Industry-relevant training in Business, Technology, and Design to help professionals and graduates upskill for real-world careers.
Fun, engaging games to boost memory, math fluency, typing speed, and English skillsβperfect for learners of all ages.
Enroll to start learning
Youβve not yet enrolled in this course. Please enroll for free to listen to audio lessons, classroom podcasts and take mock test.
Listen to a student-teacher conversation explaining the topic in a relatable way.
Signup and Enroll to the course for listening the Audio Lesson
Good morning, class! Today, we are diving into how to divide a polynomial by a monomial. First, can anyone remind me what a polynomial is?
A polynomial is an expression that consists of variables and coefficients, combined using addition, subtraction, and multiplication.
Exactly! And what about a monomial?
A monomial is a single term that can be a number, variable, or the product of numbers and variables.
Great! Now, letβs explore how to divide a polynomial by a monomial. What do you think is the first step?
Maybe we should factor the polynomial?
Exactly! Let's take the polynomial `4yΒ³ + 5yΒ² + 6y` and divide it by `2y`. We start by factoring out `2y`.
So, we rewrite the polynomial to show that `2y` is common in all terms?
That's right! And then we can simplify further. Letβs summarize: We factor out `2y` from each term.
Signup and Enroll to the course for listening the Audio Lesson
Now that weβve factored out `2y`, can you simplify `4yΒ³, 5yΒ²,` and `6y` individually divided by `2y`?
For `4yΒ³ Γ· 2y`, we get `2yΒ²`. For `5yΒ² Γ· 2y`, it simplifies to `2.5y`, which is `y`. And for `6y Γ· 2y`, it's `3`.
Excellent work! Now, can we gather these results back together?
Yes! We can write it as `2yΒ² + 2.5y + 3`.
Good job! Remember, separating the common factor helps us divide each term easily.
This makes division less complicated!
Exactly! So, whenever you see a polynomial division, look for those common factors.
Signup and Enroll to the course for listening the Audio Lesson
Now, letβs discuss another way to perform polynomial division. Instead of factoring out common terms, we can directly divide each term. Can anyone explain how this method works?
We just divide `4yΒ³`, `5yΒ²`, and `6y` by `2y` directly?
Exactly! Letβs run through it with our example: `4yΒ³ + 5yΒ² + 6y` divided by `2y`.
Right! So, `4yΒ³ Γ· 2y = 2yΒ²`, `5yΒ² Γ· 2y = 2.5y`, and `6y Γ· 2y = 3`.
Well done! And what do we get when we summarize these results?
We still get `2yΒ² + 2.5y + 3`!
Exactly! Both methods lead to the same result. Itβs important to be comfortable with both approaches.
Read a summary of the section's main ideas. Choose from Basic, Medium, or Detailed.
The section teaches the process of dividing a polynomial by a monomial using two methods: separating common factors from each term or dividing each term individually. This process helps simplify expressions and is essential for algebraic manipulations.
In this section, we delve into the process of dividing a polynomial by a monomial, an essential skill in algebra. A polynomial can consist of multiple terms, and when we want to divide such an expression by a monomial, we can utilize two effective methods.
Example:
For instance, consider dividing the polynomial 4yΒ³ + 5yΒ² + 6y
by the monomial 2y
. We can express each term in this polynomial in terms of 2y
, allowing for simplification:
2y
:4yΒ³ + 5yΒ² + 6y = 2y(2yΒ² + y + 3)
(4yΒ³ + 5yΒ² + 6y) Γ· 2y = 2yΒ² + y + 3
.Through this section, students will understand how to effectively handle polynomial expressions when divided by monomials, vital for more advanced algebraic concepts.
Example : Divide \( 18(x^2y + y^2z + z^2x) \) by \( 6xyz \) using both methods.
Solution:
\[ 18(x^2y + y^2z + z^2x) = 18 \cdot (x^2y) + 18 \cdot (y^2z) + 18 \cdot (z^2x) \]
\[ = 3 \cdot 6(x^2y + y^2z + z^2x) \]
Taking out the common factor, we have:
\[ = 3\cdot6(x + y + z) \]
Therefore,
\[ \frac{18(x^2y + y^2z + z^2x)}{6xyz} = 3(x + y + z) \]
Alternately, \( 18(x^2y + y^2z + z^2x) \) can also be simplified to \( 3x^2y + 3y^2z + 3z^2x = 3(x^2y + y^2z + z^2x) \)
\[ = 3\cdot 6(x + y + z) \]
Dive deep into the subject with an immersive audiobook experience.
Signup and Enroll to the course for listening the Audio Book
Let us consider the division of the trinomial 4y3 + 5y2 + 6y by the monomial 2y.
In polynomial division, we want to divide a polynomial expression by a monomial. For instance, we are dividing the polynomial 4yΒ³ + 5yΒ² + 6y by 2y. This process involves determining how many times the monomial fits into each term of the polynomial.
Think of this division as sharing a bag of candies (the polynomial) among friends (the monomial). If each friend gets a certain number of candies, you need to know how many bags you have for each friend to get their fair share.
Signup and Enroll to the course for listening the Audio Book
4y3 + 5y2 + 6y = (2 Γ 2 Γ y Γ y Γ y) + (5 Γ y Γ y) + (2 Γ 3 Γ y) (Here, we expressed each term of the polynomial in factor form) we find that 2 Γ y is common in each term.
