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4.5. Example Problems
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Today, we're going to solve a differential equation. Let's begin with the equation d²y/dx² + 4dy/dx + 13y = 0. Can anyone tell me what we need to do first?
We need to find the characteristic equation!
Exactly! The characteristic equation for this differential equation will be r² + 4r + 13 = 0. Now, who can tell me how to solve for r?
We can use the quadratic formula, right?
Yes! The quadratic formula is r = (-b ± √D)/2a. What's the discriminant D here?
D = b² - 4ac, so it would be 4² - 4 × 1 × 13, which gives us -36.
Correct! Since D is negative, what does that tell us about our roots?
It means they will be complex conjugates!
That's right! The roots are r = -2 ± 3i. Who can write down the general solution for y(x)?
It will be y(x) = e^(-2x)(C₁ cos(3x) + C₂ sin(3x)).
Excellent! This solution represents a damped oscillation. Let’s summarize: What does each part of this solution represent?
The e^(-2x) part shows the decay of amplitude, and the cos and sin parts show oscillatory behavior.
Great recap! Remember this form, as it’s essential for understanding oscillations.
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Now that we understand how to solve these equations, let’s examine an application in civil engineering. For example, consider a building with a mass of 1 kg, a damping coefficient of 2, and a stiffness of 5. What would the differential equation look like?
It would be d²y/dt² + 2dy/dt + 5y = 0.
Correct! Let's find the roots using the characteristic equation. Who can summarize our findings so far?
We get r = -1 ± 2i, so the general solution would be y(t) = e^(-t)(C₁ cos(2t) + C₂ sin(2t)).
Exactly! What does this solution indicate concerning the building's vibrations?
The building vibrates at a frequency of 2 rad/s with exponential decay due to the damping effect.
Precisely! Understanding this helps engineers design more durable and safer buildings. Can anyone explain why damping is important in this context?
Damping is crucial because it reduces the amplitude of vibrations which could lead to structural failure.
Well done! Damping prevents excessive oscillations, thereby ensuring structures remain safe under dynamic loads.
Overview
Short Summary
This section presents practical example problems illustrating the application of second-order linear differential equations with complex roots.
Medium Summary
The section provides two example problems related to differential equations that display complex roots, including their solutions and applications in civil engineering contexts. The first example demonstrates a numerical solution process, while the second example discusses the impact of structural damping in buildings.
Detailed Summary
In this section, we explore two example problems focusing on second-order linear differential equations that yield complex roots. Example 1 illustrates the solving of a homogeneous differential equation, presenting the characteristic equation and deriving the general solution. The roots derived are complex conjugates, which leads to the formulation of the general oscillatory solution that characterizes the behavior of the system. This foundational method is crucial for understanding the vibrational responses of structures.
Example 2 extends these concepts into civil engineering applications, where real-world implications are assessed in the modeling of damped vibrations in buildings. By assigning values for mass, damping coefficient, and stiffness, students can observe how the resulting solutions illustrate the system's behavior during oscillations as well as the implications for architectural safety. These examples serve as a fundamental bridge between the theoretical aspects of differential equations and their practical applications in engineering.
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Audio Book
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Create a free accountExample 1: Solve:
d2y dy +4 +13y =0
dx2 dx
Solution: Characteristic equation: −4± 16−52 r2+4r+13=0⇒r = =−2±3i
So the general solution is: y(x)=e−2x(C cos3x+C sin3x)
Detailed Explanation
In this example, we are given a second-order differential equation in standard form. To solve it, we first need to find the characteristic equation which is derived from the original differential equation. After rearranging the equation and factoring, we find the roots, which in this case are complex: r = −2 ± 3i. These roots indicate that our solution will involve exponential decay multiplied by sinusoidal functions. The general solution derived from these roots is y(x) = e^(-2x)(C cos(3x) + C sin(3x)), where C is a constant determined by boundary conditions.
Examples & Analogies
Think of a swing that is in a park. If you give the swing a push, it moves back and forth. Now, imagine the swing isn’t just moving normally; it gradually gets slower until it eventually stops. In the context of our example, the swing's decreasing motion and eventual stillness is analogous to the behavior of the solution: it vibrates (like the sine and cosine components) but also slows down over time (exponential decay).
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Create a free accountExample 2 (Application in Civil Engineering): A building undergoes a damped vibration modeled by:
d2y dy m +c +ky =0 dt2 dt
With: • Mass m=1 • Damping coefficient c=2 • Stiffness k =5
Then: d2y dy +2 +5y =0⇒r =−1±2i⇒y(t)=e−t(C cos2t+C sin2t)
Detailed Explanation
This example illustrates a real-world application in civil engineering, where the performance of a building under vibrations is modeled. The differential equation represents a mass-spring-damper system characterized by a specific mass, damping coefficient, and stiffness. When we analyze the characteristic equation that arises from this setup, we find complex roots, r = −1 ± 2i. This suggests that the system will exhibit damped oscillations. The solution represents how the building vibrates over time (y(t) = e^(-t)(C cos(2t) + C sin(2t))). The e^(-t) part implies the building’s vibrations decay over time, indicating safety against potential failures.
Examples & Analogies
Imagine a car dampening the bumps while driving along a rocky road. Just like the shock absorbers in the car’s suspension system, our example describes how a building responds to vibrations. The mass of the building and the damping effect of its materials work together to avoid excessive movements. To visualize it further, think of a tightrope walker swaying gently; as they shift positions, their movements gradually lessen until they stabilize, similar to how the building's vibrations decrease due to damping.
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Key concepts
Core takeaways and short definitions to help you quickly recall the key ideas from this section.
- Characteristic Equation:
The derived polynomial equation that helps to determine the nature of solutions for the differential equation.
- Damped Vibrations:
Vibrations that reduce in amplitude over time, essential for assessing the performance of structures.
- Complex Roots:
Indicate oscillatory motion in systems, with implications for structural designs.
Examples
Step-by-step examples to apply the section's ideas and test your understanding.
Example 1 demonstrates the solution of the differential equation d²y/dx² + 4dy/dx + 13y = 0, leading to complex conjugate roots.
Example 2 illustrates a real application in civil engineering, where damped vibrations of a building are modeled and interpreted based on given parameters.
Memory aids
When roots are complex, oscillations can flex, with damping in hand, we prevent structures from wreck.
Imagine a tall building swaying in the wind, but with damping systems in place, it remains steady, preventing any damage.
Flash Cards
Glossary
Damped Oscillation
A type of oscillation that decreases in amplitude over time due to energy loss, often modeled by an exponential decay function.
Complex Conjugate Roots
Roots of a polynomial that appear in pairs of the form a ± bi, where i is the imaginary unit.
Characteristic Equation
The polynomial equation derived from a differential equation that helps determine the nature of its solutions.
Damping Coefficient
A parameter that quantifies the damping effect in a system, influencing the rate of decay of oscillations.