Example of Latent Heat Calculation - 10.3.5 | 10. Quantity of Heat | ICSE Class 11 Engineering Science
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Interactive Audio Lesson

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Latent Heat of Fusion

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0:00
Teacher
Teacher

Today we're going to dive into latent heat, specifically the latent heat of fusion. This is the heat required to change a solid into a liquid without changing its temperature. Can anyone give an example of a substance that undergoes this change?

Student 1
Student 1

Ice melting into water!

Teacher
Teacher

Exactly! So, when ice melts at 0Β°C, it absorbs heat without rising in temperature. This heat is called the latent heat of fusion, and for ice, it's 334 kJ/kg. Remember this number; a nice acronym is 'FUSE'β€”F for Fusion, U for Up (as in temperature remains the same), S for Solid to liquid, and E for Energy needed.

Student 2
Student 2

Got it! So, if I have 1 kg of ice, I would need 334 kJ of heat to melt it, right?

Teacher
Teacher

Excellent! So how much heat would you need for 0.5 kg of ice?

Student 3
Student 3

That would be 167 kJ.

Teacher
Teacher

Correct! 0.5 kg times 334 kJ/kg gives us 167 kJ. Always remember: for half the mass, halve the energy!

Latent Heat of Vaporization

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0:00
Teacher
Teacher

Next, let’s look at the latent heat of vaporization. This is the heat required to turn a liquid into a gas without changing the temperature. Anyone know the latent heat of vaporization for water?

Student 4
Student 4

Isn't it 2260 kJ/kg?

Teacher
Teacher

Spot on! Now, using the formula Q = mL, if you wanted to vaporize 0.2 kg of water, how much heat would you need?

Student 1
Student 1

I would calculate Q as 0.2 kg multiplied by 2260 kJ/kg, which equals 452 kJ.

Teacher
Teacher

Right again! That means you need 452 kJ to turn 0.2 kg of water at 100Β°C into steamβ€”keep those numbers handy!

Application of Latent Heat Calculations

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0:00
Teacher
Teacher

Let's apply what we've learned. Imagine you're making ice cream using an ice mixture. How does the principle of latent heat come into play?

Student 2
Student 2

The ice absorbs heat as it melts, which cools the mixture down without raising its temperature!

Teacher
Teacher

Exactly! The melting ice helps keep the ice cream base cool while absorbing heat, thus utilizing the latent heat of fusion beautifully in the process.

Student 3
Student 3

So it’s about the balance of energy transfer, not just the temperature!

Teacher
Teacher

Very insightful! We'll see this energy balance in other scenarios, such as boiling water, where heat absorbed leads to a phase change.

Introduction & Overview

Read a summary of the section's main ideas. Choose from Basic, Medium, or Detailed.

Quick Overview

This section explains the calculation of latent heat, illustrating how it is used in phase changes without a temperature change.

Standard

The section provides a detailed analysis of latent heat calculation, focusing on the latent heat of fusion and vaporization through examples. It highlights how to apply the formula Q=mL to find the heat required for phase changes.

Detailed

Example of Latent Heat Calculation

This section covers the essential concept of latent heat and its calculation in phase changes. Latent heat is defined as the heat needed to change the state of a substance without altering its temperature. Two critical types are elaborated:

Types of Latent Heat

  1. Latent Heat of Fusion: Heat required for a solid to become liquid at a constant temperature (e.g., melting of ice).
  2. Latent Heat of Vaporization: Heatrequired for a liquid to become a gas at constant temperature (e.g., boiling of water).

Formula

The general formula used for calculating latent heat is:

Q = mL
- Q = Heat energy (in Joules)
- m = Mass of the substance (in kilograms)
- L = Latent heat of fusion or vaporization (in J/kg)

Examples

An example provided is the calculation of heat required to melt 500 grams of ice at 0Β°C using the latent heat of fusion. This calculation facilitates understanding of how to apply the formula in practical scenarios. The latent heat of fusion of ice is specified as 334 kJ/kg, leading to:

Q = 0.5 Γ— 334 = 167 kJ

This shows that 167 kJ of heat is necessary to melt 500 grams of ice.

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Audio Book

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Introduction to Latent Heat Example

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To melt 500 grams of ice at 0Β°C, using the latent heat of fusion:
Q=0.5Γ—334=167 kJ
Q = 0.5 imes 334 = 167 \, \text{kJ}

Detailed Explanation

In this example, we are calculating how much heat energy is needed to melt ice. The formula used is Q = mL, where Q is the heat energy required, m is the mass of the substance (in kilograms), and L is the latent heat of fusion (in J/kg). In this case, 500 grams of ice needs to be melted, which is equal to 0.5 kilograms. The latent heat of fusion for ice is given as 334 kJ/kg. Therefore, by multiplying the mass (0.5 kg) by the latent heat (334 kJ/kg), we find that 167 kJ of heat is required to melt the ice.

Examples & Analogies

Imagine you are trying to make ice cubes melt to fill a glass with cold water. You notice that when you put ice in the glass, it doesn't immediately turn into water but instead just sits there until it has absorbed enough heat. This is because the ice requires a specific amount of heat to change its state from solid to liquid without a temperature change. In total, to melt the 500 grams of ice, you would need to use 167 kJ of energy from your surroundings to successfully complete this state change.

Definitions & Key Concepts

Learn essential terms and foundational ideas that form the basis of the topic.

Key Concepts

  • Latent Heat: Heat absorbed during a phase change without temperature change.

  • Latent Heat of Fusion: Specifically pertains to the solid-to-liquid transition.

  • Latent Heat of Vaporization: Pertains to the liquid-to-gas transition.

Examples & Real-Life Applications

See how the concepts apply in real-world scenarios to understand their practical implications.

Examples

  • An example provided is the calculation of heat required to melt 500 grams of ice at 0Β°C using the latent heat of fusion. This calculation facilitates understanding of how to apply the formula in practical scenarios. The latent heat of fusion of ice is specified as 334 kJ/kg, leading to:

  • Q = 0.5 Γ— 334 = 167 kJ

  • This shows that 167 kJ of heat is necessary to melt 500 grams of ice.

Memory Aids

Use mnemonics, acronyms, or visual cues to help remember key information more easily.

🎡 Rhymes Time

  • Ice can melt, so cold and bright, with energy absorbedβ€”it feels just right!

πŸ“– Fascinating Stories

  • Imagine a winter day where the sun shines bright. The warmth brings ice to meltβ€”but wait! It stays the same! This magic is called latent heat, where energy is in play.

🧠 Other Memory Gems

  • F.L.E.E. - Fusion, Latent, Energy Endurance – remember how energy endures in phase changes!

🎯 Super Acronyms

L.A.V.E. - Latent, Absorbed, Vaporization, Energy – for remembering vaporization basics.

Flash Cards

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Glossary of Terms

Review the Definitions for terms.

  • Term: Latent Heat

    Definition:

    Heat required to change the state of a substance without changing its temperature.

  • Term: Latent Heat of Fusion

    Definition:

    The heat required to change a substance from solid to liquid at constant temperature.

  • Term: Latent Heat of Vaporization

    Definition:

    The heat required to change a substance from liquid to gas at constant temperature.