Problem 1: Chlorine’s Average Atomic Mass - 6.1 | Unit 2: Atomic Structure | IB Grade 11: Chemistry
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6.1 - Problem 1: Chlorine’s Average Atomic Mass

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Interactive Audio Lesson

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Introduction to Isotopic Abundance

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0:00
Teacher
Teacher

Today, we’ll explore chlorine's average atomic mass and how we calculate it using isotopic abundance. Can anyone remind me what an isotope is?

Student 1
Student 1

Isotopes are atoms of the same element that have different numbers of neutrons.

Teacher
Teacher

Exactly! For example, chlorine has two main stable isotopes: chlorine-35 and chlorine-37. How do we think these isotopes affect the average atomic mass?

Student 2
Student 2

Does the average atomic mass depend on how much of each isotope is present?

Teacher
Teacher

Exactly! That’s called the isotopic abundance. Let’s move on to calculate the average atomic mass. We'll start by looking at the percent abundances of each isotope.

Converting Percent Abundances

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0:00
Teacher
Teacher

First, we need to convert the abundances from percentages to fractions. Can anyone help me convert 75.78% into a decimal?

Student 3
Student 3

It would be 0.7578!

Teacher
Teacher

Great job! Now, how about 24.22%?

Student 4
Student 4

That would be 0.2422!

Teacher
Teacher

Correct! Now, why do we convert them like this?

Student 1
Student 1

Because we need to use these fractions to calculate the contribution of each isotope to the average atomic mass!

Teacher
Teacher

Exactly! Let’s move on to the next step.

Calculating Mass Contributions

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0:00
Teacher
Teacher

Now, we multiply each isotope’s mass by its fraction. For chlorine-35, what’s the calculation?

Student 2
Student 2

It would be 0.7578 multiplied by 34.9688527.

Teacher
Teacher

Excellent! Can anyone calculate that for me?

Student 3
Student 3

That gives approximately 26.5073 mass-units!

Teacher
Teacher

Perfect! Now, let's do the same for chlorine-37.

Student 4
Student 4

We multiply 0.2422 by 36.9659026 to get around 8.9458 mass-units.

Teacher
Teacher

Exactly right! So how do we find the average atomic mass?

Finding the Average Atomic Mass

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0:00
Teacher
Teacher

Now that we have both contributions, what’s the last step?

Student 1
Student 1

Add both contributions together!

Teacher
Teacher

Correct! What do we get?

Student 2
Student 2

26.5073 plus 8.9458 equals 35.4531 mass-units.

Teacher
Teacher

Great job everyone! The average atomic mass of chlorine is about 35.45 mass-units. Why is this important to know?

Student 3
Student 3

Because that’s how it’s listed in the periodic table!

Teacher
Teacher

Exactly! Great work today!

Introduction & Overview

Read a summary of the section's main ideas. Choose from Basic, Medium, or Detailed.

Quick Overview

This section describes how to compute the average atomic mass of chlorine based on the isotopic abundance of its stable isotopes.

Standard

The average atomic mass of chlorine is calculated as a weighted average of its isotopes, chlorine-35 and chlorine-37, using their respective masses and percent abundances. The process involves converting percentages to fractions, multiplying each isotope's mass by its fraction, and summing the results to find the average atomic mass.

Detailed

Chlorine's Average Atomic Mass Calculation

This section provides a systematic method for calculating the average atomic mass of chlorine, which is crucial for understanding its properties in chemistry. Chlorine primarily consists of two stable isotopes: chlorine-35 (mass = 34.9688527 mass-units, abundance = 75.78%) and chlorine-37 (mass = 36.9659026 mass-units, abundance = 24.22%).

Calculation Steps:

  1. Convert Percentages to Fractions: Convert the percent abundances into decimal form:
  2. For chlorine-35: 75.78% = 0.7578
  3. For chlorine-37: 24.22% = 0.2422
  4. Multiply Each Isotope’s Mass by Its Fraction:
  5. Chlorine-35 contribution: 0.7578 × 34.9688527 = 26.5073 mass-units
  6. Chlorine-37 contribution: 0.2422 × 36.9659026 = 8.9458 mass-units
  7. Sum the Contributions: Add the contributions of each isotope to obtain the average atomic mass:
  8. Average atomic mass = 26.5073 + 8.9458 = 35.4531 mass-units.

Significance

This average atomic mass of approximately 35.45 mass-units is why chlorine is listed with this atomic weight in periodic tables. Understanding isotopes and their contributions is essential for applications in fields like chemistry, medicine, and nuclear physics.

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Introduction to Atomic Mass Calculation

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Given:
● Chlorine-35, mass = 34.9688527 mass-units, abundance = 75.78%
● Chlorine-37, mass = 36.9659026 mass-units, abundance = 24.22%
Compute: The average atomic mass of chlorine.

