STRESS AND STRAIN - 8.2 | 8. MECHANICAL PROPERTIES OF SOLIDS | CBSE 11 Physics Part 2
K12 Students

Academics

AI-Powered learning for Grades 8–12, aligned with major Indian and international curricula.

Professionals

Professional Courses

Industry-relevant training in Business, Technology, and Design to help professionals and graduates upskill for real-world careers.

Games

Interactive Games

Fun, engaging games to boost memory, math fluency, typing speed, and English skillsβ€”perfect for learners of all ages.

Interactive Audio Lesson

Listen to a student-teacher conversation explaining the topic in a relatable way.

Introduction to Stress

Unlock Audio Lesson

Signup and Enroll to the course for listening the Audio Lesson

0:00
Teacher
Teacher

Today, we’ll discuss the concept of stress, which is the restorative force per unit area when a force is applied to a solid body. Does anyone know how we can calculate stress?

Student 1
Student 1

Isn't it something like force divided by area?

Teacher
Teacher

Exactly! The formula for stress is Οƒ = F/A, where F is the applied force and A is the cross-sectional area. Remember, the unit of stress is Pascal (Pa), which is equivalent to N/mΒ².

Student 2
Student 2

What happens when we apply that force?

Teacher
Teacher

Good question! When a force is applied, it can cause deformation, which brings us to the next concept β€” strain.

Teacher
Teacher

Let's summarize: Stress is defined as force per area, and its unit is Pascal. Now, let's dive into strain.

Understanding Strain

Unlock Audio Lesson

Signup and Enroll to the course for listening the Audio Lesson

0:00
Teacher
Teacher

Strain is defined as the ratio of change in dimension to the original dimension. Who can tell me the formula for longitudinal strain?

Student 3
Student 3

It's Ξ”L over L, right? Where Ξ”L is the change in length?

Teacher
Teacher

Correct! Longitudinal strain is indeed Ξ”L/L. There are also other types of strain like shearing strain and volumetric strain. Can anyone tell me what shearing strain relates to?

Student 4
Student 4

Is it related to how much one part of the material slides over another part?

Teacher
Teacher

Yes! That’s right! Shearing strain is defined as the ratio of the displacement (Ξ”x) between two sections to the original length (L). Great job!

Teacher
Teacher

To recap: Strain is Ξ”L/L for longitudinal strain, and there are also shearing and volumetric strains based on the types of forces applied.

Application of Stress and Strain in Engineering

Unlock Audio Lesson

Signup and Enroll to the course for listening the Audio Lesson

0:00
Teacher
Teacher

Now, let's talk about how stress and strain apply in engineering and real-world applications. Why do you think understanding these concepts is essential when designing buildings or bridges?

Student 1
Student 1

Because if we don't consider stress and strain, the structures could fail, right?

Teacher
Teacher

Exactly! Engineers must ensure the materials used can withstand the stress without exceeding their elastic limits. Do you remember the different types of stress?

Student 2
Student 2

Tensile, compressive, and shearing stress!

Teacher
Teacher

Correct! Each type of stress affects the materials differently, and knowing these helps in making informed design decisions. For example, a bridge must be designed to handle not only the weight of vehicles but also any lateral forces from the wind.

Teacher
Teacher

To summarize, stress and strain are crucial for safety and efficiency in engineering, and understanding their various forms is key to successful design.

Introduction & Overview

Read a summary of the section's main ideas. Choose from Basic, Medium, or Detailed.

Quick Overview

This section discusses stress and strain in solids, describing how forces applied to bodies cause deformation.

Standard

The section introduces the concepts of stress as a restoring force per unit area and strain as the ratio of change in dimension to the original dimension. It categorizes stress into tensile, compressive, and shearing, while highlighting the relevance of these concepts in engineering and design.

Detailed

Stress and Strain

In mechanics, when external forces are applied to a body at static equilibrium, they lead to deformations, either noticeable or otherwise. This section explains two foundational concepts: stress and strain.

  • Stress is defined as the restoring force generated in an object per unit area and can be calculated using the formula:

Stress (Οƒ) = F/A
where F is the applied force and A is the cross-sectional area. The unit of stress is Pascal (Pa).

  • Strain, on the other hand, refers to the deformation of an object relative to its original dimensions, expressed as the ratio of change in dimension to the original dimension. The type of strain varies by the kind of stress applied:
  • Longitudinal Strain (s = βˆ†L/L): Caused by tensile or compressive stress.
  • Shearing Strain (βˆ†x/L = tanΞΈ): Resulting from tangential forces while the object remains parallel between two sections.
  • Volumetric Strain (βˆ†V/V): Occurs due to uniform pressure applied to a solid, resulting in a change in volume without altering its shape.

Additionally, the section exemplifies stress and strain applications, emphasizing their significance in engineering and everyday structures, like buildings and bridges.

