Details of Instruction Fetching - 30.1.2 | 30. Examples of Multiple Bus Architecture | Computer Organisation and Architecture - Vol 2
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Understanding Bus Architectures

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Teacher
Teacher

Welcome everyone! Today, we’re diving into the differences between single and multiple bus architectures in a CPU. Can anyone tell me why bus architectures are critical in computing?

Student 1
Student 1

I think they connect different parts of the computer to communicate.

Teacher
Teacher

Exactly! They enable communication between components. So, what happens when we have more than one bus?

Student 2
Student 2

It can handle more data at once, right?

Teacher
Teacher

Precisely! Multiple buses allow for parallel processing. Remember the acronym MIPS for Multiple Instruction Parallel Systems, which highlights this efficiency.

Instruction Fetching with Multiple Buses

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Teacher
Teacher

Now, let’s look at an example of adding registers R1 and R2 using a multiple bus architecture. What do you think the advantages are?

Student 3
Student 3

Maybe it fetches the instructions quicker because it gets data from multiple places?

Teacher
Teacher

Right, it can fetch multiple parts simultaneously without temporary registers! Can someone explain how the PC interacts with the MAR?

Student 4
Student 4

The PC outputs its value to the MAR, so it knows where to read instructions from.

Teacher
Teacher

Great! And by avoiding the need for temporary storage, we save steps. MIPs comes into play again here.

Limitations of Multiple Buses

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Teacher
Teacher

While we see advantages of multiple buses, there are exceptions. What do you think can cause drawbacks?

Student 1
Student 1

Maybe some instructions don’t require much data, so the bus advantage isn’t significant?

Teacher
Teacher

Correct! For example, when loading values from memory, the steps can appear similar on both architectures. Why do we think that is?

Student 2
Student 2

Because the overall pattern of fetching stays consistent across other instructions?

Teacher
Teacher

Exactly! Consistently, both architectures have to get the instruction from the MAR, which means sometimes the advantages balance out.

Practical Example Discussion

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Teacher
Teacher

Let’s break down a practical example! When we issue an instruction to load from memory into R1, what steps do we take with multiple buses?

Student 3
Student 3

First, the PC outputs to the MAR and reads the instruction.

Teacher
Teacher

Great, and what comes next?

Student 4
Student 4

We wait for the instruction to show up in the memory data register.

Teacher
Teacher

Exactly! And then we move that to the register. Can you think why having more buses might complicate this?

Student 1
Student 1

Maybe we have to specify different buses for output?

Teacher
Teacher

Right! The use of buses becomes more explicit, highlighting how we can manage data flow effectively.

Introduction & Overview

Read a summary of the section's main ideas. Choose from Basic, Medium, or Detailed.

Quick Overview

This section explores the advantages and limitations of a multiple bus architecture for instruction fetching compared to a single bus architecture.

Standard

The section discusses two scenarios involving the addition of registers to illustrate the efficiency of multiple buses in fetching instructions and how this architecture handles instructions without the need for temporary registers. It also highlights instances where the multiple bus architecture may not offer significant advantages.

Detailed

In this section, we delve into two distinct examples to understand the instruction fetching process in multiple bus architectures versus single bus architectures. First, we demonstrate the benefits of using a three-bus system when adding registers R1 and R2, showcasing how this architecture allows for parallel processing without needing temporary registers (such as Z or Y). The program counter's (PC) output directs the memory address register (MAR), facilitating a smoother flow where the memory can be read, and the program counter can be updated in a single step.

The section emphasizes that while multiple buses enhance efficiency by allowing more components to operate simultaneously, there can be exceptions where the advantages diminish, particularly in instructions such as loading a value from memory that requires fewer inherent complexities. Analyzing the instruction fetching details in both architectures provides insights into the architectural decisions that affect performance, efficiency, and overall processing time.

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Audio Book

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Example of Instruction Fetching

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Now, we are going to take two examples; in one example we will show that what are the advantages of having three buses and another case we will show that we do not get so much advantage, if you are considering a multiple bus architecture. Two extremes that means two different instructions we will take and show, but for most of the cases we are always going to have an advantage, because that is very obvious because if you have multiple buses things will go parallelly, but for one or two stray examples we can see where the advantage is not there in fact, you are having more hardware, but still the number of stages are not reducing.

Detailed Explanation

This chunk introduces the concept of comparing two examples to demonstrate the advantages of a multiple bus architecture versus a single bus architecture for instruction fetching. The idea is to show how multiple buses allow operations to occur simultaneously, resulting in better performance. However, there are exceptions where having more buses may not yield significant benefits due to increased hardware complexity and unchanged stages in processing.

Examples & Analogies

Think of a highway with multiple lanes (multiple buses) where cars can travel side by side, allowing for faster movement. In contrast, imagine a single-lane road (single bus) where only one car can go at a time. While having more lanes often allows for quicker travel, there might be unique situations, like road construction, where the extra lanes do not help if the road still has to slow down or stop.

Instruction Fetching Process

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So, the first case we are going to take is add 𝑅 into 𝑅 . So, what is the thing? So, two variables 1 2 already available in 𝑅 and 𝑅 and then one you have to do it. So, first is you have to fetch the instruction. So, how do you fetch the instruction? Basically program counter output value will go to memory address register in, that is as simple as for single bus architecture then you put the memory in read mode here you select 0; that means, you want to add the constant and increment program counter and add.

