to your push (28 kg), you can feel how that would add up to a lot of effort - equivalent to needing to overcome 1,400 kg just to get the bike moving smoothly!

Understanding Penetration Resistance

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Now we need to find the penetration resistance. It is given to you in the problem that the tyre is sinking to the depth of 6 centimeters into the surface. So, you know that for each centimeter of penetration the amount of effort needed is 6 kg per ton per centimeter.

Detailed Explanation

Penetration resistance relates to how deep the tire sinks into the surface. For every centimeter of depth, there is a vertical pressure that must be overcome to pull the tire back up. Here, the depth is 6 cm, and the resistance is 6 kg per ton for every centimeter. So, for a gross weight of 50 tons, the penetration resistance is calculated by multiplying 6 kg * 50 tons * 6 cm, which equals 1800 kg.

Examples & Analogies

Imagine standing in a pool of mud. As you push down into the mud with your feet (like the tire sinking), it gets more difficult to lift your foot back up from the sinking position. If you sink down more (each centimeter), the effort you need to exert to lift your foot becomes greater, just like the additional weight of 1800 kg that must be lifted for the 6 cm penetration into the soil!

Total Resistance Calculation

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Now we can find the total resistance, that is nothing but add your rolling resistance and the penetration resistance. It is nothing but your 1400 kg + 1800 kg, so that gives me the answer as 3200 kg is the total resistance.

Detailed Explanation

To find the total resistance that a machine faces while operating, we add the rolling resistance (1400 kg) and the penetration resistance (1800 kg). This calculation leads us to understand the full force that must be overcome by the machine, totaling 3200 kg. It's vital for deciding how much power the machine must generate to work properly on a project site.

Examples & Analogies

Similar to trying to push a car up a hill (rolling resistance), while simultaneously also having to lift your foot out of the mud (penetration resistance). If you combine both actions into one big effect, like needing to push against gravity while dealing with the mud, you realize how much more effort (3200 kg of total resistance) you need to safely get the car moving!

Tractive Effort Requirement

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So, I need tractive effort of at least 3200 kg to overcome this resistance in a project site. So, the total tractive effort needed to overcome this resistance is 3200 kg.

Detailed Explanation

At this stage, we summarize the requirements for the machine: to successfully operate in the given conditions, it needs at least 3200 kg of tractive effort to move against the rolling and penetration resistance. This concept is critical because it helps determine what type of machine or vehicle should be selected for the job.

Examples & Analogies

Think about a team of people trying to push a heavy object up a slippery ramp. If they know they need a certain number of volunteers (a force of 3200 kg) to push effectively, this information will guide them in choosing how many people they need to bring to successfully push that object up the ramp without stalling!

Grade Resistance Overview

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Most often you can see that equipment has to climb up a slope. So, when the machine is climbing up the slope, obviously you need some additional efforts to make it move up the slope because it is pulling against the gravity. So, there is a force opposing the movement of the machine when it is moving up the slope that is causing grade resistance.

Detailed Explanation

Grade resistance refers to the additional force that a machine must overcome when it ascends a slope. This resistance occurs because the weight of the machine works against gravity. Thus, climbing a hill requires more effort (trarctive effort) than traversing flat ground, highlighting the need for careful route planning.

Examples & Analogies

Imagine riding a bicycle up a hill. The push you need to exert is significantly higher than cycling on level ground because gravity opposes your upward movement. Likewise, machines face this increased resistance when they navigate slopes.

Explaining Grade Assistance

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When your machine is moving down the slope, you can see that the amount of power needed gets reduced because it can easily move down by the gravity, so the gravitational force will help you to easily move the machine. So, in that case, the amount of power needed gets reduced, so that is called as grade assistance.

Detailed Explanation

Grade assistance occurs when a machine moves downhill. In this scenario, gravity acts in favor of the machine, reducing the power needed to maintain movement. Essentially, machines benefit from a gravitational assist (like a push) while going down steep slopes.

Examples & Analogies

Think of sliding down a slide at the park. It’s so much easier and requires little effort compared to climbing up. Similarly, when machines go downhill, gravity helps them, reducing the energy (or power) they need to utilize.

Grade Resistance and Assistance Relationship

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So, to overcome this grade resistance that depends upon the percentage of the slope how steep is your slope? According to the tractive force requirement will vary. So, greater the percentage of your slope the amount of tractive effort needed will be more.

Detailed Explanation

The amount of tractive effort required increases as the slope percentage grows steeper. For instance, a greater slope necessitates a higher force to pull equipment upwards and vice versa for downhill equipment. Understanding this helps in choosing routes or machinery properly.

Examples & Analogies

Imagine trying to roll a heavy suitcase up a steep hill versus a gradual incline. The steeper the hill (greater the slope percentage), the harder it is to pull that suitcase, which translates directly into the tractive effort needed for a machine on a slope.

Calculating Grade Resistance

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Say for example, for 1% of grade so the amount of tractive effort needed to overcome this 1% of grade is 10 kg per ton. So, this is a simple guideline which they have worked out in literature.

Detailed Explanation

Here, we utilize an established guideline: to overcome a 1% grade, a machine requires 10 kg of tractive effort per ton. For small slopes (up to 10%), this rule simplifies estimating the needed force, which helps engineers plan effective routes.

Examples & Analogies

You can think of this like knowing how many calories you would burn while walking up a real hill. If you know that walking up a 1% incline burns a certain number of calories per distance, it becomes easier to estimate how many calories you’ll burn when hiking up steeper hills.