Youtube Videos

Mechanical Properties of Solids One Shot | Class 11th Physics NCERT With Ashu Sir
Mechanical Properties of Solids One Shot | Class 11th Physics NCERT With Ashu Sir
Stress Strain Curve For a Metallic Wire Physics Class 11 Term 2 || Mechanical Properties of Solids
Stress Strain Curve For a Metallic Wire Physics Class 11 Term 2 || Mechanical Properties of Solids
Physics Mechanical Properties of Solids part 2 (Stress) CBSE class 11
Physics Mechanical Properties of Solids part 2 (Stress) CBSE class 11
Stress, Strain and Hooke's Law | Mechanical Properties of Solids | Physics | Class 11
Stress, Strain and Hooke's Law | Mechanical Properties of Solids | Physics | Class 11
Stress and Strain | Mechanical Properties of Solids | Don't Memorise
Stress and Strain | Mechanical Properties of Solids | Don't Memorise
Mechanical properties of Solids class 11 - CBSE JEE NEET | One Shot | Chapter 9
Mechanical properties of Solids class 11 - CBSE JEE NEET | One Shot | Chapter 9
Stress & Strain - Mechanical Properties of Solids | Class 11 Physics Chapter 8 | CBSE
Stress & Strain - Mechanical Properties of Solids | Class 11 Physics Chapter 8 | CBSE
Mechanical Properties of Solids | Class 11 Physics Chapter 8 One Shot | New NCERT CBSE
Mechanical Properties of Solids | Class 11 Physics Chapter 8 One Shot | New NCERT CBSE
Mechanical Properties of Solids Class 11 One Shot | NCERT Physics Full Chapter-8 Revision| CBSE 2025
Mechanical Properties of Solids Class 11 One Shot | NCERT Physics Full Chapter-8 Revision| CBSE 2025
Mechanical Properties of Solids | CBSE Class 11th Physics | Full Chapter in πŸ”Ÿ MinsπŸ”₯ | Rapid Revision
Mechanical Properties of Solids | CBSE Class 11th Physics | Full Chapter in πŸ”Ÿ MinsπŸ”₯ | Rapid Revision

Audio Book

Dive deep into the subject with an immersive audiobook experience.

Definition of Stress

Unlock Audio Book

Signup and Enroll to the course for listening the Audio Book

When forces are applied on a body in such a manner that the body is still in static equilibrium, it is deformed to a small or large extent depending upon the nature of the material of the body and the magnitude of the deforming force. The restoring force per unit area is known as stress.

Detailed Explanation

When a solid object is subjected to an external force, it undergoes deformation. This deformation is countered by an internal restoring force exerted by the material, which tries to return the object to its original shape. Stress is defined as this restoring force per unit area. Thus, if we have a force (F) acting on a surface with an area (A), the stress (Οƒ) can be calculated using the formula Οƒ = F/A. The SI unit of stress is pascal (Pa), which is equivalent to N/mΒ².

Examples & Analogies

Think of stress as how hard you press down with your finger on a soft sponge. The harder you press (increased force), the more the surface of the sponge deforms (more stress applied). If you stop pressing, the sponge wants to return to its original shape, similar to how materials behave under applied stress.

Types of Stress

Unlock Audio Book

Signup and Enroll to the course for listening the Audio Book

There are three ways in which a solid may change its dimensions when an external force acts on it. These are: tensile stress, compressive stress, and shear stress.

Detailed Explanation

When an external force is applied to a solid, it can experience different types of stress based on the direction of that force. Tensile stress occurs when forces are applied to stretch the material (like pulling a rubber band). Compressive stress happens when forces push the material, causing it to compress (like pressing down on a sponge). Shear stress is observed when forces are applied parallel to the surface, causing layers of the material to slide over each other (imagine sliding one deck of cards over another).

Examples & Analogies

Visualize a piece of clay. If you pull on it from opposite ends, you're applying tensile stress. If you push the clay down, you're applying compressive stress. If you press down on one side of the clay while keeping the other side steady, you're applying shear stress, causing the clay to distort.

Strain and Its Relation to Stress

Unlock Audio Book

Signup and Enroll to the course for listening the Audio Book

The change in length Ξ”L to the original length L of the body is called longitudinal strain. Longitudinal strain is defined as Ξ”L/L.

Detailed Explanation

Strain is a measure of how much deformation a material undergoes in response to an applied stress. For longitudinal strain, it quantifies the change in length (Ξ”L) of a material compared to its original length (L). The formula for longitudinal strain is expressed as Ξ΅ = Ξ”L / L, which is a dimensionless quantity since it’s a ratio of lengths.

