Industry-relevant training in Business, Technology, and Design to help professionals and graduates upskill for real-world careers.
Fun, engaging games to boost memory, math fluency, typing speed, and English skills—perfect for learners of all ages.
Enroll to start learning
You’ve not yet enrolled in this course. Please enroll for free to listen to audio lessons, classroom podcasts and take mock test.
Listen to a student-teacher conversation explaining the topic in a relatable way.
Signup and Enroll to the course for listening the Audio Lesson
Today, we’ll explore chlorine's average atomic mass and how we calculate it using isotopic abundance. Can anyone remind me what an isotope is?
Isotopes are atoms of the same element that have different numbers of neutrons.
Exactly! For example, chlorine has two main stable isotopes: chlorine-35 and chlorine-37. How do we think these isotopes affect the average atomic mass?
Does the average atomic mass depend on how much of each isotope is present?
Exactly! That’s called the isotopic abundance. Let’s move on to calculate the average atomic mass. We'll start by looking at the percent abundances of each isotope.
Signup and Enroll to the course for listening the Audio Lesson
First, we need to convert the abundances from percentages to fractions. Can anyone help me convert 75.78% into a decimal?
It would be 0.7578!
Great job! Now, how about 24.22%?
That would be 0.2422!
Correct! Now, why do we convert them like this?
Because we need to use these fractions to calculate the contribution of each isotope to the average atomic mass!
Exactly! Let’s move on to the next step.
Signup and Enroll to the course for listening the Audio Lesson
Now, we multiply each isotope’s mass by its fraction. For chlorine-35, what’s the calculation?
It would be 0.7578 multiplied by 34.9688527.
Excellent! Can anyone calculate that for me?
That gives approximately 26.5073 mass-units!
Perfect! Now, let's do the same for chlorine-37.
We multiply 0.2422 by 36.9659026 to get around 8.9458 mass-units.
Exactly right! So how do we find the average atomic mass?
Signup and Enroll to the course for listening the Audio Lesson
Now that we have both contributions, what’s the last step?
Add both contributions together!
Correct! What do we get?
26.5073 plus 8.9458 equals 35.4531 mass-units.
Great job everyone! The average atomic mass of chlorine is about 35.45 mass-units. Why is this important to know?
Because that’s how it’s listed in the periodic table!
Exactly! Great work today!
Read a summary of the section's main ideas. Choose from Basic, Medium, or Detailed.
The average atomic mass of chlorine is calculated as a weighted average of its isotopes, chlorine-35 and chlorine-37, using their respective masses and percent abundances. The process involves converting percentages to fractions, multiplying each isotope's mass by its fraction, and summing the results to find the average atomic mass.
This section provides a systematic method for calculating the average atomic mass of chlorine, which is crucial for understanding its properties in chemistry. Chlorine primarily consists of two stable isotopes: chlorine-35 (mass = 34.9688527 mass-units, abundance = 75.78%) and chlorine-37 (mass = 36.9659026 mass-units, abundance = 24.22%).
This average atomic mass of approximately 35.45 mass-units is why chlorine is listed with this atomic weight in periodic tables. Understanding isotopes and their contributions is essential for applications in fields like chemistry, medicine, and nuclear physics.
Dive deep into the subject with an immersive audiobook experience.
Signup and Enroll to the course for listening the Audio Book
Given:
● Chlorine-35, mass = 34.9688527 mass-units, abundance = 75.78%
● Chlorine-37, mass = 36.9659026 mass-units, abundance = 24.22%
Compute: The average atomic mass of chlorine.
This problem involves calculating the average atomic mass of chlorine, which is a weighted average of the masses of its isotopes. To do this, we need to know the mass and the natural abundance (percentage) of each isotope. Here, we have two isotopes of chlorine: Chlorine-35 and Chlorine-37. We will convert their abundances from percentages to fractions and then use these fractions to calculate the average atomic mass based on their respective masses.
Think of the average atomic mass as a way of calculating a student's grade based on various assessments. If a student scores differently on two exams but spends more time on one exam, we weight the final grade reflects both performance levels proportionally to the importance of each exam. Similarly, in our atomic mass calculation, the percentages act like weights, influencing how much each isotope contributes to the overall average.
Signup and Enroll to the course for listening the Audio Book
To convert percentages to fractions, we simply divide the percentage by 100. For Chlorine-35, we take 75.78% and convert it to decimal form by dividing by 100, resulting in 0.7578. For Chlorine-37, we do the same with 24.22%, resulting in 0.2422. This step is important because we will use these decimal forms as multipliers in the average calculation.
Converting percentages to fractions is like converting a recipe. If a recipe calls for percentages of ingredients (like 75% flour), you would convert that to a usable amount for a specific total quantity. For example, for 100 grams of total ingredients, you would need 75.78 grams of flour, just like we convert percentages to fractions for our calculations.
Signup and Enroll to the course for listening the Audio Book
In this step, we calculate the contribution of each isotope to the average atomic mass. We take the mass of each isotope and multiply it by its respective fraction (the decimal we calculated earlier). For Chlorine-35, we multiply its mass (34.9688527) by its fraction (0.7578), yielding 26.5073 mass-units. For Chlorine-37, we do a similar calculation, yielding 8.9458 mass-units. Finally, we sum these contributions to obtain the average atomic mass of chlorine, which is approximately 35.4531 mass-units.
Imagine you're mixing two different colored paints, and you want to find the average color. You would calculate how much each paint contributes to the final color based on how much paint you have of each color. Similarly, we are weighting how much each isotope contributes to the overall atomic mass based on its abundance.
Signup and Enroll to the course for listening the Audio Book
Therefore, the average atomic mass of chlorine is about 35.45 mass-units.
In conclusion, we see that the average atomic mass for chlorine is 35.4531 mass-units, which we round off to 35.45 mass-units for simplicity. This value reflects the combined contributions of both Chlorine-35 and Chlorine-37 based on their natural abundances.
Think of the average atomic mass as the collective average score for a group of students. The average score tells you how the students performed overall, incorporating everyone’s contributions relative to how much they participated. The average atomic mass does the same by showing how the isotopes of chlorine contribute to what we recognize as chlorine's mass.
Learn essential terms and foundational ideas that form the basis of the topic.
Key Concepts
Isotopes are variants of elements with the same number of protons but different neutrons.
Average atomic mass is a weighted average based on the abundances of isotopes.
Chlorine has two primary isotopes: chlorine-35 and chlorine-37.
See how the concepts apply in real-world scenarios to understand their practical implications.
To find the average atomic mass of chlorine, calculate the contribution of chlorine-35 and chlorine-37 based on their isotopic abundances.
Chlorine-35 has a mass of 34.9688527 and an abundance of 75.78%, while chlorine-37 has a mass of 36.9659026 with an abundance of 24.22%.
Use mnemonics, acronyms, or visual cues to help remember key information more easily.
Chlorine’s weight is not just fate, it’s isotopes that we calculate!
Remember A.B.C. when calculating averages: Abundance x Mass = Contribution!
Once, the isotopes of chlorine had a contest to see who could show off their weight - and together they calculated their average to help everyone understand them better!
Review key concepts with flashcards.
Review the Definitions for terms.
Term: Isotope
Definition:
Atoms of the same element with different numbers of neutrons.
Term: Abundance
Definition:
The relative amount of a particular isotope in a sample, often expressed as a percentage.
Term: Average Atomic Mass
Definition:
The weighted average mass of an element's isotopes based on their natural abundances.
Term: Mass Unit
Definition:
A unit of mass used to express atomic and molecular weights; based on the carbon-12 atom.