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Today we'll explore the common emitter amplifier, an essential circuit in analog electronics. Can anyone tell me what the main function of this amplifier is?
Isn't it used to amplify voltages?
Exactly! It amplifies voltages. Now, it primarily achieves this through a specific configuration. What do you think are the important components involved?
I think transistors are crucial parts of the circuit?
Yes, we use transistors, particularly bipolar junction transistors, in a common emitter configuration. Now, let's remember: the acronym "ACT" can help us recall the primary role of an amplifier β 'Amplify, Couple, Transform'.
What do you mean by coupling?
Great question! Coupling refers to connecting stages of circuits together to ensure proper signal transmission, which often involves matching impedances. To summarize, the common emitter amplifier is vital for voltage amplification, utilizing well-configured transistors for optimal performance.
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In our amplifier analysis, we use current mirrors for biasing the transistor. Can someone explain why biasing is critical?
It helps to maintain a constant operating point for the transistors, right?
Exactly! Biasing keeps the transistor in the active region. In our circuit, if we want to ensure equal currents in matched transistors, we must use current mirrors effectively. For instance, if we want a collector current of 2 mA, what would that translate to for the base current if the transistor's beta is 100?
That would be 20 Β΅A, since the collector current is beta times the base current.
Well done! So, to achieve this, we must choose precise resistor values for biasing. Let's take a note: for our circuit, this involves calculating resistances accurately to ensure the expected collector current.
Can you remind us how we calculate that resistance?
Of course! The resistance can be calculated using Ohm's law and, in our case, comes out to be 570 kβ¦. So, biasing is essential for optimal performance in our common emitter setup.
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Let's now calculate the voltage gain of our common emitter amplifier. What do we need for this calculation?
I think we need to know the output resistance and the transconductance?
That's correct! The formula for voltage gain is negative transconductance times output resistance. Can we recall the values we calculated for output resistances?
I remember the output resistance was around 25 kβ¦!
Exactly! Plugging in the values gives us a calculated voltage gain close to 2000. Let's remember that voltage gain often reflects how effectively an amplifier can increase signal strength. Summarizing, output resistance and voltage gain are decisive factors that impact circuit design.
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What happens if we consider non-ideal conditions like finite beta and various early voltages?
The current might not match as perfectly?
Exactly. If there is a mismatch, it can lead to voltage deviation from our calculations. In practice, the output voltage can significantly change if early voltage differs between devices. A rule here is to always consider these imperfections; they can shift our expected outcomes.
Is there a way to model this effect?
Great thought! Modeling these variations would involve adjusting our designs to account for tolerances. Remember, unanticipated variations in component behavior can lead to significant performance differences in analog circuits.
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The common emitter amplifier leverages current mirrors to bias active loads and achieve specific collector currents. Key parameters such as output resistance and voltage gain are also calculated, demonstrating the amplifier's high performance.
The common emitter amplifier is an essential configuration used extensively in analog electronic circuits. This section delves into the principles behind this amplifier, especially its application using current mirrors for biasing active loads. Constant collector currents are crucial for the amplifier's operation, and here, it is established that both transistors within the common emitter setup can be assumed identical. By ensuring that the base currents of the corresponding configurations are equal, the appropriate biasing can be achieved using matched resistances. The section includes a numerical example that illustrates how to calculate the collector current and determine the necessary resistor values for establishing a desired output current.
Following initial calculations, the section transitions to establishing the small-signal model for the amplifier. Key characteristics such as output resistance and voltage gain are calculated, showcasing the amplifier's performance metrics, which suggest a high output resistance and a significant voltage gain close to 2000. The section also traces potential deviations in output voltage when finite base currents and mismatched early voltages are considered. Lastly, implications of current mirrors are outlined in more complex examples such as differential amplifiers, revealing the versatility and utility of the common emitter amplifier in real-world applications.
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Dear students, welcome back after the break. So, we are going through different numerical examples and now we are going to talk about one common emitter amplifier which is using current mirror and particularly to bias the active load say Q.
In this section, we are discussing a specific type of amplifier known as the common emitter amplifier. This amplifier uses a current mirror to help bias the active load, which refers to the component Q that is essential for the amplifier's operation. The design of this amplifier allows for better control of the current flowing through the amplifying devices, enabling more efficient operation.