Examples & Analogies

Consider stretching a rubber band. If you pull it from its original length of 10 cm to a new length of 12 cm, the change in length (Ξ”L) is 2 cm. The strain would be 2 cm / 10 cm = 0.2 or 20%. This indicates how much the band has deformed relative to its original size.

Shearing Stress and Strain

Unlock Audio Book

Signup and Enroll to the course for listening the Audio Book

When two equal and opposite deforming forces are applied parallel to the cross-sectional area of the cylinder, there is a relative displacement βˆ†x between opposite faces of the cylinder. The strain is known as shearing strain and is defined as the ratio of relative displacement of the faces βˆ†x to the length of the cylinder L.

Detailed Explanation

When forces are applied parallel to a surface, the material experiences shear stress that causes layers to slide over one another. The resulting displacement (βˆ†x) between two faces of the object divided by the length (L) gives us shearing strain. This can be expressed as Ξ³ = βˆ†x / L, which typically involves small angles where the tangent can be approximated as equal to the angle in radians.

Examples & Analogies

Imagine a thick book lying flat on a table. If you push the top of the book sideways while keeping the bottom fixed, the top slides over the bottom, creating an angle with respect to the vertical. This sliding motion is similar to shear deformation, where the book's layers experience shearing stress.

Hydraulic Compression

Unlock Audio Book

Signup and Enroll to the course for listening the Audio Book

In this scenario, a solid sphere placed in the fluid under high pressure is compressed uniformly on all sides. The force applied by the fluid acts in a perpendicular direction at each point of the surface, leading to a decrease in its volume without any change of its geometrical shape.

Detailed Explanation

Hydraulic compression occurs when a fluid exerts pressure evenly across the surface of an object. This results in volume strain expressed as the ratio of the change in volume (Ξ”V) to the original volume (V). The internal restoring forces counteract this pressure, allowing the material to potentially return to its original state when the pressure is released.

Examples & Analogies

Think about a sponge submerged in water under pressure. The water compresses the sponge equally from all sides. Even though the sponge gets smaller in size, its shape remains consistent until the pressure is released, at which point the sponge can restore itself.

Definitions & Key Concepts

Learn essential terms and foundational ideas that form the basis of the topic.

Key Concepts

  • Stress: The force per unit area causing deformation in a solid.

  • Strain: The measure of deformation representing the displacement between particles in a material.

  • Tensile Stress: Stress that occurs when a material is pulled or stretched.

  • Compressive Stress: Stress that occurs when a material is compressed or squished.

  • Shearing Stress: Stress that occurs when forces cause different parts of a material to move in parallel.

  • Hydraulic Stress: Stress that results from pressure exerted by a surrounding fluid.

  • Longitudinal Strain: Change in length compared to the original length due to applied force.

  • Shearing Strain: The displacement of layers relative to each other due to shear force.

  • Volume Strain: Change in volume relative to the original volume.

Examples & Real-Life Applications

See how the concepts apply in real-world scenarios to understand their practical implications.

Examples

  • A rubber band stretched by a force demonstrates tensile stress, with the elongation being the strain.

  • When pressing a deck of cards sideways, the relative sliding shows shearing stress.

  • When a balloon is inflated, the external air pressure causes hydraulic stress on the skin of the balloon, leading to volume strain.

Memory Aids

Use mnemonics, acronyms, or visual cues to help remember key information more easily.

🎡 Rhymes Time

  • Stress is a force, per area it shows,

πŸ“– Fascinating Stories

  • Imagine a brave rope, stretched tight in a tug-of-war game.

🧠 Other Memory Gems

  • Remember 'S' for Stress and 'S' for Shear - both involve forces that persevere.

🎯 Super Acronyms

Use the acronym 'SST' for Stress types

  • Tension
  • Shear
  • and Compression.

Flash Cards

Review key concepts with flashcards.

Glossary of Terms

Review the Definitions for terms.

  • Term: Stress

    Definition:

    The restoring force per unit area when an external force is applied to a solid.

  • Term: Strain

    Definition:

    The ratio of change in dimension to its original dimension due to applied stress.

  • Term: Tensile Stress

    Definition:

    Stress created by a force that tends to stretch or elongate a material.

  • Term: Compressive Stress

    Definition:

    Stress that results from forces that tend to compress or shorten a material.

  • Term: Shearing Stress

    Definition:

    Stress resulting from applied forces that slide one part of a material parallel to another.

  • Term: Hydraulic Stress

    Definition:

    Stress exerted on an object submerged in a fluid, applying pressure at all points.

  • Term: Longitudinal Strain

    Definition:

    Strain due to change in length, calculated as the change in length divided by the original length.

  • Term: Shearing Strain

    Definition:

    Strain that occurs when forces cause two adjacent parts of a material to slide relative to one another.

  • Term: Volume Strain

    Definition:

    Strain that involves a change in volume relative to the original volume.