In this step, we rewrite each term of the polynomial in its factor form to spot common factors. Here, 2y is a common factor in each term: 4yΒ³ can be factored as 2y(2yΒ²), 5yΒ² as 2y(2.5y), and 6y can be factored as 2y(3). This identification allows us to factor out 2y from the entire polynomial.
Imagine a group project where everyone has shared responsibilities. If everyone is responsible for bringing 2 notebooks, you can factor out the notebooks from each person's contribution and just account for the dwindled amount of resources separately.
Signup and Enroll to the course for listening the Audio Book
Therefore, (4y3 + 5y2 + 6y) Γ· 2y = 2y(2yΒ² + y + 3) = 2yΒ² + y + 3.
Once the common factor 2y is factored out, we can divide the whole polynomial by 2y. The polynomial simplifies to 2yΒ² + y + 3, which are the new coefficients of each term after the division. This shows how many 'units' of y we have in each term.
Consider dividing a pizza (the polynomial) into slices (the monomial). After removing an equal number of slices (the common factor), you simply count how many entire slices are left in total, leading to a simpler understanding of your remaining pizza.
Signup and Enroll to the course for listening the Audio Book
Alternatively, we could divide each term of the trinomial by the monomial using the cancellation method.
In this alternative approach, we separately divide each term of the polynomial by the monomial. For 4yΒ³ Γ· 2y, we get 2yΒ²; for 5yΒ² Γ· 2y, we get 2.5y; and for 6y Γ· 2y, we get 3. When summed up, this results in 2yΒ² + 2.5y + 3, adding simplicity to the process through direct calculation.
Imagine splitting tasks among friends: if each friend can handle one specific task at a time, you divide each task equally, leading to a straightforward understanding of how many tasks are left once shared.
Signup and Enroll to the course for listening the Audio Book
Therefore, using both methods, we arrive at the result of the division of the polynomial by the monomial.
This final section summarizes that whether factoring out the common monomial or directly dividing each term, both methods provide a consistent and accurate result.
This is akin to using two different approaches to budgeting a project. Regardless of how you track expensesβby category (factoring) or individually (direct division)βthe total expenditure will remain the same, reinforcing that you can achieve the same goal through varied methods.
Learn essential terms and foundational ideas that form the basis of the topic.
Key Concepts
Factorization: The polynomial is expressed as a sum of terms, each of which can be factorized to identify common factors with the monomial.
Common Factors: We take the common factor out from each term in the polynomial, allowing us to simplify the expression.
Division of Each Term: Alternatively, we can directly divide each term of the polynomial by the monomial, which often leads to a straightforward simplification.
Example:
For instance, consider dividing the polynomial 4yΒ³ + 5yΒ² + 6y
by the monomial 2y
. We can express each term in this polynomial in terms of 2y
, allowing for simplification:
Factor out 2y
:
4yΒ³ + 5yΒ² + 6y = 2y(2yΒ² + y + 3)
The division then yields a simplified result as follows:
(4yΒ³ + 5yΒ² + 6y) Γ· 2y = 2yΒ² + y + 3
.
Through this section, students will understand how to effectively handle polynomial expressions when divided by monomials, vital for more advanced algebraic concepts.
Example : Divide \( 18(x^2y + y^2z + z^2x) \) by \( 6xyz \) using both methods.
Solution:
\[ 18(x^2y + y^2z + z^2x) = 18 \cdot (x^2y) + 18 \cdot (y^2z) + 18 \cdot (z^2x) \]
\[ = 3 \cdot 6(x^2y + y^2z + z^2x) \]
Taking out the common factor, we have:
\[ = 3\cdot6(x + y + z) \]
Therefore,
\[ \frac{18(x^2y + y^2z + z^2x)}{6xyz} = 3(x + y + z) \]
Alternately, \( 18(x^2y + y^2z + z^2x) \) can also be simplified to \( 3x^2y + 3y^2z + 3z^2x = 3(x^2y + y^2z + z^2x) \)
\[ = 3\cdot 6(x + y + z) \]
See how the concepts apply in real-world scenarios to understand their practical implications.
To divide the polynomial 4yΒ³ + 5yΒ² + 6y by the monomial 2y: Factor out 2y, yielding the result 2y(2yΒ² + y + 3) which simplifies to 2yΒ² + y + 3.
Dividing 24(xΒ²y + xyΒ² + xyz) by 8xyz results in 3(x + y + z) after common factor removal.
Use mnemonics, acronyms, or visual cues to help remember key information more easily.
Dividing by monomial, itβs simple, donβt fear, just take out whatβs shared, keep the process clear.
Imagine you have a box of different fruits represented as a polynomial. To share evenly, you take out what all fruits have in common - the monomial - and then see what remains for sharing!
Use 'FACTOR' to remember: Factor Out Common Terms, then Apply Simplifying Rules.
Review key concepts with flashcards.
Review the Definitions for terms.
Term: Polynomial
Definition:
An algebraic expression made up of one or more terms, with variables represented in non-negative integer exponents.
Term: Monomial
Definition:
A single term that can be a number, a variable, or a product of numbers and variables.
Term: Common Factor
Definition:
A number or expression that divides each term of a polynomial without leaving a remainder.