Practice Rate-Determining Step and the Steady-State Approximation - 4.6 | Unit 6: Chemical Kinetics | IB Grade 11: Chemistry
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Rate-Determining Step and the Steady-State Approximation

4.6 - Rate-Determining Step and the Steady-State Approximation

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Practice Questions

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Question 1 Easy

What is the rate-determining step (RDS)?

💡 Hint: Think about which step limits the reaction speed.

Question 2 Easy

Explain how the steady-state approximation is used in kinetic studies.

💡 Hint: Consider why it's useful to assume intermediates don't change significantly during the reaction.

1 more question available

Interactive Quizzes

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Question 1

What defines the rate-determining step in a multi-step reaction?

The fastest step
The slowest step
The step with the most intermediates

💡 Hint: Think about which step limits the speed of the entire reaction.

Question 2

True or False: The steady-state approximation allows for changing concentrations of intermediates.

True
False

💡 Hint: What does 'constant' mean in this context?

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Challenge Problems

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Challenge 1 Hard

Consider a reaction mechanism with three steps: A + B ⇌ C (fast), C → D (slow, RDS), and D → E (fast). Using the steady-state approximation, derive the rate law for the formation of E.

💡 Hint: What equilibrium constant can help connect A and B to C?

Challenge 2 Hard

Explain how the introduction of a catalyst could change the rate-determining step in a reaction mechanism.

💡 Hint: Consider how catalysts affect energy barriers.

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