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11.1.7. Worked Example

Interactive Audio Lesson

Session 1: Introduction to the Wave Equation

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Sarah
SarahInstructor

Let's start with the basics. What is the one-dimensional wave equation?

Noah
Noah

Is it the equation that describes how waves propagate through a medium?

Sarah
SarahInstructor

Exactly! The wave equation models the movement of waves, such as sound or water waves, along one dimension. Can anyone tell me the standard form of this equation?

Isabella
Isabella

I think it goes like this: ∂2u∂t2=c2∂2u∂x2\frac{\partial^2 u}{\partial t^2} = c^2 \frac{\partial^2 u}{\partial x^2}!

Sarah
SarahInstructor

Great! Here, u(x,t)u(x,t) represents displacement, and cc is the wave speed. Remember this equation as it is foundational in understanding wave behavior.

Session 2: Setting the Problem

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Robert
RobertInstructor

Now, let’s take a look at our specific problem. We have the wave equation: ∂2u∂t2=4∂2u∂x2\frac{\partial^2 u}{\partial t^2} = 4 \frac{\partial^2 u}{\partial x^2}. What boundary conditions do we have?

Akash
Akash

We have u(0,t)=0u(0,t) = 0 and u(π,t)=0u(\pi,t) = 0.

Robert
RobertInstructor

Right! These fixed boundary conditions mean the ends of our string do not move. And what about the initial conditions?

Ananya
Ananya

The initial displacement is u(x,0)=sin⁡(x)u(x,0) = \sin(x), and the initial velocity is ∂u∂t(x,0)=0\frac{\partial u}{\partial t}(x,0) = 0.

Robert
RobertInstructor

Perfect! We will use these to find our solution.

Session 3: Applying Separation of Variables

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Sarah
SarahInstructor

To solve this using separation of variables, we assume a solution of the form u(x,t)=X(x)T(t)u(x,t) = X(x)T(t). Can anyone derive this relationship?

Noah
Noah

We break the equation into two parts: one depending on xx and the other on tt.

Sarah
SarahInstructor

Exactly! By substituting back into our wave equation, we can separate the variables. Now, given that the initial displacement is sin⁡(x)\sin(x), how does this help us express the solution?

Isabella
Isabella

It tells us that the solution will involve the sine function for the spatial part!

Sarah
SarahInstructor

Great! So what would our solution be?

Akash
Akash

I think it would be u(x,t)=cos⁡(2t)sin⁡(x)u(x,t) = \cos(2t)\sin(x)!

Sarah
SarahInstructor

Exactly right! This shows the wave behavior with respect to time and space.

Session 4: Concluding the Example

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Robert
RobertInstructor

To summarize, we covered how we set the boundary and initial conditions for our wave equation problem. We used separation of variables to arrive at our solution, which demonstrates how waves propagate in the string.

Ananya
Ananya

So, we basically applied the principles from earlier sections and now we see how they connect to real wave scenarios!

Robert
RobertInstructor

Precisely! Understanding this worked example helps solidify our grasp on solving wave equations with real-world applications.