Think of this amplifier as a specialized valve (the current mirror) controlling the flow of water (electrons) through different pipes (transistors). By using this valve, we can ensure that the right amount of water flows through our system, improving performance.
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To get the I current of transistor-1 and collector current of transistor-4 equal, we want the current flow through transistor-2 to be equal to current flow through transistor-1...we are using current mirror and transistor-1; it is the amplifying device then we are assuming that Q and Q are identical and also we are assuming that whatever this Q and Q are also identical.
This section explains the concept of current matching within the circuit. To ensure that the currents in various transistors are equal, the use of identical transistors (Q1 and Q2) is crucial. This identical nature allows for consistent performance based on the assumption that they operate under the same conditions. When the current through one transistor is accurately mirrored in another, it establishes a reliable amplification.
Imagine you have two identical water bottles; if you fill one halfway, and another is designed to mirror that, it will also match halfway. This ensures that both bottles have the same amount of water, just as the transistors have the same current.
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So, to get the value of this R1 to get 20 Β΅A, the R1 should be = 570 kβ¦. So, the value of this resistance as well as this resistance they are = 570 kβ¦.
In this part, we learn how to determine the value of bias resistance needed for the desired current. By calculating that a resistance value of 570 k⦠is necessary to achieve a bias current of 20 ¡A, we can ensure that the amplifier operates effectively within its specifications. This resistance plays a key role in controlling the base current going into the transistor.
Consider this like setting up a water fountain; if you want a specific water flow (current), you must adjust the size of the nozzle (resistance). A larger nozzle allows more water, just as a lower resistance allows more current.
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With this information let us try to find the small signal output resistance and voltage gain of the amplifier. So, we are assuming both the devices are in active region.
Here, we evaluate the amplifier's output resistance and the voltage gain based on the previously established values and design. The small signal output resistance is derived from the individual resistances of the transistors and the overall configuration. The provided calculations indicate a high voltage gain expected from the amplifier, which signifies its strength in amplifying signals.
Itβs similar to a microphone boosting your voice; it takes the small sound (input) and increases it to a level that can be heard clearly in a large auditorium (output). The output resistance is like the size of the microphone's speaker; it affects how efficiently sound can be projected.
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Now we like to get what will be the gain of this amplifier. ... the voltage here it is 12 β 0.6, so that is 11.4 V.
This section derives the DC output voltage from the amplifier, illustrating the circuit's practical functionality. The voltage across components is crucial as it influences how well the amplifier will perform. The DC output voltage calculation takes into account voltage drops and equivalent currents, ultimately leading to a consistent output voltage maintained at 11.4 V.
If you think of a car engine, the voltage is akin to fuel in the tank. To ensure the car runs smoothly, the right amount of fuel (voltage) must be supplied, so it functions efficientlyβstarting, running, and accelerating as needed.
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Key Concepts
Transistor: A semiconductor device that can amplify current.
Biasing: The process of setting a transistor's operating point.
Current Mirror: Circuit configuration that reflects a current across multiple transistors.
Voltage Gain: The ratio of output voltage to input voltage in an amplifier.
Output Resistance: The resistance that the circuit presents at the output.
See how the concepts apply in real-world scenarios to understand their practical implications.
HTML5 Codec Example Amplification: Applying a voltage through common emitter.
Calculating Base Current: Using Ξ² to derive base current from collector current in a common emitter amplifier.
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Common emitter, high and bright, amplifying signals to new height!
Imagine a tiny signal trying to shout above noise. The common emitter amplifier is like a megaphone, making that signal louder and clearer for all to hear.
Remember 'BATS' β for Base current, Active region, Transistor, Signal gain when learning about amplifiers.
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Review the Definitions for terms.
Term: Common Emitter Amplifier
Definition:
A basic transistor amplifier configuration used primarily for voltage amplification.
Term: Current Mirror
Definition:
A circuit configuration that copies a current from one active device to another, maintaining consistent currents.
Term: Beta (Ξ²)
Definition:
The current gain of a transistor, representing the ratio of collector current to base current.
Term: Output Resistance (Rout)
Definition:
The resistance seen by the output of an amplifier, affecting gain and performance.
Term: Voltage Gain (Av)
Definition:
The factor by which an amplifier increases the voltage of a signal.
Term: Early Voltage (VA)
Definition:
A parameter that indicates the output conductance of a transistor, impacting its performance.