Elastic Potential Energy in a Stretched Wire
Enroll to start learning
You’ve not yet enrolled in this course. Please enroll for free to listen to audio lessons, classroom podcasts and take practice test.
Interactive Audio Lesson
Listen to a student-teacher conversation explaining the topic in a relatable way.
Introduction to Elastic Potential Energy
🔒 Unlock Audio Lesson
Sign up and enroll to listen to this audio lesson
Today, we'll learn about elastic potential energy in a wire. Can anyone explain what happens when we stretch a wire?
I think stretching a wire requires a force, and the wire gets longer.
That's correct! The work done by the force is stored in the wire as elastic potential energy. Why do you think this energy is important?
Because the wire can return to its original shape after we stop applying the force!
Exactly! This is crucial in applications like springs. Remember, the energy stored is a function of stress and strain.
Mathematical Relationships
🔒 Unlock Audio Lesson
Sign up and enroll to listen to this audio lesson
Let's dive into the equations. When we stretch the wire, we apply a force, right? Can someone write the formula for the force acting in terms of Young's modulus?
It should be F = YA × (l/L)!
Great! Now, if we want to find the work done as we stretch the wire from L to L + l, what equation do we use?
We can integrate, right? So W would be the integral of that force over the length.
Exactly! Integrating gives us the total work done, or the elastic potential energy stored, represented as u = (1/2) × σ × ε. This connection is key for engineers!
Significance of Elastic Potential Energy
🔒 Unlock Audio Lesson
Sign up and enroll to listen to this audio lesson
Why do we care about the elastic potential energy in designs like bridges or cranes?
Because we need materials that can handle stress without permanent deformation!
Correct! It's risky to exceed the elastic limit of a material. Can you visualize a scenario where knowing this might save lives?
If a cable in a crane stretched too much and broke?
Exactly! Understanding these concepts helps us design safer and more efficient structures.
Calculations of Work and Energy
🔒 Unlock Audio Lesson
Sign up and enroll to listen to this audio lesson
Let's do a quick calculation together. If we have a wire with L = 2 m and A = 1 × 10^-4 m², with a Young’s modulus of 200 GPa, what would the elastic potential energy be if the wire is stretched by 0.01 m?
I think we use the formula for work done!
Yes, we start with calculating stress and strain first. What is the stress here?
Stress would be 200 GPa × (0.01/2) = 1 GPa!
Good! And the energy would then be calculated using u = (1/2) × σ × ε. You’re getting it!
Introduction & Overview
Read summaries of the section's main ideas at different levels of detail.
Quick Overview
Standard
When a wire is stretched due to an applied force, work is performed against inter-atomic forces, resulting in the storage of elastic potential energy. The mathematical relation depicts the dependence on Young's modulus, stress, strain, and the wire's volume.
Detailed
Elastic Potential Energy in a Stretched Wire
When a wire experiences tensile stress, work must be done against the inter-atomic forces to elongate the wire. The work done on the wire is stored as elastic potential energy, which can be released when the wire returns to its original length after the force is removed. For a wire of original length L and cross-sectional area A subjected to a deforming force F, if the length is elongated by a small amount l, we can establish the relationship:
Mathematical Relationships
Using Young's modulus (Y) which relates stress (σ) and strain (ε), we can express the work done (W) in increasing the length of the wire:
- The force can be described as:
$$F = YA \frac{l}{L}$$
- The incremental work done, $dW$ is related to the force and an infinitesimal change in length, leading to:
$$dW = F \cdot dl = YA \frac{l}{L} dl$$
- The total work done in stretching from length L to L + l can be integrated:
$$W = \int_0^{l} \frac{1}{2} YA \frac{l}{L} dl = \frac{1}{2} Y \cdot \text{strain}^2 \cdot \text{volume of the wire}$$
- Hence, the elastic potential energy per unit volume is:
$$u = \frac{1}{2} \sigma \epsilon$$
This relationship illustrates that the stored elastic potential energy is not just a function of the material properties but also of the geometry and the deformation applied.
Youtube Videos
Audio Book
Dive deep into the subject with an immersive audiobook experience.
Work Done Against Inter-atomic Forces
Chapter 1 of 5
🔒 Unlock Audio Chapter
Sign up and enroll to access the full audio experience
Chapter Content
When a wire is put under a tensile stress, work is done against the inter-atomic forces.
Detailed Explanation
When a wire is stretched, atomic forces attempt to return it to its original shape. To elongate the wire, external force must be applied, overcoming these forces. This work done is stored as elastic potential energy in the wire.
