Analysis and Design Exercises - 3.5 | 3. Op-Amp Feedback Configurations | Linear Integrated Circuits
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3.5 - Analysis and Design Exercises

Practice

Interactive Audio Lesson

Listen to a student-teacher conversation explaining the topic in a relatable way.

Inverting Amplifier Design

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0:00
Teacher
Teacher

Today we'll focus on designing an inverting amplifier. Can anyone tell me what the gain equation is for this configuration?

Student 1
Student 1

Is it A_v equals negative R_f over R_in?

Teacher
Teacher

Exactly! That's right. A great way to remember it is using the mnemonic 'Viking - ReseRvoir'. The 'R' in Viking stands for feedback and the negative sign indicates inversion. Now, if we want a gain of -20 and choose R_in as 1 kΞ©, how do we find R_f?

Student 2
Student 2

We just rearrange the equation, right? So R_f would be 20 times 1kΞ©.

Teacher
Teacher

Correct! So what would R_f be?

Student 3
Student 3

That would be 20 kΞ©.

Teacher
Teacher

Excellent! This is how we can effectively design our circuits for specific gains. Remember to always check your calculations.

Non-Inverting Amplifier Design

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0:00
Teacher
Teacher

Next, let's design a non-inverting amplifier. What is the gain equation for this configuration?

Student 4
Student 4

Is it A_v = 1 + R_f over R_in?

Teacher
Teacher

Yes! To remember this, you can use the mnemonic 'One Plus R'. So if I want a gain of 11 and R_in is fixed at 10 kΞ©, how would you find R_f?

Student 1
Student 1

We can set up the equation: 11 = 1 + R_f over 10 kΞ©.

Teacher
Teacher

Correct! What do we find R_f to be?

Student 2
Student 2

R_f would equal 100 kΞ©.

Teacher
Teacher

Great team work! That’s how a non-inverting amplifier is designed effectively.

Differential Amplifier Design

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0:00
Teacher
Teacher

Finally, let's discuss the differential amplifier. What good is this configuration?

Student 3
Student 3

It amplifies the difference between two input signals.

Teacher
Teacher

Exactly! The gain is determined by the resistors. How would you set the gain to 10, assuming R_1 is 10 kΞ©?

Student 4
Student 4

I'd calculate R_2 to be 100 kΞ©.

Teacher
Teacher

Correct! By setting R_2 to 100 kΞ©, we achieve the desired gain of 10. Remember to consider the importance of both R_3 and R_4 as well when designing.

Student 1
Student 1

So we can also make R_3 and R_4 equal to maintain proper balance?

Teacher
Teacher

That's right! Balancing those values helps reduce noise and enhance performance.

Introduction & Overview

Read a summary of the section's main ideas. Choose from Basic, Medium, or Detailed.

Quick Overview

This section presents design exercises for inverting, non-inverting, and differential amplifiers using operational amplifiers.

Standard

The section includes practical design examples of various amplifier configurations, guiding students through the calculations necessary to achieve specific gains in operational amplifier circuits.

Detailed

Analysis and Design Exercises

This section focuses on hands-on design exercises using operational amplifiers (Op-Amps), specifically the inverting amplifier, non-inverting amplifier, and differential amplifier configurations. For each configuration, examples are provided where students can apply their knowledge about gain equations to specify resistor values that achieve desired amplification.

The designs include:

  • Inverting Amplifier Design: Students will learn to achieve a gain of -20, leading to a practical application where they must calculate the required feedback resistor based on a specified input.
  • Non-Inverting Amplifier Design: Students will design a non-inverting amplifier with a gain of 11, reinforcing their understanding of how to manipulate resistor values in relation to the desired gain.
  • Differential Amplifier Design: Students will have to amplify the difference between two signals using appropriate resistor configurations, specifically achieving a gain of 10.

Through these exercises, students will gain confidence in designing and analyzing Op-Amp circuits critical for various applications in electronics.

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Audio Book

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Example 1: Inverting Amplifier Design

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Given an input voltage of 5V, design an inverting amplifier with a gain of -20 using an op-amp.

● Solution:
β—‹ The gain equation for the inverting amplifier is:
Av=βˆ’RfRinA_v = -\frac{R_f}{R_{in}}
β—‹ Set the gain to -20:
βˆ’20=βˆ’RfRin-20 = -\frac{R_f}{R_{in}}
β—‹ Choose R₁ = 1 kΞ©, and solve for Rβ‚‚:
Rf=20Γ—1kΞ©=20kΞ©R_f = 20 \times 1kΞ© = 20kΞ©
β—‹ Therefore, Rβ‚‚ = 20 kΞ©.

Detailed Explanation

This example shows how to design an inverting amplifier with a specified gain of -20. First, we start with the desired gain formula. We rearrange it to express the feedback resistor in terms of the input resistor. Since we want R₁ to be 1 kΞ©, we can substitute that into our equation to find Rβ‚‚, which is the feedback resistor. In this case, as we perform the calculation, we find that Rβ‚‚ needs to be 20 kΞ© to achieve the desired gain.

Examples & Analogies

Imagine you're controlling the volume of a speaker using a knob that adjusts how much of the original sound is played back inverted. If you turn the knob to a setting that makes the volume lower, similar to setting the gain to -20, the system requires precise components (like R₁ and Rβ‚‚) to get the volume just right without distortion.