Detailed Explanation

This problem involves calculating the average atomic mass of chlorine, which is a weighted average of the masses of its isotopes. To do this, we need to know the mass and the natural abundance (percentage) of each isotope. Here, we have two isotopes of chlorine: Chlorine-35 and Chlorine-37. We will convert their abundances from percentages to fractions and then use these fractions to calculate the average atomic mass based on their respective masses.

Examples & Analogies

Think of the average atomic mass as a way of calculating a student's grade based on various assessments. If a student scores differently on two exams but spends more time on one exam, we weight the final grade reflects both performance levels proportionally to the importance of each exam. Similarly, in our atomic mass calculation, the percentages act like weights, influencing how much each isotope contributes to the overall average.

Calculating Fractions from Percentages

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  1. Convert percentages to fractions: 75.78% → 0.7578; 24.22% → 0.2422.

Detailed Explanation

To convert percentages to fractions, we simply divide the percentage by 100. For Chlorine-35, we take 75.78% and convert it to decimal form by dividing by 100, resulting in 0.7578. For Chlorine-37, we do the same with 24.22%, resulting in 0.2422. This step is important because we will use these decimal forms as multipliers in the average calculation.

Examples & Analogies

Converting percentages to fractions is like converting a recipe. If a recipe calls for percentages of ingredients (like 75% flour), you would convert that to a usable amount for a specific total quantity. For example, for 100 grams of total ingredients, you would need 75.78 grams of flour, just like we convert percentages to fractions for our calculations.

Weighted Average Calculation of Atomic Mass

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  1. Multiply each isotope’s mass by its fraction:
    • 0.7578 × 34.9688527 = 26.5073 mass-units
    • 0.2422 × 36.9659026 = 8.9458 mass-units
  2. Add them: 26.5073 + 8.9458 = 35.4531 mass-units.

Detailed Explanation

In this step, we calculate the contribution of each isotope to the average atomic mass. We take the mass of each isotope and multiply it by its respective fraction (the decimal we calculated earlier). For Chlorine-35, we multiply its mass (34.9688527) by its fraction (0.7578), yielding 26.5073 mass-units. For Chlorine-37, we do a similar calculation, yielding 8.9458 mass-units. Finally, we sum these contributions to obtain the average atomic mass of chlorine, which is approximately 35.4531 mass-units.

Examples & Analogies

Imagine you're mixing two different colored paints, and you want to find the average color. You would calculate how much each paint contributes to the final color based on how much paint you have of each color. Similarly, we are weighting how much each isotope contributes to the overall atomic mass based on its abundance.

Conclusion: Average Atomic Mass of Chlorine

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Therefore, the average atomic mass of chlorine is about 35.45 mass-units.

Detailed Explanation

In conclusion, we see that the average atomic mass for chlorine is 35.4531 mass-units, which we round off to 35.45 mass-units for simplicity. This value reflects the combined contributions of both Chlorine-35 and Chlorine-37 based on their natural abundances.

Examples & Analogies

Think of the average atomic mass as the collective average score for a group of students. The average score tells you how the students performed overall, incorporating everyone’s contributions relative to how much they participated. The average atomic mass does the same by showing how the isotopes of chlorine contribute to what we recognize as chlorine's mass.

Definitions & Key Concepts

Learn essential terms and foundational ideas that form the basis of the topic.

Key Concepts

  • Isotopes are variants of elements with the same number of protons but different neutrons.

  • Average atomic mass is a weighted average based on the abundances of isotopes.

  • Chlorine has two primary isotopes: chlorine-35 and chlorine-37.

Examples & Real-Life Applications

See how the concepts apply in real-world scenarios to understand their practical implications.

Examples

  • To find the average atomic mass of chlorine, calculate the contribution of chlorine-35 and chlorine-37 based on their isotopic abundances.

  • Chlorine-35 has a mass of 34.9688527 and an abundance of 75.78%, while chlorine-37 has a mass of 36.9659026 with an abundance of 24.22%.

Memory Aids

Use mnemonics, acronyms, or visual cues to help remember key information more easily.

🎵 Rhymes Time

  • Chlorine’s weight is not just fate, it’s isotopes that we calculate!

🧠 Other Memory Gems

  • Remember A.B.C. when calculating averages: Abundance x Mass = Contribution!

📖 Fascinating Stories

  • Once, the isotopes of chlorine had a contest to see who could show off their weight - and together they calculated their average to help everyone understand them better!

🎯 Super Acronyms

C.A.M. - Contribution = Abundance multiplied by Mass.

Flash Cards

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Glossary of Terms

Review the Definitions for terms.

  • Term: Isotope

    Definition:

    Atoms of the same element with different numbers of neutrons.

  • Term: Abundance

    Definition:

    The relative amount of a particular isotope in a sample, often expressed as a percentage.

  • Term: Average Atomic Mass

    Definition:

    The weighted average mass of an element's isotopes based on their natural abundances.

  • Term: Mass Unit

    Definition:

    A unit of mass used to express atomic and molecular weights; based on the carbon-12 atom.