Equivalent Gradient Conversion

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So, you know the rolling resistance in kg per ton, so you know that 1% of grade is equal to 10 kg per ton. So, you divide it by 10 kg per ton, you will get the equivalent gradient percentage.

Detailed Explanation

Rolling resistance can also be represented as a percentage gradient. Knowing that 1% of grade relates to 10 kg per ton allows us to convert rolling resistance (expressed in kg per ton) into an equivalent gradient percentage. This dual representation helps in understanding operational conditions better.

Examples & Analogies

Think of it like measuring your height both in feet and meters. Knowing how to convert between these units means you can better communicate your height regardless of who you're talking to, whether they prefer one unit over the other!

Estimating Usable Power

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So, the available power is determined by the SAE rating. So, there is an organization called as SAE Society of Automotive Engineers, it is a US based organization. So, in India also we have an organization SAE India.

Detailed Explanation

The power available for a machine is dictated by its SAE rating, which is standardized across the industry. These ratings are essential as they inform users of the machine’s capabilities. Understanding these ratings aids in ensuring the selected machine meets the power requirements based on the calculated resistances.

Examples & Analogies

Consider it like knowing the horsepower of a car - it gives you an idea of how fast the car can go or how much weight it can carry. Just as car ratings inform buyers, SAE ratings provide critical insights for those selecting construction machines.

Usable Power & Project Conditions

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The usable power will obviously be different depending upon the project conditions that depend upon the altitude of your project site and the temperature at your place.

Detailed Explanation

The efficiency of a machine's operation changes based on project conditions, such as altitude and temperature. These conditions can limit how much power a machine can effectively use, making it essential to consider them when planning operations.

Examples & Analogies

Think about trying to run at different altitudes - it's generally harder at higher altitudes due to less oxygen available. Similarly, machines may perform differently in varying project conditions, reminding us we can’t always reach that maximum potential advertised!

Calculating Usable Force

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Usable force is nothing but weight on the paver running gear multiplied by the coefficient of traction of the travel surface.

Detailed Explanation

The amount of usable force that a machine can exert depends on the weight pressing down on its driving wheels and the traction available on the surface. By multiplying these two factors, we understand how much effective force the machine can generate for movement.

Examples & Analogies

Imagine a strong friend trying to push a heavy cart on ice. If there’s no grip (low traction), they can’t push it effectively. Conversely, on a rough surface, they could push a heavier load due to better traction allowing them to exert the full force!

Rimpull vs. Drawbar Pull

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The usable power you can express in terms of rimpull or drawbar pull. So, depending upon the mounting of your machine. So, if it is going to be wheel or tyre mounted machine, we call it as rimpull. The usable tractive force developed at the point of contact between the tyre and the ground is called as a rimpull.

Detailed Explanation

Rimpull (for wheeled machines) and drawbar pull (for tracked machines) are terms used to define how much force is available to a machine for traction. Understanding these terms is crucial for users to assess a machine's performance based on its design and functionality.

Examples & Analogies

Consider how a car can pull someone in a sled on a snowy road versus a tractor pulling heavy loads through a muddy field. The car might have high rimpull on hard surfaces, while the tractor’s drawbar pull comes into play in rugged terrains.

Definitions & Key Concepts

Learn essential terms and foundational ideas that form the basis of the topic.

Key Concepts

  • Total Resistance: The combined force opposing the motion of a vehicle due to rolling and grade resistance.

  • Usable Power: The power available for productive work after overcoming all resistances.

  • Grade Resistance vs. Grade Assistance: The difference in power requirements when going uphill (resistance) versus downhill (assistance).

Examples & Real-Life Applications

See how the concepts apply in real-world scenarios to understand their practical implications.

Examples

  • If a machine weighs 50 tons and the rolling resistance is 28 kg per ton, the total rolling resistance is 50 tons * 28 kg/ton = 1400 kg.

  • For a slope of 4%, the tractive effort required is calculated as 4% * 10 kg/ton * 15 tons = 600 kg of grade resistance.

Memory Aids

Use mnemonics, acronyms, or visual cues to help remember key information more easily.

🎵 Rhymes Time

  • When up the hill we go with might, grade resistance puts up a fight.

📖 Fascinating Stories

  • Imagine riding a bike uphill; the steeper the hill, the more effort you need. This is like how machines need more force to overcome grade resistance.

🧠 Other Memory Gems

  • Remember 'R.G.U.' to recall:

🧠 Other Memory Gems

  • Rolling Resistance,

  • Required Power,

🧠 Other Memory Gems

  • Grade Resistance,

  • Grade Resistance,

🧠 Other Memory Gems

  • Usable Power.

🎯 Super Acronyms

<p class="md

  • text-base text-sm leading-relaxed text-gray-600">G.R.R.A. helps to remember

🧠 Other Memory Gems

  • Assistance while going down.

Flash Cards

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Glossary of Terms

Review the Definitions for terms.

  • Term: Rolling Resistance

    Definition:

    The resistance that a vehicle experiences when rolling over a surface, typically expressed in kg per ton.

  • Term: Grade Resistance

    Definition:

    The additional resistance encountered by a vehicle when moving uphill against gravity.

  • Term: Grade Assistance

    Definition:

    The reduction in power needed when moving downhill, due to gravitational pull aiding the motion.

  • Term: Total Resistance

    Definition:

    The sum of rolling resistance and grade resistance that a vehicle must overcome during operation.

  • Term: Usable Power

    Definition:

    The amount of power available for productive work after accounting for resistance forces.

  • Term: Tractive Effort

    Definition:

    The force required to move a vehicle, specifically in relation to overcoming resistance.