Example 2: Non-Inverting Amplifier Design

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Design a non-inverting amplifier with a gain of 11 using an op-amp and resistors.

● Solution:
β—‹ The gain equation for the non-inverting amplifier is:
Av=1+RfRinA_v = 1 + \frac{R_f}{R_{in}}
β—‹ Set the gain to 11:
11=1+RfRin11 = 1 + \frac{R_f}{R_{in}}
β—‹ Solve for R_f and assume R₁ = 10 kΞ©:
Rf=(11βˆ’1)Γ—10kΞ©=100kΞ©R_f = (11 - 1) \times 10kΞ© = 100kΞ©
β—‹ Therefore, Rβ‚‚ = 100 kΞ©.

Detailed Explanation

In this example, we are tasked with designing a non-inverting amplifier. The procedure begins with the gain equation and setting it equal to 11, which indicates that we want the output to be 11 times the input signal. Using the assumption that R₁ is 10 kΞ©, we can replace this in our formula and solve for the feedback resistor, R_f. This results in R₁ needing to be 100 kΞ© to achieve the proper amplification.

Examples & Analogies

Think of a non-inverting amplifier as a volume control on a speaker where the output sound directly mimics the input sound, but louder. If you want it to be 11 times louder, you adjust the system (using specific resistances, like R₁ and Rβ‚‚) to ensure you achieve that without flipping the sound upside down, like flipping a photo wrong-side up.

Example 3: Differential Amplifier Design

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Design a differential amplifier that amplifies the difference between two input signals by a factor of 10.

● Solution:
β—‹ The gain for the differential amplifier is:
Av=R2R1=R4R3A_v = \frac{R_2}{R_1} = \frac{R_4}{R_3}
β—‹ Set the gain to 10 and choose R₁ = 10 kΞ©, so:
R2=10Γ—10kΞ©=100kΞ©R_2 = 10 \times 10kΞ© = 100kΞ©
β—‹ Therefore, R₃ = 10 kΞ© and Rβ‚„ = 100 kΞ©.

Detailed Explanation

This example involves designing a differential amplifier, which takes two input signals and amplifies the difference between them. We start again with the gain formula for differential amplifiers and set it to 10 because we want to amplify the difference by this factor. By choosing R₁ to be 10 kΞ©, we can determine Rβ‚‚ and find that it also needs to be 100 kΞ©. This ensures that the configuration is capable of amplifying the difference between the two input signals effectively.

Examples & Analogies

Think of a differential amplifier like a referee in a sports game who only pays attention to the difference in scores between two teams. If Team A scores 10 points and Team B scores 0, the difference is significant. Just like the referee, the differential amplifier focuses on the difference rather than individual inputs, requiring a balanced setup (using R₁ and Rβ‚‚) to ensure accurate amplification of that difference.

Definitions & Key Concepts

Learn essential terms and foundational ideas that form the basis of the topic.

Key Concepts

  • Inverting Amplifier: Provides negative gain and inverts the input signal based on the ratio of resistors R_f and R_in.

  • Non-Inverting Amplifier: Amplifies the input signal with gain equal to 1 + (R_f/R_in) without inversion.

  • Differential Amplifier: Amplifies the voltage difference between two inputs and is used in applications requiring signal conditioning.

Examples & Real-Life Applications

See how the concepts apply in real-world scenarios to understand their practical implications.

Examples

  • Example 1: Designing an inverting amplifier for a gain of -20 with an input of 5V, resulting in R_f = 20 kΞ© and R_in = 1 kΞ©.

  • Example 2: Designing a non-inverting amplifier with a gain of 11, using R_f = 100 kΞ© and R_in = 10 kΞ©.

  • Example 3: Designing a differential amplifier to amplify the difference between two input signals by a factor of 10, with R_f = 100 kΞ© and R_in = 10 kΞ©.

Memory Aids

Use mnemonics, acronyms, or visual cues to help remember key information more easily.

🎡 Rhymes Time

  • Inverting from the front, negative you must flaunt; Gain is computed like a charm, make sure you don't cause harm.

πŸ“– Fascinating Stories

  • Once, a curious engineer wanted to build a talking robot. He used a non-inverting amplifier so that every word flowed perfectly without changeβ€”a design that worked wonders in keeping conversations in harmony!

🧠 Other Memory Gems

  • Remember β€˜Gain of Non-Inverting is One Plus R’, helping us keep track of resistor values.

🎯 Super Acronyms

D.R.A.F.T. for Differential amplifier

  • Determine resistors
  • Apply values
  • Find output
  • Test differences.

Flash Cards

Review key concepts with flashcards.

Glossary of Terms

Review the Definitions for terms.

  • Term: Inverting Amplifier

    Definition:

    An operational amplifier configuration that provides a negative gain, inverting the input signal.

  • Term: NonInverting Amplifier

    Definition:

    An operational amplifier configuration that amplifies the input signal without inversion.

  • Term: Differential Amplifier

    Definition:

    An operational amplifier configuration that amplifies the difference between two input signals.

  • Term: Gain

    Definition:

    The ratio of output voltage to input voltage in an amplifier.