Examples & Analogies
Think of stretching a rubber band. When you pull on it, you're doing work against the forces that try to keep it at its original length. The more you stretch it, the more energy you store in the band.
Relationship Between Force, Length, and Potential Energy
Chapter 2 of 5
🔒 Unlock Audio Chapter
Sign up and enroll to access the full audio experience
Chapter Content
When a wire of original length L and area of cross-section A is subjected to a deforming force F along the length of the wire, let the length of the wire be elongated by l. Then from Eq. (8.8), we have F = YA × (l/L).
Detailed Explanation
This equation derives from the definition of Young's modulus (Y), which describes how much a wire will elongate (l) when a certain force (F) is applied. The relationship indicates that the force required to stretch the wire is proportional to its cross-sectional area and inversely proportional to its original length.
Examples & Analogies
Imagine trying to stretch two different lengths of wire; a longer wire takes less force to stretch a certain distance than a shorter one. This is because the longer wire can distribute the stress more evenly.
Calculating Work Done During Elongation
Chapter 3 of 5
🔒 Unlock Audio Chapter
Sign up and enroll to access the full audio experience
Chapter Content
Now for a further elongation of infinitesimal small length d l, work done d W is F × dl or YAldl/L.
Detailed Explanation
The work done (dW) to stretch the wire by an infinitesimal length (dl) can be calculated by multiplying the force (F) by the small change in length (dl). This relationship integrates the force applied over the length to find the total work done (W) during the entire elongation.
Examples & Analogies
Think of pushing a swing. The further you push it (elongate it), the more effort (work) you exert to keep it moving—similarly, the effort increases as you stretch a wire more.
Formula for Elastic Potential Energy
Chapter 4 of 5
🔒 Unlock Audio Chapter
Sign up and enroll to access the full audio experience
Chapter Content
The amount of work done ( W) in increasing the length of the wire from L to L + l, that is from l = 0 to l = l is W = (1/2) × Young’s modulus × strain² × volume of the wire.
Detailed Explanation
This formula reveals that the total elastic potential energy (W) stored in the wire equals half the product of Young’s modulus (Y), the square of the strain, and the volume of the wire. This indicates that stronger materials and greater deformations lead to more stored energy.
Examples & Analogies
Consider a charged battery. The more you charge it (like the more you stretch the wire), the more energy it stores. Similarly, the wire retains energy based on how much it is stretched and its material properties.
Elastic Potential Energy per Unit Volume
Chapter 5 of 5
🔒 Unlock Audio Chapter
Sign up and enroll to access the full audio experience
Chapter Content
Therefore the elastic potential energy per unit volume of the wire (u) is u = (1/2) × σ × ε.
Detailed Explanation
The formula u = (1/2) × σ × ε tells us how much elastic potential energy is stored in a given volume of material. Here, σ is stress, and ε is strain. This signifies that the energy density increases with stress and strain, consolidating the relationship between deformation and energy storage.
Examples & Analogies
Think of a sponge. The denser the sponge, the more energy (or force) it takes to compress it, which relates to how much potential energy it can store when compressed.
Key Concepts
-
Elastic Potential Energy: Energy stored when a wire is stretched, derived from work done against inter-atomic forces.
-
Young's Modulus: Relates stress with strain; crucial for understanding how materials behave under load.
-
Work Done: Energy required to stretch a wire, calculated through the force applied over a distance.
Examples & Applications
Example 1: A steel wire of 2 m length with a cross-section of 1 cm² stretched by 1 cm stores elastic potential energy that can be calculated using the established formulas.
Example 2: A rubber band when stretched stores elastic potential energy, and this energy can be used for propulsion when released.
Memory Aids
Interactive tools to help you remember key concepts
Rhymes
Stretch the wire, feel it grow, Energy stored, now you know!
Stories
Imagine a rubber band, stretched tight, holds energy like a superhero ready for flight!
Memory Tools
W = 1/2 × stress × strain, remember: that's how energy is gained!
Acronyms
EPE for Elastic Potential Energy
Energy Packed Easily.
Flash Cards
Glossary
- Elastic Potential Energy
The energy stored in a body when it is deformed elastically, proportional to the stress and strain applied.
- Tensile Stress
The stress that occurs when forces are applied to stretch a material.
- Young's Modulus
A measure of the stiffness of a solid material and a factor that relates stress to strain.
- Strain
The measure of deformation representing the displacement between particles in a material body.
- Work Done
The energy transferred by a force acting over a distance, in this case, the force stretching the wire.
Reference links
Supplementary resources to enhance your learning experience.