Detailed Explanation

In this chunk, the focus is on the instruction fetching process, specifically for the operation add R1 into R2. The first step involves fetching the instruction by taking the output from the program counter (PC) and moving it to the memory address register (MAR). This step sets up the system to read from memory by selecting the correct mode and value to add and also incrementing the program counter to point to the next instruction.

Examples & Analogies

Imagine you're following a recipe (the instruction) to make a dish. The program counter is like your bookmark in the recipe book, indicating which step you're currently on. When you fetch the instruction, it's like checking your current step in the recipe, preparing to gather the next ingredients (data) you need to proceed.

Temporary Registers and Control Signals

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But if you look at a single bus architecture, we had another signal that is called 𝑍 . Because the output of program counter plus constant has to store in a separate temporary register which we call it Z or Y and we have to wait till this step is over then only you can write the value to the program counter. But in this case as we have already seen we do not require any kind of a temporary register.

Detailed Explanation

This chunk explains the role of temporary registers in the fetching process. In a single bus architecture, a temporary register (Z or Y) would be necessary to hold an interim value while waiting to update the program counter after fetching the instruction. However, in the new architecture being discussed, this temporary register is not needed, simplifying the fetching process.

Examples & Analogies

Consider a person gathering ingredients for cooking. In a single bus architecture, they might set aside some ingredients on a counter (temporary register) before moving them to the pot (program counter). In the optimized architecture, they can directly place the ingredients into the pot without the need for a temporary setting area, making the cooking process smoother and faster.

Bus Architecture Flexibility

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So, even if I can take the input from here, but we are not doing it, because the PC is writing through bus B; but it can also be done, but if you have to you have to take the output for program counter through bus A, you have to disconnect this line and you have to disconnect this line. So, any option you can take. So, as I told you this is a very flexible architecture you can have your own design in this case we are taking this.

Detailed Explanation

This chunk discusses the flexibility of the bus architecture. It highlights that while there are preferred methods, different configurations can be chosen based on the design needs. This adaptability allows engineers to optimize the systems in ways that work best for them.

Examples & Analogies

Think of a flexible electrical wiring system in a house. While it’s standard to use certain configurations for efficiency, an electrician can choose to rearrange connections to suit the needs of specific appliances or lighting configurations—just as engineers can adjust bus connections.

Final Steps of Instruction Fetching

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Next stage is simple you have to make PC in read the value of output to the PC, and wait till the memory response. And if you look at the single bus architecture, these things were very similar you have to read the value of PC, WMFC, but also you had a sin single instruction called 𝑍 . 𝑍 will go to the value of PC in, but here PC in will not require any 𝑍 , because out already bus C is carrying the value of the new value of the program counter.

Detailed Explanation

In this final step of instruction fetching, the program counter is updated directly from bus C without needing a temporary register. This process is similar in a single bus architecture, but again emphasizes how the multiple bus system streamlines the fetching and updating process by reducing control signals and stages.

Examples & Analogies

If we liken the program counter to a reader turning pages in a book, in a single bus architecture, the reader might pause to hold bookmarks (temporary registers) for various steps. In contrast, with a more streamlined method, readers can just flip pages directly without needing to hold their place elsewhere, making for a faster reading experience.

Definitions & Key Concepts

Learn essential terms and foundational ideas that form the basis of the topic.

Key Concepts

  • Multiple Bus Advantage: Enhances instruction fetching by allowing parallel operations.

  • Single Bus Limitation: May complicate data flow and requires temporary registers.

  • Instruction Fetching: The process of retrieving instructions from memory for execution.

Examples & Real-Life Applications

See how the concepts apply in real-world scenarios to understand their practical implications.

Examples

  • In a three-bus architecture, fetching the instruction and updating the program counter can happen simultaneously, improving efficiency.

  • Loading a register from memory might not see different steps in both architectures as they follow a consistent fetching pattern.

Memory Aids

Use mnemonics, acronyms, or visual cues to help remember key information more easily.

🎵 Rhymes Time

  • Bus architectures here and there, with multiple buses, data can share!

📖 Fascinating Stories

  • Imagine a busy post office: with multiple workers (buses), they can deliver letters (data) simultaneously.

🧠 Other Memory Gems

  • MIPS: Multiple Instructions Parallel Systems helps remember the advantage of multiple bus architectures.

🎯 Super Acronyms

MANA

  • Multiple Architecture Navigates Access
  • emphasizing why a multiple bus architecture is efficient.

Flash Cards

Review key concepts with flashcards.

Glossary of Terms

Review the Definitions for terms.

  • Term: Program Counter (PC)

    Definition:

    A register that contains the address of the next instruction to be executed.

  • Term: Memory Address Register (MAR)

    Definition:

    A register that holds the address of the memory location to be accessed.

  • Term: Multiple Bus Architecture

    Definition:

    A computer architecture that uses more than one bus for data transfer, allowing parallel operations.

  • Term: Single Bus Architecture

    Definition:

    A simpler architecture that uses one bus for data transfer, which can complicate data handling.

  • Term: Temporary Register

    Definition:

    A register used to hold intermediate values during computations.